I have this issue with script: TypeError: 'FirefoxWebElement' object is not iterable
I am having a problem executing this script:
pic_hrefs = [elem.get_attribute('a href') for elem in hrefs]
Traceback (most recent call last):
File "IB.py", line 56, in <module>
kidCudix.like_photo('comfort')
File "IB.py", line 41, in like_photo
pic_hrefs = [elem.get_attribute('a href') for elem in hrefs]
TypeError: 'FirefoxWebElement' object is not iterable
python selenium object iterable
edited Nov 25 '18 at 14:10
Guy
19.3k72250
asked Nov 25 '18 at 14:06
licensedelicensede
83
add a comment |
I am having a problem executing this script:
pic_hrefs = [elem.get_attribute('a href') for elem in hrefs]
Traceback (most recent call last):
File "IB.py", line 56, in <module>
kidCudix.like_photo('comfort')
File "IB.py", line 41, in like_photo
pic_hrefs = [elem.get_attribute('a href') for elem in hrefs]
TypeError: 'FirefoxWebElement' object is not iterable
python selenium object iterable
edited Nov 25 '18 at 14:10
Guy
19.3k72250
asked Nov 25 '18 at 14:06
licensedelicensede
83
2
You haven't shown whathrefsis
– roganjosh
Nov 25 '18 at 14:08
1
get_attributereturn single string, you can't iterate over it. Not to mention in your case it will returnNone, there is no attributea href. Tryhref.
– Guy
Nov 25 '18 at 14:12
@Guy, it's true that the attribute is incorrect and will cause an error, but that's not the error he is hitting (yet). The OP is not trying to iterate over the result ofget_attribute.
– Corey Goldberg
Nov 25 '18 at 17:22
1
@Guy, nope, it would iterate overhrefsand applyget_attrbuteto each element
– Corey Goldberg
Nov 25 '18 at 19:15
add a comment |
I am having a problem executing this script:
pic_hrefs = [elem.get_attribute('a href') for elem in hrefs]
Traceback (most recent call last):
File "IB.py", line 56, in <module>
kidCudix.like_photo('comfort')
File "IB.py", line 41, in like_photo
pic_hrefs = [elem.get_attribute('a href') for elem in hrefs]
TypeError: 'FirefoxWebElement' object is not iterable
python selenium object iterable
edited Nov 25 '18 at 14:10
Guy
19.3k72250
asked Nov 25 '18 at 14:06
licensedelicensede
83
I am having a problem executing this script:
pic_hrefs = [elem.get_attribute('a href') for elem in hrefs]
Traceback (most recent call last):
File "IB.py", line 56, in <module>
kidCudix.like_photo('comfort')
File "IB.py", line 41, in like_photo
pic_hrefs = [elem.get_attribute('a href') for elem in hrefs]
TypeError: 'FirefoxWebElement' object is not iterable
python selenium object iterable
python selenium object iterable
edited Nov 25 '18 at 14:10
Guy
19.3k72250
asked Nov 25 '18 at 14:06
licensedelicensede
83
edited Nov 25 '18 at 14:10
Guy
19.3k72250
asked Nov 25 '18 at 14:06
licensedelicensede
83
edited Nov 25 '18 at 14:10
Guy
19.3k72250
edited Nov 25 '18 at 14:10
Guy
19.3k72250
edited Nov 25 '18 at 14:10
Guy
19.3k72250
19.3k72250
asked Nov 25 '18 at 14:06
licensedelicensede
83
asked Nov 25 '18 at 14:06
licensedelicensede
83
asked Nov 25 '18 at 14:06
licensedelicensede
83
83
2
You haven't shown whathrefsis
– roganjosh
Nov 25 '18 at 14:08
1
get_attributereturn single string, you can't iterate over it. Not to mention in your case it will returnNone, there is no attributea href. Tryhref.
– Guy
Nov 25 '18 at 14:12
@Guy, it's true that the attribute is incorrect and will cause an error, but that's not the error he is hitting (yet). The OP is not trying to iterate over the result ofget_attribute.
– Corey Goldberg
Nov 25 '18 at 17:22
1
@Guy, nope, it would iterate overhrefsand applyget_attrbuteto each element
– Corey Goldberg
Nov 25 '18 at 19:15
add a comment |
2
You haven't shown whathrefsis
– roganjosh
Nov 25 '18 at 14:08
1
get_attributereturn single string, you can't iterate over it. Not to mention in your case it will returnNone, there is no attributea href. Tryhref.
– Guy
Nov 25 '18 at 14:12
@Guy, it's true that the attribute is incorrect and will cause an error, but that's not the error he is hitting (yet). The OP is not trying to iterate over the result ofget_attribute.
– Corey Goldberg
Nov 25 '18 at 17:22
1
@Guy, nope, it would iterate overhrefsand applyget_attrbuteto each element
– Corey Goldberg
Nov 25 '18 at 19:15
2
2
You haven't shown what
hrefs is– roganjosh
Nov 25 '18 at 14:08
You haven't shown what
hrefs is– roganjosh
Nov 25 '18 at 14:08
1
1
get_attribute return single string, you can't iterate over it. Not to mention in your case it will return None, there is no attribute a href. Try href.– Guy
Nov 25 '18 at 14:12
get_attribute return single string, you can't iterate over it. Not to mention in your case it will return None, there is no attribute a href. Try href.– Guy
Nov 25 '18 at 14:12
@Guy, it's true that the attribute is incorrect and will cause an error, but that's not the error he is hitting (yet). The OP is not trying to iterate over the result of
get_attribute.– Corey Goldberg
Nov 25 '18 at 17:22
@Guy, it's true that the attribute is incorrect and will cause an error, but that's not the error he is hitting (yet). The OP is not trying to iterate over the result of
get_attribute.– Corey Goldberg
Nov 25 '18 at 17:22
1
1
@Guy, nope, it would iterate over
hrefs and apply get_attrbute to each element– Corey Goldberg
Nov 25 '18 at 19:15
@Guy, nope, it would iterate over
hrefs and apply get_attrbute to each element– Corey Goldberg
Nov 25 '18 at 19:15
add a comment |
1 Answer
1
active
oldest
votes
Firstly, elem.get_attribute('a href') is problematic since 'a href' is not a valid attribute. Instead, you want to use elem.get_attribute('href').
However, that's not the error you are hitting.
The error message (TypeError: 'FirefoxWebElement' object is not iterable) implies that your input iterable (hrefs) is of the type FirefoxWebElement, which can't be used with a list comprehension since a single FirefoxWebElement is not iterable. Instead of a single element, you need to use a list of elements in your list comprehension. (A list comprehension creates a list from another input iterable). Your comprehension should be something like:
hrefs = [elem.get_attribute('href') for elem in elements]
Example:
The question is vague, but you are likely trying to create a list of links on a web page. To get a list of all links, the general pattern is:
- create a webdriver
- navigate to a page
- locate all elements that represent anchor tags
- extract the
hrefattribute from each element and store them in a list
You could do that with code like:
from selenium import webdriver
driver = webdriver.Firefox()
driver.get('https://some_url')
elements = driver.find_elements_by_tag_name('a')
hrefs = [elem.get_attribute('href') for elem in elements]
Notice that find_elements_by_tag_name('a') returns a list of WebElement, which I use in the subsequent list comprehension. Also notice that the method used is find_elements_by_tag_name (plural). This differs from find_element_by_tag_name (singular) which would only locate a single element.
answered Nov 25 '18 at 17:21
Corey GoldbergCorey Goldberg
37.8k22110125
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Firstly, elem.get_attribute('a href') is problematic since 'a href' is not a valid attribute. Instead, you want to use elem.get_attribute('href').
However, that's not the error you are hitting.
The error message (TypeError: 'FirefoxWebElement' object is not iterable) implies that your input iterable (hrefs) is of the type FirefoxWebElement, which can't be used with a list comprehension since a single FirefoxWebElement is not iterable. Instead of a single element, you need to use a list of elements in your list comprehension. (A list comprehension creates a list from another input iterable). Your comprehension should be something like:
hrefs = [elem.get_attribute('href') for elem in elements]
Example:
The question is vague, but you are likely trying to create a list of links on a web page. To get a list of all links, the general pattern is:
- create a webdriver
- navigate to a page
- locate all elements that represent anchor tags
- extract the
hrefattribute from each element and store them in a list
You could do that with code like:
from selenium import webdriver
driver = webdriver.Firefox()
driver.get('https://some_url')
elements = driver.find_elements_by_tag_name('a')
hrefs = [elem.get_attribute('href') for elem in elements]
Notice that find_elements_by_tag_name('a') returns a list of WebElement, which I use in the subsequent list comprehension. Also notice that the method used is find_elements_by_tag_name (plural). This differs from find_element_by_tag_name (singular) which would only locate a single element.
answered Nov 25 '18 at 17:21
Corey GoldbergCorey Goldberg
37.8k22110125
add a comment |
Firstly, elem.get_attribute('a href') is problematic since 'a href' is not a valid attribute. Instead, you want to use elem.get_attribute('href').
However, that's not the error you are hitting.
The error message (TypeError: 'FirefoxWebElement' object is not iterable) implies that your input iterable (hrefs) is of the type FirefoxWebElement, which can't be used with a list comprehension since a single FirefoxWebElement is not iterable. Instead of a single element, you need to use a list of elements in your list comprehension. (A list comprehension creates a list from another input iterable). Your comprehension should be something like:
hrefs = [elem.get_attribute('href') for elem in elements]
Example:
The question is vague, but you are likely trying to create a list of links on a web page. To get a list of all links, the general pattern is:
- create a webdriver
- navigate to a page
- locate all elements that represent anchor tags
- extract the
hrefattribute from each element and store them in a list
You could do that with code like:
from selenium import webdriver
driver = webdriver.Firefox()
driver.get('https://some_url')
elements = driver.find_elements_by_tag_name('a')
hrefs = [elem.get_attribute('href') for elem in elements]
Notice that find_elements_by_tag_name('a') returns a list of WebElement, which I use in the subsequent list comprehension. Also notice that the method used is find_elements_by_tag_name (plural). This differs from find_element_by_tag_name (singular) which would only locate a single element.
answered Nov 25 '18 at 17:21
Corey GoldbergCorey Goldberg
37.8k22110125
add a comment |
Firstly, elem.get_attribute('a href') is problematic since 'a href' is not a valid attribute. Instead, you want to use elem.get_attribute('href').
However, that's not the error you are hitting.
The error message (TypeError: 'FirefoxWebElement' object is not iterable) implies that your input iterable (hrefs) is of the type FirefoxWebElement, which can't be used with a list comprehension since a single FirefoxWebElement is not iterable. Instead of a single element, you need to use a list of elements in your list comprehension. (A list comprehension creates a list from another input iterable). Your comprehension should be something like:
hrefs = [elem.get_attribute('href') for elem in elements]
Example:
The question is vague, but you are likely trying to create a list of links on a web page. To get a list of all links, the general pattern is:
- create a webdriver
- navigate to a page
- locate all elements that represent anchor tags
- extract the
hrefattribute from each element and store them in a list
You could do that with code like:
from selenium import webdriver
driver = webdriver.Firefox()
driver.get('https://some_url')
elements = driver.find_elements_by_tag_name('a')
hrefs = [elem.get_attribute('href') for elem in elements]
Notice that find_elements_by_tag_name('a') returns a list of WebElement, which I use in the subsequent list comprehension. Also notice that the method used is find_elements_by_tag_name (plural). This differs from find_element_by_tag_name (singular) which would only locate a single element.
answered Nov 25 '18 at 17:21
Corey GoldbergCorey Goldberg
37.8k22110125
Firstly, elem.get_attribute('a href') is problematic since 'a href' is not a valid attribute. Instead, you want to use elem.get_attribute('href').
However, that's not the error you are hitting.
The error message (TypeError: 'FirefoxWebElement' object is not iterable) implies that your input iterable (hrefs) is of the type FirefoxWebElement, which can't be used with a list comprehension since a single FirefoxWebElement is not iterable. Instead of a single element, you need to use a list of elements in your list comprehension. (A list comprehension creates a list from another input iterable). Your comprehension should be something like:
hrefs = [elem.get_attribute('href') for elem in elements]
Example:
The question is vague, but you are likely trying to create a list of links on a web page. To get a list of all links, the general pattern is:
- create a webdriver
- navigate to a page
- locate all elements that represent anchor tags
- extract the
hrefattribute from each element and store them in a list
You could do that with code like:
from selenium import webdriver
driver = webdriver.Firefox()
driver.get('https://some_url')
elements = driver.find_elements_by_tag_name('a')
hrefs = [elem.get_attribute('href') for elem in elements]
Notice that find_elements_by_tag_name('a') returns a list of WebElement, which I use in the subsequent list comprehension. Also notice that the method used is find_elements_by_tag_name (plural). This differs from find_element_by_tag_name (singular) which would only locate a single element.
answered Nov 25 '18 at 17:21
Corey GoldbergCorey Goldberg
37.8k22110125
edited Nov 26 '18 at 18:26
answered Nov 25 '18 at 17:21
Corey GoldbergCorey Goldberg
37.8k22110125
answered Nov 25 '18 at 17:21
Corey GoldbergCorey Goldberg
37.8k22110125
answered Nov 25 '18 at 17:21
Corey GoldbergCorey Goldberg
37.8k22110125
37.8k22110125
add a comment |
add a comment |
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2
You haven't shown what
hrefsis– roganjosh
Nov 25 '18 at 14:08
1
get_attributereturn single string, you can't iterate over it. Not to mention in your case it will returnNone, there is no attributea href. Tryhref.– Guy
Nov 25 '18 at 14:12
@Guy, it's true that the attribute is incorrect and will cause an error, but that's not the error he is hitting (yet). The OP is not trying to iterate over the result of
get_attribute.– Corey Goldberg
Nov 25 '18 at 17:22
1
@Guy, nope, it would iterate over
hrefsand applyget_attrbuteto each element– Corey Goldberg
Nov 25 '18 at 19:15