What's golang's equivalent to PHP/Ruby's unpack(“C*”, . )?
Been searching around, still new to golang, PHP and ruby have an unpack function that unpacks a binary into an array. I'm trying to figure out how to do the following in golang.
$test = "1023";
print_r(unpack("C*", $test)); // [1,0,2,3]
Or
s = "1023"
arr = s.unpack("C*")
p(arr) # [1,0,2,3]
What's the best approach to doing this using golang?
go
edited Nov 25 '18 at 21:08
Peter O.
21k95969
asked Nov 25 '18 at 13:49
extsexts
7,46631116
add a comment |
Been searching around, still new to golang, PHP and ruby have an unpack function that unpacks a binary into an array. I'm trying to figure out how to do the following in golang.
$test = "1023";
print_r(unpack("C*", $test)); // [1,0,2,3]
Or
s = "1023"
arr = s.unpack("C*")
p(arr) # [1,0,2,3]
What's the best approach to doing this using golang?
go
edited Nov 25 '18 at 21:08
Peter O.
21k95969
asked Nov 25 '18 at 13:49
extsexts
7,46631116
add a comment |
Been searching around, still new to golang, PHP and ruby have an unpack function that unpacks a binary into an array. I'm trying to figure out how to do the following in golang.
$test = "1023";
print_r(unpack("C*", $test)); // [1,0,2,3]
Or
s = "1023"
arr = s.unpack("C*")
p(arr) # [1,0,2,3]
What's the best approach to doing this using golang?
go
edited Nov 25 '18 at 21:08
Peter O.
21k95969
asked Nov 25 '18 at 13:49
extsexts
7,46631116
Been searching around, still new to golang, PHP and ruby have an unpack function that unpacks a binary into an array. I'm trying to figure out how to do the following in golang.
$test = "1023";
print_r(unpack("C*", $test)); // [1,0,2,3]
Or
s = "1023"
arr = s.unpack("C*")
p(arr) # [1,0,2,3]
What's the best approach to doing this using golang?
go
go
edited Nov 25 '18 at 21:08
Peter O.
21k95969
asked Nov 25 '18 at 13:49
extsexts
7,46631116
edited Nov 25 '18 at 21:08
Peter O.
21k95969
asked Nov 25 '18 at 13:49
extsexts
7,46631116
edited Nov 25 '18 at 21:08
Peter O.
21k95969
edited Nov 25 '18 at 21:08
Peter O.
21k95969
edited Nov 25 '18 at 21:08
Peter O.
21k95969
21k95969
asked Nov 25 '18 at 13:49
extsexts
7,46631116
asked Nov 25 '18 at 13:49
extsexts
7,46631116
asked Nov 25 '18 at 13:49
extsexts
7,46631116
7,46631116
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Please note first that your PHP string of "1023" is a string consisting of the 4 bytes x01,x00, x02, x03 since the "1" are interpreted as octal. See the documentation for double quoted strings for details.
In Go the syntax 1 is not correct. As in C an octal sequence is required to have 3 digits, i.e. 01. Thus, the PHP string "1023" is in Go "01000203" (which would also work in PHP). With this in mind unpacking is easy and no special function like unpack is needed for this:
package main
import "fmt"
func main() {
s := "01000203"
b := byte(s)
fmt.Print(b)
}
Output:
[1 0 2 3]
answered Nov 25 '18 at 14:01
Steffen UllrichSteffen Ullrich
62k359100
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Please note first that your PHP string of "1023" is a string consisting of the 4 bytes x01,x00, x02, x03 since the "1" are interpreted as octal. See the documentation for double quoted strings for details.
In Go the syntax 1 is not correct. As in C an octal sequence is required to have 3 digits, i.e. 01. Thus, the PHP string "1023" is in Go "01000203" (which would also work in PHP). With this in mind unpacking is easy and no special function like unpack is needed for this:
package main
import "fmt"
func main() {
s := "01000203"
b := byte(s)
fmt.Print(b)
}
Output:
[1 0 2 3]
answered Nov 25 '18 at 14:01
Steffen UllrichSteffen Ullrich
62k359100
add a comment |
Please note first that your PHP string of "1023" is a string consisting of the 4 bytes x01,x00, x02, x03 since the "1" are interpreted as octal. See the documentation for double quoted strings for details.
In Go the syntax 1 is not correct. As in C an octal sequence is required to have 3 digits, i.e. 01. Thus, the PHP string "1023" is in Go "01000203" (which would also work in PHP). With this in mind unpacking is easy and no special function like unpack is needed for this:
package main
import "fmt"
func main() {
s := "01000203"
b := byte(s)
fmt.Print(b)
}
Output:
[1 0 2 3]
answered Nov 25 '18 at 14:01
Steffen UllrichSteffen Ullrich
62k359100
add a comment |
Please note first that your PHP string of "1023" is a string consisting of the 4 bytes x01,x00, x02, x03 since the "1" are interpreted as octal. See the documentation for double quoted strings for details.
In Go the syntax 1 is not correct. As in C an octal sequence is required to have 3 digits, i.e. 01. Thus, the PHP string "1023" is in Go "01000203" (which would also work in PHP). With this in mind unpacking is easy and no special function like unpack is needed for this:
package main
import "fmt"
func main() {
s := "01000203"
b := byte(s)
fmt.Print(b)
}
Output:
[1 0 2 3]
answered Nov 25 '18 at 14:01
Steffen UllrichSteffen Ullrich
62k359100
Please note first that your PHP string of "1023" is a string consisting of the 4 bytes x01,x00, x02, x03 since the "1" are interpreted as octal. See the documentation for double quoted strings for details.
In Go the syntax 1 is not correct. As in C an octal sequence is required to have 3 digits, i.e. 01. Thus, the PHP string "1023" is in Go "01000203" (which would also work in PHP). With this in mind unpacking is easy and no special function like unpack is needed for this:
package main
import "fmt"
func main() {
s := "01000203"
b := byte(s)
fmt.Print(b)
}
Output:
[1 0 2 3]
answered Nov 25 '18 at 14:01
Steffen UllrichSteffen Ullrich
62k359100
edited Nov 25 '18 at 14:26
answered Nov 25 '18 at 14:01
Steffen UllrichSteffen Ullrich
62k359100
answered Nov 25 '18 at 14:01
Steffen UllrichSteffen Ullrich
62k359100
answered Nov 25 '18 at 14:01
Steffen UllrichSteffen Ullrich
62k359100
62k359100
add a comment |
add a comment |
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