Combinatorics based binary sequence
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We all know the standard base-$2$ representation of integers and many of you will know of Gray codes. Does anybody know of a name (or something I can use to find a good reference) for a method of sequencing a binary representation so that numbers higher in the sequence have more bits set? For example,
$$000, 001, 010, 100, 011, 101, 110, 111.$$
We set $i$ bits until all $n choose i$ combinations are used, then increment $i$. Does this sequence have a name?
combinatorics binary
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add a comment |
$begingroup$
We all know the standard base-$2$ representation of integers and many of you will know of Gray codes. Does anybody know of a name (or something I can use to find a good reference) for a method of sequencing a binary representation so that numbers higher in the sequence have more bits set? For example,
$$000, 001, 010, 100, 011, 101, 110, 111.$$
We set $i$ bits until all $n choose i$ combinations are used, then increment $i$. Does this sequence have a name?
combinatorics binary
$endgroup$
add a comment |
$begingroup$
We all know the standard base-$2$ representation of integers and many of you will know of Gray codes. Does anybody know of a name (or something I can use to find a good reference) for a method of sequencing a binary representation so that numbers higher in the sequence have more bits set? For example,
$$000, 001, 010, 100, 011, 101, 110, 111.$$
We set $i$ bits until all $n choose i$ combinations are used, then increment $i$. Does this sequence have a name?
combinatorics binary
$endgroup$
We all know the standard base-$2$ representation of integers and many of you will know of Gray codes. Does anybody know of a name (or something I can use to find a good reference) for a method of sequencing a binary representation so that numbers higher in the sequence have more bits set? For example,
$$000, 001, 010, 100, 011, 101, 110, 111.$$
We set $i$ bits until all $n choose i$ combinations are used, then increment $i$. Does this sequence have a name?
combinatorics binary
combinatorics binary
edited Dec 12 '18 at 10:07
Klangen
1,72811334
1,72811334
asked Mar 25 '13 at 15:26
KevinKevin
61
61
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This would be ordering binary words by bit count (sideways sum, Hamming weight) and lexicographically within one class. Don't know of any more standard name for this ordering.
There is actually a fairly fast algorithm to find the lexicographically next word with the same bit count if it exists. It is a nice exercice to describe it.
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1 Answer
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1 Answer
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$begingroup$
This would be ordering binary words by bit count (sideways sum, Hamming weight) and lexicographically within one class. Don't know of any more standard name for this ordering.
There is actually a fairly fast algorithm to find the lexicographically next word with the same bit count if it exists. It is a nice exercice to describe it.
$endgroup$
add a comment |
$begingroup$
This would be ordering binary words by bit count (sideways sum, Hamming weight) and lexicographically within one class. Don't know of any more standard name for this ordering.
There is actually a fairly fast algorithm to find the lexicographically next word with the same bit count if it exists. It is a nice exercice to describe it.
$endgroup$
add a comment |
$begingroup$
This would be ordering binary words by bit count (sideways sum, Hamming weight) and lexicographically within one class. Don't know of any more standard name for this ordering.
There is actually a fairly fast algorithm to find the lexicographically next word with the same bit count if it exists. It is a nice exercice to describe it.
$endgroup$
This would be ordering binary words by bit count (sideways sum, Hamming weight) and lexicographically within one class. Don't know of any more standard name for this ordering.
There is actually a fairly fast algorithm to find the lexicographically next word with the same bit count if it exists. It is a nice exercice to describe it.
answered Mar 25 '13 at 15:56
Marc van LeeuwenMarc van Leeuwen
86.9k5107222
86.9k5107222
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