Regular expression with iterator
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I am trying to scrape prices from online commerce store. I am iterating through the products on page and included it in the regular expression. Despite escaping the curly brackets, the regular expression does not work. (findall returns an empty list)
HTML code returned by soup.findall:
[<div class="ps4-price at-min-price-1"> from 29 GBP </div>]
[<div class="ps4-price at-min-price-2"> from 35 GBP </div>]
Python coode:
for product in range(21):
min_prices_text = str(soup.findAll("div", class_="ps4-price at-
min- price-{}".format(product)))
min_price = re.findall('<div class="ps4-price at-min-price-
{{}}"> (.+?)<'.format(product), str(min_prices_text))
regex python-3.x
New contributor
add a comment |
up vote
-1
down vote
favorite
I am trying to scrape prices from online commerce store. I am iterating through the products on page and included it in the regular expression. Despite escaping the curly brackets, the regular expression does not work. (findall returns an empty list)
HTML code returned by soup.findall:
[<div class="ps4-price at-min-price-1"> from 29 GBP </div>]
[<div class="ps4-price at-min-price-2"> from 35 GBP </div>]
Python coode:
for product in range(21):
min_prices_text = str(soup.findAll("div", class_="ps4-price at-
min- price-{}".format(product)))
min_price = re.findall('<div class="ps4-price at-min-price-
{{}}"> (.+?)<'.format(product), str(min_prices_text))
regex python-3.x
New contributor
Trymin_prices = soup.find_all("div", class_="ps4-price")
and thenarr =
,for el in min_prices:
,arr.append(re.sub(r'D+', '', el.string))
=>print(list(map(int, arr)))
. If you need to make sure there are both classes listed, trymin_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
2 days ago
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
2 days ago
BTW, your formatted string is broken,{{}}
is actually a couple of literal braces. You need to use single ones,{}
, there.
– Wiktor Stribiżew
2 days ago
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I am trying to scrape prices from online commerce store. I am iterating through the products on page and included it in the regular expression. Despite escaping the curly brackets, the regular expression does not work. (findall returns an empty list)
HTML code returned by soup.findall:
[<div class="ps4-price at-min-price-1"> from 29 GBP </div>]
[<div class="ps4-price at-min-price-2"> from 35 GBP </div>]
Python coode:
for product in range(21):
min_prices_text = str(soup.findAll("div", class_="ps4-price at-
min- price-{}".format(product)))
min_price = re.findall('<div class="ps4-price at-min-price-
{{}}"> (.+?)<'.format(product), str(min_prices_text))
regex python-3.x
New contributor
I am trying to scrape prices from online commerce store. I am iterating through the products on page and included it in the regular expression. Despite escaping the curly brackets, the regular expression does not work. (findall returns an empty list)
HTML code returned by soup.findall:
[<div class="ps4-price at-min-price-1"> from 29 GBP </div>]
[<div class="ps4-price at-min-price-2"> from 35 GBP </div>]
Python coode:
for product in range(21):
min_prices_text = str(soup.findAll("div", class_="ps4-price at-
min- price-{}".format(product)))
min_price = re.findall('<div class="ps4-price at-min-price-
{{}}"> (.+?)<'.format(product), str(min_prices_text))
regex python-3.x
regex python-3.x
New contributor
New contributor
New contributor
asked 2 days ago
dzakob
11
11
New contributor
New contributor
Trymin_prices = soup.find_all("div", class_="ps4-price")
and thenarr =
,for el in min_prices:
,arr.append(re.sub(r'D+', '', el.string))
=>print(list(map(int, arr)))
. If you need to make sure there are both classes listed, trymin_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
2 days ago
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
2 days ago
BTW, your formatted string is broken,{{}}
is actually a couple of literal braces. You need to use single ones,{}
, there.
– Wiktor Stribiżew
2 days ago
add a comment |
Trymin_prices = soup.find_all("div", class_="ps4-price")
and thenarr =
,for el in min_prices:
,arr.append(re.sub(r'D+', '', el.string))
=>print(list(map(int, arr)))
. If you need to make sure there are both classes listed, trymin_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
2 days ago
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
2 days ago
BTW, your formatted string is broken,{{}}
is actually a couple of literal braces. You need to use single ones,{}
, there.
– Wiktor Stribiżew
2 days ago
Try
min_prices = soup.find_all("div", class_="ps4-price")
and then arr =
, for el in min_prices:
, arr.append(re.sub(r'D+', '', el.string))
=> print(list(map(int, arr)))
. If you need to make sure there are both classes listed, try min_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
2 days ago
Try
min_prices = soup.find_all("div", class_="ps4-price")
and then arr =
, for el in min_prices:
, arr.append(re.sub(r'D+', '', el.string))
=> print(list(map(int, arr)))
. If you need to make sure there are both classes listed, try min_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
2 days ago
1
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
2 days ago
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
2 days ago
BTW, your formatted string is broken,
{{}}
is actually a couple of literal braces. You need to use single ones, {}
, there.– Wiktor Stribiżew
2 days ago
BTW, your formatted string is broken,
{{}}
is actually a couple of literal braces. You need to use single ones, {}
, there.– Wiktor Stribiżew
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
add a comment |
up vote
0
down vote
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
add a comment |
up vote
0
down vote
up vote
0
down vote
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
You may access the .string
property of the elements you get with findAll
, and only apply the regex to the plain text. E.g., since you expect only single integer numbers there, you may apply re.sub(r'D+', '', min_prices_text.string)
on those strings.
See example code:
results =
for product in range(21):
min_prices_text = soup.find("div", class_="ps4-price at-min-price-{}".format(product))
if min_prices_text:
results.append(re.sub(r'D+', '', min_prices_text.string))
print(results) # => ['29', '35']
Or use list(map(int, results))
if you want to cast the list of strings to integer.
answered 2 days ago
Wiktor Stribiżew
301k16122197
301k16122197
add a comment |
add a comment |
dzakob is a new contributor. Be nice, and check out our Code of Conduct.
dzakob is a new contributor. Be nice, and check out our Code of Conduct.
dzakob is a new contributor. Be nice, and check out our Code of Conduct.
dzakob is a new contributor. Be nice, and check out our Code of Conduct.
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Try
min_prices = soup.find_all("div", class_="ps4-price")
and thenarr =
,for el in min_prices:
,arr.append(re.sub(r'D+', '', el.string))
=>print(list(map(int, arr)))
. If you need to make sure there are both classes listed, trymin_prices = soup.find_all("div", class_=re.compile(r"ps4-price at-min-price-d+"))
– Wiktor Stribiżew
2 days ago
1
Maybe don't use regex to parse HTML content.
– Tim Biegeleisen
2 days ago
BTW, your formatted string is broken,
{{}}
is actually a couple of literal braces. You need to use single ones,{}
, there.– Wiktor Stribiżew
2 days ago