I am not able to access data as per POJO class
Hi I have following json response, I am not able to access data of 'edit' jsonobject, how to create pojo for that?
Example
{
"result":"",
"responseMessage":"",
"edit":{
"id":"156",
"user_id":"5466",
},
"data":[
{
"dataid":"1",
"dataname":"tt"
},
{
"dataid":"2",
"dataname":"tt"
}
]
}
How to create pojo class for this response
android getter-setter pojo
add a comment |
Hi I have following json response, I am not able to access data of 'edit' jsonobject, how to create pojo for that?
Example
{
"result":"",
"responseMessage":"",
"edit":{
"id":"156",
"user_id":"5466",
},
"data":[
{
"dataid":"1",
"dataname":"tt"
},
{
"dataid":"2",
"dataname":"tt"
}
]
}
How to create pojo class for this response
android getter-setter pojo
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 '18 at 5:33
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 '18 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 '18 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 '18 at 5:54
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 '18 at 6:16
add a comment |
Hi I have following json response, I am not able to access data of 'edit' jsonobject, how to create pojo for that?
Example
{
"result":"",
"responseMessage":"",
"edit":{
"id":"156",
"user_id":"5466",
},
"data":[
{
"dataid":"1",
"dataname":"tt"
},
{
"dataid":"2",
"dataname":"tt"
}
]
}
How to create pojo class for this response
android getter-setter pojo
Hi I have following json response, I am not able to access data of 'edit' jsonobject, how to create pojo for that?
Example
{
"result":"",
"responseMessage":"",
"edit":{
"id":"156",
"user_id":"5466",
},
"data":[
{
"dataid":"1",
"dataname":"tt"
},
{
"dataid":"2",
"dataname":"tt"
}
]
}
How to create pojo class for this response
android getter-setter pojo
android getter-setter pojo
edited Nov 22 '18 at 10:56
AwaisMajeed
678319
678319
asked Nov 22 '18 at 5:29
Nilima Nilima
307
307
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 '18 at 5:33
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 '18 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 '18 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 '18 at 5:54
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 '18 at 6:16
add a comment |
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 '18 at 5:33
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 '18 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 '18 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 '18 at 5:54
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 '18 at 6:16
1
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 '18 at 5:33
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 '18 at 5:33
2
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 '18 at 5:34
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 '18 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 '18 at 5:35
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 '18 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 '18 at 5:54
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 '18 at 5:54
1
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 '18 at 6:16
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 '18 at 6:16
add a comment |
3 Answers
3
active
oldest
votes
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
add a comment |
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 '18 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 '18 at 12:08
add a comment |
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
add a comment |
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
add a comment |
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
answered Nov 22 '18 at 5:41
AwaisMajeedAwaisMajeed
678319
678319
add a comment |
add a comment |
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 '18 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 '18 at 12:08
add a comment |
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 '18 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 '18 at 12:08
add a comment |
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
answered Nov 22 '18 at 5:37
Chandrani ChatterjeeChandrani Chatterjee
403215
403215
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 '18 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 '18 at 12:08
add a comment |
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 '18 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 '18 at 12:08
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 '18 at 9:23
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 '18 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 '18 at 12:08
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 '18 at 12:08
add a comment |
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
add a comment |
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
add a comment |
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
answered Nov 22 '18 at 5:37
Android TeamAndroid Team
7,54011033
7,54011033
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
add a comment |
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 '18 at 6:09
add a comment |
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1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 '18 at 5:33
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 '18 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 '18 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 '18 at 5:54
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 '18 at 6:16