Error Message: “TOK_ALLCOLREF is not supported in current context” while using nested select in hive2.3.3
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when i use the nested select in hive like this
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from
(Select month,day, remote_addr,count(1) as pv
from ods_weblog_detail group by remote_addr,month,day) as a;
it returns the error message："TOK_ALLCOLREF is not supported in current context".
but when I select a.month,a.day and sum(a.pv)/count(a.*) seperately like this:
Select
sum(a.pv)/count(a.*)
from
(Select month,day, remote_addr,count(*) as pv from ods_weblog_detail group by remote_addr,month,day) as a;
OR this:
Select
a.month,a.day
from
(Select month,day, remote_addr,count(*) as pv
from
ods_weblog_detail
group by remote_addr,month,day) as a;
Both statements give me the right answer.
So why can't I select these three(a.month,a.day and sum(a.pv)/count(a.*)) together in one statement? thanks a lot!!!
select hive bigdata
edited Nov 27 '18 at 1:31
Gaurang Shah
3,58521537
asked Nov 27 '18 at 1:28
Spark SunSpark Sun
1
add a comment |
when i use the nested select in hive like this
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from
(Select month,day, remote_addr,count(1) as pv
from ods_weblog_detail group by remote_addr,month,day) as a;
it returns the error message："TOK_ALLCOLREF is not supported in current context".
but when I select a.month,a.day and sum(a.pv)/count(a.*) seperately like this:
Select
sum(a.pv)/count(a.*)
from
(Select month,day, remote_addr,count(*) as pv from ods_weblog_detail group by remote_addr,month,day) as a;
OR this:
Select
a.month,a.day
from
(Select month,day, remote_addr,count(*) as pv
from
ods_weblog_detail
group by remote_addr,month,day) as a;
Both statements give me the right answer.
So why can't I select these three(a.month,a.day and sum(a.pv)/count(a.*)) together in one statement? thanks a lot!!!
select hive bigdata
edited Nov 27 '18 at 1:31
Gaurang Shah
3,58521537
asked Nov 27 '18 at 1:28
Spark SunSpark Sun
1
add a comment |
when i use the nested select in hive like this
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from
(Select month,day, remote_addr,count(1) as pv
from ods_weblog_detail group by remote_addr,month,day) as a;
it returns the error message："TOK_ALLCOLREF is not supported in current context".
but when I select a.month,a.day and sum(a.pv)/count(a.*) seperately like this:
Select
sum(a.pv)/count(a.*)
from
(Select month,day, remote_addr,count(*) as pv from ods_weblog_detail group by remote_addr,month,day) as a;
OR this:
Select
a.month,a.day
from
(Select month,day, remote_addr,count(*) as pv
from
ods_weblog_detail
group by remote_addr,month,day) as a;
Both statements give me the right answer.
So why can't I select these three(a.month,a.day and sum(a.pv)/count(a.*)) together in one statement? thanks a lot!!!
select hive bigdata
edited Nov 27 '18 at 1:31
Gaurang Shah
3,58521537
asked Nov 27 '18 at 1:28
Spark SunSpark Sun
1
when i use the nested select in hive like this
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from
(Select month,day, remote_addr,count(1) as pv
from ods_weblog_detail group by remote_addr,month,day) as a;
it returns the error message："TOK_ALLCOLREF is not supported in current context".
but when I select a.month,a.day and sum(a.pv)/count(a.*) seperately like this:
Select
sum(a.pv)/count(a.*)
from
(Select month,day, remote_addr,count(*) as pv from ods_weblog_detail group by remote_addr,month,day) as a;
OR this:
Select
a.month,a.day
from
(Select month,day, remote_addr,count(*) as pv
from
ods_weblog_detail
group by remote_addr,month,day) as a;
Both statements give me the right answer.
So why can't I select these three(a.month,a.day and sum(a.pv)/count(a.*)) together in one statement? thanks a lot!!!
select hive bigdata
select hive bigdata
edited Nov 27 '18 at 1:31
Gaurang Shah
3,58521537
asked Nov 27 '18 at 1:28
Spark SunSpark Sun
1
edited Nov 27 '18 at 1:31
Gaurang Shah
3,58521537
asked Nov 27 '18 at 1:28
Spark SunSpark Sun
1
edited Nov 27 '18 at 1:31
Gaurang Shah
3,58521537
edited Nov 27 '18 at 1:31
Gaurang Shah
3,58521537
edited Nov 27 '18 at 1:31
Gaurang Shah
3,58521537
3,58521537
asked Nov 27 '18 at 1:28
Spark SunSpark Sun
1
asked Nov 27 '18 at 1:28
Spark SunSpark Sun
1
asked Nov 27 '18 at 1:28
Spark SunSpark Sun
1
1
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The query is missing a group by.
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from (select month,day, remote_addr,count(1) as pv
from ods_weblog_detail
group by remote_addr,month,day
) a
group by a.month,a.day
The query can also be simplified as below.
select month,day,remote_addr
,sum(count(*)) over(partition by month,day,remote_addr)/count(*) over(partition by month,day) as res
from ods_weblog_detail
answered Nov 27 '18 at 11:44
Vamsi PrabhalaVamsi Prabhala
41.8k42140
thanks, i've solved this proplem~
– Spark Sun
Dec 5 '18 at 9:09
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The query is missing a group by.
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from (select month,day, remote_addr,count(1) as pv
from ods_weblog_detail
group by remote_addr,month,day
) a
group by a.month,a.day
The query can also be simplified as below.
select month,day,remote_addr
,sum(count(*)) over(partition by month,day,remote_addr)/count(*) over(partition by month,day) as res
from ods_weblog_detail
answered Nov 27 '18 at 11:44
Vamsi PrabhalaVamsi Prabhala
41.8k42140
thanks, i've solved this proplem~
– Spark Sun
Dec 5 '18 at 9:09
add a comment |
The query is missing a group by.
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from (select month,day, remote_addr,count(1) as pv
from ods_weblog_detail
group by remote_addr,month,day
) a
group by a.month,a.day
The query can also be simplified as below.
select month,day,remote_addr
,sum(count(*)) over(partition by month,day,remote_addr)/count(*) over(partition by month,day) as res
from ods_weblog_detail
answered Nov 27 '18 at 11:44
Vamsi PrabhalaVamsi Prabhala
41.8k42140
thanks, i've solved this proplem~
– Spark Sun
Dec 5 '18 at 9:09
add a comment |
The query is missing a group by.
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from (select month,day, remote_addr,count(1) as pv
from ods_weblog_detail
group by remote_addr,month,day
) a
group by a.month,a.day
The query can also be simplified as below.
select month,day,remote_addr
,sum(count(*)) over(partition by month,day,remote_addr)/count(*) over(partition by month,day) as res
from ods_weblog_detail
answered Nov 27 '18 at 11:44
Vamsi PrabhalaVamsi Prabhala
41.8k42140
The query is missing a group by.
Select
a.month,
a.day,
sum(a.pv)/count(a.*)
from (select month,day, remote_addr,count(1) as pv
from ods_weblog_detail
group by remote_addr,month,day
) a
group by a.month,a.day
The query can also be simplified as below.
select month,day,remote_addr
,sum(count(*)) over(partition by month,day,remote_addr)/count(*) over(partition by month,day) as res
from ods_weblog_detail
answered Nov 27 '18 at 11:44
Vamsi PrabhalaVamsi Prabhala
41.8k42140
answered Nov 27 '18 at 11:44
Vamsi PrabhalaVamsi Prabhala
41.8k42140
answered Nov 27 '18 at 11:44
Vamsi PrabhalaVamsi Prabhala
41.8k42140
answered Nov 27 '18 at 11:44
Vamsi PrabhalaVamsi Prabhala
41.8k42140
41.8k42140
thanks, i've solved this proplem~
– Spark Sun
Dec 5 '18 at 9:09
add a comment |
thanks, i've solved this proplem~
– Spark Sun
Dec 5 '18 at 9:09
thanks, i've solved this proplem~
– Spark Sun
Dec 5 '18 at 9:09
thanks, i've solved this proplem~
– Spark Sun
Dec 5 '18 at 9:09
add a comment |
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