Split string into list contains alphabetical bullet list
5
My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]
The code which i have used is not providing me the desired result
re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)
Please help me regarding this
python string python-3.x
edited Nov 22 '18 at 12:24
Patrick Artner
23.1k62343
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
373210
add a comment |
5
My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]
The code which i have used is not providing me the desired result
re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)
Please help me regarding this
python string python-3.x
edited Nov 22 '18 at 12:24
Patrick Artner
23.1k62343
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
373210
Is it possible to have a string likea) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?
– lxop
Nov 22 '18 at 12:16
You are missing therat the start of your regex pattern string.
– usr2564301
Nov 22 '18 at 12:26
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails forc) A
– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
add a comment |
5
5
5
My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]
The code which i have used is not providing me the desired result
re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)
Please help me regarding this
python string python-3.x
edited Nov 22 '18 at 12:24
Patrick Artner
23.1k62343
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
373210
My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]
The code which i have used is not providing me the desired result
re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)
Please help me regarding this
python string python-3.x
python string python-3.x
edited Nov 22 '18 at 12:24
Patrick Artner
23.1k62343
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
373210
edited Nov 22 '18 at 12:24
Patrick Artner
23.1k62343
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
373210
edited Nov 22 '18 at 12:24
Patrick Artner
23.1k62343
edited Nov 22 '18 at 12:24
Patrick Artner
23.1k62343
edited Nov 22 '18 at 12:24
Patrick Artner
23.1k62343
23.1k62343
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
373210
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
373210
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
373210
373210
Is it possible to have a string likea) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?
– lxop
Nov 22 '18 at 12:16
You are missing therat the start of your regex pattern string.
– usr2564301
Nov 22 '18 at 12:26
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails forc) A
– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
add a comment |
Is it possible to have a string likea) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?
– lxop
Nov 22 '18 at 12:16
You are missing therat the start of your regex pattern string.
– usr2564301
Nov 22 '18 at 12:26
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails forc) A
– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
Is it possible to have a string like
a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?– lxop
Nov 22 '18 at 12:16
Is it possible to have a string like
a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?– lxop
Nov 22 '18 at 12:16
You are missing the
r at the start of your regex pattern string.– usr2564301
Nov 22 '18 at 12:26
You are missing the
r at the start of your regex pattern string.– usr2564301
Nov 22 '18 at 12:26
1
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails for
c) A– planetmaker
Nov 22 '18 at 12:46
@SarthakNegi that fails for
c) A– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
add a comment |
2 Answers
2
active
oldest
votes
3
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
23.1k62343
add a comment |
1
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
41k42853
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53430766%2fsplit-string-into-list-contains-alphabetical-bullet-list%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
23.1k62343
add a comment |
3
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
23.1k62343
add a comment |
3
3
3
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
23.1k62343
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
23.1k62343
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
23.1k62343
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
23.1k62343
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
23.1k62343
23.1k62343
add a comment |
add a comment |
1
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
41k42853
add a comment |
1
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
41k42853
add a comment |
1
1
1
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
41k42853
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
41k42853
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
41k42853
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
41k42853
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
41k42853
41k42853
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53430766%2fsplit-string-into-list-contains-alphabetical-bullet-list%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Is it possible to have a string like
a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?– lxop
Nov 22 '18 at 12:16
You are missing the
rat the start of your regex pattern string.– usr2564301
Nov 22 '18 at 12:26
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails for
c) A– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26