Homogeneous Fredholm integral equation of the first kind with positive symmetric kernel











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Given the equation
$$int^{1}_{-1}K(|x-t|)varphi(t)dt=0,$$
where the kernel is positive: $K(x)>0$; equation is satisfied for $xin [-1,1]$. $K(x)$ and $varphi(x)$ are real and continuous functions. I'm looking for nontrivial solutions $varphi(x)$.



Unfortunately, the explicit form of kernel $K(x)$ is unknown, but approximately K(x) is close to $exp(-lambda x)$.



I suppose, that if kernel $K(x)$ is not constant, then only trivial solutions exist. (If kernel is constant, then any odd function satisfies the equation.) Is this so? And how to prove it?










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    Given the equation
    $$int^{1}_{-1}K(|x-t|)varphi(t)dt=0,$$
    where the kernel is positive: $K(x)>0$; equation is satisfied for $xin [-1,1]$. $K(x)$ and $varphi(x)$ are real and continuous functions. I'm looking for nontrivial solutions $varphi(x)$.



    Unfortunately, the explicit form of kernel $K(x)$ is unknown, but approximately K(x) is close to $exp(-lambda x)$.



    I suppose, that if kernel $K(x)$ is not constant, then only trivial solutions exist. (If kernel is constant, then any odd function satisfies the equation.) Is this so? And how to prove it?










    share|cite|improve this question







    New contributor




    And111 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















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      Given the equation
      $$int^{1}_{-1}K(|x-t|)varphi(t)dt=0,$$
      where the kernel is positive: $K(x)>0$; equation is satisfied for $xin [-1,1]$. $K(x)$ and $varphi(x)$ are real and continuous functions. I'm looking for nontrivial solutions $varphi(x)$.



      Unfortunately, the explicit form of kernel $K(x)$ is unknown, but approximately K(x) is close to $exp(-lambda x)$.



      I suppose, that if kernel $K(x)$ is not constant, then only trivial solutions exist. (If kernel is constant, then any odd function satisfies the equation.) Is this so? And how to prove it?










      share|cite|improve this question







      New contributor




      And111 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Given the equation
      $$int^{1}_{-1}K(|x-t|)varphi(t)dt=0,$$
      where the kernel is positive: $K(x)>0$; equation is satisfied for $xin [-1,1]$. $K(x)$ and $varphi(x)$ are real and continuous functions. I'm looking for nontrivial solutions $varphi(x)$.



      Unfortunately, the explicit form of kernel $K(x)$ is unknown, but approximately K(x) is close to $exp(-lambda x)$.



      I suppose, that if kernel $K(x)$ is not constant, then only trivial solutions exist. (If kernel is constant, then any odd function satisfies the equation.) Is this so? And how to prove it?







      integral-equations






      share|cite|improve this question







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      And111 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question







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      Check out our Code of Conduct.









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      share|cite|improve this question






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      asked Nov 20 at 20:06









      And111

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