How would I write this reportCandidates' function better?

This is the input data in array named candidatesArray:

[ 

 {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},

 {"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},

 {"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}

]

I need to transform in this collection as a result of the function:

{candidates: [

    {name: "George", age: 19, phone: "32-991-511"},

    {name: "Hailee", age: 31, phone: "32-991-513"},

    {name: "Anna", age: 23, phone: "32-991-512"}

],

languages: [

    {lang:"javascript",count:1}, 

    {lang:"java", count:2}, 

    {lang:"php", count:2}, 

    {lang:"regex", count:1}

]}

The function repCandidates:

const reportCandidates = (candidatesArray) => { return repObject}

I need to write it in javascript ES6

I shouldn't use loops(for, while, repeat) but foreach is allowed and it could be better if I use "reduce" function

The candidates should be return by their name, age and phone organized by their graduate_date.

The languages should be returned with their counter in alphabetic order .

Visit https://codepen.io/rillervincci/pen/NEyMoV?editors=0010 to see my code, please.

edited Nov 22 '18 at 5:51

Mark Meyer

38k33159

asked Nov 22 '18 at 5:40

Riller Vincci

add a comment |

This is the input data in array named candidatesArray:

[ 

 {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},

 {"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},

 {"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}

]

I need to transform in this collection as a result of the function:

{candidates: [

    {name: "George", age: 19, phone: "32-991-511"},

    {name: "Hailee", age: 31, phone: "32-991-513"},

    {name: "Anna", age: 23, phone: "32-991-512"}

],

languages: [

    {lang:"javascript",count:1}, 

    {lang:"java", count:2}, 

    {lang:"php", count:2}, 

    {lang:"regex", count:1}

]}

The function repCandidates:

const reportCandidates = (candidatesArray) => { return repObject}

I need to write it in javascript ES6

I shouldn't use loops(for, while, repeat) but foreach is allowed and it could be better if I use "reduce" function

The candidates should be return by their name, age and phone organized by their graduate_date.

The languages should be returned with their counter in alphabetic order .

Visit https://codepen.io/rillervincci/pen/NEyMoV?editors=0010 to see my code, please.

edited Nov 22 '18 at 5:51

Mark Meyer

38k33159

asked Nov 22 '18 at 5:40

Riller Vincci

add a comment |

This is the input data in array named candidatesArray:

[ 

 {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},

 {"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},

 {"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}

]

I need to transform in this collection as a result of the function:

{candidates: [

    {name: "George", age: 19, phone: "32-991-511"},

    {name: "Hailee", age: 31, phone: "32-991-513"},

    {name: "Anna", age: 23, phone: "32-991-512"}

],

languages: [

    {lang:"javascript",count:1}, 

    {lang:"java", count:2}, 

    {lang:"php", count:2}, 

    {lang:"regex", count:1}

]}

The function repCandidates:

const reportCandidates = (candidatesArray) => { return repObject}

I need to write it in javascript ES6

I shouldn't use loops(for, while, repeat) but foreach is allowed and it could be better if I use "reduce" function

The candidates should be return by their name, age and phone organized by their graduate_date.

The languages should be returned with their counter in alphabetic order .

Visit https://codepen.io/rillervincci/pen/NEyMoV?editors=0010 to see my code, please.

edited Nov 22 '18 at 5:51

Mark Meyer

38k33159

asked Nov 22 '18 at 5:40

Riller Vincci

This is the input data in array named candidatesArray:

[ 

 {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},

 {"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},

 {"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}

]

I need to transform in this collection as a result of the function:

{candidates: [

    {name: "George", age: 19, phone: "32-991-511"},

    {name: "Hailee", age: 31, phone: "32-991-513"},

    {name: "Anna", age: 23, phone: "32-991-512"}

],

languages: [

    {lang:"javascript",count:1}, 

    {lang:"java", count:2}, 

    {lang:"php", count:2}, 

    {lang:"regex", count:1}

]}

The function repCandidates:

const reportCandidates = (candidatesArray) => { return repObject}

I need to write it in javascript ES6

I shouldn't use loops(for, while, repeat) but foreach is allowed and it could be better if I use "reduce" function

The candidates should be return by their name, age and phone organized by their graduate_date.

The languages should be returned with their counter in alphabetic order .

Visit https://codepen.io/rillervincci/pen/NEyMoV?editors=0010 to see my code, please.

javascript arrays json sorting collections

edited Nov 22 '18 at 5:51

Mark Meyer

38k33159

asked Nov 22 '18 at 5:40

Riller Vincci

edited Nov 22 '18 at 5:51

Mark Meyer

38k33159

asked Nov 22 '18 at 5:40

Riller Vincci

edited Nov 22 '18 at 5:51

Mark Meyer

38k33159

edited Nov 22 '18 at 5:51

Mark Meyer

38k33159

edited Nov 22 '18 at 5:51

Mark Meyer

38k33159

asked Nov 22 '18 at 5:40

Riller Vincci

asked Nov 22 '18 at 5:40

Riller Vincci

asked Nov 22 '18 at 5:40

Riller Vincci

add a comment |

3 Answers
3

active

oldest

votes

One option would be to first reduce into the candidates subobject, while pushing the langauges of each to an array.

After iterating, sort the candidates and remove the graduate_date property from each candidate, then use reduce again to transform the languages array into one indexed by language, incrementing the count property each time:

const input = [{

  "name": "george",

  "languages": ["php", "javascript", "java"],

  "age": 19,

  "graduate_date": 1044064800000,

  "phone": "32-991-511"

}, {

  "name": "anna",

  "languages": ["java", "javascript"],

  "age": 23,

  "graduate_date": 1391220000000,

  "phone": "32-991-512"

}, {

  "name": "hailee",

  "languages": ["regex", "javascript", "perl", "go", "java"],

  "age": 31,

  "graduate_date": 1296525600000,

  "phone": "32-991-513"

}];





const output = input.reduce((a, { languages, ...rest }) => {

  a.candidates.push(rest);

  a.languages.push(...languages);

  return a;

}, { candidates: , languages:  });



output.candidates.sort((a, b) => a.graduate_date - b.graduate_date);

output.candidates.forEach(candidate => delete candidate.graduate_date);



output.languages = Object.values(

  output.languages.reduce((a, lang) => {

    if (!a[lang]) a[lang] = { lang, count: 0 };

    a[lang].count++;

    return a;

  }, {})

);

output.languages.sort((a, b) => a.lang.localeCompare(b.lang));



console.log(output);

edited Nov 22 '18 at 6:02

answered Nov 22 '18 at 5:47

CertainPerformance

80.8k143865

Wow that's amazing! I would never imagine do it like that. Very good... So how could I order the candidates by graduate date in desc and languages in alphabetic order

– Riller Vincci
Nov 22 '18 at 5:59

The candidates are already being sorted, see the sort function, to sort the languages by language, use localeCompare on their lang properties

– CertainPerformance
Nov 22 '18 at 6:02

Can I use this to make first letter of the names like lowercase? name = name.charAt(0).toUpperCase() + name.slice(1); a.candidates.push({ name, age, phone });

– Riller Vincci
Nov 22 '18 at 6:20

You want to make each first character uppercase? Yep, that code looks like it would work, but note that you can use bracket notation instead of charAt for less syntax noise, eg name[0].toUpperCase()

– CertainPerformance
Nov 22 '18 at 6:21

Bracket notation? that's new to me

– Riller Vincci
Nov 22 '18 at 6:24

|
show 2 more comments

It's common practice to do everything in a reduce(), but sometimes it's easier to read if you break it up a bit. This creates a counter object as a helper to to track the language counts. map()s over the array to pull out the languages and personal info and then puts it all together:

let arr = [ {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]

 

let lang_counter = {

  // helper keeps counts of unique items

  counts:{},

  add(arr){

     arr.forEach(item => this.counts[item] = this.counts[item] ? this.counts[item] + 1 : 1)

  },

  toarray(){

    return Object.entries(this.counts).map(([key, val]) => ({[key]: val}))

  }

}



// iterate over object to create candidates 

let candidates = arr.map(row => {

  let {languages, ...person} = row

  lang_counter.add(languages)  // side effect

  return person

})



// put them together

console.log({candidates, languages:lang_counter.toarray()})

answered Nov 22 '18 at 6:14

Mark Meyer

38k33159

Yeaah That's nice bro. I've changed some things to make all names receive the first letter in uppercase and organize all languages in alphabetical order. Thank you!!!

– Riller Vincci
Nov 22 '18 at 6:40

add a comment |

You can use Array.reduce and Object.values like below

let arr = [{"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]





let res = arr.reduce((o, {name, age, phone, graduate_date, languages}) => {

    o.candidates.push({name, age, phone, graduate_date})

  

    languages.forEach(l => {

      o.languages[l] = o.languages[l] || { lang:l, count: 0 }

      o.languages[l].count++

    })

  

    return o

  }

 , { candidates: , languages: {}})



res.candidates = res.candidates.sort((a,b) => a.graduate_date - b.graduate_date)

                               .map(({ graduate_date, ...rest }) => rest)



res.languages = Object.values(res.languages).sort((a,b) => a.lang.localeCompare(b.lang))

  

console.log(res)

edited Nov 22 '18 at 6:40

answered Nov 22 '18 at 6:05

Nitish Narang

2,938815

1

It's very interesting You've used map function to organize candidates Woow Congratulations... Thank you

– Riller Vincci
Nov 22 '18 at 6:44

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

One option would be to first reduce into the candidates subobject, while pushing the langauges of each to an array.

const input = [{

  "name": "george",

  "languages": ["php", "javascript", "java"],

  "age": 19,

  "graduate_date": 1044064800000,

  "phone": "32-991-511"

}, {

  "name": "anna",

  "languages": ["java", "javascript"],

  "age": 23,

  "graduate_date": 1391220000000,

  "phone": "32-991-512"

}, {

  "name": "hailee",

  "languages": ["regex", "javascript", "perl", "go", "java"],

  "age": 31,

  "graduate_date": 1296525600000,

  "phone": "32-991-513"

}];





const output = input.reduce((a, { languages, ...rest }) => {

  a.candidates.push(rest);

  a.languages.push(...languages);

  return a;

}, { candidates: , languages:  });



output.candidates.sort((a, b) => a.graduate_date - b.graduate_date);

output.candidates.forEach(candidate => delete candidate.graduate_date);



output.languages = Object.values(

  output.languages.reduce((a, lang) => {

    if (!a[lang]) a[lang] = { lang, count: 0 };

    a[lang].count++;

    return a;

  }, {})

);

output.languages.sort((a, b) => a.lang.localeCompare(b.lang));



console.log(output);

edited Nov 22 '18 at 6:02

answered Nov 22 '18 at 5:47

CertainPerformance

80.8k143865

Wow that's amazing! I would never imagine do it like that. Very good... So how could I order the candidates by graduate date in desc and languages in alphabetic order

– Riller Vincci
Nov 22 '18 at 5:59

The candidates are already being sorted, see the sort function, to sort the languages by language, use localeCompare on their lang properties

– CertainPerformance
Nov 22 '18 at 6:02

Can I use this to make first letter of the names like lowercase? name = name.charAt(0).toUpperCase() + name.slice(1); a.candidates.push({ name, age, phone });

– Riller Vincci
Nov 22 '18 at 6:20

You want to make each first character uppercase? Yep, that code looks like it would work, but note that you can use bracket notation instead of charAt for less syntax noise, eg name[0].toUpperCase()

– CertainPerformance
Nov 22 '18 at 6:21

Bracket notation? that's new to me

– Riller Vincci
Nov 22 '18 at 6:24

|
show 2 more comments

One option would be to first reduce into the candidates subobject, while pushing the langauges of each to an array.

const input = [{

  "name": "george",

  "languages": ["php", "javascript", "java"],

  "age": 19,

  "graduate_date": 1044064800000,

  "phone": "32-991-511"

}, {

  "name": "anna",

  "languages": ["java", "javascript"],

  "age": 23,

  "graduate_date": 1391220000000,

  "phone": "32-991-512"

}, {

  "name": "hailee",

  "languages": ["regex", "javascript", "perl", "go", "java"],

  "age": 31,

  "graduate_date": 1296525600000,

  "phone": "32-991-513"

}];





const output = input.reduce((a, { languages, ...rest }) => {

  a.candidates.push(rest);

  a.languages.push(...languages);

  return a;

}, { candidates: , languages:  });



output.candidates.sort((a, b) => a.graduate_date - b.graduate_date);

output.candidates.forEach(candidate => delete candidate.graduate_date);



output.languages = Object.values(

  output.languages.reduce((a, lang) => {

    if (!a[lang]) a[lang] = { lang, count: 0 };

    a[lang].count++;

    return a;

  }, {})

);

output.languages.sort((a, b) => a.lang.localeCompare(b.lang));



console.log(output);

edited Nov 22 '18 at 6:02

answered Nov 22 '18 at 5:47

CertainPerformance

80.8k143865

Wow that's amazing! I would never imagine do it like that. Very good... So how could I order the candidates by graduate date in desc and languages in alphabetic order

– Riller Vincci
Nov 22 '18 at 5:59

The candidates are already being sorted, see the sort function, to sort the languages by language, use localeCompare on their lang properties

– CertainPerformance
Nov 22 '18 at 6:02

Can I use this to make first letter of the names like lowercase? name = name.charAt(0).toUpperCase() + name.slice(1); a.candidates.push({ name, age, phone });

– Riller Vincci
Nov 22 '18 at 6:20

You want to make each first character uppercase? Yep, that code looks like it would work, but note that you can use bracket notation instead of charAt for less syntax noise, eg name[0].toUpperCase()

– CertainPerformance
Nov 22 '18 at 6:21

Bracket notation? that's new to me

– Riller Vincci
Nov 22 '18 at 6:24

|
show 2 more comments

One option would be to first reduce into the candidates subobject, while pushing the langauges of each to an array.

const input = [{

  "name": "george",

  "languages": ["php", "javascript", "java"],

  "age": 19,

  "graduate_date": 1044064800000,

  "phone": "32-991-511"

}, {

  "name": "anna",

  "languages": ["java", "javascript"],

  "age": 23,

  "graduate_date": 1391220000000,

  "phone": "32-991-512"

}, {

  "name": "hailee",

  "languages": ["regex", "javascript", "perl", "go", "java"],

  "age": 31,

  "graduate_date": 1296525600000,

  "phone": "32-991-513"

}];





const output = input.reduce((a, { languages, ...rest }) => {

  a.candidates.push(rest);

  a.languages.push(...languages);

  return a;

}, { candidates: , languages:  });



output.candidates.sort((a, b) => a.graduate_date - b.graduate_date);

output.candidates.forEach(candidate => delete candidate.graduate_date);



output.languages = Object.values(

  output.languages.reduce((a, lang) => {

    if (!a[lang]) a[lang] = { lang, count: 0 };

    a[lang].count++;

    return a;

  }, {})

);

output.languages.sort((a, b) => a.lang.localeCompare(b.lang));



console.log(output);

edited Nov 22 '18 at 6:02

answered Nov 22 '18 at 5:47

CertainPerformance

80.8k143865

One option would be to first reduce into the candidates subobject, while pushing the langauges of each to an array.

const input = [{

  "name": "george",

  "languages": ["php", "javascript", "java"],

  "age": 19,

  "graduate_date": 1044064800000,

  "phone": "32-991-511"

}, {

  "name": "anna",

  "languages": ["java", "javascript"],

  "age": 23,

  "graduate_date": 1391220000000,

  "phone": "32-991-512"

}, {

  "name": "hailee",

  "languages": ["regex", "javascript", "perl", "go", "java"],

  "age": 31,

  "graduate_date": 1296525600000,

  "phone": "32-991-513"

}];





const output = input.reduce((a, { languages, ...rest }) => {

  a.candidates.push(rest);

  a.languages.push(...languages);

  return a;

}, { candidates: , languages:  });



output.candidates.sort((a, b) => a.graduate_date - b.graduate_date);

output.candidates.forEach(candidate => delete candidate.graduate_date);



output.languages = Object.values(

  output.languages.reduce((a, lang) => {

    if (!a[lang]) a[lang] = { lang, count: 0 };

    a[lang].count++;

    return a;

  }, {})

);

output.languages.sort((a, b) => a.lang.localeCompare(b.lang));



console.log(output);

const input = [{

  "name": "george",

  "languages": ["php", "javascript", "java"],

  "age": 19,

  "graduate_date": 1044064800000,

  "phone": "32-991-511"

}, {

  "name": "anna",

  "languages": ["java", "javascript"],

  "age": 23,

  "graduate_date": 1391220000000,

  "phone": "32-991-512"

}, {

  "name": "hailee",

  "languages": ["regex", "javascript", "perl", "go", "java"],

  "age": 31,

  "graduate_date": 1296525600000,

  "phone": "32-991-513"

}];





const output = input.reduce((a, { languages, ...rest }) => {

  a.candidates.push(rest);

  a.languages.push(...languages);

  return a;

}, { candidates: , languages:  });



output.candidates.sort((a, b) => a.graduate_date - b.graduate_date);

output.candidates.forEach(candidate => delete candidate.graduate_date);



output.languages = Object.values(

  output.languages.reduce((a, lang) => {

    if (!a[lang]) a[lang] = { lang, count: 0 };

    a[lang].count++;

    return a;

  }, {})

);

output.languages.sort((a, b) => a.lang.localeCompare(b.lang));



console.log(output);

const input = [{

  "name": "george",

  "languages": ["php", "javascript", "java"],

  "age": 19,

  "graduate_date": 1044064800000,

  "phone": "32-991-511"

}, {

  "name": "anna",

  "languages": ["java", "javascript"],

  "age": 23,

  "graduate_date": 1391220000000,

  "phone": "32-991-512"

}, {

  "name": "hailee",

  "languages": ["regex", "javascript", "perl", "go", "java"],

  "age": 31,

  "graduate_date": 1296525600000,

  "phone": "32-991-513"

}];





const output = input.reduce((a, { languages, ...rest }) => {

  a.candidates.push(rest);

  a.languages.push(...languages);

  return a;

}, { candidates: , languages:  });



output.candidates.sort((a, b) => a.graduate_date - b.graduate_date);

output.candidates.forEach(candidate => delete candidate.graduate_date);



output.languages = Object.values(

  output.languages.reduce((a, lang) => {

    if (!a[lang]) a[lang] = { lang, count: 0 };

    a[lang].count++;

    return a;

  }, {})

);

output.languages.sort((a, b) => a.lang.localeCompare(b.lang));



console.log(output);

edited Nov 22 '18 at 6:02

answered Nov 22 '18 at 5:47

CertainPerformance

80.8k143865

edited Nov 22 '18 at 6:02

answered Nov 22 '18 at 5:47

CertainPerformance

80.8k143865

answered Nov 22 '18 at 5:47

CertainPerformance

80.8k143865

answered Nov 22 '18 at 5:47

CertainPerformance

80.8k143865

Wow that's amazing! I would never imagine do it like that. Very good... So how could I order the candidates by graduate date in desc and languages in alphabetic order

– Riller Vincci
Nov 22 '18 at 5:59

The candidates are already being sorted, see the sort function, to sort the languages by language, use localeCompare on their lang properties

– CertainPerformance
Nov 22 '18 at 6:02

Can I use this to make first letter of the names like lowercase? name = name.charAt(0).toUpperCase() + name.slice(1); a.candidates.push({ name, age, phone });

– Riller Vincci
Nov 22 '18 at 6:20

You want to make each first character uppercase? Yep, that code looks like it would work, but note that you can use bracket notation instead of charAt for less syntax noise, eg name[0].toUpperCase()

– CertainPerformance
Nov 22 '18 at 6:21

Bracket notation? that's new to me

– Riller Vincci
Nov 22 '18 at 6:24

|
show 2 more comments

Wow that's amazing! I would never imagine do it like that. Very good... So how could I order the candidates by graduate date in desc and languages in alphabetic order

– Riller Vincci
Nov 22 '18 at 5:59

The candidates are already being sorted, see the sort function, to sort the languages by language, use localeCompare on their lang properties

– CertainPerformance
Nov 22 '18 at 6:02

Can I use this to make first letter of the names like lowercase? name = name.charAt(0).toUpperCase() + name.slice(1); a.candidates.push({ name, age, phone });

– Riller Vincci
Nov 22 '18 at 6:20

You want to make each first character uppercase? Yep, that code looks like it would work, but note that you can use bracket notation instead of charAt for less syntax noise, eg name[0].toUpperCase()

– CertainPerformance
Nov 22 '18 at 6:21

Bracket notation? that's new to me

– Riller Vincci
Nov 22 '18 at 6:24

Wow that's amazing! I would never imagine do it like that. Very good... So how could I order the candidates by graduate date in desc and languages in alphabetic order

– Riller Vincci
Nov 22 '18 at 5:59

The candidates are already being sorted, see the sort function, to sort the languages by language, use localeCompare on their lang properties

– CertainPerformance
Nov 22 '18 at 6:02

Can I use this to make first letter of the names like lowercase? name = name.charAt(0).toUpperCase() + name.slice(1); a.candidates.push({ name, age, phone });

– Riller Vincci
Nov 22 '18 at 6:20

You want to make each first character uppercase? Yep, that code looks like it would work, but note that you can use bracket notation instead of charAt for less syntax noise, eg name[0].toUpperCase()

– CertainPerformance
Nov 22 '18 at 6:21

Bracket notation? that's new to me

– Riller Vincci
Nov 22 '18 at 6:24

|
show 2 more comments

let arr = [ {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]

 

let lang_counter = {

  // helper keeps counts of unique items

  counts:{},

  add(arr){

     arr.forEach(item => this.counts[item] = this.counts[item] ? this.counts[item] + 1 : 1)

  },

  toarray(){

    return Object.entries(this.counts).map(([key, val]) => ({[key]: val}))

  }

}



// iterate over object to create candidates 

let candidates = arr.map(row => {

  let {languages, ...person} = row

  lang_counter.add(languages)  // side effect

  return person

})



// put them together

console.log({candidates, languages:lang_counter.toarray()})

answered Nov 22 '18 at 6:14

Mark Meyer

38k33159

Yeaah That's nice bro. I've changed some things to make all names receive the first letter in uppercase and organize all languages in alphabetical order. Thank you!!!

– Riller Vincci
Nov 22 '18 at 6:40

add a comment |

let arr = [ {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]

 

let lang_counter = {

  // helper keeps counts of unique items

  counts:{},

  add(arr){

     arr.forEach(item => this.counts[item] = this.counts[item] ? this.counts[item] + 1 : 1)

  },

  toarray(){

    return Object.entries(this.counts).map(([key, val]) => ({[key]: val}))

  }

}



// iterate over object to create candidates 

let candidates = arr.map(row => {

  let {languages, ...person} = row

  lang_counter.add(languages)  // side effect

  return person

})



// put them together

console.log({candidates, languages:lang_counter.toarray()})

answered Nov 22 '18 at 6:14

Mark Meyer

38k33159

Yeaah That's nice bro. I've changed some things to make all names receive the first letter in uppercase and organize all languages in alphabetical order. Thank you!!!

– Riller Vincci
Nov 22 '18 at 6:40

add a comment |

let arr = [ {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]

 

let lang_counter = {

  // helper keeps counts of unique items

  counts:{},

  add(arr){

     arr.forEach(item => this.counts[item] = this.counts[item] ? this.counts[item] + 1 : 1)

  },

  toarray(){

    return Object.entries(this.counts).map(([key, val]) => ({[key]: val}))

  }

}



// iterate over object to create candidates 

let candidates = arr.map(row => {

  let {languages, ...person} = row

  lang_counter.add(languages)  // side effect

  return person

})



// put them together

console.log({candidates, languages:lang_counter.toarray()})

answered Nov 22 '18 at 6:14

Mark Meyer

38k33159

let arr = [ {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]

 

let lang_counter = {

  // helper keeps counts of unique items

  counts:{},

  add(arr){

     arr.forEach(item => this.counts[item] = this.counts[item] ? this.counts[item] + 1 : 1)

  },

  toarray(){

    return Object.entries(this.counts).map(([key, val]) => ({[key]: val}))

  }

}



// iterate over object to create candidates 

let candidates = arr.map(row => {

  let {languages, ...person} = row

  lang_counter.add(languages)  // side effect

  return person

})



// put them together

console.log({candidates, languages:lang_counter.toarray()})

let arr = [ {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]

 

let lang_counter = {

  // helper keeps counts of unique items

  counts:{},

  add(arr){

     arr.forEach(item => this.counts[item] = this.counts[item] ? this.counts[item] + 1 : 1)

  },

  toarray(){

    return Object.entries(this.counts).map(([key, val]) => ({[key]: val}))

  }

}



// iterate over object to create candidates 

let candidates = arr.map(row => {

  let {languages, ...person} = row

  lang_counter.add(languages)  // side effect

  return person

})



// put them together

console.log({candidates, languages:lang_counter.toarray()})

let arr = [ {"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]

 

let lang_counter = {

  // helper keeps counts of unique items

  counts:{},

  add(arr){

     arr.forEach(item => this.counts[item] = this.counts[item] ? this.counts[item] + 1 : 1)

  },

  toarray(){

    return Object.entries(this.counts).map(([key, val]) => ({[key]: val}))

  }

}



// iterate over object to create candidates 

let candidates = arr.map(row => {

  let {languages, ...person} = row

  lang_counter.add(languages)  // side effect

  return person

})



// put them together

console.log({candidates, languages:lang_counter.toarray()})

answered Nov 22 '18 at 6:14

Mark Meyer

38k33159

answered Nov 22 '18 at 6:14

Mark Meyer

38k33159

answered Nov 22 '18 at 6:14

Mark Meyer

38k33159

answered Nov 22 '18 at 6:14

Mark Meyer

38k33159

Yeaah That's nice bro. I've changed some things to make all names receive the first letter in uppercase and organize all languages in alphabetical order. Thank you!!!

– Riller Vincci
Nov 22 '18 at 6:40

add a comment |

Yeaah That's nice bro. I've changed some things to make all names receive the first letter in uppercase and organize all languages in alphabetical order. Thank you!!!

– Riller Vincci
Nov 22 '18 at 6:40

Yeaah That's nice bro. I've changed some things to make all names receive the first letter in uppercase and organize all languages in alphabetical order. Thank you!!!

– Riller Vincci
Nov 22 '18 at 6:40

add a comment |

You can use Array.reduce and Object.values like below

let arr = [{"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]





let res = arr.reduce((o, {name, age, phone, graduate_date, languages}) => {

    o.candidates.push({name, age, phone, graduate_date})

  

    languages.forEach(l => {

      o.languages[l] = o.languages[l] || { lang:l, count: 0 }

      o.languages[l].count++

    })

  

    return o

  }

 , { candidates: , languages: {}})



res.candidates = res.candidates.sort((a,b) => a.graduate_date - b.graduate_date)

                               .map(({ graduate_date, ...rest }) => rest)



res.languages = Object.values(res.languages).sort((a,b) => a.lang.localeCompare(b.lang))

  

console.log(res)

edited Nov 22 '18 at 6:40

answered Nov 22 '18 at 6:05

Nitish Narang

2,938815

1

It's very interesting You've used map function to organize candidates Woow Congratulations... Thank you

– Riller Vincci
Nov 22 '18 at 6:44

add a comment |

You can use Array.reduce and Object.values like below

let arr = [{"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]





let res = arr.reduce((o, {name, age, phone, graduate_date, languages}) => {

    o.candidates.push({name, age, phone, graduate_date})

  

    languages.forEach(l => {

      o.languages[l] = o.languages[l] || { lang:l, count: 0 }

      o.languages[l].count++

    })

  

    return o

  }

 , { candidates: , languages: {}})



res.candidates = res.candidates.sort((a,b) => a.graduate_date - b.graduate_date)

                               .map(({ graduate_date, ...rest }) => rest)



res.languages = Object.values(res.languages).sort((a,b) => a.lang.localeCompare(b.lang))

  

console.log(res)

edited Nov 22 '18 at 6:40

answered Nov 22 '18 at 6:05

Nitish Narang

2,938815

1

It's very interesting You've used map function to organize candidates Woow Congratulations... Thank you

– Riller Vincci
Nov 22 '18 at 6:44

add a comment |

You can use Array.reduce and Object.values like below

let arr = [{"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]





let res = arr.reduce((o, {name, age, phone, graduate_date, languages}) => {

    o.candidates.push({name, age, phone, graduate_date})

  

    languages.forEach(l => {

      o.languages[l] = o.languages[l] || { lang:l, count: 0 }

      o.languages[l].count++

    })

  

    return o

  }

 , { candidates: , languages: {}})



res.candidates = res.candidates.sort((a,b) => a.graduate_date - b.graduate_date)

                               .map(({ graduate_date, ...rest }) => rest)



res.languages = Object.values(res.languages).sort((a,b) => a.lang.localeCompare(b.lang))

  

console.log(res)

edited Nov 22 '18 at 6:40

answered Nov 22 '18 at 6:05

Nitish Narang

2,938815

You can use Array.reduce and Object.values like below

let arr = [{"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]





let res = arr.reduce((o, {name, age, phone, graduate_date, languages}) => {

    o.candidates.push({name, age, phone, graduate_date})

  

    languages.forEach(l => {

      o.languages[l] = o.languages[l] || { lang:l, count: 0 }

      o.languages[l].count++

    })

  

    return o

  }

 , { candidates: , languages: {}})



res.candidates = res.candidates.sort((a,b) => a.graduate_date - b.graduate_date)

                               .map(({ graduate_date, ...rest }) => rest)



res.languages = Object.values(res.languages).sort((a,b) => a.lang.localeCompare(b.lang))

  

console.log(res)

let arr = [{"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]





let res = arr.reduce((o, {name, age, phone, graduate_date, languages}) => {

    o.candidates.push({name, age, phone, graduate_date})

  

    languages.forEach(l => {

      o.languages[l] = o.languages[l] || { lang:l, count: 0 }

      o.languages[l].count++

    })

  

    return o

  }

 , { candidates: , languages: {}})



res.candidates = res.candidates.sort((a,b) => a.graduate_date - b.graduate_date)

                               .map(({ graduate_date, ...rest }) => rest)



res.languages = Object.values(res.languages).sort((a,b) => a.lang.localeCompare(b.lang))

  

console.log(res)

let arr = [{"name":"george","languages":["php","javascript","java"],"age":19,"graduate_date":1044064800000,"phone":"32-991-511"},{"name":"anna","languages":["java","javascript"],"age":23,"graduate_date":1391220000000,"phone":"32-991-512"},{"name":"hailee","languages":["regex","javascript","perl","go","java"],"age":31,"graduate_date":1296525600000,"phone":"32-991-513"}]





let res = arr.reduce((o, {name, age, phone, graduate_date, languages}) => {

    o.candidates.push({name, age, phone, graduate_date})

  

    languages.forEach(l => {

      o.languages[l] = o.languages[l] || { lang:l, count: 0 }

      o.languages[l].count++

    })

  

    return o

  }

 , { candidates: , languages: {}})



res.candidates = res.candidates.sort((a,b) => a.graduate_date - b.graduate_date)

                               .map(({ graduate_date, ...rest }) => rest)



res.languages = Object.values(res.languages).sort((a,b) => a.lang.localeCompare(b.lang))

  

console.log(res)

edited Nov 22 '18 at 6:40

answered Nov 22 '18 at 6:05

Nitish Narang

2,938815

edited Nov 22 '18 at 6:40

answered Nov 22 '18 at 6:05

Nitish Narang

2,938815

answered Nov 22 '18 at 6:05

Nitish Narang

2,938815

answered Nov 22 '18 at 6:05

Nitish Narang

2,938815

1

It's very interesting You've used map function to organize candidates Woow Congratulations... Thank you

– Riller Vincci
Nov 22 '18 at 6:44

add a comment |

1

It's very interesting You've used map function to organize candidates Woow Congratulations... Thank you

– Riller Vincci
Nov 22 '18 at 6:44

It's very interesting You've used map function to organize candidates Woow Congratulations... Thank you

– Riller Vincci
Nov 22 '18 at 6:44

add a comment |

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