$57$ companies. $10$ displayed at random. Probability of being displayed?
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- In my industry our clients are presented with $10$ companies from a possible $57$ to select and send work to. They only choose $1$.
What is the probability that a company is displayed in the $10$ shown to the client?
My attempt: $dfrac{10}{57}$
- Another group of companies are in a separate pot and $2$ are displayed from a possible $10$. What is the probability that a company is displayed in the $2$ shown to the client?
Apologies if this appears basic or I have failed to include any relevant information - I have no idea where to begin!
probability
edited Nov 21 at 15:32
N. F. Taussig
42.8k93254
asked Nov 21 at 12:24
Dan W
1
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Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
0
down vote
favorite
- In my industry our clients are presented with $10$ companies from a possible $57$ to select and send work to. They only choose $1$.
What is the probability that a company is displayed in the $10$ shown to the client?
My attempt: $dfrac{10}{57}$
- Another group of companies are in a separate pot and $2$ are displayed from a possible $10$. What is the probability that a company is displayed in the $2$ shown to the client?
Apologies if this appears basic or I have failed to include any relevant information - I have no idea where to begin!
probability
edited Nov 21 at 15:32
N. F. Taussig
42.8k93254
asked Nov 21 at 12:24
Dan W
1
New contributor
Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 at 15:34
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
- In my industry our clients are presented with $10$ companies from a possible $57$ to select and send work to. They only choose $1$.
What is the probability that a company is displayed in the $10$ shown to the client?
My attempt: $dfrac{10}{57}$
- Another group of companies are in a separate pot and $2$ are displayed from a possible $10$. What is the probability that a company is displayed in the $2$ shown to the client?
Apologies if this appears basic or I have failed to include any relevant information - I have no idea where to begin!
probability
edited Nov 21 at 15:32
N. F. Taussig
42.8k93254
asked Nov 21 at 12:24
Dan W
1
New contributor
Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
- In my industry our clients are presented with $10$ companies from a possible $57$ to select and send work to. They only choose $1$.
What is the probability that a company is displayed in the $10$ shown to the client?
My attempt: $dfrac{10}{57}$
- Another group of companies are in a separate pot and $2$ are displayed from a possible $10$. What is the probability that a company is displayed in the $2$ shown to the client?
Apologies if this appears basic or I have failed to include any relevant information - I have no idea where to begin!
probability
probability
edited Nov 21 at 15:32
N. F. Taussig
42.8k93254
asked Nov 21 at 12:24
Dan W
1
New contributor
Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Nov 21 at 15:32
N. F. Taussig
42.8k93254
asked Nov 21 at 12:24
Dan W
1
New contributor
Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Nov 21 at 15:32
N. F. Taussig
42.8k93254
edited Nov 21 at 15:32
N. F. Taussig
42.8k93254
edited Nov 21 at 15:32
N. F. Taussig
42.8k93254
42.8k93254
asked Nov 21 at 12:24
Dan W
1
New contributor
Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 21 at 12:24
Dan W
1
asked Nov 21 at 12:24
Dan W
1
1
New contributor
Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Dan W is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 at 15:34
add a comment |
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 at 15:34
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 at 12:30
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 at 12:36
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 at 15:34
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 at 15:34
add a comment |
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Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 at 15:34