From DAHA to trigonometric DAHA in the $(C_1^V,C_1)$ case
It is known that a generic DAHA associated with a root system can degenerate to the trigonometric/rational DAHAs. Unfortunately, I do not understand most of the literature.
The DAHA of type $(C_1^V,C_1)$ is defined in terms of generators $(t_0,t_1,t_2,t_3)$ which satisfy
$t_i+t_i^{-1}=p_i, hspace{0.5cm} t_0 t_1 t_2 t_3=q^{-1}$.
What is the corresponding trigonometric DAHA?
abstract-algebra
asked Nov 30 at 14:27
Gropillon
286
add a comment |
It is known that a generic DAHA associated with a root system can degenerate to the trigonometric/rational DAHAs. Unfortunately, I do not understand most of the literature.
The DAHA of type $(C_1^V,C_1)$ is defined in terms of generators $(t_0,t_1,t_2,t_3)$ which satisfy
$t_i+t_i^{-1}=p_i, hspace{0.5cm} t_0 t_1 t_2 t_3=q^{-1}$.
What is the corresponding trigonometric DAHA?
abstract-algebra
asked Nov 30 at 14:27
Gropillon
286
add a comment |
It is known that a generic DAHA associated with a root system can degenerate to the trigonometric/rational DAHAs. Unfortunately, I do not understand most of the literature.
The DAHA of type $(C_1^V,C_1)$ is defined in terms of generators $(t_0,t_1,t_2,t_3)$ which satisfy
$t_i+t_i^{-1}=p_i, hspace{0.5cm} t_0 t_1 t_2 t_3=q^{-1}$.
What is the corresponding trigonometric DAHA?
abstract-algebra
asked Nov 30 at 14:27
Gropillon
286
It is known that a generic DAHA associated with a root system can degenerate to the trigonometric/rational DAHAs. Unfortunately, I do not understand most of the literature.
The DAHA of type $(C_1^V,C_1)$ is defined in terms of generators $(t_0,t_1,t_2,t_3)$ which satisfy
$t_i+t_i^{-1}=p_i, hspace{0.5cm} t_0 t_1 t_2 t_3=q^{-1}$.
What is the corresponding trigonometric DAHA?
abstract-algebra
abstract-algebra
asked Nov 30 at 14:27
Gropillon
286
asked Nov 30 at 14:27
Gropillon
286
asked Nov 30 at 14:27
Gropillon
286
asked Nov 30 at 14:27
Gropillon
286
asked Nov 30 at 14:27
Gropillon
286
286
add a comment |
add a comment |
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