Solving second order time-dependent PDE











up vote
1
down vote

favorite
1












I am trying to solve a non-linear second order PDE as given below.
$$partial_{t}u+upartial_{x}u=partial_{xx}u+u$$
with periodic boundary condition: $$u(x,t)=u(x+2pi,t)$$ and initial condition: $$u(x,0)=u_{0}(x)$$
I am using a fractional step method to solve this problem as shown below.




  • 1st step: Non-linear part $$partial_{t}u=-upartial_{x}u$$

  • 2nd step: Linear part $$partial_{t}u=partial_{xx}u+u$$
    using Fourier discretization in space.


But I do not get reasonable results and there are oscillations.
Any suggestions for any other method for solving such PDEs?










share|cite|improve this question
























  • Why not just method of lines in direction $t$?
    – Federico
    Nov 21 at 16:45












  • Also, the Cauchy problem for this PDE doesn't seem always very well posed. I suspect you get only local existence in time.
    – Federico
    Nov 21 at 16:53










  • Consider for instance the simpler $partial_t u = u(1-partial_t u)$. If $partial_tu>-1$, then solutions try to grow exponentially and then I don't know if your PDE blows up...
    – Federico
    Nov 21 at 16:55










  • If your PDE is not well behaved, no matter how good a numerical scheme you pick, it will never avoid blow-ups
    – Federico
    Nov 21 at 16:56










  • You are asking if there is one of the members who can solve the $1$-D Navier-Stokes equation...
    – Daniele Tampieri
    Nov 21 at 17:21















up vote
1
down vote

favorite
1












I am trying to solve a non-linear second order PDE as given below.
$$partial_{t}u+upartial_{x}u=partial_{xx}u+u$$
with periodic boundary condition: $$u(x,t)=u(x+2pi,t)$$ and initial condition: $$u(x,0)=u_{0}(x)$$
I am using a fractional step method to solve this problem as shown below.




  • 1st step: Non-linear part $$partial_{t}u=-upartial_{x}u$$

  • 2nd step: Linear part $$partial_{t}u=partial_{xx}u+u$$
    using Fourier discretization in space.


But I do not get reasonable results and there are oscillations.
Any suggestions for any other method for solving such PDEs?










share|cite|improve this question
























  • Why not just method of lines in direction $t$?
    – Federico
    Nov 21 at 16:45












  • Also, the Cauchy problem for this PDE doesn't seem always very well posed. I suspect you get only local existence in time.
    – Federico
    Nov 21 at 16:53










  • Consider for instance the simpler $partial_t u = u(1-partial_t u)$. If $partial_tu>-1$, then solutions try to grow exponentially and then I don't know if your PDE blows up...
    – Federico
    Nov 21 at 16:55










  • If your PDE is not well behaved, no matter how good a numerical scheme you pick, it will never avoid blow-ups
    – Federico
    Nov 21 at 16:56










  • You are asking if there is one of the members who can solve the $1$-D Navier-Stokes equation...
    – Daniele Tampieri
    Nov 21 at 17:21













up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





I am trying to solve a non-linear second order PDE as given below.
$$partial_{t}u+upartial_{x}u=partial_{xx}u+u$$
with periodic boundary condition: $$u(x,t)=u(x+2pi,t)$$ and initial condition: $$u(x,0)=u_{0}(x)$$
I am using a fractional step method to solve this problem as shown below.




  • 1st step: Non-linear part $$partial_{t}u=-upartial_{x}u$$

  • 2nd step: Linear part $$partial_{t}u=partial_{xx}u+u$$
    using Fourier discretization in space.


But I do not get reasonable results and there are oscillations.
Any suggestions for any other method for solving such PDEs?










share|cite|improve this question















I am trying to solve a non-linear second order PDE as given below.
$$partial_{t}u+upartial_{x}u=partial_{xx}u+u$$
with periodic boundary condition: $$u(x,t)=u(x+2pi,t)$$ and initial condition: $$u(x,0)=u_{0}(x)$$
I am using a fractional step method to solve this problem as shown below.




  • 1st step: Non-linear part $$partial_{t}u=-upartial_{x}u$$

  • 2nd step: Linear part $$partial_{t}u=partial_{xx}u+u$$
    using Fourier discretization in space.


But I do not get reasonable results and there are oscillations.
Any suggestions for any other method for solving such PDEs?







pde numerical-methods






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 23 at 17:46









Harry49

5,6302929




5,6302929










asked Nov 21 at 16:39









math123

163




163












  • Why not just method of lines in direction $t$?
    – Federico
    Nov 21 at 16:45












  • Also, the Cauchy problem for this PDE doesn't seem always very well posed. I suspect you get only local existence in time.
    – Federico
    Nov 21 at 16:53










  • Consider for instance the simpler $partial_t u = u(1-partial_t u)$. If $partial_tu>-1$, then solutions try to grow exponentially and then I don't know if your PDE blows up...
    – Federico
    Nov 21 at 16:55










  • If your PDE is not well behaved, no matter how good a numerical scheme you pick, it will never avoid blow-ups
    – Federico
    Nov 21 at 16:56










  • You are asking if there is one of the members who can solve the $1$-D Navier-Stokes equation...
    – Daniele Tampieri
    Nov 21 at 17:21


















  • Why not just method of lines in direction $t$?
    – Federico
    Nov 21 at 16:45












  • Also, the Cauchy problem for this PDE doesn't seem always very well posed. I suspect you get only local existence in time.
    – Federico
    Nov 21 at 16:53










  • Consider for instance the simpler $partial_t u = u(1-partial_t u)$. If $partial_tu>-1$, then solutions try to grow exponentially and then I don't know if your PDE blows up...
    – Federico
    Nov 21 at 16:55










  • If your PDE is not well behaved, no matter how good a numerical scheme you pick, it will never avoid blow-ups
    – Federico
    Nov 21 at 16:56










  • You are asking if there is one of the members who can solve the $1$-D Navier-Stokes equation...
    – Daniele Tampieri
    Nov 21 at 17:21
















Why not just method of lines in direction $t$?
– Federico
Nov 21 at 16:45






Why not just method of lines in direction $t$?
– Federico
Nov 21 at 16:45














Also, the Cauchy problem for this PDE doesn't seem always very well posed. I suspect you get only local existence in time.
– Federico
Nov 21 at 16:53




Also, the Cauchy problem for this PDE doesn't seem always very well posed. I suspect you get only local existence in time.
– Federico
Nov 21 at 16:53












Consider for instance the simpler $partial_t u = u(1-partial_t u)$. If $partial_tu>-1$, then solutions try to grow exponentially and then I don't know if your PDE blows up...
– Federico
Nov 21 at 16:55




Consider for instance the simpler $partial_t u = u(1-partial_t u)$. If $partial_tu>-1$, then solutions try to grow exponentially and then I don't know if your PDE blows up...
– Federico
Nov 21 at 16:55












If your PDE is not well behaved, no matter how good a numerical scheme you pick, it will never avoid blow-ups
– Federico
Nov 21 at 16:56




If your PDE is not well behaved, no matter how good a numerical scheme you pick, it will never avoid blow-ups
– Federico
Nov 21 at 16:56












You are asking if there is one of the members who can solve the $1$-D Navier-Stokes equation...
– Daniele Tampieri
Nov 21 at 17:21




You are asking if there is one of the members who can solve the $1$-D Navier-Stokes equation...
– Daniele Tampieri
Nov 21 at 17:21















active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














 

draft saved


draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3007977%2fsolving-second-order-time-dependent-pde%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown






























active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes
















 

draft saved


draft discarded



















































 


draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3007977%2fsolving-second-order-time-dependent-pde%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Wiesbaden

Marschland

Dieringhausen