Input string was not in a correct format #2
double temp;
temp = (double)Convert.ToDouble("1234.5678");
Hey Lads and Ladies, I can't for the life of me figure out why the above line isn't working. The above line gives me a runtime error that says;
An unhandled exception of type
System.FormatException occurred in
mscorlib.dll
Additional information: Input string
was not in a correct format.
c# .net parsing double
edited Dec 24 '12 at 20:00
John Saunders
147k22204362
asked Mar 11 '11 at 16:11
Keith LoughnaneKeith Loughnane
1601117
add a comment |
double temp;
temp = (double)Convert.ToDouble("1234.5678");
Hey Lads and Ladies, I can't for the life of me figure out why the above line isn't working. The above line gives me a runtime error that says;
An unhandled exception of type
System.FormatException occurred in
mscorlib.dll
Additional information: Input string
was not in a correct format.
c# .net parsing double
edited Dec 24 '12 at 20:00
John Saunders
147k22204362
asked Mar 11 '11 at 16:11
Keith LoughnaneKeith Loughnane
1601117
4
+1 for hey ladies ;)
– Armance
Dec 15 '11 at 17:06
add a comment |
double temp;
temp = (double)Convert.ToDouble("1234.5678");
Hey Lads and Ladies, I can't for the life of me figure out why the above line isn't working. The above line gives me a runtime error that says;
An unhandled exception of type
System.FormatException occurred in
mscorlib.dll
Additional information: Input string
was not in a correct format.
c# .net parsing double
edited Dec 24 '12 at 20:00
John Saunders
147k22204362
asked Mar 11 '11 at 16:11
Keith LoughnaneKeith Loughnane
1601117
double temp;
temp = (double)Convert.ToDouble("1234.5678");
Hey Lads and Ladies, I can't for the life of me figure out why the above line isn't working. The above line gives me a runtime error that says;
An unhandled exception of type
System.FormatException occurred in
mscorlib.dll
Additional information: Input string
was not in a correct format.
c# .net parsing double
c# .net parsing double
edited Dec 24 '12 at 20:00
John Saunders
147k22204362
asked Mar 11 '11 at 16:11
Keith LoughnaneKeith Loughnane
1601117
edited Dec 24 '12 at 20:00
John Saunders
147k22204362
asked Mar 11 '11 at 16:11
Keith LoughnaneKeith Loughnane
1601117
edited Dec 24 '12 at 20:00
John Saunders
147k22204362
edited Dec 24 '12 at 20:00
John Saunders
147k22204362
edited Dec 24 '12 at 20:00
John Saunders
147k22204362
147k22204362
asked Mar 11 '11 at 16:11
Keith LoughnaneKeith Loughnane
1601117
asked Mar 11 '11 at 16:11
Keith LoughnaneKeith Loughnane
1601117
asked Mar 11 '11 at 16:11
Keith LoughnaneKeith Loughnane
1601117
1601117
4
+1 for hey ladies ;)
– Armance
Dec 15 '11 at 17:06
add a comment |
4
+1 for hey ladies ;)
– Armance
Dec 15 '11 at 17:06
4
4
+1 for hey ladies ;)
– Armance
Dec 15 '11 at 17:06
+1 for hey ladies ;)
– Armance
Dec 15 '11 at 17:06
add a comment |
10 Answers
10
active
oldest
votes
As far as I know the Convert methods use the current locale to do such conversions. In this case I'd guess your current locale would expect a comma as decimal point. Try to set the current locale for your application or the conversion to some language/country where dots are used (e.g. en_US). The method should provide a second optional parameter to provide a IFormatProvider as an alternative solution.
answered Mar 11 '11 at 16:16
MarioMario
29.3k44165
Thanks, That was it.
– Keith Loughnane
Mar 14 '11 at 13:07
add a comment |
In order to convert string to double without an exception:
An unhandled exception of type System.FormatException occurred in
mscorlib.dll
Additional information: Input string was not in a correct format.
make it culture-insensitive by providing second parameter value CultureInfo.InvariantCulture, for example:
double.Parse("1234.5678", CultureInfo.InvariantCulture)
answered Dec 24 '12 at 19:41
Vadim GremyachevVadim Gremyachev
35k770113
add a comment |
first solution (as mentioned in other posts):
double temp = double.Parse("1234.5678", CultureInfo.InvariantCulture);
second solution - make it default to current thread:
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
double temp = double.Parse("1234.5678");
third solution - make it default to block of code:
var prevCurrentCulture = Thread.CurrentThread.CurrentCulture;
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
...
double temp = double.Parse("1234.5678");
...
Thread.CurrentThread.CurrentCulture = prevCurrentCulture;
answered Dec 15 '14 at 11:11
BachorBachor
41079
add a comment |
You may be somehow using a european local. In some countries the . and , in numbers is reversed.
answered Mar 11 '11 at 16:17
Steve WellensSteve Wellens
19.1k22054
add a comment |
Hi as Mario says you must parse it taking into account the regional settings.
double temp = double.Parse("1234.5678", System.Globalization.CultureInfo.CurrentCulture);
Regards.
answered Mar 11 '11 at 16:23
Marco MedranoMarco Medrano
584
add a comment |
Check your regional settings. Your decimal symbol needs to be ".".
answered Mar 11 '11 at 16:16
Tertius GeldenhuysTertius Geldenhuys
352214
add a comment |
double temp = double.Parse("1234,5678");
answered Mar 11 '11 at 16:14
AchilleterzoAchilleterzo
686514
add a comment |
I recommend you use TryParse instead, so you don't need to handle parsing exceptions.
double temp = 0;
if (double.TryParse("123.456", out temp)
{
Console.WriteLine(string.Format("Parsed temp: {0}", temp);
}
else
{
Console.WriteLine("Input value was not able to be parsed.");
}
answered Mar 11 '11 at 16:17
Mike AtlasMike Atlas
7,00333456
add a comment |
I don't see any problem with the above code.it works fine and prints the value 1234.5678. I have tried it in VS2008. Probably, something to do with locale settings on your machine.
answered Mar 11 '11 at 16:15
KumarKumar
97447
add a comment |
I found the problem when you let the text box empty then
this error occurs so try this one to handle it.
An unhandled exception of type System.FormatException occurred in
mscorlib.dll Additional information: Input string was not in a correct
format.
if (!string.IsNullOrEmpty(Txt1.Text)) {int _qty = (int)Convert.ToInt32(Txt1.Text);}
edited Nov 22 '18 at 9:04
Moritz
57.6k19131184
answered Nov 22 '18 at 8:58
Tahir ShahzadTahir Shahzad
1
add a comment |
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10 Answers
10
active
oldest
votes
10 Answers
10
active
oldest
votes
active
oldest
votes
active
oldest
votes
As far as I know the Convert methods use the current locale to do such conversions. In this case I'd guess your current locale would expect a comma as decimal point. Try to set the current locale for your application or the conversion to some language/country where dots are used (e.g. en_US). The method should provide a second optional parameter to provide a IFormatProvider as an alternative solution.
answered Mar 11 '11 at 16:16
MarioMario
29.3k44165
Thanks, That was it.
– Keith Loughnane
Mar 14 '11 at 13:07
add a comment |
As far as I know the Convert methods use the current locale to do such conversions. In this case I'd guess your current locale would expect a comma as decimal point. Try to set the current locale for your application or the conversion to some language/country where dots are used (e.g. en_US). The method should provide a second optional parameter to provide a IFormatProvider as an alternative solution.
answered Mar 11 '11 at 16:16
MarioMario
29.3k44165
Thanks, That was it.
– Keith Loughnane
Mar 14 '11 at 13:07
add a comment |
As far as I know the Convert methods use the current locale to do such conversions. In this case I'd guess your current locale would expect a comma as decimal point. Try to set the current locale for your application or the conversion to some language/country where dots are used (e.g. en_US). The method should provide a second optional parameter to provide a IFormatProvider as an alternative solution.
answered Mar 11 '11 at 16:16
MarioMario
29.3k44165
As far as I know the Convert methods use the current locale to do such conversions. In this case I'd guess your current locale would expect a comma as decimal point. Try to set the current locale for your application or the conversion to some language/country where dots are used (e.g. en_US). The method should provide a second optional parameter to provide a IFormatProvider as an alternative solution.
answered Mar 11 '11 at 16:16
MarioMario
29.3k44165
answered Mar 11 '11 at 16:16
MarioMario
29.3k44165
answered Mar 11 '11 at 16:16
MarioMario
29.3k44165
answered Mar 11 '11 at 16:16
MarioMario
29.3k44165
29.3k44165
Thanks, That was it.
– Keith Loughnane
Mar 14 '11 at 13:07
add a comment |
Thanks, That was it.
– Keith Loughnane
Mar 14 '11 at 13:07
Thanks, That was it.
– Keith Loughnane
Mar 14 '11 at 13:07
Thanks, That was it.
– Keith Loughnane
Mar 14 '11 at 13:07
add a comment |
In order to convert string to double without an exception:
An unhandled exception of type System.FormatException occurred in
mscorlib.dll
Additional information: Input string was not in a correct format.
make it culture-insensitive by providing second parameter value CultureInfo.InvariantCulture, for example:
double.Parse("1234.5678", CultureInfo.InvariantCulture)
answered Dec 24 '12 at 19:41
Vadim GremyachevVadim Gremyachev
35k770113
add a comment |
In order to convert string to double without an exception:
An unhandled exception of type System.FormatException occurred in
mscorlib.dll
Additional information: Input string was not in a correct format.
make it culture-insensitive by providing second parameter value CultureInfo.InvariantCulture, for example:
double.Parse("1234.5678", CultureInfo.InvariantCulture)
answered Dec 24 '12 at 19:41
Vadim GremyachevVadim Gremyachev
35k770113
add a comment |
In order to convert string to double without an exception:
An unhandled exception of type System.FormatException occurred in
mscorlib.dll
Additional information: Input string was not in a correct format.
make it culture-insensitive by providing second parameter value CultureInfo.InvariantCulture, for example:
double.Parse("1234.5678", CultureInfo.InvariantCulture)
answered Dec 24 '12 at 19:41
Vadim GremyachevVadim Gremyachev
35k770113
In order to convert string to double without an exception:
An unhandled exception of type System.FormatException occurred in
mscorlib.dll
Additional information: Input string was not in a correct format.
make it culture-insensitive by providing second parameter value CultureInfo.InvariantCulture, for example:
double.Parse("1234.5678", CultureInfo.InvariantCulture)
answered Dec 24 '12 at 19:41
Vadim GremyachevVadim Gremyachev
35k770113
edited Nov 28 '13 at 11:52
answered Dec 24 '12 at 19:41
Vadim GremyachevVadim Gremyachev
35k770113
answered Dec 24 '12 at 19:41
Vadim GremyachevVadim Gremyachev
35k770113
answered Dec 24 '12 at 19:41
Vadim GremyachevVadim Gremyachev
35k770113
35k770113
add a comment |
add a comment |
first solution (as mentioned in other posts):
double temp = double.Parse("1234.5678", CultureInfo.InvariantCulture);
second solution - make it default to current thread:
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
double temp = double.Parse("1234.5678");
third solution - make it default to block of code:
var prevCurrentCulture = Thread.CurrentThread.CurrentCulture;
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
...
double temp = double.Parse("1234.5678");
...
Thread.CurrentThread.CurrentCulture = prevCurrentCulture;
answered Dec 15 '14 at 11:11
BachorBachor
41079
add a comment |
first solution (as mentioned in other posts):
double temp = double.Parse("1234.5678", CultureInfo.InvariantCulture);
second solution - make it default to current thread:
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
double temp = double.Parse("1234.5678");
third solution - make it default to block of code:
var prevCurrentCulture = Thread.CurrentThread.CurrentCulture;
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
...
double temp = double.Parse("1234.5678");
...
Thread.CurrentThread.CurrentCulture = prevCurrentCulture;
answered Dec 15 '14 at 11:11
BachorBachor
41079
add a comment |
first solution (as mentioned in other posts):
double temp = double.Parse("1234.5678", CultureInfo.InvariantCulture);
second solution - make it default to current thread:
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
double temp = double.Parse("1234.5678");
third solution - make it default to block of code:
var prevCurrentCulture = Thread.CurrentThread.CurrentCulture;
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
...
double temp = double.Parse("1234.5678");
...
Thread.CurrentThread.CurrentCulture = prevCurrentCulture;
answered Dec 15 '14 at 11:11
BachorBachor
41079
first solution (as mentioned in other posts):
double temp = double.Parse("1234.5678", CultureInfo.InvariantCulture);
second solution - make it default to current thread:
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
double temp = double.Parse("1234.5678");
third solution - make it default to block of code:
var prevCurrentCulture = Thread.CurrentThread.CurrentCulture;
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
...
double temp = double.Parse("1234.5678");
...
Thread.CurrentThread.CurrentCulture = prevCurrentCulture;
answered Dec 15 '14 at 11:11
BachorBachor
41079
answered Dec 15 '14 at 11:11
BachorBachor
41079
answered Dec 15 '14 at 11:11
BachorBachor
41079
answered Dec 15 '14 at 11:11
BachorBachor
41079
41079
add a comment |
add a comment |
You may be somehow using a european local. In some countries the . and , in numbers is reversed.
answered Mar 11 '11 at 16:17
Steve WellensSteve Wellens
19.1k22054
add a comment |
You may be somehow using a european local. In some countries the . and , in numbers is reversed.
answered Mar 11 '11 at 16:17
Steve WellensSteve Wellens
19.1k22054
add a comment |
You may be somehow using a european local. In some countries the . and , in numbers is reversed.
answered Mar 11 '11 at 16:17
Steve WellensSteve Wellens
19.1k22054
You may be somehow using a european local. In some countries the . and , in numbers is reversed.
answered Mar 11 '11 at 16:17
Steve WellensSteve Wellens
19.1k22054
answered Mar 11 '11 at 16:17
Steve WellensSteve Wellens
19.1k22054
answered Mar 11 '11 at 16:17
Steve WellensSteve Wellens
19.1k22054
answered Mar 11 '11 at 16:17
Steve WellensSteve Wellens
19.1k22054
19.1k22054
add a comment |
add a comment |
Hi as Mario says you must parse it taking into account the regional settings.
double temp = double.Parse("1234.5678", System.Globalization.CultureInfo.CurrentCulture);
Regards.
answered Mar 11 '11 at 16:23
Marco MedranoMarco Medrano
584
add a comment |
Hi as Mario says you must parse it taking into account the regional settings.
double temp = double.Parse("1234.5678", System.Globalization.CultureInfo.CurrentCulture);
Regards.
answered Mar 11 '11 at 16:23
Marco MedranoMarco Medrano
584
add a comment |
Hi as Mario says you must parse it taking into account the regional settings.
double temp = double.Parse("1234.5678", System.Globalization.CultureInfo.CurrentCulture);
Regards.
answered Mar 11 '11 at 16:23
Marco MedranoMarco Medrano
584
Hi as Mario says you must parse it taking into account the regional settings.
double temp = double.Parse("1234.5678", System.Globalization.CultureInfo.CurrentCulture);
Regards.
answered Mar 11 '11 at 16:23
Marco MedranoMarco Medrano
584
answered Mar 11 '11 at 16:23
Marco MedranoMarco Medrano
584
answered Mar 11 '11 at 16:23
Marco MedranoMarco Medrano
584
answered Mar 11 '11 at 16:23
Marco MedranoMarco Medrano
584
584
add a comment |
add a comment |
Check your regional settings. Your decimal symbol needs to be ".".
answered Mar 11 '11 at 16:16
Tertius GeldenhuysTertius Geldenhuys
352214
add a comment |
Check your regional settings. Your decimal symbol needs to be ".".
answered Mar 11 '11 at 16:16
Tertius GeldenhuysTertius Geldenhuys
352214
add a comment |
Check your regional settings. Your decimal symbol needs to be ".".
answered Mar 11 '11 at 16:16
Tertius GeldenhuysTertius Geldenhuys
352214
Check your regional settings. Your decimal symbol needs to be ".".
answered Mar 11 '11 at 16:16
Tertius GeldenhuysTertius Geldenhuys
352214
answered Mar 11 '11 at 16:16
Tertius GeldenhuysTertius Geldenhuys
352214
answered Mar 11 '11 at 16:16
Tertius GeldenhuysTertius Geldenhuys
352214
answered Mar 11 '11 at 16:16
Tertius GeldenhuysTertius Geldenhuys
352214
352214
add a comment |
add a comment |
double temp = double.Parse("1234,5678");
answered Mar 11 '11 at 16:14
AchilleterzoAchilleterzo
686514
add a comment |
double temp = double.Parse("1234,5678");
answered Mar 11 '11 at 16:14
AchilleterzoAchilleterzo
686514
add a comment |
double temp = double.Parse("1234,5678");
answered Mar 11 '11 at 16:14
AchilleterzoAchilleterzo
686514
double temp = double.Parse("1234,5678");
answered Mar 11 '11 at 16:14
AchilleterzoAchilleterzo
686514
answered Mar 11 '11 at 16:14
AchilleterzoAchilleterzo
686514
answered Mar 11 '11 at 16:14
AchilleterzoAchilleterzo
686514
answered Mar 11 '11 at 16:14
AchilleterzoAchilleterzo
686514
686514
add a comment |
add a comment |
I recommend you use TryParse instead, so you don't need to handle parsing exceptions.
double temp = 0;
if (double.TryParse("123.456", out temp)
{
Console.WriteLine(string.Format("Parsed temp: {0}", temp);
}
else
{
Console.WriteLine("Input value was not able to be parsed.");
}
answered Mar 11 '11 at 16:17
Mike AtlasMike Atlas
7,00333456
add a comment |
I recommend you use TryParse instead, so you don't need to handle parsing exceptions.
double temp = 0;
if (double.TryParse("123.456", out temp)
{
Console.WriteLine(string.Format("Parsed temp: {0}", temp);
}
else
{
Console.WriteLine("Input value was not able to be parsed.");
}
answered Mar 11 '11 at 16:17
Mike AtlasMike Atlas
7,00333456
add a comment |
I recommend you use TryParse instead, so you don't need to handle parsing exceptions.
double temp = 0;
if (double.TryParse("123.456", out temp)
{
Console.WriteLine(string.Format("Parsed temp: {0}", temp);
}
else
{
Console.WriteLine("Input value was not able to be parsed.");
}
answered Mar 11 '11 at 16:17
Mike AtlasMike Atlas
7,00333456
I recommend you use TryParse instead, so you don't need to handle parsing exceptions.
double temp = 0;
if (double.TryParse("123.456", out temp)
{
Console.WriteLine(string.Format("Parsed temp: {0}", temp);
}
else
{
Console.WriteLine("Input value was not able to be parsed.");
}
answered Mar 11 '11 at 16:17
Mike AtlasMike Atlas
7,00333456
answered Mar 11 '11 at 16:17
Mike AtlasMike Atlas
7,00333456
answered Mar 11 '11 at 16:17
Mike AtlasMike Atlas
7,00333456
answered Mar 11 '11 at 16:17
Mike AtlasMike Atlas
7,00333456
7,00333456
add a comment |
add a comment |
I don't see any problem with the above code.it works fine and prints the value 1234.5678. I have tried it in VS2008. Probably, something to do with locale settings on your machine.
answered Mar 11 '11 at 16:15
KumarKumar
97447
add a comment |
I don't see any problem with the above code.it works fine and prints the value 1234.5678. I have tried it in VS2008. Probably, something to do with locale settings on your machine.
answered Mar 11 '11 at 16:15
KumarKumar
97447
add a comment |
I don't see any problem with the above code.it works fine and prints the value 1234.5678. I have tried it in VS2008. Probably, something to do with locale settings on your machine.
answered Mar 11 '11 at 16:15
KumarKumar
97447
I don't see any problem with the above code.it works fine and prints the value 1234.5678. I have tried it in VS2008. Probably, something to do with locale settings on your machine.
answered Mar 11 '11 at 16:15
KumarKumar
97447
edited Mar 11 '11 at 16:20
answered Mar 11 '11 at 16:15
KumarKumar
97447
answered Mar 11 '11 at 16:15
KumarKumar
97447
answered Mar 11 '11 at 16:15
KumarKumar
97447
97447
add a comment |
add a comment |
I found the problem when you let the text box empty then
this error occurs so try this one to handle it.
An unhandled exception of type System.FormatException occurred in
mscorlib.dll Additional information: Input string was not in a correct
format.
if (!string.IsNullOrEmpty(Txt1.Text)) {int _qty = (int)Convert.ToInt32(Txt1.Text);}
edited Nov 22 '18 at 9:04
Moritz
57.6k19131184
answered Nov 22 '18 at 8:58
Tahir ShahzadTahir Shahzad
1
add a comment |
I found the problem when you let the text box empty then
this error occurs so try this one to handle it.
An unhandled exception of type System.FormatException occurred in
mscorlib.dll Additional information: Input string was not in a correct
format.
if (!string.IsNullOrEmpty(Txt1.Text)) {int _qty = (int)Convert.ToInt32(Txt1.Text);}
edited Nov 22 '18 at 9:04
Moritz
57.6k19131184
answered Nov 22 '18 at 8:58
Tahir ShahzadTahir Shahzad
1
add a comment |
I found the problem when you let the text box empty then
this error occurs so try this one to handle it.
An unhandled exception of type System.FormatException occurred in
mscorlib.dll Additional information: Input string was not in a correct
format.
if (!string.IsNullOrEmpty(Txt1.Text)) {int _qty = (int)Convert.ToInt32(Txt1.Text);}
edited Nov 22 '18 at 9:04
Moritz
57.6k19131184
answered Nov 22 '18 at 8:58
Tahir ShahzadTahir Shahzad
1
I found the problem when you let the text box empty then
this error occurs so try this one to handle it.
An unhandled exception of type System.FormatException occurred in
mscorlib.dll Additional information: Input string was not in a correct
format.
if (!string.IsNullOrEmpty(Txt1.Text)) {int _qty = (int)Convert.ToInt32(Txt1.Text);}
edited Nov 22 '18 at 9:04
Moritz
57.6k19131184
answered Nov 22 '18 at 8:58
Tahir ShahzadTahir Shahzad
1
edited Nov 22 '18 at 9:04
Moritz
57.6k19131184
edited Nov 22 '18 at 9:04
Moritz
57.6k19131184
edited Nov 22 '18 at 9:04
Moritz
57.6k19131184
57.6k19131184
answered Nov 22 '18 at 8:58
Tahir ShahzadTahir Shahzad
1
answered Nov 22 '18 at 8:58
Tahir ShahzadTahir Shahzad
1
answered Nov 22 '18 at 8:58
Tahir ShahzadTahir Shahzad
1
1
add a comment |
add a comment |
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+1 for hey ladies ;)
– Armance
Dec 15 '11 at 17:06