How to use an expression in select count(…)? (Doctrine)





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I have User and UserGroup entities. Each user has a group (UserGroup), and each user has a boss (User).



I would like to get a list of groups, and decide if the current user is the boss of someone in the group. I already implemented this in SQL, and now I tried to solve it using Doctrine. This is what I tried:



$qb = em()->createQueryBuilder()
->select(array('gr.id AS group_id', 'gr.name AS group_name', 'COUNT(us.boss = :current_user_id)>0 AS is_boss'))
->from('AppEntityUserGroup', 'ug')
->leftJoin('AppEntityUser', 'us', 'WITH', 'us.group = ug.id')

->setParameter('current_user_id', $_SESSION['uid'])

->groupby('gr.id')
;

$groups = $qb->getQuery()->getScalarResult();


Unfortunately I get an uncaught QueryException, and I have no idea how to fix that. How is it possible to put an expression inside the COUNT(...) function?










share|improve this question

























  • What is the error message? And you should groupBy with all columns, not only id.

    – Felippe Duarte
    Nov 26 '18 at 19:37













  • It works without the COUNT(...) part. The error message just contains the DQL query: SELECT gr.id AS group_id, gr.name AS group_name, COUNT(us.boss = :current_user_id)>0 AS is_boss FROM AppEntityUserGroup ug LEFT JOIN AppEntityUser us WITH us.group = ug.id GROUP BY gr.id

    – Iter Ator
    Nov 26 '18 at 19:45




















0















I have User and UserGroup entities. Each user has a group (UserGroup), and each user has a boss (User).



I would like to get a list of groups, and decide if the current user is the boss of someone in the group. I already implemented this in SQL, and now I tried to solve it using Doctrine. This is what I tried:



$qb = em()->createQueryBuilder()
->select(array('gr.id AS group_id', 'gr.name AS group_name', 'COUNT(us.boss = :current_user_id)>0 AS is_boss'))
->from('AppEntityUserGroup', 'ug')
->leftJoin('AppEntityUser', 'us', 'WITH', 'us.group = ug.id')

->setParameter('current_user_id', $_SESSION['uid'])

->groupby('gr.id')
;

$groups = $qb->getQuery()->getScalarResult();


Unfortunately I get an uncaught QueryException, and I have no idea how to fix that. How is it possible to put an expression inside the COUNT(...) function?










share|improve this question

























  • What is the error message? And you should groupBy with all columns, not only id.

    – Felippe Duarte
    Nov 26 '18 at 19:37













  • It works without the COUNT(...) part. The error message just contains the DQL query: SELECT gr.id AS group_id, gr.name AS group_name, COUNT(us.boss = :current_user_id)>0 AS is_boss FROM AppEntityUserGroup ug LEFT JOIN AppEntityUser us WITH us.group = ug.id GROUP BY gr.id

    – Iter Ator
    Nov 26 '18 at 19:45
















0












0








0








I have User and UserGroup entities. Each user has a group (UserGroup), and each user has a boss (User).



I would like to get a list of groups, and decide if the current user is the boss of someone in the group. I already implemented this in SQL, and now I tried to solve it using Doctrine. This is what I tried:



$qb = em()->createQueryBuilder()
->select(array('gr.id AS group_id', 'gr.name AS group_name', 'COUNT(us.boss = :current_user_id)>0 AS is_boss'))
->from('AppEntityUserGroup', 'ug')
->leftJoin('AppEntityUser', 'us', 'WITH', 'us.group = ug.id')

->setParameter('current_user_id', $_SESSION['uid'])

->groupby('gr.id')
;

$groups = $qb->getQuery()->getScalarResult();


Unfortunately I get an uncaught QueryException, and I have no idea how to fix that. How is it possible to put an expression inside the COUNT(...) function?










share|improve this question
















I have User and UserGroup entities. Each user has a group (UserGroup), and each user has a boss (User).



I would like to get a list of groups, and decide if the current user is the boss of someone in the group. I already implemented this in SQL, and now I tried to solve it using Doctrine. This is what I tried:



$qb = em()->createQueryBuilder()
->select(array('gr.id AS group_id', 'gr.name AS group_name', 'COUNT(us.boss = :current_user_id)>0 AS is_boss'))
->from('AppEntityUserGroup', 'ug')
->leftJoin('AppEntityUser', 'us', 'WITH', 'us.group = ug.id')

->setParameter('current_user_id', $_SESSION['uid'])

->groupby('gr.id')
;

$groups = $qb->getQuery()->getScalarResult();


Unfortunately I get an uncaught QueryException, and I have no idea how to fix that. How is it possible to put an expression inside the COUNT(...) function?







php sql doctrine-orm






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 27 '18 at 13:22







Iter Ator

















asked Nov 26 '18 at 19:35









Iter AtorIter Ator

2,14673580




2,14673580













  • What is the error message? And you should groupBy with all columns, not only id.

    – Felippe Duarte
    Nov 26 '18 at 19:37













  • It works without the COUNT(...) part. The error message just contains the DQL query: SELECT gr.id AS group_id, gr.name AS group_name, COUNT(us.boss = :current_user_id)>0 AS is_boss FROM AppEntityUserGroup ug LEFT JOIN AppEntityUser us WITH us.group = ug.id GROUP BY gr.id

    – Iter Ator
    Nov 26 '18 at 19:45





















  • What is the error message? And you should groupBy with all columns, not only id.

    – Felippe Duarte
    Nov 26 '18 at 19:37













  • It works without the COUNT(...) part. The error message just contains the DQL query: SELECT gr.id AS group_id, gr.name AS group_name, COUNT(us.boss = :current_user_id)>0 AS is_boss FROM AppEntityUserGroup ug LEFT JOIN AppEntityUser us WITH us.group = ug.id GROUP BY gr.id

    – Iter Ator
    Nov 26 '18 at 19:45



















What is the error message? And you should groupBy with all columns, not only id.

– Felippe Duarte
Nov 26 '18 at 19:37







What is the error message? And you should groupBy with all columns, not only id.

– Felippe Duarte
Nov 26 '18 at 19:37















It works without the COUNT(...) part. The error message just contains the DQL query: SELECT gr.id AS group_id, gr.name AS group_name, COUNT(us.boss = :current_user_id)>0 AS is_boss FROM AppEntityUserGroup ug LEFT JOIN AppEntityUser us WITH us.group = ug.id GROUP BY gr.id

– Iter Ator
Nov 26 '18 at 19:45







It works without the COUNT(...) part. The error message just contains the DQL query: SELECT gr.id AS group_id, gr.name AS group_name, COUNT(us.boss = :current_user_id)>0 AS is_boss FROM AppEntityUserGroup ug LEFT JOIN AppEntityUser us WITH us.group = ug.id GROUP BY gr.id

– Iter Ator
Nov 26 '18 at 19:45














1 Answer
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1














You can use Mysql case function to do this:



$queryBuilder->addSelect('case when COUNT(case when us.boss = :current_user_id then 1 else 0 end)>0 then 1 else 0 end AS is_boss');


Reference




  • Is it possible to specify condition in Count()?






share|improve this answer
























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    1 Answer
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    You can use Mysql case function to do this:



    $queryBuilder->addSelect('case when COUNT(case when us.boss = :current_user_id then 1 else 0 end)>0 then 1 else 0 end AS is_boss');


    Reference




    • Is it possible to specify condition in Count()?






    share|improve this answer




























      1














      You can use Mysql case function to do this:



      $queryBuilder->addSelect('case when COUNT(case when us.boss = :current_user_id then 1 else 0 end)>0 then 1 else 0 end AS is_boss');


      Reference




      • Is it possible to specify condition in Count()?






      share|improve this answer


























        1












        1








        1







        You can use Mysql case function to do this:



        $queryBuilder->addSelect('case when COUNT(case when us.boss = :current_user_id then 1 else 0 end)>0 then 1 else 0 end AS is_boss');


        Reference




        • Is it possible to specify condition in Count()?






        share|improve this answer













        You can use Mysql case function to do this:



        $queryBuilder->addSelect('case when COUNT(case when us.boss = :current_user_id then 1 else 0 end)>0 then 1 else 0 end AS is_boss');


        Reference




        • Is it possible to specify condition in Count()?







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 27 '18 at 22:32









        Jannes BotisJannes Botis

        8,30421227




        8,30421227
































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