Question on proving that the rationals are countably infinite












0












$begingroup$


I just a question on a proof for the rationals being countably infinite from a textbook. We consider the following function, a mapping from $Bbb Q$ to $Bbb N$



$$f(x) = begin{cases}
0, & text{if $x$ = 0} \
2^m 3^n, & text{if $x$ > 0} \
2^m 3^n cdot 5 &text{if $x$ < 0}
end{cases} where x = frac mn and gcd(m,n) = 1 $$



One can see that it is injective by the uniqueness of prime factorization but how is it surjective?










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$endgroup$












  • $begingroup$
    surjective onto what?
    $endgroup$
    – mathworker21
    Dec 25 '18 at 11:44










  • $begingroup$
    Onto the natural numbers. Added it now to the question
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:47






  • 1




    $begingroup$
    wait what? how could it possibly be surjective. how would you get 7
    $endgroup$
    – mathworker21
    Dec 25 '18 at 11:48










  • $begingroup$
    @mathworker21 What I was wondering. If we are trying to show that it is countably infinite then we wish to establish a bijection from Q to N and that what was given in the book
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:50












  • $begingroup$
    Or it is only necessary for there to be an injection between Q and N?
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:50


















0












$begingroup$


I just a question on a proof for the rationals being countably infinite from a textbook. We consider the following function, a mapping from $Bbb Q$ to $Bbb N$



$$f(x) = begin{cases}
0, & text{if $x$ = 0} \
2^m 3^n, & text{if $x$ > 0} \
2^m 3^n cdot 5 &text{if $x$ < 0}
end{cases} where x = frac mn and gcd(m,n) = 1 $$



One can see that it is injective by the uniqueness of prime factorization but how is it surjective?










share|cite|improve this question











$endgroup$












  • $begingroup$
    surjective onto what?
    $endgroup$
    – mathworker21
    Dec 25 '18 at 11:44










  • $begingroup$
    Onto the natural numbers. Added it now to the question
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:47






  • 1




    $begingroup$
    wait what? how could it possibly be surjective. how would you get 7
    $endgroup$
    – mathworker21
    Dec 25 '18 at 11:48










  • $begingroup$
    @mathworker21 What I was wondering. If we are trying to show that it is countably infinite then we wish to establish a bijection from Q to N and that what was given in the book
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:50












  • $begingroup$
    Or it is only necessary for there to be an injection between Q and N?
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:50
















0












0








0





$begingroup$


I just a question on a proof for the rationals being countably infinite from a textbook. We consider the following function, a mapping from $Bbb Q$ to $Bbb N$



$$f(x) = begin{cases}
0, & text{if $x$ = 0} \
2^m 3^n, & text{if $x$ > 0} \
2^m 3^n cdot 5 &text{if $x$ < 0}
end{cases} where x = frac mn and gcd(m,n) = 1 $$



One can see that it is injective by the uniqueness of prime factorization but how is it surjective?










share|cite|improve this question











$endgroup$




I just a question on a proof for the rationals being countably infinite from a textbook. We consider the following function, a mapping from $Bbb Q$ to $Bbb N$



$$f(x) = begin{cases}
0, & text{if $x$ = 0} \
2^m 3^n, & text{if $x$ > 0} \
2^m 3^n cdot 5 &text{if $x$ < 0}
end{cases} where x = frac mn and gcd(m,n) = 1 $$



One can see that it is injective by the uniqueness of prime factorization but how is it surjective?







functions rational-numbers






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 25 '18 at 11:45







forward_behind1

















asked Dec 25 '18 at 11:44









forward_behind1forward_behind1

32




32












  • $begingroup$
    surjective onto what?
    $endgroup$
    – mathworker21
    Dec 25 '18 at 11:44










  • $begingroup$
    Onto the natural numbers. Added it now to the question
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:47






  • 1




    $begingroup$
    wait what? how could it possibly be surjective. how would you get 7
    $endgroup$
    – mathworker21
    Dec 25 '18 at 11:48










  • $begingroup$
    @mathworker21 What I was wondering. If we are trying to show that it is countably infinite then we wish to establish a bijection from Q to N and that what was given in the book
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:50












  • $begingroup$
    Or it is only necessary for there to be an injection between Q and N?
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:50




















  • $begingroup$
    surjective onto what?
    $endgroup$
    – mathworker21
    Dec 25 '18 at 11:44










  • $begingroup$
    Onto the natural numbers. Added it now to the question
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:47






  • 1




    $begingroup$
    wait what? how could it possibly be surjective. how would you get 7
    $endgroup$
    – mathworker21
    Dec 25 '18 at 11:48










  • $begingroup$
    @mathworker21 What I was wondering. If we are trying to show that it is countably infinite then we wish to establish a bijection from Q to N and that what was given in the book
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:50












  • $begingroup$
    Or it is only necessary for there to be an injection between Q and N?
    $endgroup$
    – forward_behind1
    Dec 25 '18 at 11:50


















$begingroup$
surjective onto what?
$endgroup$
– mathworker21
Dec 25 '18 at 11:44




$begingroup$
surjective onto what?
$endgroup$
– mathworker21
Dec 25 '18 at 11:44












$begingroup$
Onto the natural numbers. Added it now to the question
$endgroup$
– forward_behind1
Dec 25 '18 at 11:47




$begingroup$
Onto the natural numbers. Added it now to the question
$endgroup$
– forward_behind1
Dec 25 '18 at 11:47




1




1




$begingroup$
wait what? how could it possibly be surjective. how would you get 7
$endgroup$
– mathworker21
Dec 25 '18 at 11:48




$begingroup$
wait what? how could it possibly be surjective. how would you get 7
$endgroup$
– mathworker21
Dec 25 '18 at 11:48












$begingroup$
@mathworker21 What I was wondering. If we are trying to show that it is countably infinite then we wish to establish a bijection from Q to N and that what was given in the book
$endgroup$
– forward_behind1
Dec 25 '18 at 11:50






$begingroup$
@mathworker21 What I was wondering. If we are trying to show that it is countably infinite then we wish to establish a bijection from Q to N and that what was given in the book
$endgroup$
– forward_behind1
Dec 25 '18 at 11:50














$begingroup$
Or it is only necessary for there to be an injection between Q and N?
$endgroup$
– forward_behind1
Dec 25 '18 at 11:50






$begingroup$
Or it is only necessary for there to be an injection between Q and N?
$endgroup$
– forward_behind1
Dec 25 '18 at 11:50












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