How to convert continous data to Categorical in python?
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All,
My dataset looks like following, and I Would like to add one column which can convert my last column i.e Day_of_The_week to Mon, Tue, Wed.
Note: Day_of_the_week include 5 days : Mon,Tue,Wed,Thurs,Fri. I checked link but couldn't figure out how to implement in my dataframe
I would like to convert my pandas dataframe as below:
Being a newbie to python,if you could provide explanation, that will be great!
python pandas numeric categorical-data continuous
asked Nov 26 '18 at 23:50
biggboss2019biggboss2019
9919
add a comment |
0
All,
My dataset looks like following, and I Would like to add one column which can convert my last column i.e Day_of_The_week to Mon, Tue, Wed.
Note: Day_of_the_week include 5 days : Mon,Tue,Wed,Thurs,Fri. I checked link but couldn't figure out how to implement in my dataframe
I would like to convert my pandas dataframe as below:
Being a newbie to python,if you could provide explanation, that will be great!
python pandas numeric categorical-data continuous
asked Nov 26 '18 at 23:50
biggboss2019biggboss2019
9919
add a comment |
0
0
0
All,
My dataset looks like following, and I Would like to add one column which can convert my last column i.e Day_of_The_week to Mon, Tue, Wed.
Note: Day_of_the_week include 5 days : Mon,Tue,Wed,Thurs,Fri. I checked link but couldn't figure out how to implement in my dataframe
I would like to convert my pandas dataframe as below:
Being a newbie to python,if you could provide explanation, that will be great!
python pandas numeric categorical-data continuous
asked Nov 26 '18 at 23:50
biggboss2019biggboss2019
9919
All,
My dataset looks like following, and I Would like to add one column which can convert my last column i.e Day_of_The_week to Mon, Tue, Wed.
Note: Day_of_the_week include 5 days : Mon,Tue,Wed,Thurs,Fri. I checked link but couldn't figure out how to implement in my dataframe
I would like to convert my pandas dataframe as below:
Being a newbie to python,if you could provide explanation, that will be great!
python pandas numeric categorical-data continuous
python pandas numeric categorical-data continuous
asked Nov 26 '18 at 23:50
biggboss2019biggboss2019
9919
asked Nov 26 '18 at 23:50
biggboss2019biggboss2019
9919
asked Nov 26 '18 at 23:50
biggboss2019biggboss2019
9919
asked Nov 26 '18 at 23:50
biggboss2019biggboss2019
9919
asked Nov 26 '18 at 23:50
biggboss2019biggboss2019
9919
9919
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
calendar.day_name + pd.Series.map
You can construct a dictionary and then map your integer series to a list of day strings:
import pandas as pd
from calendar import day_name
from collections import deque
df = pd.DataFrame({'Day_of_the_week': [2, 3, 4, 4, 5, 6, 6]})
days = deque(day_name)
days.rotate(df['Day_of_the_week'].iat[0]) # rotate days
days_map = dict(enumerate(days)) # construct dictionary
df['Day_Factor'] = df['Day_of_the_week'].map(days_map)
print(df)
Day_of_the_week Day_Factor
0 2 Monday
1 3 Tuesday
2 4 Wednesday
3 4 Wednesday
4 5 Thursday
5 6 Friday
6 6 Friday
answered Nov 26 '18 at 23:56
jppjpp
103k2167117
Thanks! The dictionary key's assigned 0 to Friday. I would like to assign key 6 to Friday. Is there a way to do that ? I would like my dictionary to start with 2 as Monday and ends at Key 6- Friday.
– biggboss2019
Nov 27 '18 at 0:13
@biggboss2019, Yes, as you can see that's what my logic does, you are rotating days by 2 days. Since theday_namehas Monday at index 0, but you want it at index 2. To hardcode this, use2instead ofdf['Day_of_the_week'].iat[0].
– jpp
Nov 27 '18 at 0:16
1
Great. Thanks!!
– biggboss2019
Nov 27 '18 at 0:23
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
calendar.day_name + pd.Series.map
You can construct a dictionary and then map your integer series to a list of day strings:
import pandas as pd
from calendar import day_name
from collections import deque
df = pd.DataFrame({'Day_of_the_week': [2, 3, 4, 4, 5, 6, 6]})
days = deque(day_name)
days.rotate(df['Day_of_the_week'].iat[0]) # rotate days
days_map = dict(enumerate(days)) # construct dictionary
df['Day_Factor'] = df['Day_of_the_week'].map(days_map)
print(df)
Day_of_the_week Day_Factor
0 2 Monday
1 3 Tuesday
2 4 Wednesday
3 4 Wednesday
4 5 Thursday
5 6 Friday
6 6 Friday
answered Nov 26 '18 at 23:56
jppjpp
103k2167117
Thanks! The dictionary key's assigned 0 to Friday. I would like to assign key 6 to Friday. Is there a way to do that ? I would like my dictionary to start with 2 as Monday and ends at Key 6- Friday.
– biggboss2019
Nov 27 '18 at 0:13
@biggboss2019, Yes, as you can see that's what my logic does, you are rotating days by 2 days. Since theday_namehas Monday at index 0, but you want it at index 2. To hardcode this, use2instead ofdf['Day_of_the_week'].iat[0].
– jpp
Nov 27 '18 at 0:16
1
Great. Thanks!!
– biggboss2019
Nov 27 '18 at 0:23
add a comment |
1
calendar.day_name + pd.Series.map
You can construct a dictionary and then map your integer series to a list of day strings:
import pandas as pd
from calendar import day_name
from collections import deque
df = pd.DataFrame({'Day_of_the_week': [2, 3, 4, 4, 5, 6, 6]})
days = deque(day_name)
days.rotate(df['Day_of_the_week'].iat[0]) # rotate days
days_map = dict(enumerate(days)) # construct dictionary
df['Day_Factor'] = df['Day_of_the_week'].map(days_map)
print(df)
Day_of_the_week Day_Factor
0 2 Monday
1 3 Tuesday
2 4 Wednesday
3 4 Wednesday
4 5 Thursday
5 6 Friday
6 6 Friday
answered Nov 26 '18 at 23:56
jppjpp
103k2167117
Thanks! The dictionary key's assigned 0 to Friday. I would like to assign key 6 to Friday. Is there a way to do that ? I would like my dictionary to start with 2 as Monday and ends at Key 6- Friday.
– biggboss2019
Nov 27 '18 at 0:13
@biggboss2019, Yes, as you can see that's what my logic does, you are rotating days by 2 days. Since theday_namehas Monday at index 0, but you want it at index 2. To hardcode this, use2instead ofdf['Day_of_the_week'].iat[0].
– jpp
Nov 27 '18 at 0:16
1
Great. Thanks!!
– biggboss2019
Nov 27 '18 at 0:23
add a comment |
1
1
1
calendar.day_name + pd.Series.map
You can construct a dictionary and then map your integer series to a list of day strings:
import pandas as pd
from calendar import day_name
from collections import deque
df = pd.DataFrame({'Day_of_the_week': [2, 3, 4, 4, 5, 6, 6]})
days = deque(day_name)
days.rotate(df['Day_of_the_week'].iat[0]) # rotate days
days_map = dict(enumerate(days)) # construct dictionary
df['Day_Factor'] = df['Day_of_the_week'].map(days_map)
print(df)
Day_of_the_week Day_Factor
0 2 Monday
1 3 Tuesday
2 4 Wednesday
3 4 Wednesday
4 5 Thursday
5 6 Friday
6 6 Friday
answered Nov 26 '18 at 23:56
jppjpp
103k2167117
calendar.day_name + pd.Series.map
You can construct a dictionary and then map your integer series to a list of day strings:
import pandas as pd
from calendar import day_name
from collections import deque
df = pd.DataFrame({'Day_of_the_week': [2, 3, 4, 4, 5, 6, 6]})
days = deque(day_name)
days.rotate(df['Day_of_the_week'].iat[0]) # rotate days
days_map = dict(enumerate(days)) # construct dictionary
df['Day_Factor'] = df['Day_of_the_week'].map(days_map)
print(df)
Day_of_the_week Day_Factor
0 2 Monday
1 3 Tuesday
2 4 Wednesday
3 4 Wednesday
4 5 Thursday
5 6 Friday
6 6 Friday
answered Nov 26 '18 at 23:56
jppjpp
103k2167117
answered Nov 26 '18 at 23:56
jppjpp
103k2167117
answered Nov 26 '18 at 23:56
jppjpp
103k2167117
answered Nov 26 '18 at 23:56
jppjpp
103k2167117
103k2167117
Thanks! The dictionary key's assigned 0 to Friday. I would like to assign key 6 to Friday. Is there a way to do that ? I would like my dictionary to start with 2 as Monday and ends at Key 6- Friday.
– biggboss2019
Nov 27 '18 at 0:13
@biggboss2019, Yes, as you can see that's what my logic does, you are rotating days by 2 days. Since theday_namehas Monday at index 0, but you want it at index 2. To hardcode this, use2instead ofdf['Day_of_the_week'].iat[0].
– jpp
Nov 27 '18 at 0:16
1
Great. Thanks!!
– biggboss2019
Nov 27 '18 at 0:23
add a comment |
Thanks! The dictionary key's assigned 0 to Friday. I would like to assign key 6 to Friday. Is there a way to do that ? I would like my dictionary to start with 2 as Monday and ends at Key 6- Friday.
– biggboss2019
Nov 27 '18 at 0:13
@biggboss2019, Yes, as you can see that's what my logic does, you are rotating days by 2 days. Since theday_namehas Monday at index 0, but you want it at index 2. To hardcode this, use2instead ofdf['Day_of_the_week'].iat[0].
– jpp
Nov 27 '18 at 0:16
1
Great. Thanks!!
– biggboss2019
Nov 27 '18 at 0:23
Thanks! The dictionary key's assigned 0 to Friday. I would like to assign key 6 to Friday. Is there a way to do that ? I would like my dictionary to start with 2 as Monday and ends at Key 6- Friday.
– biggboss2019
Nov 27 '18 at 0:13
Thanks! The dictionary key's assigned 0 to Friday. I would like to assign key 6 to Friday. Is there a way to do that ? I would like my dictionary to start with 2 as Monday and ends at Key 6- Friday.
– biggboss2019
Nov 27 '18 at 0:13
@biggboss2019, Yes, as you can see that's what my logic does, you are rotating days by 2 days. Since the
day_name has Monday at index 0, but you want it at index 2. To hardcode this, use 2 instead of df['Day_of_the_week'].iat[0].– jpp
Nov 27 '18 at 0:16
@biggboss2019, Yes, as you can see that's what my logic does, you are rotating days by 2 days. Since the
day_name has Monday at index 0, but you want it at index 2. To hardcode this, use 2 instead of df['Day_of_the_week'].iat[0].– jpp
Nov 27 '18 at 0:16
1
1
Great. Thanks!!
– biggboss2019
Nov 27 '18 at 0:23
Great. Thanks!!
– biggboss2019
Nov 27 '18 at 0:23
add a comment |
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