stop groupby from making 2 combination same pair in python dataframe





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I am working on IPL dataset from Kaggle (https://www.kaggle.com/manasgarg/ipl).
I want to sum up the runs made by two people as pair and I have prepared my data.
When I am trying a GROUPBY on the dataframe columns (batsman and non_striker) it is making 2 combination of the same pair.
like (a,b) and (b,a) - rather I wish it should consider it as same.
As I can't drop rows any further.



import pandas as pd

df = pd.read_csv("C:\Users\Yash\AppData\Local\Programs\Python\Python36-32\Machine Learning\IPL\deliveries.csv")
df = df[(df["is_super_over"] != 1)]
df["pri_key"] = df["match_id"].astype(str) + "-" + df["inning"].astype(str)
openners = df[(df["over"] == 1) & (df["ball"] == 1)]
openners = openners[["pri_key", "batsman", "non_striker"]]
openners = openners.rename(columns = {"batsman":"batter1", "non_striker":"batter2"})
df = pd.merge(df, openners, on="pri_key")
df = df[["batsman", "non_striker", "batter1", "batter2", "batsman_runs"]]
df = df[((df["batsman"] == df["batter1"]) | (df["batsman"] == df["batter2"]))
& ((df["non_striker"] == df["batter1"]) | (df["non_striker"] == df["batter2"]))]

df1 = df.groupby(["batsman" , "non_striker"], group_keys = False)["batsman_runs"].agg("sum")
df1.nlargest(10)

Result:
batsman non_striker
DA Warner S Dhawan 1294
S Dhawan DA Warner 823
RV Uthappa G Gambhir 781
DR Smith BB McCullum 684
CH Gayle V Kohli 674
MEK Hussey M Vijay 666
M Vijay MEK Hussey 629
G Gambhir RV Uthappa 611
BB McCullum DR Smith 593
CH Gayle TM Dilshan 537


and, I want to keep 1 pair as unique



for those who don't understand cricket
I have a dataframe



batsman    non_striker    runs
a b 2
a b 3
b a 1
c d 6
d c 1
d c 4
b a 3
e f 1
f e 2
f e 6

df1 = df.groupby(["batsman" , "non_striker"], group_keys = False)["batsman_runs"].agg("sum")
df1.nlargest(30)

output:
batsman non_striker runs
a b 5
b a 4
c d 6
d c 5
e f 1
f e 8

expected output:
batsman non_striker runs
a b 9
c d 11
e f 9


what should I do? Please advise....










share|improve this question























  • Join df['batsman_non_striker'] = df['batsman'] + df['non_striker ']; sort the values ''.join(sorted(batsman_non_striker)), and then df.groupby('(batsman_non_striker').agg('sum')

    – Ken Dekalb
    Nov 26 '18 at 19:27


















5















I am working on IPL dataset from Kaggle (https://www.kaggle.com/manasgarg/ipl).
I want to sum up the runs made by two people as pair and I have prepared my data.
When I am trying a GROUPBY on the dataframe columns (batsman and non_striker) it is making 2 combination of the same pair.
like (a,b) and (b,a) - rather I wish it should consider it as same.
As I can't drop rows any further.



import pandas as pd

df = pd.read_csv("C:\Users\Yash\AppData\Local\Programs\Python\Python36-32\Machine Learning\IPL\deliveries.csv")
df = df[(df["is_super_over"] != 1)]
df["pri_key"] = df["match_id"].astype(str) + "-" + df["inning"].astype(str)
openners = df[(df["over"] == 1) & (df["ball"] == 1)]
openners = openners[["pri_key", "batsman", "non_striker"]]
openners = openners.rename(columns = {"batsman":"batter1", "non_striker":"batter2"})
df = pd.merge(df, openners, on="pri_key")
df = df[["batsman", "non_striker", "batter1", "batter2", "batsman_runs"]]
df = df[((df["batsman"] == df["batter1"]) | (df["batsman"] == df["batter2"]))
& ((df["non_striker"] == df["batter1"]) | (df["non_striker"] == df["batter2"]))]

df1 = df.groupby(["batsman" , "non_striker"], group_keys = False)["batsman_runs"].agg("sum")
df1.nlargest(10)

Result:
batsman non_striker
DA Warner S Dhawan 1294
S Dhawan DA Warner 823
RV Uthappa G Gambhir 781
DR Smith BB McCullum 684
CH Gayle V Kohli 674
MEK Hussey M Vijay 666
M Vijay MEK Hussey 629
G Gambhir RV Uthappa 611
BB McCullum DR Smith 593
CH Gayle TM Dilshan 537


and, I want to keep 1 pair as unique



for those who don't understand cricket
I have a dataframe



batsman    non_striker    runs
a b 2
a b 3
b a 1
c d 6
d c 1
d c 4
b a 3
e f 1
f e 2
f e 6

df1 = df.groupby(["batsman" , "non_striker"], group_keys = False)["batsman_runs"].agg("sum")
df1.nlargest(30)

output:
batsman non_striker runs
a b 5
b a 4
c d 6
d c 5
e f 1
f e 8

expected output:
batsman non_striker runs
a b 9
c d 11
e f 9


what should I do? Please advise....










share|improve this question























  • Join df['batsman_non_striker'] = df['batsman'] + df['non_striker ']; sort the values ''.join(sorted(batsman_non_striker)), and then df.groupby('(batsman_non_striker').agg('sum')

    – Ken Dekalb
    Nov 26 '18 at 19:27














5












5








5








I am working on IPL dataset from Kaggle (https://www.kaggle.com/manasgarg/ipl).
I want to sum up the runs made by two people as pair and I have prepared my data.
When I am trying a GROUPBY on the dataframe columns (batsman and non_striker) it is making 2 combination of the same pair.
like (a,b) and (b,a) - rather I wish it should consider it as same.
As I can't drop rows any further.



import pandas as pd

df = pd.read_csv("C:\Users\Yash\AppData\Local\Programs\Python\Python36-32\Machine Learning\IPL\deliveries.csv")
df = df[(df["is_super_over"] != 1)]
df["pri_key"] = df["match_id"].astype(str) + "-" + df["inning"].astype(str)
openners = df[(df["over"] == 1) & (df["ball"] == 1)]
openners = openners[["pri_key", "batsman", "non_striker"]]
openners = openners.rename(columns = {"batsman":"batter1", "non_striker":"batter2"})
df = pd.merge(df, openners, on="pri_key")
df = df[["batsman", "non_striker", "batter1", "batter2", "batsman_runs"]]
df = df[((df["batsman"] == df["batter1"]) | (df["batsman"] == df["batter2"]))
& ((df["non_striker"] == df["batter1"]) | (df["non_striker"] == df["batter2"]))]

df1 = df.groupby(["batsman" , "non_striker"], group_keys = False)["batsman_runs"].agg("sum")
df1.nlargest(10)

Result:
batsman non_striker
DA Warner S Dhawan 1294
S Dhawan DA Warner 823
RV Uthappa G Gambhir 781
DR Smith BB McCullum 684
CH Gayle V Kohli 674
MEK Hussey M Vijay 666
M Vijay MEK Hussey 629
G Gambhir RV Uthappa 611
BB McCullum DR Smith 593
CH Gayle TM Dilshan 537


and, I want to keep 1 pair as unique



for those who don't understand cricket
I have a dataframe



batsman    non_striker    runs
a b 2
a b 3
b a 1
c d 6
d c 1
d c 4
b a 3
e f 1
f e 2
f e 6

df1 = df.groupby(["batsman" , "non_striker"], group_keys = False)["batsman_runs"].agg("sum")
df1.nlargest(30)

output:
batsman non_striker runs
a b 5
b a 4
c d 6
d c 5
e f 1
f e 8

expected output:
batsman non_striker runs
a b 9
c d 11
e f 9


what should I do? Please advise....










share|improve this question














I am working on IPL dataset from Kaggle (https://www.kaggle.com/manasgarg/ipl).
I want to sum up the runs made by two people as pair and I have prepared my data.
When I am trying a GROUPBY on the dataframe columns (batsman and non_striker) it is making 2 combination of the same pair.
like (a,b) and (b,a) - rather I wish it should consider it as same.
As I can't drop rows any further.



import pandas as pd

df = pd.read_csv("C:\Users\Yash\AppData\Local\Programs\Python\Python36-32\Machine Learning\IPL\deliveries.csv")
df = df[(df["is_super_over"] != 1)]
df["pri_key"] = df["match_id"].astype(str) + "-" + df["inning"].astype(str)
openners = df[(df["over"] == 1) & (df["ball"] == 1)]
openners = openners[["pri_key", "batsman", "non_striker"]]
openners = openners.rename(columns = {"batsman":"batter1", "non_striker":"batter2"})
df = pd.merge(df, openners, on="pri_key")
df = df[["batsman", "non_striker", "batter1", "batter2", "batsman_runs"]]
df = df[((df["batsman"] == df["batter1"]) | (df["batsman"] == df["batter2"]))
& ((df["non_striker"] == df["batter1"]) | (df["non_striker"] == df["batter2"]))]

df1 = df.groupby(["batsman" , "non_striker"], group_keys = False)["batsman_runs"].agg("sum")
df1.nlargest(10)

Result:
batsman non_striker
DA Warner S Dhawan 1294
S Dhawan DA Warner 823
RV Uthappa G Gambhir 781
DR Smith BB McCullum 684
CH Gayle V Kohli 674
MEK Hussey M Vijay 666
M Vijay MEK Hussey 629
G Gambhir RV Uthappa 611
BB McCullum DR Smith 593
CH Gayle TM Dilshan 537


and, I want to keep 1 pair as unique



for those who don't understand cricket
I have a dataframe



batsman    non_striker    runs
a b 2
a b 3
b a 1
c d 6
d c 1
d c 4
b a 3
e f 1
f e 2
f e 6

df1 = df.groupby(["batsman" , "non_striker"], group_keys = False)["batsman_runs"].agg("sum")
df1.nlargest(30)

output:
batsman non_striker runs
a b 5
b a 4
c d 6
d c 5
e f 1
f e 8

expected output:
batsman non_striker runs
a b 9
c d 11
e f 9


what should I do? Please advise....







python pandas






share|improve this question













share|improve this question











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asked Nov 26 '18 at 19:15









Yash MishraYash Mishra

264




264













  • Join df['batsman_non_striker'] = df['batsman'] + df['non_striker ']; sort the values ''.join(sorted(batsman_non_striker)), and then df.groupby('(batsman_non_striker').agg('sum')

    – Ken Dekalb
    Nov 26 '18 at 19:27



















  • Join df['batsman_non_striker'] = df['batsman'] + df['non_striker ']; sort the values ''.join(sorted(batsman_non_striker)), and then df.groupby('(batsman_non_striker').agg('sum')

    – Ken Dekalb
    Nov 26 '18 at 19:27

















Join df['batsman_non_striker'] = df['batsman'] + df['non_striker ']; sort the values ''.join(sorted(batsman_non_striker)), and then df.groupby('(batsman_non_striker').agg('sum')

– Ken Dekalb
Nov 26 '18 at 19:27





Join df['batsman_non_striker'] = df['batsman'] + df['non_striker ']; sort the values ''.join(sorted(batsman_non_striker)), and then df.groupby('(batsman_non_striker').agg('sum')

– Ken Dekalb
Nov 26 '18 at 19:27












3 Answers
3






active

oldest

votes


















4














You can sort the batsman and non_striker and then group the data



df[['batsman', 'non_striker']] = df[['batsman', 'non_striker']].apply(sorted, axis=1) 
df.groupby(['batsman', 'non_striker']).batsman_runs.sum().nlargest(10)


Edit: You can also use numpy for sorting the columns, which will be faster than using pandas sorted



df[['batsman', 'non_striker']] = np.sort(df[['batsman', 'non_striker']],1)
df.groupby(['batsman', 'non_striker'], sort = False).batsman_runs.sum().nlargest(10).sort_index()


Either way, you will get,



batsman         non_striker
CH Gayle V Kohli 2650
DA Warner S Dhawan 2242
AB de Villiers V Kohli 2135
G Gambhir RV Uthappa 1795
M Vijay MEK Hussey 1302
BB McCullum DR Smith 1277
KA Pollard RG Sharma 1220
MEK Hussey SK Raina 1129
AT Rayudu RG Sharma 1121
AM Rahane SR Watson 1118





share|improve this answer





















  • 1





    Perfect.... :) Thanks Vaishali... You are a true champ of IPL dataset!!!

    – Yash Mishra
    Nov 26 '18 at 19:43











  • @YashMishra, just that I have worked on it quite a bit :)

    – Vaishali
    Nov 26 '18 at 19:44











  • @YashMishra, do remember to upvote/accept the answer if it answers your query fully

    – Vaishali
    Nov 26 '18 at 19:54











  • @YashMishra, do consider accepting the answer as it closes the question and would help anyone with a similar query in the future

    – Vaishali
    Dec 14 '18 at 18:14



















1














Craete a new DataFrame using np.sort. Then groupby and sum.



import pandas as pd
import numpy as np

df1 = pd.DataFrame(np.sort(df[['batsman', 'non_striker']].values,1),
index=df.index,
columns=['player_1', 'player_2']).assign(runs = df.runs)

df1.groupby(['player_1', 'player_2']).runs.sum()


Output:



player_1  player_2
a b 9
c d 11
e f 9
Name: runs, dtype: int64





share|improve this answer































    0














    I hope I understand you right...



    What you can do is something like put the smaller value always in column A and the greater value always in column B.



    import pandas as pd
    import numpy as np

    # generate example
    values = ['a', 'b' , 'c', 'd', 'e', 'f', 'g']
    df = pd.DataFrame()
    df['batsman'] = np.random.choice(values, size=10)
    df['no_striker'] = np.random.choice(values, size=10)

    # column evaluation
    df['smaller'] = df['batsman'].where(df['batsman'] < df['no_striker'], df['no_striker'])
    df['greater'] = df['batsman'].where(df['batsman'] > df['no_striker'], df['no_striker'])





    share|improve this answer
























    • I really appreciate your effort and kindness to help but this is not exactly I am looking for.

      – Yash Mishra
      Nov 27 '18 at 17:08












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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    You can sort the batsman and non_striker and then group the data



    df[['batsman', 'non_striker']] = df[['batsman', 'non_striker']].apply(sorted, axis=1) 
    df.groupby(['batsman', 'non_striker']).batsman_runs.sum().nlargest(10)


    Edit: You can also use numpy for sorting the columns, which will be faster than using pandas sorted



    df[['batsman', 'non_striker']] = np.sort(df[['batsman', 'non_striker']],1)
    df.groupby(['batsman', 'non_striker'], sort = False).batsman_runs.sum().nlargest(10).sort_index()


    Either way, you will get,



    batsman         non_striker
    CH Gayle V Kohli 2650
    DA Warner S Dhawan 2242
    AB de Villiers V Kohli 2135
    G Gambhir RV Uthappa 1795
    M Vijay MEK Hussey 1302
    BB McCullum DR Smith 1277
    KA Pollard RG Sharma 1220
    MEK Hussey SK Raina 1129
    AT Rayudu RG Sharma 1121
    AM Rahane SR Watson 1118





    share|improve this answer





















    • 1





      Perfect.... :) Thanks Vaishali... You are a true champ of IPL dataset!!!

      – Yash Mishra
      Nov 26 '18 at 19:43











    • @YashMishra, just that I have worked on it quite a bit :)

      – Vaishali
      Nov 26 '18 at 19:44











    • @YashMishra, do remember to upvote/accept the answer if it answers your query fully

      – Vaishali
      Nov 26 '18 at 19:54











    • @YashMishra, do consider accepting the answer as it closes the question and would help anyone with a similar query in the future

      – Vaishali
      Dec 14 '18 at 18:14
















    4














    You can sort the batsman and non_striker and then group the data



    df[['batsman', 'non_striker']] = df[['batsman', 'non_striker']].apply(sorted, axis=1) 
    df.groupby(['batsman', 'non_striker']).batsman_runs.sum().nlargest(10)


    Edit: You can also use numpy for sorting the columns, which will be faster than using pandas sorted



    df[['batsman', 'non_striker']] = np.sort(df[['batsman', 'non_striker']],1)
    df.groupby(['batsman', 'non_striker'], sort = False).batsman_runs.sum().nlargest(10).sort_index()


    Either way, you will get,



    batsman         non_striker
    CH Gayle V Kohli 2650
    DA Warner S Dhawan 2242
    AB de Villiers V Kohli 2135
    G Gambhir RV Uthappa 1795
    M Vijay MEK Hussey 1302
    BB McCullum DR Smith 1277
    KA Pollard RG Sharma 1220
    MEK Hussey SK Raina 1129
    AT Rayudu RG Sharma 1121
    AM Rahane SR Watson 1118





    share|improve this answer





















    • 1





      Perfect.... :) Thanks Vaishali... You are a true champ of IPL dataset!!!

      – Yash Mishra
      Nov 26 '18 at 19:43











    • @YashMishra, just that I have worked on it quite a bit :)

      – Vaishali
      Nov 26 '18 at 19:44











    • @YashMishra, do remember to upvote/accept the answer if it answers your query fully

      – Vaishali
      Nov 26 '18 at 19:54











    • @YashMishra, do consider accepting the answer as it closes the question and would help anyone with a similar query in the future

      – Vaishali
      Dec 14 '18 at 18:14














    4












    4








    4







    You can sort the batsman and non_striker and then group the data



    df[['batsman', 'non_striker']] = df[['batsman', 'non_striker']].apply(sorted, axis=1) 
    df.groupby(['batsman', 'non_striker']).batsman_runs.sum().nlargest(10)


    Edit: You can also use numpy for sorting the columns, which will be faster than using pandas sorted



    df[['batsman', 'non_striker']] = np.sort(df[['batsman', 'non_striker']],1)
    df.groupby(['batsman', 'non_striker'], sort = False).batsman_runs.sum().nlargest(10).sort_index()


    Either way, you will get,



    batsman         non_striker
    CH Gayle V Kohli 2650
    DA Warner S Dhawan 2242
    AB de Villiers V Kohli 2135
    G Gambhir RV Uthappa 1795
    M Vijay MEK Hussey 1302
    BB McCullum DR Smith 1277
    KA Pollard RG Sharma 1220
    MEK Hussey SK Raina 1129
    AT Rayudu RG Sharma 1121
    AM Rahane SR Watson 1118





    share|improve this answer















    You can sort the batsman and non_striker and then group the data



    df[['batsman', 'non_striker']] = df[['batsman', 'non_striker']].apply(sorted, axis=1) 
    df.groupby(['batsman', 'non_striker']).batsman_runs.sum().nlargest(10)


    Edit: You can also use numpy for sorting the columns, which will be faster than using pandas sorted



    df[['batsman', 'non_striker']] = np.sort(df[['batsman', 'non_striker']],1)
    df.groupby(['batsman', 'non_striker'], sort = False).batsman_runs.sum().nlargest(10).sort_index()


    Either way, you will get,



    batsman         non_striker
    CH Gayle V Kohli 2650
    DA Warner S Dhawan 2242
    AB de Villiers V Kohli 2135
    G Gambhir RV Uthappa 1795
    M Vijay MEK Hussey 1302
    BB McCullum DR Smith 1277
    KA Pollard RG Sharma 1220
    MEK Hussey SK Raina 1129
    AT Rayudu RG Sharma 1121
    AM Rahane SR Watson 1118






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 26 '18 at 20:42

























    answered Nov 26 '18 at 19:28









    VaishaliVaishali

    22.6k41438




    22.6k41438








    • 1





      Perfect.... :) Thanks Vaishali... You are a true champ of IPL dataset!!!

      – Yash Mishra
      Nov 26 '18 at 19:43











    • @YashMishra, just that I have worked on it quite a bit :)

      – Vaishali
      Nov 26 '18 at 19:44











    • @YashMishra, do remember to upvote/accept the answer if it answers your query fully

      – Vaishali
      Nov 26 '18 at 19:54











    • @YashMishra, do consider accepting the answer as it closes the question and would help anyone with a similar query in the future

      – Vaishali
      Dec 14 '18 at 18:14














    • 1





      Perfect.... :) Thanks Vaishali... You are a true champ of IPL dataset!!!

      – Yash Mishra
      Nov 26 '18 at 19:43











    • @YashMishra, just that I have worked on it quite a bit :)

      – Vaishali
      Nov 26 '18 at 19:44











    • @YashMishra, do remember to upvote/accept the answer if it answers your query fully

      – Vaishali
      Nov 26 '18 at 19:54











    • @YashMishra, do consider accepting the answer as it closes the question and would help anyone with a similar query in the future

      – Vaishali
      Dec 14 '18 at 18:14








    1




    1





    Perfect.... :) Thanks Vaishali... You are a true champ of IPL dataset!!!

    – Yash Mishra
    Nov 26 '18 at 19:43





    Perfect.... :) Thanks Vaishali... You are a true champ of IPL dataset!!!

    – Yash Mishra
    Nov 26 '18 at 19:43













    @YashMishra, just that I have worked on it quite a bit :)

    – Vaishali
    Nov 26 '18 at 19:44





    @YashMishra, just that I have worked on it quite a bit :)

    – Vaishali
    Nov 26 '18 at 19:44













    @YashMishra, do remember to upvote/accept the answer if it answers your query fully

    – Vaishali
    Nov 26 '18 at 19:54





    @YashMishra, do remember to upvote/accept the answer if it answers your query fully

    – Vaishali
    Nov 26 '18 at 19:54













    @YashMishra, do consider accepting the answer as it closes the question and would help anyone with a similar query in the future

    – Vaishali
    Dec 14 '18 at 18:14





    @YashMishra, do consider accepting the answer as it closes the question and would help anyone with a similar query in the future

    – Vaishali
    Dec 14 '18 at 18:14













    1














    Craete a new DataFrame using np.sort. Then groupby and sum.



    import pandas as pd
    import numpy as np

    df1 = pd.DataFrame(np.sort(df[['batsman', 'non_striker']].values,1),
    index=df.index,
    columns=['player_1', 'player_2']).assign(runs = df.runs)

    df1.groupby(['player_1', 'player_2']).runs.sum()


    Output:



    player_1  player_2
    a b 9
    c d 11
    e f 9
    Name: runs, dtype: int64





    share|improve this answer




























      1














      Craete a new DataFrame using np.sort. Then groupby and sum.



      import pandas as pd
      import numpy as np

      df1 = pd.DataFrame(np.sort(df[['batsman', 'non_striker']].values,1),
      index=df.index,
      columns=['player_1', 'player_2']).assign(runs = df.runs)

      df1.groupby(['player_1', 'player_2']).runs.sum()


      Output:



      player_1  player_2
      a b 9
      c d 11
      e f 9
      Name: runs, dtype: int64





      share|improve this answer


























        1












        1








        1







        Craete a new DataFrame using np.sort. Then groupby and sum.



        import pandas as pd
        import numpy as np

        df1 = pd.DataFrame(np.sort(df[['batsman', 'non_striker']].values,1),
        index=df.index,
        columns=['player_1', 'player_2']).assign(runs = df.runs)

        df1.groupby(['player_1', 'player_2']).runs.sum()


        Output:



        player_1  player_2
        a b 9
        c d 11
        e f 9
        Name: runs, dtype: int64





        share|improve this answer













        Craete a new DataFrame using np.sort. Then groupby and sum.



        import pandas as pd
        import numpy as np

        df1 = pd.DataFrame(np.sort(df[['batsman', 'non_striker']].values,1),
        index=df.index,
        columns=['player_1', 'player_2']).assign(runs = df.runs)

        df1.groupby(['player_1', 'player_2']).runs.sum()


        Output:



        player_1  player_2
        a b 9
        c d 11
        e f 9
        Name: runs, dtype: int64






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 26 '18 at 19:28









        ALollzALollz

        16.5k41838




        16.5k41838























            0














            I hope I understand you right...



            What you can do is something like put the smaller value always in column A and the greater value always in column B.



            import pandas as pd
            import numpy as np

            # generate example
            values = ['a', 'b' , 'c', 'd', 'e', 'f', 'g']
            df = pd.DataFrame()
            df['batsman'] = np.random.choice(values, size=10)
            df['no_striker'] = np.random.choice(values, size=10)

            # column evaluation
            df['smaller'] = df['batsman'].where(df['batsman'] < df['no_striker'], df['no_striker'])
            df['greater'] = df['batsman'].where(df['batsman'] > df['no_striker'], df['no_striker'])





            share|improve this answer
























            • I really appreciate your effort and kindness to help but this is not exactly I am looking for.

              – Yash Mishra
              Nov 27 '18 at 17:08
















            0














            I hope I understand you right...



            What you can do is something like put the smaller value always in column A and the greater value always in column B.



            import pandas as pd
            import numpy as np

            # generate example
            values = ['a', 'b' , 'c', 'd', 'e', 'f', 'g']
            df = pd.DataFrame()
            df['batsman'] = np.random.choice(values, size=10)
            df['no_striker'] = np.random.choice(values, size=10)

            # column evaluation
            df['smaller'] = df['batsman'].where(df['batsman'] < df['no_striker'], df['no_striker'])
            df['greater'] = df['batsman'].where(df['batsman'] > df['no_striker'], df['no_striker'])





            share|improve this answer
























            • I really appreciate your effort and kindness to help but this is not exactly I am looking for.

              – Yash Mishra
              Nov 27 '18 at 17:08














            0












            0








            0







            I hope I understand you right...



            What you can do is something like put the smaller value always in column A and the greater value always in column B.



            import pandas as pd
            import numpy as np

            # generate example
            values = ['a', 'b' , 'c', 'd', 'e', 'f', 'g']
            df = pd.DataFrame()
            df['batsman'] = np.random.choice(values, size=10)
            df['no_striker'] = np.random.choice(values, size=10)

            # column evaluation
            df['smaller'] = df['batsman'].where(df['batsman'] < df['no_striker'], df['no_striker'])
            df['greater'] = df['batsman'].where(df['batsman'] > df['no_striker'], df['no_striker'])





            share|improve this answer













            I hope I understand you right...



            What you can do is something like put the smaller value always in column A and the greater value always in column B.



            import pandas as pd
            import numpy as np

            # generate example
            values = ['a', 'b' , 'c', 'd', 'e', 'f', 'g']
            df = pd.DataFrame()
            df['batsman'] = np.random.choice(values, size=10)
            df['no_striker'] = np.random.choice(values, size=10)

            # column evaluation
            df['smaller'] = df['batsman'].where(df['batsman'] < df['no_striker'], df['no_striker'])
            df['greater'] = df['batsman'].where(df['batsman'] > df['no_striker'], df['no_striker'])






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 26 '18 at 19:31









            MisterMonkMisterMonk

            1549




            1549













            • I really appreciate your effort and kindness to help but this is not exactly I am looking for.

              – Yash Mishra
              Nov 27 '18 at 17:08



















            • I really appreciate your effort and kindness to help but this is not exactly I am looking for.

              – Yash Mishra
              Nov 27 '18 at 17:08

















            I really appreciate your effort and kindness to help but this is not exactly I am looking for.

            – Yash Mishra
            Nov 27 '18 at 17:08





            I really appreciate your effort and kindness to help but this is not exactly I am looking for.

            – Yash Mishra
            Nov 27 '18 at 17:08


















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