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How do I use array as argument in recursion?

The procedure

void divide(int arr, int i, int j, int max, int min){

//Deklarasi

int min1, min2, max1, max2, k;//Algoritma

//1 Elemen

if(i == j){

    min = arr[i];

    max = arr[i];

}

else{

    //2 Elemen

    if(i == j-1){

        if (arr[i] > arr[j]){

            max = arr[i];

            min = arr[j];

        }

        else{

            max = arr[j];

            min = arr[i];

        }

    }

    //>2 Elemen

    else{

        k = (i+j)/2;

        divide(arr[j],i,k,max1,min1);

        divide(arr[j],k+1,j,max2,min2);

        min = (min1>min2) ? (min2) : (min1);

        max = (max1>max2) ? (max1) : (max2);

    }

}

}

The main

int main(){

int i,j,min,max,x;

i = 1;

scanf("%d",&j);



//Input the array

int arr[j];

for(x=0;x<j;x++){

    scanf("%d",&arr[x]);

}

divide(arr[j],i,j,max,min);

printf("%d %d", min, max);

}

when I execute the code, I can input the size and the array, but the program can't run(error)

Please help me, how do I pass array in a function?

When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.