how to calculate the euclidean distance between the vectors in one matrix?











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3
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I want to calculate the Euclidean distance of the vectors in the features, which is a tf.Tensor got from the network.



I tried it in the following way, but failed with error:



'Tensor' object is not iterable


So I want to calculate the distance between the rows in one matrix just through matrix,without iteration of every rows.



features, _ = mnist_net(images)
feature_matrix = np.zeros(shape=(FLAGS.batch_size,FLAGS.batch_size))
for i in range (FLAGS.batch_size):
for j in range (FLAGS.batch_size):
aa = tf.slice(features,[i,0],[1,50])
bb = tf.slice(features,[j,0],[1,50])
feature_matrix[i,j] = tf.sqrt(sum((aa-bb)**2))









share|improve this question
























  • What have you tried so far? It is better to give some code and explain your attempt.
    – Banghua Zhao
    Nov 20 at 1:30










  • What do you mean by distance here? There are a lot of distance measures
    – user7374610
    Nov 20 at 2:37










  • I have fixed the question, can you help me solve it?@Banghua Zhao@user7374610
    – Bobo Xi
    Nov 20 at 4:00















up vote
3
down vote

favorite












I want to calculate the Euclidean distance of the vectors in the features, which is a tf.Tensor got from the network.



I tried it in the following way, but failed with error:



'Tensor' object is not iterable


So I want to calculate the distance between the rows in one matrix just through matrix,without iteration of every rows.



features, _ = mnist_net(images)
feature_matrix = np.zeros(shape=(FLAGS.batch_size,FLAGS.batch_size))
for i in range (FLAGS.batch_size):
for j in range (FLAGS.batch_size):
aa = tf.slice(features,[i,0],[1,50])
bb = tf.slice(features,[j,0],[1,50])
feature_matrix[i,j] = tf.sqrt(sum((aa-bb)**2))









share|improve this question
























  • What have you tried so far? It is better to give some code and explain your attempt.
    – Banghua Zhao
    Nov 20 at 1:30










  • What do you mean by distance here? There are a lot of distance measures
    – user7374610
    Nov 20 at 2:37










  • I have fixed the question, can you help me solve it?@Banghua Zhao@user7374610
    – Bobo Xi
    Nov 20 at 4:00













up vote
3
down vote

favorite









up vote
3
down vote

favorite











I want to calculate the Euclidean distance of the vectors in the features, which is a tf.Tensor got from the network.



I tried it in the following way, but failed with error:



'Tensor' object is not iterable


So I want to calculate the distance between the rows in one matrix just through matrix,without iteration of every rows.



features, _ = mnist_net(images)
feature_matrix = np.zeros(shape=(FLAGS.batch_size,FLAGS.batch_size))
for i in range (FLAGS.batch_size):
for j in range (FLAGS.batch_size):
aa = tf.slice(features,[i,0],[1,50])
bb = tf.slice(features,[j,0],[1,50])
feature_matrix[i,j] = tf.sqrt(sum((aa-bb)**2))









share|improve this question















I want to calculate the Euclidean distance of the vectors in the features, which is a tf.Tensor got from the network.



I tried it in the following way, but failed with error:



'Tensor' object is not iterable


So I want to calculate the distance between the rows in one matrix just through matrix,without iteration of every rows.



features, _ = mnist_net(images)
feature_matrix = np.zeros(shape=(FLAGS.batch_size,FLAGS.batch_size))
for i in range (FLAGS.batch_size):
for j in range (FLAGS.batch_size):
aa = tf.slice(features,[i,0],[1,50])
bb = tf.slice(features,[j,0],[1,50])
feature_matrix[i,j] = tf.sqrt(sum((aa-bb)**2))






python tensorflow






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edited Nov 20 at 9:22









blue-phoenox

3,59681440




3,59681440










asked Nov 20 at 1:26









Bobo Xi

336




336












  • What have you tried so far? It is better to give some code and explain your attempt.
    – Banghua Zhao
    Nov 20 at 1:30










  • What do you mean by distance here? There are a lot of distance measures
    – user7374610
    Nov 20 at 2:37










  • I have fixed the question, can you help me solve it?@Banghua Zhao@user7374610
    – Bobo Xi
    Nov 20 at 4:00


















  • What have you tried so far? It is better to give some code and explain your attempt.
    – Banghua Zhao
    Nov 20 at 1:30










  • What do you mean by distance here? There are a lot of distance measures
    – user7374610
    Nov 20 at 2:37










  • I have fixed the question, can you help me solve it?@Banghua Zhao@user7374610
    – Bobo Xi
    Nov 20 at 4:00
















What have you tried so far? It is better to give some code and explain your attempt.
– Banghua Zhao
Nov 20 at 1:30




What have you tried so far? It is better to give some code and explain your attempt.
– Banghua Zhao
Nov 20 at 1:30












What do you mean by distance here? There are a lot of distance measures
– user7374610
Nov 20 at 2:37




What do you mean by distance here? There are a lot of distance measures
– user7374610
Nov 20 at 2:37












I have fixed the question, can you help me solve it?@Banghua Zhao@user7374610
– Bobo Xi
Nov 20 at 4:00




I have fixed the question, can you help me solve it?@Banghua Zhao@user7374610
– Bobo Xi
Nov 20 at 4:00












1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










You can achieve that simply with tf.norm/tf.linalg.norm:



feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)


For example:



import tensorflow as tf

with tf.Session() as sess:
features = tf.placeholder(tf.float32, [None, None])
feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)
print(sess.run(feature_matrix, feed_dict={features: [[ 1, 2, 3],
[ 4, 5, 6],
[ 7, 8, 9],
[10, 11, 12]]}))


Output:



[[ 0.        5.196152 10.392304 15.588457]
[ 5.196152 0. 5.196152 10.392304]
[10.392304 5.196152 0. 5.196152]
[15.588457 10.392304 5.196152 0. ]]




EDIT:



If you cannot use tf.norm, the following is an equivalent implementation:



sqdiff = tf.squared_difference(features[:, tf.newaxis], features)
feature_matrix = tf.sqrt(tf.reduce_sum(sqdiff, axis=-1))





share|improve this answer























  • I tried but it didn't work. The error is 'module 'tensorflow' has no attribute 'linalg'' , and the verion of Tensorflow is 1.0.1.
    – Bobo Xi
    Nov 20 at 10:22










  • @BoboXi Oh right, try with tf.norm ... 1.0.1 is pretty old though, I'm not sure if that is there either.
    – jdehesa
    Nov 20 at 10:24












  • @ jdehesa The later solution works, thank you very much!
    – Bobo Xi
    Nov 20 at 11:40










  • @BoboXi Glad it worked. Please considering marking the answer as accepted if you feel it solved your problem.
    – jdehesa
    Nov 20 at 12:41











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










You can achieve that simply with tf.norm/tf.linalg.norm:



feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)


For example:



import tensorflow as tf

with tf.Session() as sess:
features = tf.placeholder(tf.float32, [None, None])
feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)
print(sess.run(feature_matrix, feed_dict={features: [[ 1, 2, 3],
[ 4, 5, 6],
[ 7, 8, 9],
[10, 11, 12]]}))


Output:



[[ 0.        5.196152 10.392304 15.588457]
[ 5.196152 0. 5.196152 10.392304]
[10.392304 5.196152 0. 5.196152]
[15.588457 10.392304 5.196152 0. ]]




EDIT:



If you cannot use tf.norm, the following is an equivalent implementation:



sqdiff = tf.squared_difference(features[:, tf.newaxis], features)
feature_matrix = tf.sqrt(tf.reduce_sum(sqdiff, axis=-1))





share|improve this answer























  • I tried but it didn't work. The error is 'module 'tensorflow' has no attribute 'linalg'' , and the verion of Tensorflow is 1.0.1.
    – Bobo Xi
    Nov 20 at 10:22










  • @BoboXi Oh right, try with tf.norm ... 1.0.1 is pretty old though, I'm not sure if that is there either.
    – jdehesa
    Nov 20 at 10:24












  • @ jdehesa The later solution works, thank you very much!
    – Bobo Xi
    Nov 20 at 11:40










  • @BoboXi Glad it worked. Please considering marking the answer as accepted if you feel it solved your problem.
    – jdehesa
    Nov 20 at 12:41















up vote
2
down vote



accepted










You can achieve that simply with tf.norm/tf.linalg.norm:



feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)


For example:



import tensorflow as tf

with tf.Session() as sess:
features = tf.placeholder(tf.float32, [None, None])
feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)
print(sess.run(feature_matrix, feed_dict={features: [[ 1, 2, 3],
[ 4, 5, 6],
[ 7, 8, 9],
[10, 11, 12]]}))


Output:



[[ 0.        5.196152 10.392304 15.588457]
[ 5.196152 0. 5.196152 10.392304]
[10.392304 5.196152 0. 5.196152]
[15.588457 10.392304 5.196152 0. ]]




EDIT:



If you cannot use tf.norm, the following is an equivalent implementation:



sqdiff = tf.squared_difference(features[:, tf.newaxis], features)
feature_matrix = tf.sqrt(tf.reduce_sum(sqdiff, axis=-1))





share|improve this answer























  • I tried but it didn't work. The error is 'module 'tensorflow' has no attribute 'linalg'' , and the verion of Tensorflow is 1.0.1.
    – Bobo Xi
    Nov 20 at 10:22










  • @BoboXi Oh right, try with tf.norm ... 1.0.1 is pretty old though, I'm not sure if that is there either.
    – jdehesa
    Nov 20 at 10:24












  • @ jdehesa The later solution works, thank you very much!
    – Bobo Xi
    Nov 20 at 11:40










  • @BoboXi Glad it worked. Please considering marking the answer as accepted if you feel it solved your problem.
    – jdehesa
    Nov 20 at 12:41













up vote
2
down vote



accepted







up vote
2
down vote



accepted






You can achieve that simply with tf.norm/tf.linalg.norm:



feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)


For example:



import tensorflow as tf

with tf.Session() as sess:
features = tf.placeholder(tf.float32, [None, None])
feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)
print(sess.run(feature_matrix, feed_dict={features: [[ 1, 2, 3],
[ 4, 5, 6],
[ 7, 8, 9],
[10, 11, 12]]}))


Output:



[[ 0.        5.196152 10.392304 15.588457]
[ 5.196152 0. 5.196152 10.392304]
[10.392304 5.196152 0. 5.196152]
[15.588457 10.392304 5.196152 0. ]]




EDIT:



If you cannot use tf.norm, the following is an equivalent implementation:



sqdiff = tf.squared_difference(features[:, tf.newaxis], features)
feature_matrix = tf.sqrt(tf.reduce_sum(sqdiff, axis=-1))





share|improve this answer














You can achieve that simply with tf.norm/tf.linalg.norm:



feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)


For example:



import tensorflow as tf

with tf.Session() as sess:
features = tf.placeholder(tf.float32, [None, None])
feature_matrix = tf.linalg.norm(features[:, tf.newaxis] - features, axis=-1)
print(sess.run(feature_matrix, feed_dict={features: [[ 1, 2, 3],
[ 4, 5, 6],
[ 7, 8, 9],
[10, 11, 12]]}))


Output:



[[ 0.        5.196152 10.392304 15.588457]
[ 5.196152 0. 5.196152 10.392304]
[10.392304 5.196152 0. 5.196152]
[15.588457 10.392304 5.196152 0. ]]




EDIT:



If you cannot use tf.norm, the following is an equivalent implementation:



sqdiff = tf.squared_difference(features[:, tf.newaxis], features)
feature_matrix = tf.sqrt(tf.reduce_sum(sqdiff, axis=-1))






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 20 at 10:33

























answered Nov 20 at 10:14









jdehesa

21.8k43150




21.8k43150












  • I tried but it didn't work. The error is 'module 'tensorflow' has no attribute 'linalg'' , and the verion of Tensorflow is 1.0.1.
    – Bobo Xi
    Nov 20 at 10:22










  • @BoboXi Oh right, try with tf.norm ... 1.0.1 is pretty old though, I'm not sure if that is there either.
    – jdehesa
    Nov 20 at 10:24












  • @ jdehesa The later solution works, thank you very much!
    – Bobo Xi
    Nov 20 at 11:40










  • @BoboXi Glad it worked. Please considering marking the answer as accepted if you feel it solved your problem.
    – jdehesa
    Nov 20 at 12:41


















  • I tried but it didn't work. The error is 'module 'tensorflow' has no attribute 'linalg'' , and the verion of Tensorflow is 1.0.1.
    – Bobo Xi
    Nov 20 at 10:22










  • @BoboXi Oh right, try with tf.norm ... 1.0.1 is pretty old though, I'm not sure if that is there either.
    – jdehesa
    Nov 20 at 10:24












  • @ jdehesa The later solution works, thank you very much!
    – Bobo Xi
    Nov 20 at 11:40










  • @BoboXi Glad it worked. Please considering marking the answer as accepted if you feel it solved your problem.
    – jdehesa
    Nov 20 at 12:41
















I tried but it didn't work. The error is 'module 'tensorflow' has no attribute 'linalg'' , and the verion of Tensorflow is 1.0.1.
– Bobo Xi
Nov 20 at 10:22




I tried but it didn't work. The error is 'module 'tensorflow' has no attribute 'linalg'' , and the verion of Tensorflow is 1.0.1.
– Bobo Xi
Nov 20 at 10:22












@BoboXi Oh right, try with tf.norm ... 1.0.1 is pretty old though, I'm not sure if that is there either.
– jdehesa
Nov 20 at 10:24






@BoboXi Oh right, try with tf.norm ... 1.0.1 is pretty old though, I'm not sure if that is there either.
– jdehesa
Nov 20 at 10:24














@ jdehesa The later solution works, thank you very much!
– Bobo Xi
Nov 20 at 11:40




@ jdehesa The later solution works, thank you very much!
– Bobo Xi
Nov 20 at 11:40












@BoboXi Glad it worked. Please considering marking the answer as accepted if you feel it solved your problem.
– jdehesa
Nov 20 at 12:41




@BoboXi Glad it worked. Please considering marking the answer as accepted if you feel it solved your problem.
– jdehesa
Nov 20 at 12:41


















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