Does paracompact Hausdorff imply perfectly normal?












6












$begingroup$


That paracompact Hausdorff implies normal is standard and there are examples on StackExchange of perfectly normal Hausdorff spaces that are not paracompact, but I'm not sure of the answer, especially since paracompact spaces are collection-wise normal and the latter is not related to perfectly normal. (The standard example of a collection-wise normal space that is not perfectly normal is $omega_1$, which is not paracompact.)










share|cite|improve this question











$endgroup$

















    6












    $begingroup$


    That paracompact Hausdorff implies normal is standard and there are examples on StackExchange of perfectly normal Hausdorff spaces that are not paracompact, but I'm not sure of the answer, especially since paracompact spaces are collection-wise normal and the latter is not related to perfectly normal. (The standard example of a collection-wise normal space that is not perfectly normal is $omega_1$, which is not paracompact.)










    share|cite|improve this question











    $endgroup$















      6












      6








      6


      1



      $begingroup$


      That paracompact Hausdorff implies normal is standard and there are examples on StackExchange of perfectly normal Hausdorff spaces that are not paracompact, but I'm not sure of the answer, especially since paracompact spaces are collection-wise normal and the latter is not related to perfectly normal. (The standard example of a collection-wise normal space that is not perfectly normal is $omega_1$, which is not paracompact.)










      share|cite|improve this question











      $endgroup$




      That paracompact Hausdorff implies normal is standard and there are examples on StackExchange of perfectly normal Hausdorff spaces that are not paracompact, but I'm not sure of the answer, especially since paracompact spaces are collection-wise normal and the latter is not related to perfectly normal. (The standard example of a collection-wise normal space that is not perfectly normal is $omega_1$, which is not paracompact.)







      general-topology examples-counterexamples separation-axioms paracompactness






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Dec 9 '18 at 3:29









      Eric Wofsey

      183k13211338




      183k13211338










      asked Jun 24 '14 at 10:16









      chrystomathchrystomath

      332




      332






















          1 Answer
          1






          active

          oldest

          votes


















          3












          $begingroup$

          No. Consider the closed ordinal space $omega_1+1 = [0,omega_1]$. Since it is compact, it is clearly paracompact, and is also Hausdorff. But it is not perfectly normal: the (closed) singleton ${ omega_1 }$ is not a Gδ subset.






          share|cite|improve this answer









          $endgroup$









          • 1




            $begingroup$
            Thanks! So even a compact hausdorff space need not be perfectly normal.
            $endgroup$
            – chrystomath
            Jun 24 '14 at 10:51






          • 1




            $begingroup$
            @chrystomath: You're welcome! Yes, compact Hausdorff spaces need not be perfectly normal. In fact, they may fail to be even hereditarily normal: for example, the Tychonoff plank.
            $endgroup$
            – user642796
            Jun 24 '14 at 11:31













          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f845656%2fdoes-paracompact-hausdorff-imply-perfectly-normal%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3












          $begingroup$

          No. Consider the closed ordinal space $omega_1+1 = [0,omega_1]$. Since it is compact, it is clearly paracompact, and is also Hausdorff. But it is not perfectly normal: the (closed) singleton ${ omega_1 }$ is not a Gδ subset.






          share|cite|improve this answer









          $endgroup$









          • 1




            $begingroup$
            Thanks! So even a compact hausdorff space need not be perfectly normal.
            $endgroup$
            – chrystomath
            Jun 24 '14 at 10:51






          • 1




            $begingroup$
            @chrystomath: You're welcome! Yes, compact Hausdorff spaces need not be perfectly normal. In fact, they may fail to be even hereditarily normal: for example, the Tychonoff plank.
            $endgroup$
            – user642796
            Jun 24 '14 at 11:31


















          3












          $begingroup$

          No. Consider the closed ordinal space $omega_1+1 = [0,omega_1]$. Since it is compact, it is clearly paracompact, and is also Hausdorff. But it is not perfectly normal: the (closed) singleton ${ omega_1 }$ is not a Gδ subset.






          share|cite|improve this answer









          $endgroup$









          • 1




            $begingroup$
            Thanks! So even a compact hausdorff space need not be perfectly normal.
            $endgroup$
            – chrystomath
            Jun 24 '14 at 10:51






          • 1




            $begingroup$
            @chrystomath: You're welcome! Yes, compact Hausdorff spaces need not be perfectly normal. In fact, they may fail to be even hereditarily normal: for example, the Tychonoff plank.
            $endgroup$
            – user642796
            Jun 24 '14 at 11:31
















          3












          3








          3





          $begingroup$

          No. Consider the closed ordinal space $omega_1+1 = [0,omega_1]$. Since it is compact, it is clearly paracompact, and is also Hausdorff. But it is not perfectly normal: the (closed) singleton ${ omega_1 }$ is not a Gδ subset.






          share|cite|improve this answer









          $endgroup$



          No. Consider the closed ordinal space $omega_1+1 = [0,omega_1]$. Since it is compact, it is clearly paracompact, and is also Hausdorff. But it is not perfectly normal: the (closed) singleton ${ omega_1 }$ is not a Gδ subset.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jun 24 '14 at 10:22









          user642796user642796

          44.5k560116




          44.5k560116








          • 1




            $begingroup$
            Thanks! So even a compact hausdorff space need not be perfectly normal.
            $endgroup$
            – chrystomath
            Jun 24 '14 at 10:51






          • 1




            $begingroup$
            @chrystomath: You're welcome! Yes, compact Hausdorff spaces need not be perfectly normal. In fact, they may fail to be even hereditarily normal: for example, the Tychonoff plank.
            $endgroup$
            – user642796
            Jun 24 '14 at 11:31
















          • 1




            $begingroup$
            Thanks! So even a compact hausdorff space need not be perfectly normal.
            $endgroup$
            – chrystomath
            Jun 24 '14 at 10:51






          • 1




            $begingroup$
            @chrystomath: You're welcome! Yes, compact Hausdorff spaces need not be perfectly normal. In fact, they may fail to be even hereditarily normal: for example, the Tychonoff plank.
            $endgroup$
            – user642796
            Jun 24 '14 at 11:31










          1




          1




          $begingroup$
          Thanks! So even a compact hausdorff space need not be perfectly normal.
          $endgroup$
          – chrystomath
          Jun 24 '14 at 10:51




          $begingroup$
          Thanks! So even a compact hausdorff space need not be perfectly normal.
          $endgroup$
          – chrystomath
          Jun 24 '14 at 10:51




          1




          1




          $begingroup$
          @chrystomath: You're welcome! Yes, compact Hausdorff spaces need not be perfectly normal. In fact, they may fail to be even hereditarily normal: for example, the Tychonoff plank.
          $endgroup$
          – user642796
          Jun 24 '14 at 11:31






          $begingroup$
          @chrystomath: You're welcome! Yes, compact Hausdorff spaces need not be perfectly normal. In fact, they may fail to be even hereditarily normal: for example, the Tychonoff plank.
          $endgroup$
          – user642796
          Jun 24 '14 at 11:31




















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Mathematics Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f845656%2fdoes-paracompact-hausdorff-imply-perfectly-normal%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          To store a contact into the json file from server.js file using a class in NodeJS

          Marschland

          Redirect URL with Chrome Remote Debugging Android Devices