Deleting blank pages based on size in Adobe with javascript





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I am trying to delete the blank pages based on size. If it is less than the amount specified the page will be deleted. I keep getting syntax error with this. I looked all over for something similar but cannot find anything.



<script>
for (var p=this.pageSize-1; p>=0; p--) {
if (this.pageSize-1);
for (var n='8kb'; n<this.pageSize-1; n++) {
if (this.pageSize(p, n) = '8kb') {
this.deletePages(p); `enter code here`
break;
}
}
}
</script>









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  • if (this.pageSize-1); and (var n='8kb'; n<this.pageSize-1; n++) and (this.pageSize(p, n) = '8kb') are 3 places to start...

    – Stuart Siegler
    Nov 26 '18 at 21:04




















0















I am trying to delete the blank pages based on size. If it is less than the amount specified the page will be deleted. I keep getting syntax error with this. I looked all over for something similar but cannot find anything.



<script>
for (var p=this.pageSize-1; p>=0; p--) {
if (this.pageSize-1);
for (var n='8kb'; n<this.pageSize-1; n++) {
if (this.pageSize(p, n) = '8kb') {
this.deletePages(p); `enter code here`
break;
}
}
}
</script>









share|improve this question

























  • if (this.pageSize-1); and (var n='8kb'; n<this.pageSize-1; n++) and (this.pageSize(p, n) = '8kb') are 3 places to start...

    – Stuart Siegler
    Nov 26 '18 at 21:04
















0












0








0








I am trying to delete the blank pages based on size. If it is less than the amount specified the page will be deleted. I keep getting syntax error with this. I looked all over for something similar but cannot find anything.



<script>
for (var p=this.pageSize-1; p>=0; p--) {
if (this.pageSize-1);
for (var n='8kb'; n<this.pageSize-1; n++) {
if (this.pageSize(p, n) = '8kb') {
this.deletePages(p); `enter code here`
break;
}
}
}
</script>









share|improve this question
















I am trying to delete the blank pages based on size. If it is less than the amount specified the page will be deleted. I keep getting syntax error with this. I looked all over for something similar but cannot find anything.



<script>
for (var p=this.pageSize-1; p>=0; p--) {
if (this.pageSize-1);
for (var n='8kb'; n<this.pageSize-1; n++) {
if (this.pageSize(p, n) = '8kb') {
this.deletePages(p); `enter code here`
break;
}
}
}
</script>






javascript adobe acrobat






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edited Nov 26 '18 at 23:43









Nic3500

3,38581829




3,38581829










asked Nov 26 '18 at 20:45









MushiesmuMushiesmu

11




11













  • if (this.pageSize-1); and (var n='8kb'; n<this.pageSize-1; n++) and (this.pageSize(p, n) = '8kb') are 3 places to start...

    – Stuart Siegler
    Nov 26 '18 at 21:04





















  • if (this.pageSize-1); and (var n='8kb'; n<this.pageSize-1; n++) and (this.pageSize(p, n) = '8kb') are 3 places to start...

    – Stuart Siegler
    Nov 26 '18 at 21:04



















if (this.pageSize-1); and (var n='8kb'; n<this.pageSize-1; n++) and (this.pageSize(p, n) = '8kb') are 3 places to start...

– Stuart Siegler
Nov 26 '18 at 21:04







if (this.pageSize-1); and (var n='8kb'; n<this.pageSize-1; n++) and (this.pageSize(p, n) = '8kb') are 3 places to start...

– Stuart Siegler
Nov 26 '18 at 21:04














1 Answer
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Have you looked up the description of pageSize in the Acrobat JavaScript documentation??



Probably not, because there is no pageSize property in Acrobat JavaScript.



The closest which has something about the size of a page is the various pageBoxes, and they concern the dimensions.



Acrobat JavaScript has only very limited access to the content of a page, and that access is even further limited to text.



HTH.






share|improve this answer
























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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Have you looked up the description of pageSize in the Acrobat JavaScript documentation??



    Probably not, because there is no pageSize property in Acrobat JavaScript.



    The closest which has something about the size of a page is the various pageBoxes, and they concern the dimensions.



    Acrobat JavaScript has only very limited access to the content of a page, and that access is even further limited to text.



    HTH.






    share|improve this answer




























      0














      Have you looked up the description of pageSize in the Acrobat JavaScript documentation??



      Probably not, because there is no pageSize property in Acrobat JavaScript.



      The closest which has something about the size of a page is the various pageBoxes, and they concern the dimensions.



      Acrobat JavaScript has only very limited access to the content of a page, and that access is even further limited to text.



      HTH.






      share|improve this answer


























        0












        0








        0







        Have you looked up the description of pageSize in the Acrobat JavaScript documentation??



        Probably not, because there is no pageSize property in Acrobat JavaScript.



        The closest which has something about the size of a page is the various pageBoxes, and they concern the dimensions.



        Acrobat JavaScript has only very limited access to the content of a page, and that access is even further limited to text.



        HTH.






        share|improve this answer













        Have you looked up the description of pageSize in the Acrobat JavaScript documentation??



        Probably not, because there is no pageSize property in Acrobat JavaScript.



        The closest which has something about the size of a page is the various pageBoxes, and they concern the dimensions.



        Acrobat JavaScript has only very limited access to the content of a page, and that access is even further limited to text.



        HTH.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 16 '18 at 9:14









        Max WyssMax Wyss

        2,87211323




        2,87211323
































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