Relationship between two centers of circles in a Venn diagram
$begingroup$
Let $S$ be a circle of 1 unit area. No part of circles $A$ and $B$ are outside the circle $S$.
Let $n(S)=1$, $n(A)$, and $n(B)$ be the area of circle $S$, $A$, and $B$, respectively.
For the given values $n(A)=a$, $n(B)=b$, and $n(A cap B)=c$, find the relationship of their centers in terms of $a$, $b$, and $c$.
The objective is to draw both inner circles.
geometry circle
$endgroup$
|
show 1 more comment
$begingroup$
Let $S$ be a circle of 1 unit area. No part of circles $A$ and $B$ are outside the circle $S$.
Let $n(S)=1$, $n(A)$, and $n(B)$ be the area of circle $S$, $A$, and $B$, respectively.
For the given values $n(A)=a$, $n(B)=b$, and $n(A cap B)=c$, find the relationship of their centers in terms of $a$, $b$, and $c$.
The objective is to draw both inner circles.
geometry circle
$endgroup$
2
$begingroup$
When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
$endgroup$
– Karolis Juodelė
Jul 12 '12 at 8:26
$begingroup$
You've tried making a drawing?
$endgroup$
– J. M. is not a mathematician
Jul 12 '12 at 8:26
$begingroup$
@J.M.: I haven't drawn it yet because there might be many solutions.
$endgroup$
– kiss my armpit
Jul 12 '12 at 8:36
$begingroup$
If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
$endgroup$
– Rahul
Jan 22 '13 at 20:03
$begingroup$
there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
$endgroup$
– Did
Jan 26 '13 at 14:08
|
show 1 more comment
$begingroup$
Let $S$ be a circle of 1 unit area. No part of circles $A$ and $B$ are outside the circle $S$.
Let $n(S)=1$, $n(A)$, and $n(B)$ be the area of circle $S$, $A$, and $B$, respectively.
For the given values $n(A)=a$, $n(B)=b$, and $n(A cap B)=c$, find the relationship of their centers in terms of $a$, $b$, and $c$.
The objective is to draw both inner circles.
geometry circle
$endgroup$
Let $S$ be a circle of 1 unit area. No part of circles $A$ and $B$ are outside the circle $S$.
Let $n(S)=1$, $n(A)$, and $n(B)$ be the area of circle $S$, $A$, and $B$, respectively.
For the given values $n(A)=a$, $n(B)=b$, and $n(A cap B)=c$, find the relationship of their centers in terms of $a$, $b$, and $c$.
The objective is to draw both inner circles.
geometry circle
geometry circle
edited Jul 12 '12 at 8:29
kiss my armpit
asked Jul 12 '12 at 8:16
kiss my armpitkiss my armpit
2,16541834
2,16541834
2
$begingroup$
When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
$endgroup$
– Karolis Juodelė
Jul 12 '12 at 8:26
$begingroup$
You've tried making a drawing?
$endgroup$
– J. M. is not a mathematician
Jul 12 '12 at 8:26
$begingroup$
@J.M.: I haven't drawn it yet because there might be many solutions.
$endgroup$
– kiss my armpit
Jul 12 '12 at 8:36
$begingroup$
If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
$endgroup$
– Rahul
Jan 22 '13 at 20:03
$begingroup$
there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
$endgroup$
– Did
Jan 26 '13 at 14:08
|
show 1 more comment
2
$begingroup$
When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
$endgroup$
– Karolis Juodelė
Jul 12 '12 at 8:26
$begingroup$
You've tried making a drawing?
$endgroup$
– J. M. is not a mathematician
Jul 12 '12 at 8:26
$begingroup$
@J.M.: I haven't drawn it yet because there might be many solutions.
$endgroup$
– kiss my armpit
Jul 12 '12 at 8:36
$begingroup$
If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
$endgroup$
– Rahul
Jan 22 '13 at 20:03
$begingroup$
there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
$endgroup$
– Did
Jan 26 '13 at 14:08
2
2
$begingroup$
When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
$endgroup$
– Karolis Juodelė
Jul 12 '12 at 8:26
$begingroup$
When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
$endgroup$
– Karolis Juodelė
Jul 12 '12 at 8:26
$begingroup$
You've tried making a drawing?
$endgroup$
– J. M. is not a mathematician
Jul 12 '12 at 8:26
$begingroup$
You've tried making a drawing?
$endgroup$
– J. M. is not a mathematician
Jul 12 '12 at 8:26
$begingroup$
@J.M.: I haven't drawn it yet because there might be many solutions.
$endgroup$
– kiss my armpit
Jul 12 '12 at 8:36
$begingroup$
@J.M.: I haven't drawn it yet because there might be many solutions.
$endgroup$
– kiss my armpit
Jul 12 '12 at 8:36
$begingroup$
If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
$endgroup$
– Rahul
Jan 22 '13 at 20:03
$begingroup$
If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
$endgroup$
– Rahul
Jan 22 '13 at 20:03
$begingroup$
there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
$endgroup$
– Did
Jan 26 '13 at 14:08
$begingroup$
there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
$endgroup$
– Did
Jan 26 '13 at 14:08
|
show 1 more comment
1 Answer
1
active
oldest
votes
$begingroup$
I haven't gone into calculations but tried to device an algorithm for the prob
- Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$
- From the area of the $2$ inner circle find their respective radi
- Now assign variable center to the second inner circle $B$ let us call it point $X$
- From the radius and center find the equation of each of the inner circles respectively
- From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)
- Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$
- Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$
- With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$
- now the center of the circle $B$ will depend on the equation
$S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$
Now for the relation with outer circle:
- distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.
- $l = R_a+R_b+m$
- $b = max{R_a,R_b}$
- Now calculate the area $l cdot b$
- put the condition that area less than area of outer circle S.
this algorithm for relation wiht outer circle can be improved!
$endgroup$
add a comment |
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$begingroup$
I haven't gone into calculations but tried to device an algorithm for the prob
- Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$
- From the area of the $2$ inner circle find their respective radi
- Now assign variable center to the second inner circle $B$ let us call it point $X$
- From the radius and center find the equation of each of the inner circles respectively
- From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)
- Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$
- Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$
- With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$
- now the center of the circle $B$ will depend on the equation
$S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$
Now for the relation with outer circle:
- distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.
- $l = R_a+R_b+m$
- $b = max{R_a,R_b}$
- Now calculate the area $l cdot b$
- put the condition that area less than area of outer circle S.
this algorithm for relation wiht outer circle can be improved!
$endgroup$
add a comment |
$begingroup$
I haven't gone into calculations but tried to device an algorithm for the prob
- Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$
- From the area of the $2$ inner circle find their respective radi
- Now assign variable center to the second inner circle $B$ let us call it point $X$
- From the radius and center find the equation of each of the inner circles respectively
- From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)
- Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$
- Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$
- With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$
- now the center of the circle $B$ will depend on the equation
$S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$
Now for the relation with outer circle:
- distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.
- $l = R_a+R_b+m$
- $b = max{R_a,R_b}$
- Now calculate the area $l cdot b$
- put the condition that area less than area of outer circle S.
this algorithm for relation wiht outer circle can be improved!
$endgroup$
add a comment |
$begingroup$
I haven't gone into calculations but tried to device an algorithm for the prob
- Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$
- From the area of the $2$ inner circle find their respective radi
- Now assign variable center to the second inner circle $B$ let us call it point $X$
- From the radius and center find the equation of each of the inner circles respectively
- From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)
- Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$
- Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$
- With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$
- now the center of the circle $B$ will depend on the equation
$S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$
Now for the relation with outer circle:
- distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.
- $l = R_a+R_b+m$
- $b = max{R_a,R_b}$
- Now calculate the area $l cdot b$
- put the condition that area less than area of outer circle S.
this algorithm for relation wiht outer circle can be improved!
$endgroup$
I haven't gone into calculations but tried to device an algorithm for the prob
- Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$
- From the area of the $2$ inner circle find their respective radi
- Now assign variable center to the second inner circle $B$ let us call it point $X$
- From the radius and center find the equation of each of the inner circles respectively
- From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)
- Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$
- Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$
- With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$
- now the center of the circle $B$ will depend on the equation
$S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$
Now for the relation with outer circle:
- distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.
- $l = R_a+R_b+m$
- $b = max{R_a,R_b}$
- Now calculate the area $l cdot b$
- put the condition that area less than area of outer circle S.
this algorithm for relation wiht outer circle can be improved!
edited Jul 16 '12 at 15:04
Norbert
45.7k774161
45.7k774161
answered Jul 12 '12 at 9:55
nimeshkiranvermanimeshkiranverma
248412
248412
add a comment |
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2
$begingroup$
When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
$endgroup$
– Karolis Juodelė
Jul 12 '12 at 8:26
$begingroup$
You've tried making a drawing?
$endgroup$
– J. M. is not a mathematician
Jul 12 '12 at 8:26
$begingroup$
@J.M.: I haven't drawn it yet because there might be many solutions.
$endgroup$
– kiss my armpit
Jul 12 '12 at 8:36
$begingroup$
If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
$endgroup$
– Rahul
Jan 22 '13 at 20:03
$begingroup$
there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
$endgroup$
– Did
Jan 26 '13 at 14:08