python pandas iloc works on jupyter but not on flask











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I am developing an API from flask and for that I had to use pandas in between of a function. So to access a data I used pandas iloc but it shows an error 'IndexError: single positional indexer is out-of-bounds'.



Here's my code:



price = float(cf.loc[cf['company_name'] == 'Agricultural Development Bank Limited', 'Close'].iloc[0])
return price


If I run the same thing at jupyter then it works perfectly.



Cjeck out the screenshot of running this code in jupyter notebook



Please help.










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    up vote
    -3
    down vote

    favorite












    I am developing an API from flask and for that I had to use pandas in between of a function. So to access a data I used pandas iloc but it shows an error 'IndexError: single positional indexer is out-of-bounds'.



    Here's my code:



    price = float(cf.loc[cf['company_name'] == 'Agricultural Development Bank Limited', 'Close'].iloc[0])
    return price


    If I run the same thing at jupyter then it works perfectly.



    Cjeck out the screenshot of running this code in jupyter notebook



    Please help.










    share|improve this question


























      up vote
      -3
      down vote

      favorite









      up vote
      -3
      down vote

      favorite











      I am developing an API from flask and for that I had to use pandas in between of a function. So to access a data I used pandas iloc but it shows an error 'IndexError: single positional indexer is out-of-bounds'.



      Here's my code:



      price = float(cf.loc[cf['company_name'] == 'Agricultural Development Bank Limited', 'Close'].iloc[0])
      return price


      If I run the same thing at jupyter then it works perfectly.



      Cjeck out the screenshot of running this code in jupyter notebook



      Please help.










      share|improve this question















      I am developing an API from flask and for that I had to use pandas in between of a function. So to access a data I used pandas iloc but it shows an error 'IndexError: single positional indexer is out-of-bounds'.



      Here's my code:



      price = float(cf.loc[cf['company_name'] == 'Agricultural Development Bank Limited', 'Close'].iloc[0])
      return price


      If I run the same thing at jupyter then it works perfectly.



      Cjeck out the screenshot of running this code in jupyter notebook



      Please help.







      python pandas flask






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      edited Nov 19 at 16:56









      davidism

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      61.1k12154173










      asked Nov 19 at 16:49









      Aabishkar Wagle

      12




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          It's probably trying to index an empty dataframe. For illustration try running this:



          df = pd.DataFrame()
          df.iloc[0]





          share|improve this answer





















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            1 Answer
            1






            active

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            active

            oldest

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            active

            oldest

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            up vote
            0
            down vote













            It's probably trying to index an empty dataframe. For illustration try running this:



            df = pd.DataFrame()
            df.iloc[0]





            share|improve this answer

























              up vote
              0
              down vote













              It's probably trying to index an empty dataframe. For illustration try running this:



              df = pd.DataFrame()
              df.iloc[0]





              share|improve this answer























                up vote
                0
                down vote










                up vote
                0
                down vote









                It's probably trying to index an empty dataframe. For illustration try running this:



                df = pd.DataFrame()
                df.iloc[0]





                share|improve this answer












                It's probably trying to index an empty dataframe. For illustration try running this:



                df = pd.DataFrame()
                df.iloc[0]






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 19 at 18:26









                Robert

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