SimpleDateFormat parse(string str) doesn't throw an exception when str = 2011/12/12aaaaaaaaa?
up vote
9
down vote
favorite
Here is an example:
public MyDate() throws ParseException {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1));
}
2011/12/12aaa is not a valid date string. However the function prints "Mon Dec 12 00:00:00 PST 2011" and ParseException isn't thrown.
Can anyone tell me how to let SimpleDateFormat treat "2011/12/12aaa" as an invalid date string and throw an exception?
java simpledateformat parseexception
add a comment |
up vote
9
down vote
favorite
Here is an example:
public MyDate() throws ParseException {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1));
}
2011/12/12aaa is not a valid date string. However the function prints "Mon Dec 12 00:00:00 PST 2011" and ParseException isn't thrown.
Can anyone tell me how to let SimpleDateFormat treat "2011/12/12aaa" as an invalid date string and throw an exception?
java simpledateformat parseexception
add a comment |
up vote
9
down vote
favorite
up vote
9
down vote
favorite
Here is an example:
public MyDate() throws ParseException {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1));
}
2011/12/12aaa is not a valid date string. However the function prints "Mon Dec 12 00:00:00 PST 2011" and ParseException isn't thrown.
Can anyone tell me how to let SimpleDateFormat treat "2011/12/12aaa" as an invalid date string and throw an exception?
java simpledateformat parseexception
Here is an example:
public MyDate() throws ParseException {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1));
}
2011/12/12aaa is not a valid date string. However the function prints "Mon Dec 12 00:00:00 PST 2011" and ParseException isn't thrown.
Can anyone tell me how to let SimpleDateFormat treat "2011/12/12aaa" as an invalid date string and throw an exception?
java simpledateformat parseexception
java simpledateformat parseexception
edited Jan 9 '16 at 11:10
eis
34.2k894141
34.2k894141
asked Dec 8 '11 at 8:44
Terminal User
3981917
3981917
add a comment |
add a comment |
6 Answers
6
active
oldest
votes
up vote
12
down vote
accepted
The JavaDoc on parse(...)
states the following:
parsing does not necessarily use all characters up to the end of the string
It seems like you can't make SimpleDateFormat
throw an exception, but you can do the following:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
ParsePosition p = new ParsePosition( 0 );
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1,p));
if(p.getIndex() < t1.length()) {
throw new ParseException( t1, p.getIndex() );
}
Basically, you check whether the parse consumed the entire string and if not you have invalid input.
add a comment |
up vote
4
down vote
To chack whether a date is valid
The following method returns if the date is in valid otherwise it will return false.
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
Have a look on the following class which can check whether the date is valid or not
** Sample Example**
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class DateValidCheck {
public static void main(String args) {
if(new DateValidCheck().isValidDate("2011/12/12aaa")){
System.out.println("...date is valid");
}else{
System.out.println("...date is invalid...");
}
}
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
}
add a comment |
up vote
2
down vote
After it successfully parsed the entire pattern string SimpleDateFormat
stops evaluating the data it was given to parse.
1
agree... too bad
– Terminal User
Dec 8 '11 at 9:05
add a comment |
up vote
1
down vote
Java 8 LocalDate may be used:
public static boolean isDate(String date) {
try {
LocalDate.parse(date, DateTimeFormatter.ofPattern("yyyy/MM/dd"));
return true;
} catch (DateTimeParseException e) {
return false;
}
}
If input argument is "2011/12/12aaaaaaaaa"
, output is false
;
If input argument is "2011/12/12"
, output is true
add a comment |
up vote
0
down vote
Take a look on the method documentation which says: ParseException if the beginning of the specified string cannot be parsed
.
Method source code with javadoc:
/**
* Parses text from the beginning of the given string to produce a date.
* The method may not use the entire text of the given string.
* <p>
* See the {@link #parse(String, ParsePosition)} method for more information
* on date parsing.
*
* @param source A <code>String</code> whose beginning should be parsed.
* @return A <code>Date</code> parsed from the string.
* @exception ParseException if the beginning of the specified string
* cannot be parsed.
*/
public Date parse(String source) throws ParseException
{
ParsePosition pos = new ParsePosition(0);
Date result = parse(source, pos);
if (pos.index == 0)
throw new ParseException("Unparseable date: "" + source + """ ,
pos.errorIndex);
return result;
}
add a comment |
up vote
0
down vote
You can use the ParsePosition
class or the sdf.setLenient(false)
function
Docs:
http://docs.oracle.com/javase/7/docs/api/java/text/ParsePosition.html
http://docs.oracle.com/javase/7/docs/api/java/text/DateFormat.html#setLenient(boolean)
2
I think parse method only care about the start pos, not the end pos. isLenient doesn't work
– Terminal User
Dec 8 '11 at 8:57
1
When linking JavaDocs, please try to link the current version (which is 7, not 1.4.2).
– Thomas
Dec 8 '11 at 9:01
@TerminalUser mm I tried it myself with an example but setLeniet() doesn't seems to work and ParsePosition only works when there is actually a exception thrown. You can check if both Strings have the same length after parseing without an Exception and then throw an exception manual. Not fully what you request but...
– Michel
Dec 8 '11 at 9:08
add a comment |
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6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
12
down vote
accepted
The JavaDoc on parse(...)
states the following:
parsing does not necessarily use all characters up to the end of the string
It seems like you can't make SimpleDateFormat
throw an exception, but you can do the following:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
ParsePosition p = new ParsePosition( 0 );
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1,p));
if(p.getIndex() < t1.length()) {
throw new ParseException( t1, p.getIndex() );
}
Basically, you check whether the parse consumed the entire string and if not you have invalid input.
add a comment |
up vote
12
down vote
accepted
The JavaDoc on parse(...)
states the following:
parsing does not necessarily use all characters up to the end of the string
It seems like you can't make SimpleDateFormat
throw an exception, but you can do the following:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
ParsePosition p = new ParsePosition( 0 );
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1,p));
if(p.getIndex() < t1.length()) {
throw new ParseException( t1, p.getIndex() );
}
Basically, you check whether the parse consumed the entire string and if not you have invalid input.
add a comment |
up vote
12
down vote
accepted
up vote
12
down vote
accepted
The JavaDoc on parse(...)
states the following:
parsing does not necessarily use all characters up to the end of the string
It seems like you can't make SimpleDateFormat
throw an exception, but you can do the following:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
ParsePosition p = new ParsePosition( 0 );
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1,p));
if(p.getIndex() < t1.length()) {
throw new ParseException( t1, p.getIndex() );
}
Basically, you check whether the parse consumed the entire string and if not you have invalid input.
The JavaDoc on parse(...)
states the following:
parsing does not necessarily use all characters up to the end of the string
It seems like you can't make SimpleDateFormat
throw an exception, but you can do the following:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
sdf.setLenient(false);
ParsePosition p = new ParsePosition( 0 );
String t1 = "2011/12/12aaa";
System.out.println(sdf.parse(t1,p));
if(p.getIndex() < t1.length()) {
throw new ParseException( t1, p.getIndex() );
}
Basically, you check whether the parse consumed the entire string and if not you have invalid input.
edited Dec 8 '11 at 8:59
answered Dec 8 '11 at 8:48
Thomas
69k989124
69k989124
add a comment |
add a comment |
up vote
4
down vote
To chack whether a date is valid
The following method returns if the date is in valid otherwise it will return false.
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
Have a look on the following class which can check whether the date is valid or not
** Sample Example**
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class DateValidCheck {
public static void main(String args) {
if(new DateValidCheck().isValidDate("2011/12/12aaa")){
System.out.println("...date is valid");
}else{
System.out.println("...date is invalid...");
}
}
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
}
add a comment |
up vote
4
down vote
To chack whether a date is valid
The following method returns if the date is in valid otherwise it will return false.
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
Have a look on the following class which can check whether the date is valid or not
** Sample Example**
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class DateValidCheck {
public static void main(String args) {
if(new DateValidCheck().isValidDate("2011/12/12aaa")){
System.out.println("...date is valid");
}else{
System.out.println("...date is invalid...");
}
}
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
}
add a comment |
up vote
4
down vote
up vote
4
down vote
To chack whether a date is valid
The following method returns if the date is in valid otherwise it will return false.
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
Have a look on the following class which can check whether the date is valid or not
** Sample Example**
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class DateValidCheck {
public static void main(String args) {
if(new DateValidCheck().isValidDate("2011/12/12aaa")){
System.out.println("...date is valid");
}else{
System.out.println("...date is invalid...");
}
}
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
}
To chack whether a date is valid
The following method returns if the date is in valid otherwise it will return false.
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
Have a look on the following class which can check whether the date is valid or not
** Sample Example**
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class DateValidCheck {
public static void main(String args) {
if(new DateValidCheck().isValidDate("2011/12/12aaa")){
System.out.println("...date is valid");
}else{
System.out.println("...date is invalid...");
}
}
public boolean isValidDate(String date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d");
Date testDate = null;
try {
testDate = sdf.parse(date);
}
catch (ParseException e) {
return false;
}
if (!sdf.format(testDate).equals(date)) {
return false;
}
return true;
}
}
answered Dec 8 '11 at 9:46
Sunil Kumar Sahoo
36.8k45162232
36.8k45162232
add a comment |
add a comment |
up vote
2
down vote
After it successfully parsed the entire pattern string SimpleDateFormat
stops evaluating the data it was given to parse.
1
agree... too bad
– Terminal User
Dec 8 '11 at 9:05
add a comment |
up vote
2
down vote
After it successfully parsed the entire pattern string SimpleDateFormat
stops evaluating the data it was given to parse.
1
agree... too bad
– Terminal User
Dec 8 '11 at 9:05
add a comment |
up vote
2
down vote
up vote
2
down vote
After it successfully parsed the entire pattern string SimpleDateFormat
stops evaluating the data it was given to parse.
After it successfully parsed the entire pattern string SimpleDateFormat
stops evaluating the data it was given to parse.
answered Dec 8 '11 at 9:03
DerMike
8,505113956
8,505113956
1
agree... too bad
– Terminal User
Dec 8 '11 at 9:05
add a comment |
1
agree... too bad
– Terminal User
Dec 8 '11 at 9:05
1
1
agree... too bad
– Terminal User
Dec 8 '11 at 9:05
agree... too bad
– Terminal User
Dec 8 '11 at 9:05
add a comment |
up vote
1
down vote
Java 8 LocalDate may be used:
public static boolean isDate(String date) {
try {
LocalDate.parse(date, DateTimeFormatter.ofPattern("yyyy/MM/dd"));
return true;
} catch (DateTimeParseException e) {
return false;
}
}
If input argument is "2011/12/12aaaaaaaaa"
, output is false
;
If input argument is "2011/12/12"
, output is true
add a comment |
up vote
1
down vote
Java 8 LocalDate may be used:
public static boolean isDate(String date) {
try {
LocalDate.parse(date, DateTimeFormatter.ofPattern("yyyy/MM/dd"));
return true;
} catch (DateTimeParseException e) {
return false;
}
}
If input argument is "2011/12/12aaaaaaaaa"
, output is false
;
If input argument is "2011/12/12"
, output is true
add a comment |
up vote
1
down vote
up vote
1
down vote
Java 8 LocalDate may be used:
public static boolean isDate(String date) {
try {
LocalDate.parse(date, DateTimeFormatter.ofPattern("yyyy/MM/dd"));
return true;
} catch (DateTimeParseException e) {
return false;
}
}
If input argument is "2011/12/12aaaaaaaaa"
, output is false
;
If input argument is "2011/12/12"
, output is true
Java 8 LocalDate may be used:
public static boolean isDate(String date) {
try {
LocalDate.parse(date, DateTimeFormatter.ofPattern("yyyy/MM/dd"));
return true;
} catch (DateTimeParseException e) {
return false;
}
}
If input argument is "2011/12/12aaaaaaaaa"
, output is false
;
If input argument is "2011/12/12"
, output is true
answered May 16 '17 at 8:26
David
1,3441620
1,3441620
add a comment |
add a comment |
up vote
0
down vote
Take a look on the method documentation which says: ParseException if the beginning of the specified string cannot be parsed
.
Method source code with javadoc:
/**
* Parses text from the beginning of the given string to produce a date.
* The method may not use the entire text of the given string.
* <p>
* See the {@link #parse(String, ParsePosition)} method for more information
* on date parsing.
*
* @param source A <code>String</code> whose beginning should be parsed.
* @return A <code>Date</code> parsed from the string.
* @exception ParseException if the beginning of the specified string
* cannot be parsed.
*/
public Date parse(String source) throws ParseException
{
ParsePosition pos = new ParsePosition(0);
Date result = parse(source, pos);
if (pos.index == 0)
throw new ParseException("Unparseable date: "" + source + """ ,
pos.errorIndex);
return result;
}
add a comment |
up vote
0
down vote
Take a look on the method documentation which says: ParseException if the beginning of the specified string cannot be parsed
.
Method source code with javadoc:
/**
* Parses text from the beginning of the given string to produce a date.
* The method may not use the entire text of the given string.
* <p>
* See the {@link #parse(String, ParsePosition)} method for more information
* on date parsing.
*
* @param source A <code>String</code> whose beginning should be parsed.
* @return A <code>Date</code> parsed from the string.
* @exception ParseException if the beginning of the specified string
* cannot be parsed.
*/
public Date parse(String source) throws ParseException
{
ParsePosition pos = new ParsePosition(0);
Date result = parse(source, pos);
if (pos.index == 0)
throw new ParseException("Unparseable date: "" + source + """ ,
pos.errorIndex);
return result;
}
add a comment |
up vote
0
down vote
up vote
0
down vote
Take a look on the method documentation which says: ParseException if the beginning of the specified string cannot be parsed
.
Method source code with javadoc:
/**
* Parses text from the beginning of the given string to produce a date.
* The method may not use the entire text of the given string.
* <p>
* See the {@link #parse(String, ParsePosition)} method for more information
* on date parsing.
*
* @param source A <code>String</code> whose beginning should be parsed.
* @return A <code>Date</code> parsed from the string.
* @exception ParseException if the beginning of the specified string
* cannot be parsed.
*/
public Date parse(String source) throws ParseException
{
ParsePosition pos = new ParsePosition(0);
Date result = parse(source, pos);
if (pos.index == 0)
throw new ParseException("Unparseable date: "" + source + """ ,
pos.errorIndex);
return result;
}
Take a look on the method documentation which says: ParseException if the beginning of the specified string cannot be parsed
.
Method source code with javadoc:
/**
* Parses text from the beginning of the given string to produce a date.
* The method may not use the entire text of the given string.
* <p>
* See the {@link #parse(String, ParsePosition)} method for more information
* on date parsing.
*
* @param source A <code>String</code> whose beginning should be parsed.
* @return A <code>Date</code> parsed from the string.
* @exception ParseException if the beginning of the specified string
* cannot be parsed.
*/
public Date parse(String source) throws ParseException
{
ParsePosition pos = new ParsePosition(0);
Date result = parse(source, pos);
if (pos.index == 0)
throw new ParseException("Unparseable date: "" + source + """ ,
pos.errorIndex);
return result;
}
answered Dec 8 '11 at 8:58
amra
10.6k53942
10.6k53942
add a comment |
add a comment |
up vote
0
down vote
You can use the ParsePosition
class or the sdf.setLenient(false)
function
Docs:
http://docs.oracle.com/javase/7/docs/api/java/text/ParsePosition.html
http://docs.oracle.com/javase/7/docs/api/java/text/DateFormat.html#setLenient(boolean)
2
I think parse method only care about the start pos, not the end pos. isLenient doesn't work
– Terminal User
Dec 8 '11 at 8:57
1
When linking JavaDocs, please try to link the current version (which is 7, not 1.4.2).
– Thomas
Dec 8 '11 at 9:01
@TerminalUser mm I tried it myself with an example but setLeniet() doesn't seems to work and ParsePosition only works when there is actually a exception thrown. You can check if both Strings have the same length after parseing without an Exception and then throw an exception manual. Not fully what you request but...
– Michel
Dec 8 '11 at 9:08
add a comment |
up vote
0
down vote
You can use the ParsePosition
class or the sdf.setLenient(false)
function
Docs:
http://docs.oracle.com/javase/7/docs/api/java/text/ParsePosition.html
http://docs.oracle.com/javase/7/docs/api/java/text/DateFormat.html#setLenient(boolean)
2
I think parse method only care about the start pos, not the end pos. isLenient doesn't work
– Terminal User
Dec 8 '11 at 8:57
1
When linking JavaDocs, please try to link the current version (which is 7, not 1.4.2).
– Thomas
Dec 8 '11 at 9:01
@TerminalUser mm I tried it myself with an example but setLeniet() doesn't seems to work and ParsePosition only works when there is actually a exception thrown. You can check if both Strings have the same length after parseing without an Exception and then throw an exception manual. Not fully what you request but...
– Michel
Dec 8 '11 at 9:08
add a comment |
up vote
0
down vote
up vote
0
down vote
You can use the ParsePosition
class or the sdf.setLenient(false)
function
Docs:
http://docs.oracle.com/javase/7/docs/api/java/text/ParsePosition.html
http://docs.oracle.com/javase/7/docs/api/java/text/DateFormat.html#setLenient(boolean)
You can use the ParsePosition
class or the sdf.setLenient(false)
function
Docs:
http://docs.oracle.com/javase/7/docs/api/java/text/ParsePosition.html
http://docs.oracle.com/javase/7/docs/api/java/text/DateFormat.html#setLenient(boolean)
edited Dec 8 '11 at 9:04
answered Dec 8 '11 at 8:53
Michel
4,678103651
4,678103651
2
I think parse method only care about the start pos, not the end pos. isLenient doesn't work
– Terminal User
Dec 8 '11 at 8:57
1
When linking JavaDocs, please try to link the current version (which is 7, not 1.4.2).
– Thomas
Dec 8 '11 at 9:01
@TerminalUser mm I tried it myself with an example but setLeniet() doesn't seems to work and ParsePosition only works when there is actually a exception thrown. You can check if both Strings have the same length after parseing without an Exception and then throw an exception manual. Not fully what you request but...
– Michel
Dec 8 '11 at 9:08
add a comment |
2
I think parse method only care about the start pos, not the end pos. isLenient doesn't work
– Terminal User
Dec 8 '11 at 8:57
1
When linking JavaDocs, please try to link the current version (which is 7, not 1.4.2).
– Thomas
Dec 8 '11 at 9:01
@TerminalUser mm I tried it myself with an example but setLeniet() doesn't seems to work and ParsePosition only works when there is actually a exception thrown. You can check if both Strings have the same length after parseing without an Exception and then throw an exception manual. Not fully what you request but...
– Michel
Dec 8 '11 at 9:08
2
2
I think parse method only care about the start pos, not the end pos. isLenient doesn't work
– Terminal User
Dec 8 '11 at 8:57
I think parse method only care about the start pos, not the end pos. isLenient doesn't work
– Terminal User
Dec 8 '11 at 8:57
1
1
When linking JavaDocs, please try to link the current version (which is 7, not 1.4.2).
– Thomas
Dec 8 '11 at 9:01
When linking JavaDocs, please try to link the current version (which is 7, not 1.4.2).
– Thomas
Dec 8 '11 at 9:01
@TerminalUser mm I tried it myself with an example but setLeniet() doesn't seems to work and ParsePosition only works when there is actually a exception thrown. You can check if both Strings have the same length after parseing without an Exception and then throw an exception manual. Not fully what you request but...
– Michel
Dec 8 '11 at 9:08
@TerminalUser mm I tried it myself with an example but setLeniet() doesn't seems to work and ParsePosition only works when there is actually a exception thrown. You can check if both Strings have the same length after parseing without an Exception and then throw an exception manual. Not fully what you request but...
– Michel
Dec 8 '11 at 9:08
add a comment |
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