Ytukyg

Have a question here about passing a variable into a Django template. The goal is to filter a set of photos based off the type of photography. I initially wanted to do it from S3 and the folder that it was in, but that's a little beyond my skill at the moment. I went with just creating different url's that account for that. The issue I'm having is that I'd like to pass the variable into the template that extends the base_layout.html, but it won't render anything for that variable. Am I just miss-understanding how to do it?

Model.py

from django.db import models





# Create your models here.

class Gallery(models.Model):

    title = models.CharField(max_length = 50)

    body = models.TextField(max_length = 500)

    created = models.DateTimeField(auto_now_add = True)

    thumb = models.ImageField(default = 'default.jpg', blank = True)

    slug = models.SlugField(blank = True)

    order = models.CharField(max_length = 2, blank = True)



    def __str__(self):

        return self.title



    def body_preview(self):

        return self.body[:50]



class photoUrl(models.Model):

    url = models.CharField(max_length = 128)

    uploaded_on = models.DateTimeField(auto_now_add = True)



class Photos(models.Model):

    title = models.CharField(max_length = 50)

    picture = models.ImageField(blank = True)

    created = models.DateTimeField(auto_now_add = True)

    catagory = models.CharField(max_length=256, choices=[('wedding', 'wedding'), ('portrait', 'portrait'), ('landscape', 'landscape'), ('boudoir', 'boudoir'),], blank = True)



    def __str__(self):

        return self.title

views.py

from django.shortcuts import render

from django.http import HttpResponse

from django.urls import reverse

from . models import Photos



# Create your views here.





def photo_wedding(request):

    photo_list = Photos.objects.filter(catagory = 'wedding').order_by('created')

    photoCat = 'Wedding'

    return render(request, 'gallery/gallery.html', {'photo_list' : photo_list}, {'photoCat' : photoCat})

urls.py

from django.contrib import admin

from django.urls import path

from . import views



app_name='gallery'



urlpatterns = [

    path('wedding/', views.photo_wedding, name='wedding'),

    path('portrait/', views.photo_portrait, name='portrait'),

    path('landscape/', views.photo_landscape, name='landscape'),

    path('boudoir/', views.photo_boudoir, name='boudoir'),

]

gallery.html

{% extends 'gallery/base_layout.html' %}



{% load static %}



{% block gallery %}



    <div class="gallery" id="gallery">

        <div class="container">

            <div class="w3l-heading">



                <h3>{{photoCat}}</h3>



                <div class="w3ls-border"> </div>

            </div>

        </div>

{% endblock gallery %}

From the definition of render:

render(request, template_name, context=None, content_type=None, status=None, using=None)
Combines a given template with a given context dictionary and returns an HttpResponse object with that rendered text.

the render method takes the first parameter as a request, the second parameter as template_name and the third parameter is a context which is of type dictionary you choose to pass to the template, you can access all the values of dictionary with the key.

So your method should look like below:

def photo_wedding(request):

    photo_list = Photos.objects.filter(catagory = 'wedding').order_by('created')

    photoCat = 'Wedding'

    return render(request, 'gallery/gallery.html', {'photo_list' : photo_list, 'photoCat' : photoCat})

Why are you passing two dictionaries. Just add a key. That is the context data.

In class based views you can also overload the method get_context_data

With the render() function, the third argument is the context. The context is a dictionary used to send variable to templates. No need to pass two dicts

def photo_wedding(request):

    photo_list = Photos.objects.filter(catagory = 'wedding').order_by('created')

    photoCat = 'Wedding'

    context = {'photo_list' : photo_list,'photoCat' : photoCat}

    return render(request, 'gallery/gallery.html', context)