Sign of the scalar product of vectors centered at the foci in an ellipsoid












0












$begingroup$


Consider an ellipsoid for the vector $vec{x}$ with equation



begin{equation}
sqrt{ lVertvec{x}rVert^2+a^2}+sqrt{lVertvec{x}+vec{c}rVert^2+a^2}=d
end{equation}



and parameters $a$, $d$ and $vec{c}$.



Is it true, and how would you proove, the following statement:




The scalar product of $2vec{x}+vec{c}$ and $vec{x}$ is always positive.




Specifically, $2vec{x}+vec{c}$ is the sum of the two vectors $vec{x}$ and $vec{x}+vec{c}$ starting at the foci, ending and pointing to the point $vec{x}$ on the ellipsoid.










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$endgroup$












  • $begingroup$
    Are you sure the equation is correct?
    $endgroup$
    – Aretino
    Dec 21 '18 at 15:55










  • $begingroup$
    maybe you are right, the same-major axis is not long enough. Would the veridicity of the statement change if I just chose an arbitrary major axis-length?
    $endgroup$
    – Tanatofobico
    Dec 21 '18 at 16:29










  • $begingroup$
    That scalar product is positive if the angle between vectors $vec x$ and $vec x+vec c$ is always acute. But that is not the case if the ellipsoid is stretched enough.
    $endgroup$
    – Aretino
    Dec 21 '18 at 16:35










  • $begingroup$
    Indeed, but I was asking between $2vec{x}+vec{c}$ and $vec{x}$.
    $endgroup$
    – Tanatofobico
    Dec 21 '18 at 19:24










  • $begingroup$
    The answer to the statement is no, anyway. One can proove as an exercise of constrained optimization that if the eccentricity of the ellipse is higher than $frac{3}{4}$ then there always is a point where $(2vec{x}+vec{c})cdotvec{x}$ is negative.
    $endgroup$
    – Tanatofobico
    Dec 22 '18 at 13:07
















0












$begingroup$


Consider an ellipsoid for the vector $vec{x}$ with equation



begin{equation}
sqrt{ lVertvec{x}rVert^2+a^2}+sqrt{lVertvec{x}+vec{c}rVert^2+a^2}=d
end{equation}



and parameters $a$, $d$ and $vec{c}$.



Is it true, and how would you proove, the following statement:




The scalar product of $2vec{x}+vec{c}$ and $vec{x}$ is always positive.




Specifically, $2vec{x}+vec{c}$ is the sum of the two vectors $vec{x}$ and $vec{x}+vec{c}$ starting at the foci, ending and pointing to the point $vec{x}$ on the ellipsoid.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Are you sure the equation is correct?
    $endgroup$
    – Aretino
    Dec 21 '18 at 15:55










  • $begingroup$
    maybe you are right, the same-major axis is not long enough. Would the veridicity of the statement change if I just chose an arbitrary major axis-length?
    $endgroup$
    – Tanatofobico
    Dec 21 '18 at 16:29










  • $begingroup$
    That scalar product is positive if the angle between vectors $vec x$ and $vec x+vec c$ is always acute. But that is not the case if the ellipsoid is stretched enough.
    $endgroup$
    – Aretino
    Dec 21 '18 at 16:35










  • $begingroup$
    Indeed, but I was asking between $2vec{x}+vec{c}$ and $vec{x}$.
    $endgroup$
    – Tanatofobico
    Dec 21 '18 at 19:24










  • $begingroup$
    The answer to the statement is no, anyway. One can proove as an exercise of constrained optimization that if the eccentricity of the ellipse is higher than $frac{3}{4}$ then there always is a point where $(2vec{x}+vec{c})cdotvec{x}$ is negative.
    $endgroup$
    – Tanatofobico
    Dec 22 '18 at 13:07














0












0








0





$begingroup$


Consider an ellipsoid for the vector $vec{x}$ with equation



begin{equation}
sqrt{ lVertvec{x}rVert^2+a^2}+sqrt{lVertvec{x}+vec{c}rVert^2+a^2}=d
end{equation}



and parameters $a$, $d$ and $vec{c}$.



Is it true, and how would you proove, the following statement:




The scalar product of $2vec{x}+vec{c}$ and $vec{x}$ is always positive.




Specifically, $2vec{x}+vec{c}$ is the sum of the two vectors $vec{x}$ and $vec{x}+vec{c}$ starting at the foci, ending and pointing to the point $vec{x}$ on the ellipsoid.










share|cite|improve this question











$endgroup$




Consider an ellipsoid for the vector $vec{x}$ with equation



begin{equation}
sqrt{ lVertvec{x}rVert^2+a^2}+sqrt{lVertvec{x}+vec{c}rVert^2+a^2}=d
end{equation}



and parameters $a$, $d$ and $vec{c}$.



Is it true, and how would you proove, the following statement:




The scalar product of $2vec{x}+vec{c}$ and $vec{x}$ is always positive.




Specifically, $2vec{x}+vec{c}$ is the sum of the two vectors $vec{x}$ and $vec{x}+vec{c}$ starting at the foci, ending and pointing to the point $vec{x}$ on the ellipsoid.







geometry conic-sections






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share|cite|improve this question













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share|cite|improve this question








edited Dec 21 '18 at 16:29







Tanatofobico

















asked Dec 21 '18 at 14:59









TanatofobicoTanatofobico

425




425












  • $begingroup$
    Are you sure the equation is correct?
    $endgroup$
    – Aretino
    Dec 21 '18 at 15:55










  • $begingroup$
    maybe you are right, the same-major axis is not long enough. Would the veridicity of the statement change if I just chose an arbitrary major axis-length?
    $endgroup$
    – Tanatofobico
    Dec 21 '18 at 16:29










  • $begingroup$
    That scalar product is positive if the angle between vectors $vec x$ and $vec x+vec c$ is always acute. But that is not the case if the ellipsoid is stretched enough.
    $endgroup$
    – Aretino
    Dec 21 '18 at 16:35










  • $begingroup$
    Indeed, but I was asking between $2vec{x}+vec{c}$ and $vec{x}$.
    $endgroup$
    – Tanatofobico
    Dec 21 '18 at 19:24










  • $begingroup$
    The answer to the statement is no, anyway. One can proove as an exercise of constrained optimization that if the eccentricity of the ellipse is higher than $frac{3}{4}$ then there always is a point where $(2vec{x}+vec{c})cdotvec{x}$ is negative.
    $endgroup$
    – Tanatofobico
    Dec 22 '18 at 13:07


















  • $begingroup$
    Are you sure the equation is correct?
    $endgroup$
    – Aretino
    Dec 21 '18 at 15:55










  • $begingroup$
    maybe you are right, the same-major axis is not long enough. Would the veridicity of the statement change if I just chose an arbitrary major axis-length?
    $endgroup$
    – Tanatofobico
    Dec 21 '18 at 16:29










  • $begingroup$
    That scalar product is positive if the angle between vectors $vec x$ and $vec x+vec c$ is always acute. But that is not the case if the ellipsoid is stretched enough.
    $endgroup$
    – Aretino
    Dec 21 '18 at 16:35










  • $begingroup$
    Indeed, but I was asking between $2vec{x}+vec{c}$ and $vec{x}$.
    $endgroup$
    – Tanatofobico
    Dec 21 '18 at 19:24










  • $begingroup$
    The answer to the statement is no, anyway. One can proove as an exercise of constrained optimization that if the eccentricity of the ellipse is higher than $frac{3}{4}$ then there always is a point where $(2vec{x}+vec{c})cdotvec{x}$ is negative.
    $endgroup$
    – Tanatofobico
    Dec 22 '18 at 13:07
















$begingroup$
Are you sure the equation is correct?
$endgroup$
– Aretino
Dec 21 '18 at 15:55




$begingroup$
Are you sure the equation is correct?
$endgroup$
– Aretino
Dec 21 '18 at 15:55












$begingroup$
maybe you are right, the same-major axis is not long enough. Would the veridicity of the statement change if I just chose an arbitrary major axis-length?
$endgroup$
– Tanatofobico
Dec 21 '18 at 16:29




$begingroup$
maybe you are right, the same-major axis is not long enough. Would the veridicity of the statement change if I just chose an arbitrary major axis-length?
$endgroup$
– Tanatofobico
Dec 21 '18 at 16:29












$begingroup$
That scalar product is positive if the angle between vectors $vec x$ and $vec x+vec c$ is always acute. But that is not the case if the ellipsoid is stretched enough.
$endgroup$
– Aretino
Dec 21 '18 at 16:35




$begingroup$
That scalar product is positive if the angle between vectors $vec x$ and $vec x+vec c$ is always acute. But that is not the case if the ellipsoid is stretched enough.
$endgroup$
– Aretino
Dec 21 '18 at 16:35












$begingroup$
Indeed, but I was asking between $2vec{x}+vec{c}$ and $vec{x}$.
$endgroup$
– Tanatofobico
Dec 21 '18 at 19:24




$begingroup$
Indeed, but I was asking between $2vec{x}+vec{c}$ and $vec{x}$.
$endgroup$
– Tanatofobico
Dec 21 '18 at 19:24












$begingroup$
The answer to the statement is no, anyway. One can proove as an exercise of constrained optimization that if the eccentricity of the ellipse is higher than $frac{3}{4}$ then there always is a point where $(2vec{x}+vec{c})cdotvec{x}$ is negative.
$endgroup$
– Tanatofobico
Dec 22 '18 at 13:07




$begingroup$
The answer to the statement is no, anyway. One can proove as an exercise of constrained optimization that if the eccentricity of the ellipse is higher than $frac{3}{4}$ then there always is a point where $(2vec{x}+vec{c})cdotvec{x}$ is negative.
$endgroup$
– Tanatofobico
Dec 22 '18 at 13:07










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