Accessing multiple childs returns undefined
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I am trying to access the layout using @ViewChild, but when I use it with QueryList it returns undefined.
<ng-template let-service="item" backgroundColor="pink">
<FlexboxLayout flexDirection="row" backgroundColor="#26252A">
<GridLayout class="item"
[id]="service.name"
#grid
rows="*, *, 2*" columns="100, *, 10"
>
Above is html template part (not complete ofc). And here is the typescript:
@ViewChild('grid') grids: QueryList<ElementRef>;
add(){
console.log("grid " + this.grids.last.nativeElement.id);
}
So this returns : "ERROR TypeError: undefined is not an object (evaluating 'this.grids.last.nativeElement')"
angular typescript nativescript edited Nov 27 '18 at 0:47
dmcgrandle
2,3991722
asked Nov 26 '18 at 21:18
AngeloAngelo
305
add a comment |
0
I am trying to access the layout using @ViewChild, but when I use it with QueryList it returns undefined.
<ng-template let-service="item" backgroundColor="pink">
<FlexboxLayout flexDirection="row" backgroundColor="#26252A">
<GridLayout class="item"
[id]="service.name"
#grid
rows="*, *, 2*" columns="100, *, 10"
>
Above is html template part (not complete ofc). And here is the typescript:
@ViewChild('grid') grids: QueryList<ElementRef>;
add(){
console.log("grid " + this.grids.last.nativeElement.id);
}
So this returns : "ERROR TypeError: undefined is not an object (evaluating 'this.grids.last.nativeElement')"
angular typescript nativescript edited Nov 27 '18 at 0:47
dmcgrandle
2,3991722
asked Nov 26 '18 at 21:18
AngeloAngelo
305
2
You want@ViewChildren.@ViewChildis for a single element, not a list.
– John Montgomery
Nov 26 '18 at 21:32
Thank you. That worked, but for some reason when I iterate through it it shows the first element as duplicate, so instead of 2 elements, it shows 3
– Angelo
Nov 27 '18 at 8:31
add a comment |
0
0
0
I am trying to access the layout using @ViewChild, but when I use it with QueryList it returns undefined.
<ng-template let-service="item" backgroundColor="pink">
<FlexboxLayout flexDirection="row" backgroundColor="#26252A">
<GridLayout class="item"
[id]="service.name"
#grid
rows="*, *, 2*" columns="100, *, 10"
>
Above is html template part (not complete ofc). And here is the typescript:
@ViewChild('grid') grids: QueryList<ElementRef>;
add(){
console.log("grid " + this.grids.last.nativeElement.id);
}
So this returns : "ERROR TypeError: undefined is not an object (evaluating 'this.grids.last.nativeElement')"
angular typescript nativescript edited Nov 27 '18 at 0:47
dmcgrandle
2,3991722
asked Nov 26 '18 at 21:18
AngeloAngelo
305
I am trying to access the layout using @ViewChild, but when I use it with QueryList it returns undefined.
<ng-template let-service="item" backgroundColor="pink">
<FlexboxLayout flexDirection="row" backgroundColor="#26252A">
<GridLayout class="item"
[id]="service.name"
#grid
rows="*, *, 2*" columns="100, *, 10"
>
Above is html template part (not complete ofc). And here is the typescript:
@ViewChild('grid') grids: QueryList<ElementRef>;
add(){
console.log("grid " + this.grids.last.nativeElement.id);
}
So this returns : "ERROR TypeError: undefined is not an object (evaluating 'this.grids.last.nativeElement')"
angular typescript nativescript angular typescript nativescript edited Nov 27 '18 at 0:47
dmcgrandle
2,3991722
asked Nov 26 '18 at 21:18
AngeloAngelo
305
edited Nov 27 '18 at 0:47
dmcgrandle
2,3991722
asked Nov 26 '18 at 21:18
AngeloAngelo
305
edited Nov 27 '18 at 0:47
dmcgrandle
2,3991722
edited Nov 27 '18 at 0:47
dmcgrandle
2,3991722
edited Nov 27 '18 at 0:47
dmcgrandle
2,3991722
2,3991722
asked Nov 26 '18 at 21:18
AngeloAngelo
305
asked Nov 26 '18 at 21:18
AngeloAngelo
305
asked Nov 26 '18 at 21:18
AngeloAngelo
305
305
2
You want@ViewChildren.@ViewChildis for a single element, not a list.
– John Montgomery
Nov 26 '18 at 21:32
Thank you. That worked, but for some reason when I iterate through it it shows the first element as duplicate, so instead of 2 elements, it shows 3
– Angelo
Nov 27 '18 at 8:31
add a comment |
2
You want@ViewChildren.@ViewChildis for a single element, not a list.
– John Montgomery
Nov 26 '18 at 21:32
Thank you. That worked, but for some reason when I iterate through it it shows the first element as duplicate, so instead of 2 elements, it shows 3
– Angelo
Nov 27 '18 at 8:31
2
2
You want
@ViewChildren. @ViewChild is for a single element, not a list.– John Montgomery
Nov 26 '18 at 21:32
You want
@ViewChildren. @ViewChild is for a single element, not a list.– John Montgomery
Nov 26 '18 at 21:32
Thank you. That worked, but for some reason when I iterate through it it shows the first element as duplicate, so instead of 2 elements, it shows 3
– Angelo
Nov 27 '18 at 8:31
Thank you. That worked, but for some reason when I iterate through it it shows the first element as duplicate, so instead of 2 elements, it shows 3
– Angelo
Nov 27 '18 at 8:31
add a comment |
0
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2
You want
@ViewChildren.@ViewChildis for a single element, not a list.– John Montgomery
Nov 26 '18 at 21:32
Thank you. That worked, but for some reason when I iterate through it it shows the first element as duplicate, so instead of 2 elements, it shows 3
– Angelo
Nov 27 '18 at 8:31