Mixed boundary condition for the heat equation
$begingroup$
Would someone help me understand the way the solution obtained in this question:
Heat Equation Mixed Boundaries Case: Fourier Coefficients
I did not understand why in the final solution, he took $b_m$ and not $b_{2m-1}$. I am confused not just because of the rank of the coefficients, this is because according to this rank $$b_m= frac{1}{L} int_{0}^{2L} f(x) sinBig(frac{m pi x}{2L}Big)$$ or
$$b_{2m-1}= frac{1}{L} int_{0}^{2L} f(x) sinBig(frac{(2m-1) pi x}{2L}Big)$$
Sorry if I appear much confused, but I really want to understand it.
Thanks in adavnce.
pde boundary-value-problem heat-equation linear-pde
$endgroup$
add a comment |
$begingroup$
Would someone help me understand the way the solution obtained in this question:
Heat Equation Mixed Boundaries Case: Fourier Coefficients
I did not understand why in the final solution, he took $b_m$ and not $b_{2m-1}$. I am confused not just because of the rank of the coefficients, this is because according to this rank $$b_m= frac{1}{L} int_{0}^{2L} f(x) sinBig(frac{m pi x}{2L}Big)$$ or
$$b_{2m-1}= frac{1}{L} int_{0}^{2L} f(x) sinBig(frac{(2m-1) pi x}{2L}Big)$$
Sorry if I appear much confused, but I really want to understand it.
Thanks in adavnce.
pde boundary-value-problem heat-equation linear-pde
$endgroup$
1
$begingroup$
Use$sin$
for $sin$ (instead of$sin$
for $sin$).
$endgroup$
– Shaun
Dec 8 '18 at 13:22
$begingroup$
Both formulas are equivalent. The first one restricts the subscript $m$ to odd integers; the second one doesn't.
$endgroup$
– Dylan
Dec 13 '18 at 4:28
add a comment |
$begingroup$
Would someone help me understand the way the solution obtained in this question:
Heat Equation Mixed Boundaries Case: Fourier Coefficients
I did not understand why in the final solution, he took $b_m$ and not $b_{2m-1}$. I am confused not just because of the rank of the coefficients, this is because according to this rank $$b_m= frac{1}{L} int_{0}^{2L} f(x) sinBig(frac{m pi x}{2L}Big)$$ or
$$b_{2m-1}= frac{1}{L} int_{0}^{2L} f(x) sinBig(frac{(2m-1) pi x}{2L}Big)$$
Sorry if I appear much confused, but I really want to understand it.
Thanks in adavnce.
pde boundary-value-problem heat-equation linear-pde
$endgroup$
Would someone help me understand the way the solution obtained in this question:
Heat Equation Mixed Boundaries Case: Fourier Coefficients
I did not understand why in the final solution, he took $b_m$ and not $b_{2m-1}$. I am confused not just because of the rank of the coefficients, this is because according to this rank $$b_m= frac{1}{L} int_{0}^{2L} f(x) sinBig(frac{m pi x}{2L}Big)$$ or
$$b_{2m-1}= frac{1}{L} int_{0}^{2L} f(x) sinBig(frac{(2m-1) pi x}{2L}Big)$$
Sorry if I appear much confused, but I really want to understand it.
Thanks in adavnce.
pde boundary-value-problem heat-equation linear-pde
pde boundary-value-problem heat-equation linear-pde
edited Dec 8 '18 at 14:11
Nizar
asked Dec 8 '18 at 13:10
NizarNizar
2,39921023
2,39921023
1
$begingroup$
Use$sin$
for $sin$ (instead of$sin$
for $sin$).
$endgroup$
– Shaun
Dec 8 '18 at 13:22
$begingroup$
Both formulas are equivalent. The first one restricts the subscript $m$ to odd integers; the second one doesn't.
$endgroup$
– Dylan
Dec 13 '18 at 4:28
add a comment |
1
$begingroup$
Use$sin$
for $sin$ (instead of$sin$
for $sin$).
$endgroup$
– Shaun
Dec 8 '18 at 13:22
$begingroup$
Both formulas are equivalent. The first one restricts the subscript $m$ to odd integers; the second one doesn't.
$endgroup$
– Dylan
Dec 13 '18 at 4:28
1
1
$begingroup$
Use
$sin$
for $sin$ (instead of $sin$
for $sin$).$endgroup$
– Shaun
Dec 8 '18 at 13:22
$begingroup$
Use
$sin$
for $sin$ (instead of $sin$
for $sin$).$endgroup$
– Shaun
Dec 8 '18 at 13:22
$begingroup$
Both formulas are equivalent. The first one restricts the subscript $m$ to odd integers; the second one doesn't.
$endgroup$
– Dylan
Dec 13 '18 at 4:28
$begingroup$
Both formulas are equivalent. The first one restricts the subscript $m$ to odd integers; the second one doesn't.
$endgroup$
– Dylan
Dec 13 '18 at 4:28
add a comment |
0
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1
$begingroup$
Use
$sin$
for $sin$ (instead of$sin$
for $sin$).$endgroup$
– Shaun
Dec 8 '18 at 13:22
$begingroup$
Both formulas are equivalent. The first one restricts the subscript $m$ to odd integers; the second one doesn't.
$endgroup$
– Dylan
Dec 13 '18 at 4:28