Addition of Logarithmic Equation
According to the basic rules of $log$, I'm solving both $log$ terms as for first: base is $3$, $N$ is $9$ so exponent is calculated as $2$, and same for other term. But I'm confused with this '$x$'. Adding both terms $log$ according to my logic will result in $4$. But I know I'm doing something wrong here, how to treat this $x$? Is B the correct answer?
linear-algebra logarithms arithmetic
add a comment |
According to the basic rules of $log$, I'm solving both $log$ terms as for first: base is $3$, $N$ is $9$ so exponent is calculated as $2$, and same for other term. But I'm confused with this '$x$'. Adding both terms $log$ according to my logic will result in $4$. But I know I'm doing something wrong here, how to treat this $x$? Is B the correct answer?
linear-algebra logarithms arithmetic
add a comment |
According to the basic rules of $log$, I'm solving both $log$ terms as for first: base is $3$, $N$ is $9$ so exponent is calculated as $2$, and same for other term. But I'm confused with this '$x$'. Adding both terms $log$ according to my logic will result in $4$. But I know I'm doing something wrong here, how to treat this $x$? Is B the correct answer?
linear-algebra logarithms arithmetic
According to the basic rules of $log$, I'm solving both $log$ terms as for first: base is $3$, $N$ is $9$ so exponent is calculated as $2$, and same for other term. But I'm confused with this '$x$'. Adding both terms $log$ according to my logic will result in $4$. But I know I'm doing something wrong here, how to treat this $x$? Is B the correct answer?
linear-algebra logarithms arithmetic
linear-algebra logarithms arithmetic
edited Nov 30 at 15:46
Thomas Shelby
1,393216
1,393216
asked Nov 30 at 14:29
shawn k
396
396
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
HINT
Recall that
$$log_3 (9cdot x)=log_3 9+log_3 x$$
then what about $log_2 (4cdot x)$?
1
@MichaelBurr Looking at the given choices I think that this hint can be useful.
– gimusi
Nov 30 at 14:36
2
Got it!!! The answer is B. Thank you so much!!
– shawn k
Nov 30 at 14:36
@shawnk Exactly! Well done! Bye
– gimusi
Nov 30 at 14:37
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3020153%2faddition-of-logarithmic-equation%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
HINT
Recall that
$$log_3 (9cdot x)=log_3 9+log_3 x$$
then what about $log_2 (4cdot x)$?
1
@MichaelBurr Looking at the given choices I think that this hint can be useful.
– gimusi
Nov 30 at 14:36
2
Got it!!! The answer is B. Thank you so much!!
– shawn k
Nov 30 at 14:36
@shawnk Exactly! Well done! Bye
– gimusi
Nov 30 at 14:37
add a comment |
HINT
Recall that
$$log_3 (9cdot x)=log_3 9+log_3 x$$
then what about $log_2 (4cdot x)$?
1
@MichaelBurr Looking at the given choices I think that this hint can be useful.
– gimusi
Nov 30 at 14:36
2
Got it!!! The answer is B. Thank you so much!!
– shawn k
Nov 30 at 14:36
@shawnk Exactly! Well done! Bye
– gimusi
Nov 30 at 14:37
add a comment |
HINT
Recall that
$$log_3 (9cdot x)=log_3 9+log_3 x$$
then what about $log_2 (4cdot x)$?
HINT
Recall that
$$log_3 (9cdot x)=log_3 9+log_3 x$$
then what about $log_2 (4cdot x)$?
edited Nov 30 at 14:35
answered Nov 30 at 14:32
gimusi
1
1
1
@MichaelBurr Looking at the given choices I think that this hint can be useful.
– gimusi
Nov 30 at 14:36
2
Got it!!! The answer is B. Thank you so much!!
– shawn k
Nov 30 at 14:36
@shawnk Exactly! Well done! Bye
– gimusi
Nov 30 at 14:37
add a comment |
1
@MichaelBurr Looking at the given choices I think that this hint can be useful.
– gimusi
Nov 30 at 14:36
2
Got it!!! The answer is B. Thank you so much!!
– shawn k
Nov 30 at 14:36
@shawnk Exactly! Well done! Bye
– gimusi
Nov 30 at 14:37
1
1
@MichaelBurr Looking at the given choices I think that this hint can be useful.
– gimusi
Nov 30 at 14:36
@MichaelBurr Looking at the given choices I think that this hint can be useful.
– gimusi
Nov 30 at 14:36
2
2
Got it!!! The answer is B. Thank you so much!!
– shawn k
Nov 30 at 14:36
Got it!!! The answer is B. Thank you so much!!
– shawn k
Nov 30 at 14:36
@shawnk Exactly! Well done! Bye
– gimusi
Nov 30 at 14:37
@shawnk Exactly! Well done! Bye
– gimusi
Nov 30 at 14:37
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3020153%2faddition-of-logarithmic-equation%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown