Using Django admin interface with enumchoicefield
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I'm attempting to use the Django (2.1.3) admin interface with the enumchoicefield package. All goes well with creating and executing the migration and starting Django, but when I try to add an instance to the model containing the EnumChoiceField I get:
Exception Type: TypeError
Exception Value: render() got an unexpected keyword argument 'renderer'
Exception Location: /home/django/Env/rosella/lib/python3.5/site-packages/django/forms/boundfield.py in as_widget, line 93
Python Executable: /usr/local/bin/uwsgi
Python Version: 3.5.2
Model code:
from enumchoicefield import ChoiceEnum, EnumChoiceField
...
class SystemStatus(ChoiceEnum):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
class Monitor(models.Model):
...
status = EnumChoiceField(SystemStatus, default=SystemStatus.UNKNOWN)
Question: Does enumchoicefield support the admin interface?
Note: I tried doing enums using django_enumfield, but also ran into problems with the admin interface - error was 'EnumType' object is not iterable
django django-models
asked Nov 26 '18 at 23:55
Craig S. AndersonCraig S. Anderson
4,87232236
add a comment |
I'm attempting to use the Django (2.1.3) admin interface with the enumchoicefield package. All goes well with creating and executing the migration and starting Django, but when I try to add an instance to the model containing the EnumChoiceField I get:
Exception Type: TypeError
Exception Value: render() got an unexpected keyword argument 'renderer'
Exception Location: /home/django/Env/rosella/lib/python3.5/site-packages/django/forms/boundfield.py in as_widget, line 93
Python Executable: /usr/local/bin/uwsgi
Python Version: 3.5.2
Model code:
from enumchoicefield import ChoiceEnum, EnumChoiceField
...
class SystemStatus(ChoiceEnum):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
class Monitor(models.Model):
...
status = EnumChoiceField(SystemStatus, default=SystemStatus.UNKNOWN)
Question: Does enumchoicefield support the admin interface?
Note: I tried doing enums using django_enumfield, but also ran into problems with the admin interface - error was 'EnumType' object is not iterable
django django-models
asked Nov 26 '18 at 23:55
Craig S. AndersonCraig S. Anderson
4,87232236
Looks like the author was working on the issue: github.com/timheap/django-enumchoicefield/commit/…
– Jack L.
Feb 13 at 10:18
add a comment |
I'm attempting to use the Django (2.1.3) admin interface with the enumchoicefield package. All goes well with creating and executing the migration and starting Django, but when I try to add an instance to the model containing the EnumChoiceField I get:
Exception Type: TypeError
Exception Value: render() got an unexpected keyword argument 'renderer'
Exception Location: /home/django/Env/rosella/lib/python3.5/site-packages/django/forms/boundfield.py in as_widget, line 93
Python Executable: /usr/local/bin/uwsgi
Python Version: 3.5.2
Model code:
from enumchoicefield import ChoiceEnum, EnumChoiceField
...
class SystemStatus(ChoiceEnum):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
class Monitor(models.Model):
...
status = EnumChoiceField(SystemStatus, default=SystemStatus.UNKNOWN)
Question: Does enumchoicefield support the admin interface?
Note: I tried doing enums using django_enumfield, but also ran into problems with the admin interface - error was 'EnumType' object is not iterable
django django-models
asked Nov 26 '18 at 23:55
Craig S. AndersonCraig S. Anderson
4,87232236
I'm attempting to use the Django (2.1.3) admin interface with the enumchoicefield package. All goes well with creating and executing the migration and starting Django, but when I try to add an instance to the model containing the EnumChoiceField I get:
Exception Type: TypeError
Exception Value: render() got an unexpected keyword argument 'renderer'
Exception Location: /home/django/Env/rosella/lib/python3.5/site-packages/django/forms/boundfield.py in as_widget, line 93
Python Executable: /usr/local/bin/uwsgi
Python Version: 3.5.2
Model code:
from enumchoicefield import ChoiceEnum, EnumChoiceField
...
class SystemStatus(ChoiceEnum):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
class Monitor(models.Model):
...
status = EnumChoiceField(SystemStatus, default=SystemStatus.UNKNOWN)
Question: Does enumchoicefield support the admin interface?
Note: I tried doing enums using django_enumfield, but also ran into problems with the admin interface - error was 'EnumType' object is not iterable
django django-models
django django-models
asked Nov 26 '18 at 23:55
Craig S. AndersonCraig S. Anderson
4,87232236
asked Nov 26 '18 at 23:55
Craig S. AndersonCraig S. Anderson
4,87232236
edited Nov 27 '18 at 0:01
Craig S. Anderson
asked Nov 26 '18 at 23:55
Craig S. AndersonCraig S. Anderson
4,87232236
asked Nov 26 '18 at 23:55
Craig S. AndersonCraig S. Anderson
4,87232236
asked Nov 26 '18 at 23:55
Craig S. AndersonCraig S. Anderson
4,87232236
4,87232236
Looks like the author was working on the issue: github.com/timheap/django-enumchoicefield/commit/…
– Jack L.
Feb 13 at 10:18
add a comment |
Looks like the author was working on the issue: github.com/timheap/django-enumchoicefield/commit/…
– Jack L.
Feb 13 at 10:18
Looks like the author was working on the issue: github.com/timheap/django-enumchoicefield/commit/…
– Jack L.
Feb 13 at 10:18
Looks like the author was working on the issue: github.com/timheap/django-enumchoicefield/commit/…
– Jack L.
Feb 13 at 10:18
add a comment |
1 Answer
1
active
oldest
votes
I am not sure if you should use EnumChoiceField, as the library does not have any information about supports in Django 2.X. Also it has mentioned that it is using Python 3.4 in github page. Instead, consider choice fields like this:
class SystemStatus(object):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
choices = (
(UNKNOWN, "Unknown"),
(OK, 'Ok'),
(DOWN, 'Down')
)
And use it in Model:
status = models.CharField(max_length=20, choices=SystemStatus.choices, default=SystemStatus.UNKNOWN)
answered Nov 27 '18 at 0:54
ruddraruddra
16.8k42951
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I am not sure if you should use EnumChoiceField, as the library does not have any information about supports in Django 2.X. Also it has mentioned that it is using Python 3.4 in github page. Instead, consider choice fields like this:
class SystemStatus(object):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
choices = (
(UNKNOWN, "Unknown"),
(OK, 'Ok'),
(DOWN, 'Down')
)
And use it in Model:
status = models.CharField(max_length=20, choices=SystemStatus.choices, default=SystemStatus.UNKNOWN)
answered Nov 27 '18 at 0:54
ruddraruddra
16.8k42951
add a comment |
I am not sure if you should use EnumChoiceField, as the library does not have any information about supports in Django 2.X. Also it has mentioned that it is using Python 3.4 in github page. Instead, consider choice fields like this:
class SystemStatus(object):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
choices = (
(UNKNOWN, "Unknown"),
(OK, 'Ok'),
(DOWN, 'Down')
)
And use it in Model:
status = models.CharField(max_length=20, choices=SystemStatus.choices, default=SystemStatus.UNKNOWN)
answered Nov 27 '18 at 0:54
ruddraruddra
16.8k42951
add a comment |
I am not sure if you should use EnumChoiceField, as the library does not have any information about supports in Django 2.X. Also it has mentioned that it is using Python 3.4 in github page. Instead, consider choice fields like this:
class SystemStatus(object):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
choices = (
(UNKNOWN, "Unknown"),
(OK, 'Ok'),
(DOWN, 'Down')
)
And use it in Model:
status = models.CharField(max_length=20, choices=SystemStatus.choices, default=SystemStatus.UNKNOWN)
answered Nov 27 '18 at 0:54
ruddraruddra
16.8k42951
I am not sure if you should use EnumChoiceField, as the library does not have any information about supports in Django 2.X. Also it has mentioned that it is using Python 3.4 in github page. Instead, consider choice fields like this:
class SystemStatus(object):
UNKNOWN = 'Unknown'
OK = 'Ok'
DOWN = 'Down'
choices = (
(UNKNOWN, "Unknown"),
(OK, 'Ok'),
(DOWN, 'Down')
)
And use it in Model:
status = models.CharField(max_length=20, choices=SystemStatus.choices, default=SystemStatus.UNKNOWN)
answered Nov 27 '18 at 0:54
ruddraruddra
16.8k42951
edited Nov 27 '18 at 8:35
answered Nov 27 '18 at 0:54
ruddraruddra
16.8k42951
answered Nov 27 '18 at 0:54
ruddraruddra
16.8k42951
answered Nov 27 '18 at 0:54
ruddraruddra
16.8k42951
16.8k42951
add a comment |
add a comment |
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Looks like the author was working on the issue: github.com/timheap/django-enumchoicefield/commit/…
– Jack L.
Feb 13 at 10:18