Two ships leaving a port at different times and different speeds. When do they meet?
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Can someone please show me the working out to this word problem I have the answer but have no clue how to do the working out.
At noon ship A leaves port steaming at 8 knots 2 hours later ship B leaves same port on the same course steaming at 12 knots.
How far from port will ship B overtake ship A? Answer(48 miles apart)
Show me the working out please.
algebra-precalculus
edited Oct 16 '14 at 22:30
davidlowryduda♦
74.9k7119254
asked Oct 16 '14 at 22:27
math helpmath help
173
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add a comment |
$begingroup$
Can someone please show me the working out to this word problem I have the answer but have no clue how to do the working out.
At noon ship A leaves port steaming at 8 knots 2 hours later ship B leaves same port on the same course steaming at 12 knots.
How far from port will ship B overtake ship A? Answer(48 miles apart)
Show me the working out please.
algebra-precalculus
edited Oct 16 '14 at 22:30
davidlowryduda♦
74.9k7119254
asked Oct 16 '14 at 22:27
math helpmath help
173
$endgroup$
$begingroup$
Nautical miles?
$endgroup$
– ploosu2
Oct 16 '14 at 22:33
$begingroup$
yeah nautical miles
$endgroup$
– math help
Oct 16 '14 at 22:38
add a comment |
$begingroup$
Can someone please show me the working out to this word problem I have the answer but have no clue how to do the working out.
At noon ship A leaves port steaming at 8 knots 2 hours later ship B leaves same port on the same course steaming at 12 knots.
How far from port will ship B overtake ship A? Answer(48 miles apart)
Show me the working out please.
algebra-precalculus
edited Oct 16 '14 at 22:30
davidlowryduda♦
74.9k7119254
asked Oct 16 '14 at 22:27
math helpmath help
173
$endgroup$
Can someone please show me the working out to this word problem I have the answer but have no clue how to do the working out.
At noon ship A leaves port steaming at 8 knots 2 hours later ship B leaves same port on the same course steaming at 12 knots.
How far from port will ship B overtake ship A? Answer(48 miles apart)
Show me the working out please.
algebra-precalculus
algebra-precalculus
edited Oct 16 '14 at 22:30
davidlowryduda♦
74.9k7119254
asked Oct 16 '14 at 22:27
math helpmath help
173
edited Oct 16 '14 at 22:30
davidlowryduda♦
74.9k7119254
asked Oct 16 '14 at 22:27
math helpmath help
173
edited Oct 16 '14 at 22:30
davidlowryduda♦
74.9k7119254
edited Oct 16 '14 at 22:30
davidlowryduda♦
74.9k7119254
edited Oct 16 '14 at 22:30
davidlowryduda♦
74.9k7119254
74.9k7119254
asked Oct 16 '14 at 22:27
math helpmath help
173
asked Oct 16 '14 at 22:27
math helpmath help
173
asked Oct 16 '14 at 22:27
math helpmath help
173
173
$begingroup$
Nautical miles?
$endgroup$
– ploosu2
Oct 16 '14 at 22:33
$begingroup$
yeah nautical miles
$endgroup$
– math help
Oct 16 '14 at 22:38
add a comment |
$begingroup$
Nautical miles?
$endgroup$
– ploosu2
Oct 16 '14 at 22:33
$begingroup$
yeah nautical miles
$endgroup$
– math help
Oct 16 '14 at 22:38
$begingroup$
Nautical miles?
$endgroup$
– ploosu2
Oct 16 '14 at 22:33
$begingroup$
Nautical miles?
$endgroup$
– ploosu2
Oct 16 '14 at 22:33
$begingroup$
yeah nautical miles
$endgroup$
– math help
Oct 16 '14 at 22:38
$begingroup$
yeah nautical miles
$endgroup$
– math help
Oct 16 '14 at 22:38
add a comment |
3 Answers
3
active
oldest
votes
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First A goes 16 miles. Then B leaves, it takes some time to overtake A, let's say time $t$. In this time A travels $8t$ miles and B $12t$ miles. Given these we have that
$$12t = 16 + 8t$$
that is $t=4$. Hence the distance is $12t = 48$.
answered Oct 16 '14 at 22:38
ploosu2ploosu2
4,6431024
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add a comment |
$begingroup$
You might also look there relative speed of the two ships. Ship B is closing in on Ship A at 4 knots. How long with take to close their initial 16 mile separation? Answer: 4 hours.
answered Oct 17 '14 at 3:46
Dan ChristensenDan Christensen
8,64821835
$endgroup$
add a comment |
$begingroup$
$S_1 - S_2 = S_3$ which is how many knots per hour so $S_3=t$.
$S_1 times t = D$
$S_2 times t = D$
$12 - 8 = 4$
$4 times 12 = 48$ nm
$4 times 8 = 48$ nm
edited Dec 19 '18 at 3:39
Brahadeesh
6,46942363
answered Dec 19 '18 at 2:54
Dominic F HixDominic F Hix
11
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add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
First A goes 16 miles. Then B leaves, it takes some time to overtake A, let's say time $t$. In this time A travels $8t$ miles and B $12t$ miles. Given these we have that
$$12t = 16 + 8t$$
that is $t=4$. Hence the distance is $12t = 48$.
answered Oct 16 '14 at 22:38
ploosu2ploosu2
4,6431024
$endgroup$
add a comment |
$begingroup$
First A goes 16 miles. Then B leaves, it takes some time to overtake A, let's say time $t$. In this time A travels $8t$ miles and B $12t$ miles. Given these we have that
$$12t = 16 + 8t$$
that is $t=4$. Hence the distance is $12t = 48$.
answered Oct 16 '14 at 22:38
ploosu2ploosu2
4,6431024
$endgroup$
add a comment |
$begingroup$
First A goes 16 miles. Then B leaves, it takes some time to overtake A, let's say time $t$. In this time A travels $8t$ miles and B $12t$ miles. Given these we have that
$$12t = 16 + 8t$$
that is $t=4$. Hence the distance is $12t = 48$.
answered Oct 16 '14 at 22:38
ploosu2ploosu2
4,6431024
$endgroup$
First A goes 16 miles. Then B leaves, it takes some time to overtake A, let's say time $t$. In this time A travels $8t$ miles and B $12t$ miles. Given these we have that
$$12t = 16 + 8t$$
that is $t=4$. Hence the distance is $12t = 48$.
answered Oct 16 '14 at 22:38
ploosu2ploosu2
4,6431024
answered Oct 16 '14 at 22:38
ploosu2ploosu2
4,6431024
answered Oct 16 '14 at 22:38
ploosu2ploosu2
4,6431024
answered Oct 16 '14 at 22:38
ploosu2ploosu2
4,6431024
4,6431024
add a comment |
add a comment |
$begingroup$
You might also look there relative speed of the two ships. Ship B is closing in on Ship A at 4 knots. How long with take to close their initial 16 mile separation? Answer: 4 hours.
answered Oct 17 '14 at 3:46
Dan ChristensenDan Christensen
8,64821835
$endgroup$
add a comment |
$begingroup$
You might also look there relative speed of the two ships. Ship B is closing in on Ship A at 4 knots. How long with take to close their initial 16 mile separation? Answer: 4 hours.
answered Oct 17 '14 at 3:46
Dan ChristensenDan Christensen
8,64821835
$endgroup$
add a comment |
$begingroup$
You might also look there relative speed of the two ships. Ship B is closing in on Ship A at 4 knots. How long with take to close their initial 16 mile separation? Answer: 4 hours.
answered Oct 17 '14 at 3:46
Dan ChristensenDan Christensen
8,64821835
$endgroup$
You might also look there relative speed of the two ships. Ship B is closing in on Ship A at 4 knots. How long with take to close their initial 16 mile separation? Answer: 4 hours.
answered Oct 17 '14 at 3:46
Dan ChristensenDan Christensen
8,64821835
answered Oct 17 '14 at 3:46
Dan ChristensenDan Christensen
8,64821835
answered Oct 17 '14 at 3:46
Dan ChristensenDan Christensen
8,64821835
answered Oct 17 '14 at 3:46
Dan ChristensenDan Christensen
8,64821835
8,64821835
add a comment |
add a comment |
$begingroup$
$S_1 - S_2 = S_3$ which is how many knots per hour so $S_3=t$.
$S_1 times t = D$
$S_2 times t = D$
$12 - 8 = 4$
$4 times 12 = 48$ nm
$4 times 8 = 48$ nm
edited Dec 19 '18 at 3:39
Brahadeesh
6,46942363
answered Dec 19 '18 at 2:54
Dominic F HixDominic F Hix
11
$endgroup$
add a comment |
$begingroup$
$S_1 - S_2 = S_3$ which is how many knots per hour so $S_3=t$.
$S_1 times t = D$
$S_2 times t = D$
$12 - 8 = 4$
$4 times 12 = 48$ nm
$4 times 8 = 48$ nm
edited Dec 19 '18 at 3:39
Brahadeesh
6,46942363
answered Dec 19 '18 at 2:54
Dominic F HixDominic F Hix
11
$endgroup$
add a comment |
$begingroup$
$S_1 - S_2 = S_3$ which is how many knots per hour so $S_3=t$.
$S_1 times t = D$
$S_2 times t = D$
$12 - 8 = 4$
$4 times 12 = 48$ nm
$4 times 8 = 48$ nm
edited Dec 19 '18 at 3:39
Brahadeesh
6,46942363
answered Dec 19 '18 at 2:54
Dominic F HixDominic F Hix
11
$endgroup$
$S_1 - S_2 = S_3$ which is how many knots per hour so $S_3=t$.
$S_1 times t = D$
$S_2 times t = D$
$12 - 8 = 4$
$4 times 12 = 48$ nm
$4 times 8 = 48$ nm
edited Dec 19 '18 at 3:39
Brahadeesh
6,46942363
answered Dec 19 '18 at 2:54
Dominic F HixDominic F Hix
11
edited Dec 19 '18 at 3:39
Brahadeesh
6,46942363
edited Dec 19 '18 at 3:39
Brahadeesh
6,46942363
edited Dec 19 '18 at 3:39
Brahadeesh
6,46942363
6,46942363
answered Dec 19 '18 at 2:54
Dominic F HixDominic F Hix
11
answered Dec 19 '18 at 2:54
Dominic F HixDominic F Hix
11
answered Dec 19 '18 at 2:54
Dominic F HixDominic F Hix
11
11
add a comment |
add a comment |
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$begingroup$
Nautical miles?
$endgroup$
– ploosu2
Oct 16 '14 at 22:33
$begingroup$
yeah nautical miles
$endgroup$
– math help
Oct 16 '14 at 22:38