Which properties preserve by isometry?











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I know that an isometry between two surfaces preserves the 1st fundamental coefficients, geodesic curvature, and Gaussian curvature.



I wonder that how about the curvature and torsion of a curve on the surface, and 2nd fundamental coefficients?



I can’t find any counterexample and prove this question



Give some advice or comments! Thank you!










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  • Once the metric is preserved, every thing depends completely on it is.
    – Semsem
    2 days ago








  • 1




    The Second Fundamental Form (for example) depends on the embedding of a surface in some higher-dimensional Riemannian space, so it doesn't make sense to ask whether an isometry of surfaces (which makes no reference to embeddings) preserves it. Do you mean perhaps an isometry of some higher-dimensional spaces and the isometry from an embedded surface onto its image?
    – Travis
    2 days ago










  • @Travis Just elementary differential geometry level, it means 'in $mathbb{R}^{3}$ Euclidean space' case.
    – Primavera
    yesterday






  • 1




    Alright, I've written an answer that assumes you mean an isometry between surfaces, both of which are embedded in $Bbb R^3$.
    – Travis
    yesterday















up vote
0
down vote

favorite












I know that an isometry between two surfaces preserves the 1st fundamental coefficients, geodesic curvature, and Gaussian curvature.



I wonder that how about the curvature and torsion of a curve on the surface, and 2nd fundamental coefficients?



I can’t find any counterexample and prove this question



Give some advice or comments! Thank you!










share|cite|improve this question






















  • Once the metric is preserved, every thing depends completely on it is.
    – Semsem
    2 days ago








  • 1




    The Second Fundamental Form (for example) depends on the embedding of a surface in some higher-dimensional Riemannian space, so it doesn't make sense to ask whether an isometry of surfaces (which makes no reference to embeddings) preserves it. Do you mean perhaps an isometry of some higher-dimensional spaces and the isometry from an embedded surface onto its image?
    – Travis
    2 days ago










  • @Travis Just elementary differential geometry level, it means 'in $mathbb{R}^{3}$ Euclidean space' case.
    – Primavera
    yesterday






  • 1




    Alright, I've written an answer that assumes you mean an isometry between surfaces, both of which are embedded in $Bbb R^3$.
    – Travis
    yesterday













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I know that an isometry between two surfaces preserves the 1st fundamental coefficients, geodesic curvature, and Gaussian curvature.



I wonder that how about the curvature and torsion of a curve on the surface, and 2nd fundamental coefficients?



I can’t find any counterexample and prove this question



Give some advice or comments! Thank you!










share|cite|improve this question













I know that an isometry between two surfaces preserves the 1st fundamental coefficients, geodesic curvature, and Gaussian curvature.



I wonder that how about the curvature and torsion of a curve on the surface, and 2nd fundamental coefficients?



I can’t find any counterexample and prove this question



Give some advice or comments! Thank you!







differential-geometry curvature isometry






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share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 2 days ago









Primavera

2389




2389












  • Once the metric is preserved, every thing depends completely on it is.
    – Semsem
    2 days ago








  • 1




    The Second Fundamental Form (for example) depends on the embedding of a surface in some higher-dimensional Riemannian space, so it doesn't make sense to ask whether an isometry of surfaces (which makes no reference to embeddings) preserves it. Do you mean perhaps an isometry of some higher-dimensional spaces and the isometry from an embedded surface onto its image?
    – Travis
    2 days ago










  • @Travis Just elementary differential geometry level, it means 'in $mathbb{R}^{3}$ Euclidean space' case.
    – Primavera
    yesterday






  • 1




    Alright, I've written an answer that assumes you mean an isometry between surfaces, both of which are embedded in $Bbb R^3$.
    – Travis
    yesterday


















  • Once the metric is preserved, every thing depends completely on it is.
    – Semsem
    2 days ago








  • 1




    The Second Fundamental Form (for example) depends on the embedding of a surface in some higher-dimensional Riemannian space, so it doesn't make sense to ask whether an isometry of surfaces (which makes no reference to embeddings) preserves it. Do you mean perhaps an isometry of some higher-dimensional spaces and the isometry from an embedded surface onto its image?
    – Travis
    2 days ago










  • @Travis Just elementary differential geometry level, it means 'in $mathbb{R}^{3}$ Euclidean space' case.
    – Primavera
    yesterday






  • 1




    Alright, I've written an answer that assumes you mean an isometry between surfaces, both of which are embedded in $Bbb R^3$.
    – Travis
    yesterday
















Once the metric is preserved, every thing depends completely on it is.
– Semsem
2 days ago






Once the metric is preserved, every thing depends completely on it is.
– Semsem
2 days ago






1




1




The Second Fundamental Form (for example) depends on the embedding of a surface in some higher-dimensional Riemannian space, so it doesn't make sense to ask whether an isometry of surfaces (which makes no reference to embeddings) preserves it. Do you mean perhaps an isometry of some higher-dimensional spaces and the isometry from an embedded surface onto its image?
– Travis
2 days ago




The Second Fundamental Form (for example) depends on the embedding of a surface in some higher-dimensional Riemannian space, so it doesn't make sense to ask whether an isometry of surfaces (which makes no reference to embeddings) preserves it. Do you mean perhaps an isometry of some higher-dimensional spaces and the isometry from an embedded surface onto its image?
– Travis
2 days ago












@Travis Just elementary differential geometry level, it means 'in $mathbb{R}^{3}$ Euclidean space' case.
– Primavera
yesterday




@Travis Just elementary differential geometry level, it means 'in $mathbb{R}^{3}$ Euclidean space' case.
– Primavera
yesterday




1




1




Alright, I've written an answer that assumes you mean an isometry between surfaces, both of which are embedded in $Bbb R^3$.
– Travis
yesterday




Alright, I've written an answer that assumes you mean an isometry between surfaces, both of which are embedded in $Bbb R^3$.
– Travis
yesterday










1 Answer
1






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1
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Hint Consider an isometry from a subset of a plane in $Bbb R^3$ to a subset of a cylinder in $Bbb R^3$.






share|cite|improve this answer





















  • Consider the A4 paper and drawing a diagonal line on the paper. Then, both of the curvature and torsion of the diagonal line is zero in A4 paper. But, they are non-zero in cylinder in $mathbb{R}^{3}$ if we bend the A4 paper into cylinder. Right?
    – Primavera
    22 hours ago












  • It depends on how the paper is bent, but if either of the side pairs are parallel to the axis of the cylinder, for example, then the curve will have nonzero curvature and torsion. (In fact, in this particular example both will be constant.)
    – Travis
    22 hours ago










  • you’re right. I just think in my head the line trasforming into cylinderical helix. Thanks for your comments. But, I have one more question. Then, is it true that the isometry preserves 2nd fundamental coefficients? Now, the other properties are clear for me excepts for 2nd fundamental coefficients.
    – Primavera
    22 hours ago












  • What are the second fundamental forms for the two surfaces in the hint?
    – Travis
    22 hours ago










  • Oh, sorry. I have a mistake in calculating of 2nd fundamental coefficients the latter one. Thank you! Now, all things clear!
    – Primavera
    22 hours ago











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up vote
1
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Hint Consider an isometry from a subset of a plane in $Bbb R^3$ to a subset of a cylinder in $Bbb R^3$.






share|cite|improve this answer





















  • Consider the A4 paper and drawing a diagonal line on the paper. Then, both of the curvature and torsion of the diagonal line is zero in A4 paper. But, they are non-zero in cylinder in $mathbb{R}^{3}$ if we bend the A4 paper into cylinder. Right?
    – Primavera
    22 hours ago












  • It depends on how the paper is bent, but if either of the side pairs are parallel to the axis of the cylinder, for example, then the curve will have nonzero curvature and torsion. (In fact, in this particular example both will be constant.)
    – Travis
    22 hours ago










  • you’re right. I just think in my head the line trasforming into cylinderical helix. Thanks for your comments. But, I have one more question. Then, is it true that the isometry preserves 2nd fundamental coefficients? Now, the other properties are clear for me excepts for 2nd fundamental coefficients.
    – Primavera
    22 hours ago












  • What are the second fundamental forms for the two surfaces in the hint?
    – Travis
    22 hours ago










  • Oh, sorry. I have a mistake in calculating of 2nd fundamental coefficients the latter one. Thank you! Now, all things clear!
    – Primavera
    22 hours ago















up vote
1
down vote













Hint Consider an isometry from a subset of a plane in $Bbb R^3$ to a subset of a cylinder in $Bbb R^3$.






share|cite|improve this answer





















  • Consider the A4 paper and drawing a diagonal line on the paper. Then, both of the curvature and torsion of the diagonal line is zero in A4 paper. But, they are non-zero in cylinder in $mathbb{R}^{3}$ if we bend the A4 paper into cylinder. Right?
    – Primavera
    22 hours ago












  • It depends on how the paper is bent, but if either of the side pairs are parallel to the axis of the cylinder, for example, then the curve will have nonzero curvature and torsion. (In fact, in this particular example both will be constant.)
    – Travis
    22 hours ago










  • you’re right. I just think in my head the line trasforming into cylinderical helix. Thanks for your comments. But, I have one more question. Then, is it true that the isometry preserves 2nd fundamental coefficients? Now, the other properties are clear for me excepts for 2nd fundamental coefficients.
    – Primavera
    22 hours ago












  • What are the second fundamental forms for the two surfaces in the hint?
    – Travis
    22 hours ago










  • Oh, sorry. I have a mistake in calculating of 2nd fundamental coefficients the latter one. Thank you! Now, all things clear!
    – Primavera
    22 hours ago













up vote
1
down vote










up vote
1
down vote









Hint Consider an isometry from a subset of a plane in $Bbb R^3$ to a subset of a cylinder in $Bbb R^3$.






share|cite|improve this answer












Hint Consider an isometry from a subset of a plane in $Bbb R^3$ to a subset of a cylinder in $Bbb R^3$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered yesterday









Travis

58.7k765142




58.7k765142












  • Consider the A4 paper and drawing a diagonal line on the paper. Then, both of the curvature and torsion of the diagonal line is zero in A4 paper. But, they are non-zero in cylinder in $mathbb{R}^{3}$ if we bend the A4 paper into cylinder. Right?
    – Primavera
    22 hours ago












  • It depends on how the paper is bent, but if either of the side pairs are parallel to the axis of the cylinder, for example, then the curve will have nonzero curvature and torsion. (In fact, in this particular example both will be constant.)
    – Travis
    22 hours ago










  • you’re right. I just think in my head the line trasforming into cylinderical helix. Thanks for your comments. But, I have one more question. Then, is it true that the isometry preserves 2nd fundamental coefficients? Now, the other properties are clear for me excepts for 2nd fundamental coefficients.
    – Primavera
    22 hours ago












  • What are the second fundamental forms for the two surfaces in the hint?
    – Travis
    22 hours ago










  • Oh, sorry. I have a mistake in calculating of 2nd fundamental coefficients the latter one. Thank you! Now, all things clear!
    – Primavera
    22 hours ago


















  • Consider the A4 paper and drawing a diagonal line on the paper. Then, both of the curvature and torsion of the diagonal line is zero in A4 paper. But, they are non-zero in cylinder in $mathbb{R}^{3}$ if we bend the A4 paper into cylinder. Right?
    – Primavera
    22 hours ago












  • It depends on how the paper is bent, but if either of the side pairs are parallel to the axis of the cylinder, for example, then the curve will have nonzero curvature and torsion. (In fact, in this particular example both will be constant.)
    – Travis
    22 hours ago










  • you’re right. I just think in my head the line trasforming into cylinderical helix. Thanks for your comments. But, I have one more question. Then, is it true that the isometry preserves 2nd fundamental coefficients? Now, the other properties are clear for me excepts for 2nd fundamental coefficients.
    – Primavera
    22 hours ago












  • What are the second fundamental forms for the two surfaces in the hint?
    – Travis
    22 hours ago










  • Oh, sorry. I have a mistake in calculating of 2nd fundamental coefficients the latter one. Thank you! Now, all things clear!
    – Primavera
    22 hours ago
















Consider the A4 paper and drawing a diagonal line on the paper. Then, both of the curvature and torsion of the diagonal line is zero in A4 paper. But, they are non-zero in cylinder in $mathbb{R}^{3}$ if we bend the A4 paper into cylinder. Right?
– Primavera
22 hours ago






Consider the A4 paper and drawing a diagonal line on the paper. Then, both of the curvature and torsion of the diagonal line is zero in A4 paper. But, they are non-zero in cylinder in $mathbb{R}^{3}$ if we bend the A4 paper into cylinder. Right?
– Primavera
22 hours ago














It depends on how the paper is bent, but if either of the side pairs are parallel to the axis of the cylinder, for example, then the curve will have nonzero curvature and torsion. (In fact, in this particular example both will be constant.)
– Travis
22 hours ago




It depends on how the paper is bent, but if either of the side pairs are parallel to the axis of the cylinder, for example, then the curve will have nonzero curvature and torsion. (In fact, in this particular example both will be constant.)
– Travis
22 hours ago












you’re right. I just think in my head the line trasforming into cylinderical helix. Thanks for your comments. But, I have one more question. Then, is it true that the isometry preserves 2nd fundamental coefficients? Now, the other properties are clear for me excepts for 2nd fundamental coefficients.
– Primavera
22 hours ago






you’re right. I just think in my head the line trasforming into cylinderical helix. Thanks for your comments. But, I have one more question. Then, is it true that the isometry preserves 2nd fundamental coefficients? Now, the other properties are clear for me excepts for 2nd fundamental coefficients.
– Primavera
22 hours ago














What are the second fundamental forms for the two surfaces in the hint?
– Travis
22 hours ago




What are the second fundamental forms for the two surfaces in the hint?
– Travis
22 hours ago












Oh, sorry. I have a mistake in calculating of 2nd fundamental coefficients the latter one. Thank you! Now, all things clear!
– Primavera
22 hours ago




Oh, sorry. I have a mistake in calculating of 2nd fundamental coefficients the latter one. Thank you! Now, all things clear!
– Primavera
22 hours ago


















 

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