Relationship between two centers of circles in a Venn diagram












9












$begingroup$


Let $S$ be a circle of 1 unit area. No part of circles $A$ and $B$ are outside the circle $S$.



Let $n(S)=1$, $n(A)$, and $n(B)$ be the area of circle $S$, $A$, and $B$, respectively.



For the given values $n(A)=a$, $n(B)=b$, and $n(A cap B)=c$, find the relationship of their centers in terms of $a$, $b$, and $c$.



The objective is to draw both inner circles.










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
    $endgroup$
    – Karolis Juodelė
    Jul 12 '12 at 8:26










  • $begingroup$
    You've tried making a drawing?
    $endgroup$
    – J. M. is not a mathematician
    Jul 12 '12 at 8:26










  • $begingroup$
    @J.M.: I haven't drawn it yet because there might be many solutions.
    $endgroup$
    – kiss my armpit
    Jul 12 '12 at 8:36










  • $begingroup$
    If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
    $endgroup$
    – Rahul
    Jan 22 '13 at 20:03










  • $begingroup$
    there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
    $endgroup$
    – Did
    Jan 26 '13 at 14:08
















9












$begingroup$


Let $S$ be a circle of 1 unit area. No part of circles $A$ and $B$ are outside the circle $S$.



Let $n(S)=1$, $n(A)$, and $n(B)$ be the area of circle $S$, $A$, and $B$, respectively.



For the given values $n(A)=a$, $n(B)=b$, and $n(A cap B)=c$, find the relationship of their centers in terms of $a$, $b$, and $c$.



The objective is to draw both inner circles.










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
    $endgroup$
    – Karolis Juodelė
    Jul 12 '12 at 8:26










  • $begingroup$
    You've tried making a drawing?
    $endgroup$
    – J. M. is not a mathematician
    Jul 12 '12 at 8:26










  • $begingroup$
    @J.M.: I haven't drawn it yet because there might be many solutions.
    $endgroup$
    – kiss my armpit
    Jul 12 '12 at 8:36










  • $begingroup$
    If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
    $endgroup$
    – Rahul
    Jan 22 '13 at 20:03










  • $begingroup$
    there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
    $endgroup$
    – Did
    Jan 26 '13 at 14:08














9












9








9


1



$begingroup$


Let $S$ be a circle of 1 unit area. No part of circles $A$ and $B$ are outside the circle $S$.



Let $n(S)=1$, $n(A)$, and $n(B)$ be the area of circle $S$, $A$, and $B$, respectively.



For the given values $n(A)=a$, $n(B)=b$, and $n(A cap B)=c$, find the relationship of their centers in terms of $a$, $b$, and $c$.



The objective is to draw both inner circles.










share|cite|improve this question











$endgroup$




Let $S$ be a circle of 1 unit area. No part of circles $A$ and $B$ are outside the circle $S$.



Let $n(S)=1$, $n(A)$, and $n(B)$ be the area of circle $S$, $A$, and $B$, respectively.



For the given values $n(A)=a$, $n(B)=b$, and $n(A cap B)=c$, find the relationship of their centers in terms of $a$, $b$, and $c$.



The objective is to draw both inner circles.







geometry circle






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jul 12 '12 at 8:29







kiss my armpit

















asked Jul 12 '12 at 8:16









kiss my armpitkiss my armpit

2,16541834




2,16541834








  • 2




    $begingroup$
    When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
    $endgroup$
    – Karolis Juodelė
    Jul 12 '12 at 8:26










  • $begingroup$
    You've tried making a drawing?
    $endgroup$
    – J. M. is not a mathematician
    Jul 12 '12 at 8:26










  • $begingroup$
    @J.M.: I haven't drawn it yet because there might be many solutions.
    $endgroup$
    – kiss my armpit
    Jul 12 '12 at 8:36










  • $begingroup$
    If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
    $endgroup$
    – Rahul
    Jan 22 '13 at 20:03










  • $begingroup$
    there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
    $endgroup$
    – Did
    Jan 26 '13 at 14:08














  • 2




    $begingroup$
    When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
    $endgroup$
    – Karolis Juodelė
    Jul 12 '12 at 8:26










  • $begingroup$
    You've tried making a drawing?
    $endgroup$
    – J. M. is not a mathematician
    Jul 12 '12 at 8:26










  • $begingroup$
    @J.M.: I haven't drawn it yet because there might be many solutions.
    $endgroup$
    – kiss my armpit
    Jul 12 '12 at 8:36










  • $begingroup$
    If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
    $endgroup$
    – Rahul
    Jan 22 '13 at 20:03










  • $begingroup$
    there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
    $endgroup$
    – Did
    Jan 26 '13 at 14:08








2




2




$begingroup$
When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
$endgroup$
– Karolis Juodelė
Jul 12 '12 at 8:26




$begingroup$
When you say 'relationship', do you mean distance? Also, apart from giving bounds for $a$, $b$ and $c$, $S$ doesn't really do anything, does it?
$endgroup$
– Karolis Juodelė
Jul 12 '12 at 8:26












$begingroup$
You've tried making a drawing?
$endgroup$
– J. M. is not a mathematician
Jul 12 '12 at 8:26




$begingroup$
You've tried making a drawing?
$endgroup$
– J. M. is not a mathematician
Jul 12 '12 at 8:26












$begingroup$
@J.M.: I haven't drawn it yet because there might be many solutions.
$endgroup$
– kiss my armpit
Jul 12 '12 at 8:36




$begingroup$
@J.M.: I haven't drawn it yet because there might be many solutions.
$endgroup$
– kiss my armpit
Jul 12 '12 at 8:36












$begingroup$
If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
$endgroup$
– Rahul
Jan 22 '13 at 20:03




$begingroup$
If you're trying to draw an area-proportional Venn diagram, you could have $a=b=frac12$ but $c=0$, in which case there is no solution.
$endgroup$
– Rahul
Jan 22 '13 at 20:03












$begingroup$
there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
$endgroup$
– Did
Jan 26 '13 at 14:08




$begingroup$
there might be many solutions... Are you sure? For any given values of $a$ and $b$, any $0lt cltmin(a,b)$ uniquely determines the distance between their centers.
$endgroup$
– Did
Jan 26 '13 at 14:08










1 Answer
1






active

oldest

votes


















0












$begingroup$

I haven't gone into calculations but tried to device an algorithm for the prob




  1. Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$

  2. From the area of the $2$ inner circle find their respective radi

  3. Now assign variable center to the second inner circle $B$ let us call it point $X$

  4. From the radius and center find the equation of each of the inner circles respectively

  5. From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)

  6. Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$

  7. Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$

  8. With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$

  9. now the center of the circle $B$ will depend on the equation
    $S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$


Now for the relation with outer circle:




  1. distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.

  2. $l = R_a+R_b+m$

  3. $b = max{R_a,R_b}$

  4. Now calculate the area $l cdot b$

  5. put the condition that area less than area of outer circle S.


this algorithm for relation wiht outer circle can be improved!






share|cite|improve this answer











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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    I haven't gone into calculations but tried to device an algorithm for the prob




    1. Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$

    2. From the area of the $2$ inner circle find their respective radi

    3. Now assign variable center to the second inner circle $B$ let us call it point $X$

    4. From the radius and center find the equation of each of the inner circles respectively

    5. From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)

    6. Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$

    7. Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$

    8. With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$

    9. now the center of the circle $B$ will depend on the equation
      $S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$


    Now for the relation with outer circle:




    1. distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.

    2. $l = R_a+R_b+m$

    3. $b = max{R_a,R_b}$

    4. Now calculate the area $l cdot b$

    5. put the condition that area less than area of outer circle S.


    this algorithm for relation wiht outer circle can be improved!






    share|cite|improve this answer











    $endgroup$


















      0












      $begingroup$

      I haven't gone into calculations but tried to device an algorithm for the prob




      1. Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$

      2. From the area of the $2$ inner circle find their respective radi

      3. Now assign variable center to the second inner circle $B$ let us call it point $X$

      4. From the radius and center find the equation of each of the inner circles respectively

      5. From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)

      6. Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$

      7. Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$

      8. With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$

      9. now the center of the circle $B$ will depend on the equation
        $S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$


      Now for the relation with outer circle:




      1. distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.

      2. $l = R_a+R_b+m$

      3. $b = max{R_a,R_b}$

      4. Now calculate the area $l cdot b$

      5. put the condition that area less than area of outer circle S.


      this algorithm for relation wiht outer circle can be improved!






      share|cite|improve this answer











      $endgroup$
















        0












        0








        0





        $begingroup$

        I haven't gone into calculations but tried to device an algorithm for the prob




        1. Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$

        2. From the area of the $2$ inner circle find their respective radi

        3. Now assign variable center to the second inner circle $B$ let us call it point $X$

        4. From the radius and center find the equation of each of the inner circles respectively

        5. From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)

        6. Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$

        7. Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$

        8. With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$

        9. now the center of the circle $B$ will depend on the equation
          $S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$


        Now for the relation with outer circle:




        1. distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.

        2. $l = R_a+R_b+m$

        3. $b = max{R_a,R_b}$

        4. Now calculate the area $l cdot b$

        5. put the condition that area less than area of outer circle S.


        this algorithm for relation wiht outer circle can be improved!






        share|cite|improve this answer











        $endgroup$



        I haven't gone into calculations but tried to device an algorithm for the prob




        1. Fix an origin at one of the inner circle's center say of $A$ and let us call it point $O$

        2. From the area of the $2$ inner circle find their respective radi

        3. Now assign variable center to the second inner circle $B$ let us call it point $X$

        4. From the radius and center find the equation of each of the inner circles respectively

        5. From the equation of the $2$ inner circles find the equation of 'chord of contact'(also apply the intersection constraint for the same)

        6. Find the points of intersection of the the chord of the contact and any of the $2$ circles and call it points $Y$ and $Z$

        7. Now find the angle $YOZ$ and $YXZ$ and called it $alpha$ and $beta$

        8. With the help of the angles above find area of sector $YOZ$ and $YXZ$ and call it $S_a$ and $S_b$

        9. now the center of the circle $B$ will depend on the equation
          $S_a + S_b - c = S_{triangle{YOZ}} + S_{triangle{YXZ}}$


        Now for the relation with outer circle:




        1. distance between the two centers of the inner circles and call it as $m$. Let their radii are $R_a$, $R_b$.

        2. $l = R_a+R_b+m$

        3. $b = max{R_a,R_b}$

        4. Now calculate the area $l cdot b$

        5. put the condition that area less than area of outer circle S.


        this algorithm for relation wiht outer circle can be improved!







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Jul 16 '12 at 15:04









        Norbert

        45.7k774161




        45.7k774161










        answered Jul 12 '12 at 9:55









        nimeshkiranvermanimeshkiranverma

        248412




        248412






























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