Recognise this Cayley table? Almost embedded +_2











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Finding monoids represented by very simple string rewrite systems. Come to a monoid of the following form.



({0,1,2} , * )



Where * is the binary operation with the following Cayley table:



*    0    1    2
0 0 1 2
1 1 2 1
2 2 1 2


Does anyone recognise this Cayley table?



If it helps, I'd expect the next monoid in my generation, M = ({0,1,2,3}, *)
Where * is the bi.op with the Cayley table:



*    0    1    2    3
0 0 1 2 3
1 1 2 3 1
2 2 3 1 2
3 3 1 2 3


In general * for a Monoid, M=( A , *) where |A| = n



*    0    1    2 .. n-1
0 0 1 2 .. n-1
1 1 2 3 .. 1
2 2 3 4 .. 2
. . . . .
n-1 n-1 1 2 .. n-1









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  • 2




    The only question I can find in your post is "Does anyone recognise this kayley table?". Is that really what you wanted to find out?
    – MJD
    Nov 21 at 12:15






  • 1




    The nonzero elements form a submonoid isomorphic to the cyclic group of order $n$. So the monoid here is the cyclic group of order $n$ with a new identity element $0$ adjoined.
    – Derek Holt
    Nov 21 at 16:20










  • To clarify. I'm currently researching monoids which admit a presentation by a complete string rewriting system as to provide a solution to the word problem. Have produced the table from the s.r.s < a | { (aaaa, a) } >. In working through classes of string rewrite systems I've managed to find some nice paterns in the multiplication tables (probably a more correct term than Kayley table as we are outside group theory). Nice tables like modular addition have cropped up. Was wondering if this was a nice table with a name that anyone recognised.
    – O.Gage
    Nov 24 at 20:52















up vote
0
down vote

favorite












Finding monoids represented by very simple string rewrite systems. Come to a monoid of the following form.



({0,1,2} , * )



Where * is the binary operation with the following Cayley table:



*    0    1    2
0 0 1 2
1 1 2 1
2 2 1 2


Does anyone recognise this Cayley table?



If it helps, I'd expect the next monoid in my generation, M = ({0,1,2,3}, *)
Where * is the bi.op with the Cayley table:



*    0    1    2    3
0 0 1 2 3
1 1 2 3 1
2 2 3 1 2
3 3 1 2 3


In general * for a Monoid, M=( A , *) where |A| = n



*    0    1    2 .. n-1
0 0 1 2 .. n-1
1 1 2 3 .. 1
2 2 3 4 .. 2
. . . . .
n-1 n-1 1 2 .. n-1









share|cite|improve this question









New contributor




O.Gage is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 2




    The only question I can find in your post is "Does anyone recognise this kayley table?". Is that really what you wanted to find out?
    – MJD
    Nov 21 at 12:15






  • 1




    The nonzero elements form a submonoid isomorphic to the cyclic group of order $n$. So the monoid here is the cyclic group of order $n$ with a new identity element $0$ adjoined.
    – Derek Holt
    Nov 21 at 16:20










  • To clarify. I'm currently researching monoids which admit a presentation by a complete string rewriting system as to provide a solution to the word problem. Have produced the table from the s.r.s < a | { (aaaa, a) } >. In working through classes of string rewrite systems I've managed to find some nice paterns in the multiplication tables (probably a more correct term than Kayley table as we are outside group theory). Nice tables like modular addition have cropped up. Was wondering if this was a nice table with a name that anyone recognised.
    – O.Gage
    Nov 24 at 20:52













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Finding monoids represented by very simple string rewrite systems. Come to a monoid of the following form.



({0,1,2} , * )



Where * is the binary operation with the following Cayley table:



*    0    1    2
0 0 1 2
1 1 2 1
2 2 1 2


Does anyone recognise this Cayley table?



If it helps, I'd expect the next monoid in my generation, M = ({0,1,2,3}, *)
Where * is the bi.op with the Cayley table:



*    0    1    2    3
0 0 1 2 3
1 1 2 3 1
2 2 3 1 2
3 3 1 2 3


In general * for a Monoid, M=( A , *) where |A| = n



*    0    1    2 .. n-1
0 0 1 2 .. n-1
1 1 2 3 .. 1
2 2 3 4 .. 2
. . . . .
n-1 n-1 1 2 .. n-1









share|cite|improve this question









New contributor




O.Gage is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Finding monoids represented by very simple string rewrite systems. Come to a monoid of the following form.



({0,1,2} , * )



Where * is the binary operation with the following Cayley table:



*    0    1    2
0 0 1 2
1 1 2 1
2 2 1 2


Does anyone recognise this Cayley table?



If it helps, I'd expect the next monoid in my generation, M = ({0,1,2,3}, *)
Where * is the bi.op with the Cayley table:



*    0    1    2    3
0 0 1 2 3
1 1 2 3 1
2 2 3 1 2
3 3 1 2 3


In general * for a Monoid, M=( A , *) where |A| = n



*    0    1    2 .. n-1
0 0 1 2 .. n-1
1 1 2 3 .. 1
2 2 3 4 .. 2
. . . . .
n-1 n-1 1 2 .. n-1






group-theory word-problem monoid






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edited Nov 21 at 13:11









Nicky Hekster

28k53254




28k53254






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asked Nov 21 at 11:29









O.Gage

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O.Gage is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






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Check out our Code of Conduct.








  • 2




    The only question I can find in your post is "Does anyone recognise this kayley table?". Is that really what you wanted to find out?
    – MJD
    Nov 21 at 12:15






  • 1




    The nonzero elements form a submonoid isomorphic to the cyclic group of order $n$. So the monoid here is the cyclic group of order $n$ with a new identity element $0$ adjoined.
    – Derek Holt
    Nov 21 at 16:20










  • To clarify. I'm currently researching monoids which admit a presentation by a complete string rewriting system as to provide a solution to the word problem. Have produced the table from the s.r.s < a | { (aaaa, a) } >. In working through classes of string rewrite systems I've managed to find some nice paterns in the multiplication tables (probably a more correct term than Kayley table as we are outside group theory). Nice tables like modular addition have cropped up. Was wondering if this was a nice table with a name that anyone recognised.
    – O.Gage
    Nov 24 at 20:52














  • 2




    The only question I can find in your post is "Does anyone recognise this kayley table?". Is that really what you wanted to find out?
    – MJD
    Nov 21 at 12:15






  • 1




    The nonzero elements form a submonoid isomorphic to the cyclic group of order $n$. So the monoid here is the cyclic group of order $n$ with a new identity element $0$ adjoined.
    – Derek Holt
    Nov 21 at 16:20










  • To clarify. I'm currently researching monoids which admit a presentation by a complete string rewriting system as to provide a solution to the word problem. Have produced the table from the s.r.s < a | { (aaaa, a) } >. In working through classes of string rewrite systems I've managed to find some nice paterns in the multiplication tables (probably a more correct term than Kayley table as we are outside group theory). Nice tables like modular addition have cropped up. Was wondering if this was a nice table with a name that anyone recognised.
    – O.Gage
    Nov 24 at 20:52








2




2




The only question I can find in your post is "Does anyone recognise this kayley table?". Is that really what you wanted to find out?
– MJD
Nov 21 at 12:15




The only question I can find in your post is "Does anyone recognise this kayley table?". Is that really what you wanted to find out?
– MJD
Nov 21 at 12:15




1




1




The nonzero elements form a submonoid isomorphic to the cyclic group of order $n$. So the monoid here is the cyclic group of order $n$ with a new identity element $0$ adjoined.
– Derek Holt
Nov 21 at 16:20




The nonzero elements form a submonoid isomorphic to the cyclic group of order $n$. So the monoid here is the cyclic group of order $n$ with a new identity element $0$ adjoined.
– Derek Holt
Nov 21 at 16:20












To clarify. I'm currently researching monoids which admit a presentation by a complete string rewriting system as to provide a solution to the word problem. Have produced the table from the s.r.s < a | { (aaaa, a) } >. In working through classes of string rewrite systems I've managed to find some nice paterns in the multiplication tables (probably a more correct term than Kayley table as we are outside group theory). Nice tables like modular addition have cropped up. Was wondering if this was a nice table with a name that anyone recognised.
– O.Gage
Nov 24 at 20:52




To clarify. I'm currently researching monoids which admit a presentation by a complete string rewriting system as to provide a solution to the word problem. Have produced the table from the s.r.s < a | { (aaaa, a) } >. In working through classes of string rewrite systems I've managed to find some nice paterns in the multiplication tables (probably a more correct term than Kayley table as we are outside group theory). Nice tables like modular addition have cropped up. Was wondering if this was a nice table with a name that anyone recognised.
– O.Gage
Nov 24 at 20:52















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