Example of Order isomorphism in well order set












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Sir there is a theorem which says "let (X, <)and (X',<) be wosets. If they are order isomorphic to each other there is exactly one isomorphism exists "and there is an example saying that well order is essential. In a totally order set it violates by giving example f from Z to Z defined by fm( n)=m+n. Sir my doubt is, does this violets in N also??? As N is a woset,if m not equal to m' fm not equal to equal to fm' is holding there also.










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    The function $f_1:mathbb Ntomathbb N$ defined by $f_1(n)=n+1$ is order-preserving and injective, but not surjective, so it's not an isomorphism.
    – bof
    Nov 29 at 0:06


















-1














Sir there is a theorem which says "let (X, <)and (X',<) be wosets. If they are order isomorphic to each other there is exactly one isomorphism exists "and there is an example saying that well order is essential. In a totally order set it violates by giving example f from Z to Z defined by fm( n)=m+n. Sir my doubt is, does this violets in N also??? As N is a woset,if m not equal to m' fm not equal to equal to fm' is holding there also.










share|cite|improve this question


















  • 3




    The function $f_1:mathbb Ntomathbb N$ defined by $f_1(n)=n+1$ is order-preserving and injective, but not surjective, so it's not an isomorphism.
    – bof
    Nov 29 at 0:06
















-1












-1








-1







Sir there is a theorem which says "let (X, <)and (X',<) be wosets. If they are order isomorphic to each other there is exactly one isomorphism exists "and there is an example saying that well order is essential. In a totally order set it violates by giving example f from Z to Z defined by fm( n)=m+n. Sir my doubt is, does this violets in N also??? As N is a woset,if m not equal to m' fm not equal to equal to fm' is holding there also.










share|cite|improve this question













Sir there is a theorem which says "let (X, <)and (X',<) be wosets. If they are order isomorphic to each other there is exactly one isomorphism exists "and there is an example saying that well order is essential. In a totally order set it violates by giving example f from Z to Z defined by fm( n)=m+n. Sir my doubt is, does this violets in N also??? As N is a woset,if m not equal to m' fm not equal to equal to fm' is holding there also.







order-theory






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asked Nov 29 at 0:01









Resmi

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1








  • 3




    The function $f_1:mathbb Ntomathbb N$ defined by $f_1(n)=n+1$ is order-preserving and injective, but not surjective, so it's not an isomorphism.
    – bof
    Nov 29 at 0:06
















  • 3




    The function $f_1:mathbb Ntomathbb N$ defined by $f_1(n)=n+1$ is order-preserving and injective, but not surjective, so it's not an isomorphism.
    – bof
    Nov 29 at 0:06










3




3




The function $f_1:mathbb Ntomathbb N$ defined by $f_1(n)=n+1$ is order-preserving and injective, but not surjective, so it's not an isomorphism.
– bof
Nov 29 at 0:06






The function $f_1:mathbb Ntomathbb N$ defined by $f_1(n)=n+1$ is order-preserving and injective, but not surjective, so it's not an isomorphism.
– bof
Nov 29 at 0:06

















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