Parametrization of oriented circle
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I have noticed this pattern in a few questions and was wondering if it was a general rule?
When parametrizing a circle or radius 1 if the circle is clockwise is the parametrization always
$r=sin(t)i+cos(t)j$
and counterclockwise always
$r=cos(t)i+sin(t)j$
calculus
asked Dec 8 '18 at 20:28
user520403user520403
737
$endgroup$
add a comment |
$begingroup$
I have noticed this pattern in a few questions and was wondering if it was a general rule?
When parametrizing a circle or radius 1 if the circle is clockwise is the parametrization always
$r=sin(t)i+cos(t)j$
and counterclockwise always
$r=cos(t)i+sin(t)j$
calculus
asked Dec 8 '18 at 20:28
user520403user520403
737
$endgroup$
$begingroup$
Why you use j and I, why not just x an y? The direction is determined by the values of t and the functions used. draw it - may be with the aid of GeoGebra.
$endgroup$
– Moti
Dec 9 '18 at 2:26
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r = -(sin t)i + (cos t)j starts at the same point.
$endgroup$
– William Elliot
Dec 9 '18 at 3:02
add a comment |
$begingroup$
I have noticed this pattern in a few questions and was wondering if it was a general rule?
When parametrizing a circle or radius 1 if the circle is clockwise is the parametrization always
$r=sin(t)i+cos(t)j$
and counterclockwise always
$r=cos(t)i+sin(t)j$
calculus
asked Dec 8 '18 at 20:28
user520403user520403
737
$endgroup$
I have noticed this pattern in a few questions and was wondering if it was a general rule?
When parametrizing a circle or radius 1 if the circle is clockwise is the parametrization always
$r=sin(t)i+cos(t)j$
and counterclockwise always
$r=cos(t)i+sin(t)j$
calculus
calculus
asked Dec 8 '18 at 20:28
user520403user520403
737
asked Dec 8 '18 at 20:28
user520403user520403
737
asked Dec 8 '18 at 20:28
user520403user520403
737
asked Dec 8 '18 at 20:28
user520403user520403
737
asked Dec 8 '18 at 20:28
user520403user520403
737
737
$begingroup$
Why you use j and I, why not just x an y? The direction is determined by the values of t and the functions used. draw it - may be with the aid of GeoGebra.
$endgroup$
– Moti
Dec 9 '18 at 2:26
$begingroup$
r = -(sin t)i + (cos t)j starts at the same point.
$endgroup$
– William Elliot
Dec 9 '18 at 3:02
add a comment |
$begingroup$
Why you use j and I, why not just x an y? The direction is determined by the values of t and the functions used. draw it - may be with the aid of GeoGebra.
$endgroup$
– Moti
Dec 9 '18 at 2:26
$begingroup$
r = -(sin t)i + (cos t)j starts at the same point.
$endgroup$
– William Elliot
Dec 9 '18 at 3:02
$begingroup$
Why you use j and I, why not just x an y? The direction is determined by the values of t and the functions used. draw it - may be with the aid of GeoGebra.
$endgroup$
– Moti
Dec 9 '18 at 2:26
$begingroup$
Why you use j and I, why not just x an y? The direction is determined by the values of t and the functions used. draw it - may be with the aid of GeoGebra.
$endgroup$
– Moti
Dec 9 '18 at 2:26
$begingroup$
r = -(sin t)i + (cos t)j starts at the same point.
$endgroup$
– William Elliot
Dec 9 '18 at 3:02
$begingroup$
r = -(sin t)i + (cos t)j starts at the same point.
$endgroup$
– William Elliot
Dec 9 '18 at 3:02
add a comment |
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$begingroup$
Why you use j and I, why not just x an y? The direction is determined by the values of t and the functions used. draw it - may be with the aid of GeoGebra.
$endgroup$
– Moti
Dec 9 '18 at 2:26
$begingroup$
r = -(sin t)i + (cos t)j starts at the same point.
$endgroup$
– William Elliot
Dec 9 '18 at 3:02