google search using python3 script
-1
This is the code that I'm using:
import requests, sys, webbrowser, bs4
res = requests.get('https://google.com/search?q='+''.join(sys.argv[1:]))
res.raise_for_status()
soup = bs4.BeautifulSoup(res.text,"html.parser")
linkElements = soup.select('.r a')
linkToOpen = min(3, len(linkElements))
for i in range(linkToOpen):
webbrowser.open('https://google.com'+linkElements[i].get('href'))
When I try to run this code:(python search.py 'something').
I'm getting the following error:
python-3.x
edited Nov 21 '18 at 7:29
kit
1,1063616
asked Nov 21 '18 at 7:10
Mysteroius
33
add a comment |
-1
This is the code that I'm using:
import requests, sys, webbrowser, bs4
res = requests.get('https://google.com/search?q='+''.join(sys.argv[1:]))
res.raise_for_status()
soup = bs4.BeautifulSoup(res.text,"html.parser")
linkElements = soup.select('.r a')
linkToOpen = min(3, len(linkElements))
for i in range(linkToOpen):
webbrowser.open('https://google.com'+linkElements[i].get('href'))
When I try to run this code:(python search.py 'something').
I'm getting the following error:
python-3.x
edited Nov 21 '18 at 7:29
kit
1,1063616
asked Nov 21 '18 at 7:10
Mysteroius
33
can you please put your text error message instead of image.
– Ashish Kamble
Nov 21 '18 at 7:19
when i'm running : python search.py 'content to be searched' error im getting at res.raise_for_status() which simply say HTTPError raise, 503 server error..it does not redirecting me to resulted query
– Mysteroius
Nov 21 '18 at 8:20
add a comment |
-1
-1
-1
This is the code that I'm using:
import requests, sys, webbrowser, bs4
res = requests.get('https://google.com/search?q='+''.join(sys.argv[1:]))
res.raise_for_status()
soup = bs4.BeautifulSoup(res.text,"html.parser")
linkElements = soup.select('.r a')
linkToOpen = min(3, len(linkElements))
for i in range(linkToOpen):
webbrowser.open('https://google.com'+linkElements[i].get('href'))
When I try to run this code:(python search.py 'something').
I'm getting the following error:
python-3.x
edited Nov 21 '18 at 7:29
kit
1,1063616
asked Nov 21 '18 at 7:10
Mysteroius
33
This is the code that I'm using:
import requests, sys, webbrowser, bs4
res = requests.get('https://google.com/search?q='+''.join(sys.argv[1:]))
res.raise_for_status()
soup = bs4.BeautifulSoup(res.text,"html.parser")
linkElements = soup.select('.r a')
linkToOpen = min(3, len(linkElements))
for i in range(linkToOpen):
webbrowser.open('https://google.com'+linkElements[i].get('href'))
When I try to run this code:(python search.py 'something').
I'm getting the following error:
python-3.x
python-3.x
edited Nov 21 '18 at 7:29
kit
1,1063616
asked Nov 21 '18 at 7:10
Mysteroius
33
edited Nov 21 '18 at 7:29
kit
1,1063616
asked Nov 21 '18 at 7:10
Mysteroius
33
edited Nov 21 '18 at 7:29
kit
1,1063616
edited Nov 21 '18 at 7:29
kit
1,1063616
edited Nov 21 '18 at 7:29
kit
1,1063616
1,1063616
asked Nov 21 '18 at 7:10
Mysteroius
33
asked Nov 21 '18 at 7:10
Mysteroius
33
asked Nov 21 '18 at 7:10
Mysteroius
33
33
can you please put your text error message instead of image.
– Ashish Kamble
Nov 21 '18 at 7:19
when i'm running : python search.py 'content to be searched' error im getting at res.raise_for_status() which simply say HTTPError raise, 503 server error..it does not redirecting me to resulted query
– Mysteroius
Nov 21 '18 at 8:20
add a comment |
can you please put your text error message instead of image.
– Ashish Kamble
Nov 21 '18 at 7:19
when i'm running : python search.py 'content to be searched' error im getting at res.raise_for_status() which simply say HTTPError raise, 503 server error..it does not redirecting me to resulted query
– Mysteroius
Nov 21 '18 at 8:20
can you please put your text error message instead of image.
– Ashish Kamble
Nov 21 '18 at 7:19
can you please put your text error message instead of image.
– Ashish Kamble
Nov 21 '18 at 7:19
when i'm running : python search.py 'content to be searched' error im getting at res.raise_for_status() which simply say HTTPError raise, 503 server error..it does not redirecting me to resulted query
– Mysteroius
Nov 21 '18 at 8:20
when i'm running : python search.py 'content to be searched' error im getting at res.raise_for_status() which simply say HTTPError raise, 503 server error..it does not redirecting me to resulted query
– Mysteroius
Nov 21 '18 at 8:20
add a comment |
1 Answer
1
active
oldest
votes
0
Use res.status_code to determine the status,
If it returns 200, and still you are getting the error, then you might be having a bad connection
Otherwise, you must try entering the URL as 'https://www.google.com/', which is the standard URL we usually see on the browser.
Let me know if it helped you or not.
answered Nov 21 '18 at 7:21
Preetkaran Singh
101111
i have changed the format of url address still i'm getting he same error.
– Mysteroius
Nov 21 '18 at 8:24
is the status_code returning 200?
– Preetkaran Singh
Nov 21 '18 at 10:41
if you are getting any value other than 200, then you must check your internet connection, I think you are getting 503
– Preetkaran Singh
Nov 21 '18 at 10:43
played with my internet connection and Finally it returned 200 and it's also working i don't what was the problem but earlier it was not running, Thanks for the suggestion bro:)
– Mysteroius
Nov 21 '18 at 11:53
Glad to know that you got your code running fine, Happy coding :)
– Preetkaran Singh
Nov 21 '18 at 16:18
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Use res.status_code to determine the status,
If it returns 200, and still you are getting the error, then you might be having a bad connection
Otherwise, you must try entering the URL as 'https://www.google.com/', which is the standard URL we usually see on the browser.
Let me know if it helped you or not.
answered Nov 21 '18 at 7:21
Preetkaran Singh
101111
i have changed the format of url address still i'm getting he same error.
– Mysteroius
Nov 21 '18 at 8:24
is the status_code returning 200?
– Preetkaran Singh
Nov 21 '18 at 10:41
if you are getting any value other than 200, then you must check your internet connection, I think you are getting 503
– Preetkaran Singh
Nov 21 '18 at 10:43
played with my internet connection and Finally it returned 200 and it's also working i don't what was the problem but earlier it was not running, Thanks for the suggestion bro:)
– Mysteroius
Nov 21 '18 at 11:53
Glad to know that you got your code running fine, Happy coding :)
– Preetkaran Singh
Nov 21 '18 at 16:18
add a comment |
0
Use res.status_code to determine the status,
If it returns 200, and still you are getting the error, then you might be having a bad connection
Otherwise, you must try entering the URL as 'https://www.google.com/', which is the standard URL we usually see on the browser.
Let me know if it helped you or not.
answered Nov 21 '18 at 7:21
Preetkaran Singh
101111
i have changed the format of url address still i'm getting he same error.
– Mysteroius
Nov 21 '18 at 8:24
is the status_code returning 200?
– Preetkaran Singh
Nov 21 '18 at 10:41
if you are getting any value other than 200, then you must check your internet connection, I think you are getting 503
– Preetkaran Singh
Nov 21 '18 at 10:43
played with my internet connection and Finally it returned 200 and it's also working i don't what was the problem but earlier it was not running, Thanks for the suggestion bro:)
– Mysteroius
Nov 21 '18 at 11:53
Glad to know that you got your code running fine, Happy coding :)
– Preetkaran Singh
Nov 21 '18 at 16:18
add a comment |
0
0
0
Use res.status_code to determine the status,
If it returns 200, and still you are getting the error, then you might be having a bad connection
Otherwise, you must try entering the URL as 'https://www.google.com/', which is the standard URL we usually see on the browser.
Let me know if it helped you or not.
answered Nov 21 '18 at 7:21
Preetkaran Singh
101111
Use res.status_code to determine the status,
If it returns 200, and still you are getting the error, then you might be having a bad connection
Otherwise, you must try entering the URL as 'https://www.google.com/', which is the standard URL we usually see on the browser.
Let me know if it helped you or not.
answered Nov 21 '18 at 7:21
Preetkaran Singh
101111
edited Nov 21 '18 at 10:44
answered Nov 21 '18 at 7:21
Preetkaran Singh
101111
answered Nov 21 '18 at 7:21
Preetkaran Singh
101111
answered Nov 21 '18 at 7:21
Preetkaran Singh
101111
101111
i have changed the format of url address still i'm getting he same error.
– Mysteroius
Nov 21 '18 at 8:24
is the status_code returning 200?
– Preetkaran Singh
Nov 21 '18 at 10:41
if you are getting any value other than 200, then you must check your internet connection, I think you are getting 503
– Preetkaran Singh
Nov 21 '18 at 10:43
played with my internet connection and Finally it returned 200 and it's also working i don't what was the problem but earlier it was not running, Thanks for the suggestion bro:)
– Mysteroius
Nov 21 '18 at 11:53
Glad to know that you got your code running fine, Happy coding :)
– Preetkaran Singh
Nov 21 '18 at 16:18
add a comment |
i have changed the format of url address still i'm getting he same error.
– Mysteroius
Nov 21 '18 at 8:24
is the status_code returning 200?
– Preetkaran Singh
Nov 21 '18 at 10:41
if you are getting any value other than 200, then you must check your internet connection, I think you are getting 503
– Preetkaran Singh
Nov 21 '18 at 10:43
played with my internet connection and Finally it returned 200 and it's also working i don't what was the problem but earlier it was not running, Thanks for the suggestion bro:)
– Mysteroius
Nov 21 '18 at 11:53
Glad to know that you got your code running fine, Happy coding :)
– Preetkaran Singh
Nov 21 '18 at 16:18
i have changed the format of url address still i'm getting he same error.
– Mysteroius
Nov 21 '18 at 8:24
i have changed the format of url address still i'm getting he same error.
– Mysteroius
Nov 21 '18 at 8:24
is the status_code returning 200?
– Preetkaran Singh
Nov 21 '18 at 10:41
is the status_code returning 200?
– Preetkaran Singh
Nov 21 '18 at 10:41
if you are getting any value other than 200, then you must check your internet connection, I think you are getting 503
– Preetkaran Singh
Nov 21 '18 at 10:43
if you are getting any value other than 200, then you must check your internet connection, I think you are getting 503
– Preetkaran Singh
Nov 21 '18 at 10:43
played with my internet connection and Finally it returned 200 and it's also working i don't what was the problem but earlier it was not running, Thanks for the suggestion bro:)
– Mysteroius
Nov 21 '18 at 11:53
played with my internet connection and Finally it returned 200 and it's also working i don't what was the problem but earlier it was not running, Thanks for the suggestion bro:)
– Mysteroius
Nov 21 '18 at 11:53
Glad to know that you got your code running fine, Happy coding :)
– Preetkaran Singh
Nov 21 '18 at 16:18
Glad to know that you got your code running fine, Happy coding :)
– Preetkaran Singh
Nov 21 '18 at 16:18
add a comment |
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can you please put your text error message instead of image.
– Ashish Kamble
Nov 21 '18 at 7:19
when i'm running : python search.py 'content to be searched' error im getting at res.raise_for_status() which simply say HTTPError raise, 503 server error..it does not redirecting me to resulted query
– Mysteroius
Nov 21 '18 at 8:20