Javascript : Store JSON data in array
up vote
1
down vote
favorite
I have JSON like this.
[{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
},
{
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
},
{
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
I would like to store my JSON data to array.
let data = JSON.parse('[{"address":"A-D-1","batch":[{"batch_number":"B-123","cost":[{"cost":"C1"}]}]},{"address":"A-85-1","batch":[{"batch_number":"B-6562","cost":[{"cost":"C16464"}]}]},{"address":"A-522-1","batch":[{"batch_number":"B-4511","cost":[{"cost":"C8745"}]}]}]');
for (let i = 0; i < data.length; i++) {
if (data[i].batch !== undefined && data[i].batch !== null && data[i].batch.length !== undefined && data[i].batch.length > 0) {
let batchLength = data[i].batch.length
let newObject = {}
let newArray =
for (let j = 0; j < batchLength; j++) {
if (data[i].batch !== undefined && data[i].batch[j].cost !== null && data[i].batch[j].cost.length !== undefined && data[i].batch[j].cost.length > 0) {
let costLength = data[i].batch[j].cost.length
for (let k = 0; k < costLength; k++) {
newObject.location = data[i].address
newObject.batch.number = data[i].batch[j].batch_number ? data[i].batch[j].batch_number : ''
newObject.cogs = data[i].batch[j].cost[k].cost ? data[i].batch[j].cost[k].cost : ''
newArray.push(newObject)
}
}
}
}
}I have stored JSON in data variable.
I have tried below code. but I always get last index as repeatative.
Expected Output :
[
{
"address":"A-D-1",
"batch":{
"batch_number":"B-123"
},
"cost":"C1"
},
{
"address":"A-85-1",
"batch":{
"batch_number":"B-6562"
},
"cost":"C16464"
},
{
"address":"A-522-1",
"batch":{
"batch_number":"B-4511"
},
"cost":"C8745"
}
]
Any help would be great.
Thank You.
javascript json
edited Nov 19 at 17:58
tevemadar
4,1952723
asked Nov 19 at 17:11
Brijesh Patel
376
add a comment |
up vote
1
down vote
favorite
I have JSON like this.
[{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
},
{
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
},
{
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
I would like to store my JSON data to array.
let data = JSON.parse('[{"address":"A-D-1","batch":[{"batch_number":"B-123","cost":[{"cost":"C1"}]}]},{"address":"A-85-1","batch":[{"batch_number":"B-6562","cost":[{"cost":"C16464"}]}]},{"address":"A-522-1","batch":[{"batch_number":"B-4511","cost":[{"cost":"C8745"}]}]}]');
for (let i = 0; i < data.length; i++) {
if (data[i].batch !== undefined && data[i].batch !== null && data[i].batch.length !== undefined && data[i].batch.length > 0) {
let batchLength = data[i].batch.length
let newObject = {}
let newArray =
for (let j = 0; j < batchLength; j++) {
if (data[i].batch !== undefined && data[i].batch[j].cost !== null && data[i].batch[j].cost.length !== undefined && data[i].batch[j].cost.length > 0) {
let costLength = data[i].batch[j].cost.length
for (let k = 0; k < costLength; k++) {
newObject.location = data[i].address
newObject.batch.number = data[i].batch[j].batch_number ? data[i].batch[j].batch_number : ''
newObject.cogs = data[i].batch[j].cost[k].cost ? data[i].batch[j].cost[k].cost : ''
newArray.push(newObject)
}
}
}
}
}I have stored JSON in data variable.
I have tried below code. but I always get last index as repeatative.
Expected Output :
[
{
"address":"A-D-1",
"batch":{
"batch_number":"B-123"
},
"cost":"C1"
},
{
"address":"A-85-1",
"batch":{
"batch_number":"B-6562"
},
"cost":"C16464"
},
{
"address":"A-522-1",
"batch":{
"batch_number":"B-4511"
},
"cost":"C8745"
}
]
Any help would be great.
Thank You.
javascript json
edited Nov 19 at 17:58
tevemadar
4,1952723
asked Nov 19 at 17:11
Brijesh Patel
376
Do you receive the JSON data as String?
– Mis94
Nov 19 at 17:30
I get as an array of objects.
– Brijesh Patel
Nov 19 at 17:31
How should the result look like?
– tevemadar
Nov 19 at 17:32
@tevemadar. I have edited my question. Can you please check ?
– Brijesh Patel
Nov 19 at 17:38
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have JSON like this.
[{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
},
{
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
},
{
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
I would like to store my JSON data to array.
let data = JSON.parse('[{"address":"A-D-1","batch":[{"batch_number":"B-123","cost":[{"cost":"C1"}]}]},{"address":"A-85-1","batch":[{"batch_number":"B-6562","cost":[{"cost":"C16464"}]}]},{"address":"A-522-1","batch":[{"batch_number":"B-4511","cost":[{"cost":"C8745"}]}]}]');
for (let i = 0; i < data.length; i++) {
if (data[i].batch !== undefined && data[i].batch !== null && data[i].batch.length !== undefined && data[i].batch.length > 0) {
let batchLength = data[i].batch.length
let newObject = {}
let newArray =
for (let j = 0; j < batchLength; j++) {
if (data[i].batch !== undefined && data[i].batch[j].cost !== null && data[i].batch[j].cost.length !== undefined && data[i].batch[j].cost.length > 0) {
let costLength = data[i].batch[j].cost.length
for (let k = 0; k < costLength; k++) {
newObject.location = data[i].address
newObject.batch.number = data[i].batch[j].batch_number ? data[i].batch[j].batch_number : ''
newObject.cogs = data[i].batch[j].cost[k].cost ? data[i].batch[j].cost[k].cost : ''
newArray.push(newObject)
}
}
}
}
}I have stored JSON in data variable.
I have tried below code. but I always get last index as repeatative.
Expected Output :
[
{
"address":"A-D-1",
"batch":{
"batch_number":"B-123"
},
"cost":"C1"
},
{
"address":"A-85-1",
"batch":{
"batch_number":"B-6562"
},
"cost":"C16464"
},
{
"address":"A-522-1",
"batch":{
"batch_number":"B-4511"
},
"cost":"C8745"
}
]
Any help would be great.
Thank You.
javascript json
edited Nov 19 at 17:58
tevemadar
4,1952723
asked Nov 19 at 17:11
Brijesh Patel
376
I have JSON like this.
[{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
},
{
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
},
{
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
I would like to store my JSON data to array.
let data = JSON.parse('[{"address":"A-D-1","batch":[{"batch_number":"B-123","cost":[{"cost":"C1"}]}]},{"address":"A-85-1","batch":[{"batch_number":"B-6562","cost":[{"cost":"C16464"}]}]},{"address":"A-522-1","batch":[{"batch_number":"B-4511","cost":[{"cost":"C8745"}]}]}]');
for (let i = 0; i < data.length; i++) {
if (data[i].batch !== undefined && data[i].batch !== null && data[i].batch.length !== undefined && data[i].batch.length > 0) {
let batchLength = data[i].batch.length
let newObject = {}
let newArray =
for (let j = 0; j < batchLength; j++) {
if (data[i].batch !== undefined && data[i].batch[j].cost !== null && data[i].batch[j].cost.length !== undefined && data[i].batch[j].cost.length > 0) {
let costLength = data[i].batch[j].cost.length
for (let k = 0; k < costLength; k++) {
newObject.location = data[i].address
newObject.batch.number = data[i].batch[j].batch_number ? data[i].batch[j].batch_number : ''
newObject.cogs = data[i].batch[j].cost[k].cost ? data[i].batch[j].cost[k].cost : ''
newArray.push(newObject)
}
}
}
}
}I have stored JSON in data variable.
I have tried below code. but I always get last index as repeatative.
Expected Output :
[
{
"address":"A-D-1",
"batch":{
"batch_number":"B-123"
},
"cost":"C1"
},
{
"address":"A-85-1",
"batch":{
"batch_number":"B-6562"
},
"cost":"C16464"
},
{
"address":"A-522-1",
"batch":{
"batch_number":"B-4511"
},
"cost":"C8745"
}
]
Any help would be great.
Thank You.
let data = JSON.parse('[{"address":"A-D-1","batch":[{"batch_number":"B-123","cost":[{"cost":"C1"}]}]},{"address":"A-85-1","batch":[{"batch_number":"B-6562","cost":[{"cost":"C16464"}]}]},{"address":"A-522-1","batch":[{"batch_number":"B-4511","cost":[{"cost":"C8745"}]}]}]');
for (let i = 0; i < data.length; i++) {
if (data[i].batch !== undefined && data[i].batch !== null && data[i].batch.length !== undefined && data[i].batch.length > 0) {
let batchLength = data[i].batch.length
let newObject = {}
let newArray =
for (let j = 0; j < batchLength; j++) {
if (data[i].batch !== undefined && data[i].batch[j].cost !== null && data[i].batch[j].cost.length !== undefined && data[i].batch[j].cost.length > 0) {
let costLength = data[i].batch[j].cost.length
for (let k = 0; k < costLength; k++) {
newObject.location = data[i].address
newObject.batch.number = data[i].batch[j].batch_number ? data[i].batch[j].batch_number : ''
newObject.cogs = data[i].batch[j].cost[k].cost ? data[i].batch[j].cost[k].cost : ''
newArray.push(newObject)
}
}
}
}
}let data = JSON.parse('[{"address":"A-D-1","batch":[{"batch_number":"B-123","cost":[{"cost":"C1"}]}]},{"address":"A-85-1","batch":[{"batch_number":"B-6562","cost":[{"cost":"C16464"}]}]},{"address":"A-522-1","batch":[{"batch_number":"B-4511","cost":[{"cost":"C8745"}]}]}]');
for (let i = 0; i < data.length; i++) {
if (data[i].batch !== undefined && data[i].batch !== null && data[i].batch.length !== undefined && data[i].batch.length > 0) {
let batchLength = data[i].batch.length
let newObject = {}
let newArray =
for (let j = 0; j < batchLength; j++) {
if (data[i].batch !== undefined && data[i].batch[j].cost !== null && data[i].batch[j].cost.length !== undefined && data[i].batch[j].cost.length > 0) {
let costLength = data[i].batch[j].cost.length
for (let k = 0; k < costLength; k++) {
newObject.location = data[i].address
newObject.batch.number = data[i].batch[j].batch_number ? data[i].batch[j].batch_number : ''
newObject.cogs = data[i].batch[j].cost[k].cost ? data[i].batch[j].cost[k].cost : ''
newArray.push(newObject)
}
}
}
}
}javascript json
javascript json
edited Nov 19 at 17:58
tevemadar
4,1952723
asked Nov 19 at 17:11
Brijesh Patel
376
edited Nov 19 at 17:58
tevemadar
4,1952723
asked Nov 19 at 17:11
Brijesh Patel
376
edited Nov 19 at 17:58
tevemadar
4,1952723
edited Nov 19 at 17:58
tevemadar
4,1952723
edited Nov 19 at 17:58
tevemadar
4,1952723
4,1952723
asked Nov 19 at 17:11
Brijesh Patel
376
asked Nov 19 at 17:11
Brijesh Patel
376
asked Nov 19 at 17:11
Brijesh Patel
376
376
Do you receive the JSON data as String?
– Mis94
Nov 19 at 17:30
I get as an array of objects.
– Brijesh Patel
Nov 19 at 17:31
How should the result look like?
– tevemadar
Nov 19 at 17:32
@tevemadar. I have edited my question. Can you please check ?
– Brijesh Patel
Nov 19 at 17:38
add a comment |
Do you receive the JSON data as String?
– Mis94
Nov 19 at 17:30
I get as an array of objects.
– Brijesh Patel
Nov 19 at 17:31
How should the result look like?
– tevemadar
Nov 19 at 17:32
@tevemadar. I have edited my question. Can you please check ?
– Brijesh Patel
Nov 19 at 17:38
Do you receive the JSON data as String?
– Mis94
Nov 19 at 17:30
Do you receive the JSON data as String?
– Mis94
Nov 19 at 17:30
I get as an array of objects.
– Brijesh Patel
Nov 19 at 17:31
I get as an array of objects.
– Brijesh Patel
Nov 19 at 17:31
How should the result look like?
– tevemadar
Nov 19 at 17:32
How should the result look like?
– tevemadar
Nov 19 at 17:32
@tevemadar. I have edited my question. Can you please check ?
– Brijesh Patel
Nov 19 at 17:38
@tevemadar. I have edited my question. Can you please check ?
– Brijesh Patel
Nov 19 at 17:38
add a comment |
2 Answers
2
active
oldest
votes
up vote
0
down vote
You mean something like this?
const someArray = [{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
}, {
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
}, {
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
console.log(someArray.map(item => {
return {
address:item.address,
batch_number: item.batch && item.batch[0].batch_number,
cost: item.batch && item.batch[0].cost[0].cost
}
}))answered Nov 19 at 17:28
Arulmozhi Manikandan
1665
yes but I can have multiple arrays inside each array. so how can I solve that issue ?
– Brijesh Patel
Nov 19 at 17:29
add a comment |
up vote
0
down vote
You can use below method to retrieve the same in array format.
const data = JSON.parse(someArray);
console.log (data[0].address);
answered Nov 19 at 17:40
Murali
34
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You mean something like this?
const someArray = [{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
}, {
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
}, {
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
console.log(someArray.map(item => {
return {
address:item.address,
batch_number: item.batch && item.batch[0].batch_number,
cost: item.batch && item.batch[0].cost[0].cost
}
}))answered Nov 19 at 17:28
Arulmozhi Manikandan
1665
yes but I can have multiple arrays inside each array. so how can I solve that issue ?
– Brijesh Patel
Nov 19 at 17:29
add a comment |
up vote
0
down vote
You mean something like this?
const someArray = [{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
}, {
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
}, {
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
console.log(someArray.map(item => {
return {
address:item.address,
batch_number: item.batch && item.batch[0].batch_number,
cost: item.batch && item.batch[0].cost[0].cost
}
}))answered Nov 19 at 17:28
Arulmozhi Manikandan
1665
yes but I can have multiple arrays inside each array. so how can I solve that issue ?
– Brijesh Patel
Nov 19 at 17:29
add a comment |
up vote
0
down vote
up vote
0
down vote
You mean something like this?
const someArray = [{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
}, {
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
}, {
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
console.log(someArray.map(item => {
return {
address:item.address,
batch_number: item.batch && item.batch[0].batch_number,
cost: item.batch && item.batch[0].cost[0].cost
}
}))answered Nov 19 at 17:28
Arulmozhi Manikandan
1665
You mean something like this?
const someArray = [{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
}, {
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
}, {
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
console.log(someArray.map(item => {
return {
address:item.address,
batch_number: item.batch && item.batch[0].batch_number,
cost: item.batch && item.batch[0].cost[0].cost
}
}))const someArray = [{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
}, {
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
}, {
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
console.log(someArray.map(item => {
return {
address:item.address,
batch_number: item.batch && item.batch[0].batch_number,
cost: item.batch && item.batch[0].cost[0].cost
}
}))const someArray = [{
"address": "A-D-1",
"batch": [{
"batch_number": "B-123",
"cost": [{
"cost": "C1"
}]
}]
}, {
"address": "A-85-1",
"batch": [{
"batch_number": "B-6562",
"cost": [{
"cost": "C16464"
}]
}]
}, {
"address": "A-522-1",
"batch": [{
"batch_number": "B-4511",
"cost": [{
"cost": "C8745"
}]
}]
}]
console.log(someArray.map(item => {
return {
address:item.address,
batch_number: item.batch && item.batch[0].batch_number,
cost: item.batch && item.batch[0].cost[0].cost
}
}))answered Nov 19 at 17:28
Arulmozhi Manikandan
1665
answered Nov 19 at 17:28
Arulmozhi Manikandan
1665
answered Nov 19 at 17:28
Arulmozhi Manikandan
1665
answered Nov 19 at 17:28
Arulmozhi Manikandan
1665
1665
yes but I can have multiple arrays inside each array. so how can I solve that issue ?
– Brijesh Patel
Nov 19 at 17:29
add a comment |
yes but I can have multiple arrays inside each array. so how can I solve that issue ?
– Brijesh Patel
Nov 19 at 17:29
yes but I can have multiple arrays inside each array. so how can I solve that issue ?
– Brijesh Patel
Nov 19 at 17:29
yes but I can have multiple arrays inside each array. so how can I solve that issue ?
– Brijesh Patel
Nov 19 at 17:29
add a comment |
up vote
0
down vote
You can use below method to retrieve the same in array format.
const data = JSON.parse(someArray);
console.log (data[0].address);
answered Nov 19 at 17:40
Murali
34
add a comment |
up vote
0
down vote
You can use below method to retrieve the same in array format.
const data = JSON.parse(someArray);
console.log (data[0].address);
answered Nov 19 at 17:40
Murali
34
add a comment |
up vote
0
down vote
up vote
0
down vote
You can use below method to retrieve the same in array format.
const data = JSON.parse(someArray);
console.log (data[0].address);
answered Nov 19 at 17:40
Murali
34
You can use below method to retrieve the same in array format.
const data = JSON.parse(someArray);
console.log (data[0].address);
answered Nov 19 at 17:40
Murali
34
answered Nov 19 at 17:40
Murali
34
answered Nov 19 at 17:40
Murali
34
answered Nov 19 at 17:40
Murali
34
34
add a comment |
add a comment |
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Do you receive the JSON data as String?
– Mis94
Nov 19 at 17:30
I get as an array of objects.
– Brijesh Patel
Nov 19 at 17:31
How should the result look like?
– tevemadar
Nov 19 at 17:32
@tevemadar. I have edited my question. Can you please check ?
– Brijesh Patel
Nov 19 at 17:38