Pathfinding algorithm constrained to one-way roads












0















Say I have 5 "towns": A, B, C, D and E.



Now I want to figure out a path between these towns, but I am constrained to roads, for example A only has roads to B, C and E and B only has a road to C etc.



I can't visit a town twice and the roads are only one-way. I want to "visit" all the towns. How would I programmatically solve this?



I've already tried starting at A, then seeing what roads there are and checking each option, although all my tries so far at implementing this have failed.










share|improve this question

























  • What have you done so far? I did a quick google search and a few introduction popped up. Could you please add your attempts you did so far? Finally, you are mentioning three towns but to me it looks like every character represents one town and you have five characters (=5 towns).

    – Alex_P
    Nov 24 '18 at 8:12











  • sounds very similar to node pathing in a network

    – John Lord
    Nov 24 '18 at 8:24











  • @Alex_P Sorry, there are indeed 5 towns, that was a typo. Could you link the resources you found? I couldn't really find anything myself, but that might just be my search query. As for what I've already tried, I've updated the post with that.

    – Melluh
    Nov 24 '18 at 8:48











  • Did you see the links I posted? Did you find them before?

    – Alex_P
    Nov 24 '18 at 15:19











  • Voting to close due to lack of research. The keywords to google are "directed graphs" and "traveling salesman problem"

    – BlueRaja - Danny Pflughoeft
    Nov 24 '18 at 17:14
















0















Say I have 5 "towns": A, B, C, D and E.



Now I want to figure out a path between these towns, but I am constrained to roads, for example A only has roads to B, C and E and B only has a road to C etc.



I can't visit a town twice and the roads are only one-way. I want to "visit" all the towns. How would I programmatically solve this?



I've already tried starting at A, then seeing what roads there are and checking each option, although all my tries so far at implementing this have failed.










share|improve this question

























  • What have you done so far? I did a quick google search and a few introduction popped up. Could you please add your attempts you did so far? Finally, you are mentioning three towns but to me it looks like every character represents one town and you have five characters (=5 towns).

    – Alex_P
    Nov 24 '18 at 8:12











  • sounds very similar to node pathing in a network

    – John Lord
    Nov 24 '18 at 8:24











  • @Alex_P Sorry, there are indeed 5 towns, that was a typo. Could you link the resources you found? I couldn't really find anything myself, but that might just be my search query. As for what I've already tried, I've updated the post with that.

    – Melluh
    Nov 24 '18 at 8:48











  • Did you see the links I posted? Did you find them before?

    – Alex_P
    Nov 24 '18 at 15:19











  • Voting to close due to lack of research. The keywords to google are "directed graphs" and "traveling salesman problem"

    – BlueRaja - Danny Pflughoeft
    Nov 24 '18 at 17:14














0












0








0








Say I have 5 "towns": A, B, C, D and E.



Now I want to figure out a path between these towns, but I am constrained to roads, for example A only has roads to B, C and E and B only has a road to C etc.



I can't visit a town twice and the roads are only one-way. I want to "visit" all the towns. How would I programmatically solve this?



I've already tried starting at A, then seeing what roads there are and checking each option, although all my tries so far at implementing this have failed.










share|improve this question
















Say I have 5 "towns": A, B, C, D and E.



Now I want to figure out a path between these towns, but I am constrained to roads, for example A only has roads to B, C and E and B only has a road to C etc.



I can't visit a town twice and the roads are only one-way. I want to "visit" all the towns. How would I programmatically solve this?



I've already tried starting at A, then seeing what roads there are and checking each option, although all my tries so far at implementing this have failed.







algorithm path-finding






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 9:57









Gihan Saranga Siriwardhana

615424




615424










asked Nov 24 '18 at 8:05









MelluhMelluh

14




14













  • What have you done so far? I did a quick google search and a few introduction popped up. Could you please add your attempts you did so far? Finally, you are mentioning three towns but to me it looks like every character represents one town and you have five characters (=5 towns).

    – Alex_P
    Nov 24 '18 at 8:12











  • sounds very similar to node pathing in a network

    – John Lord
    Nov 24 '18 at 8:24











  • @Alex_P Sorry, there are indeed 5 towns, that was a typo. Could you link the resources you found? I couldn't really find anything myself, but that might just be my search query. As for what I've already tried, I've updated the post with that.

    – Melluh
    Nov 24 '18 at 8:48











  • Did you see the links I posted? Did you find them before?

    – Alex_P
    Nov 24 '18 at 15:19











  • Voting to close due to lack of research. The keywords to google are "directed graphs" and "traveling salesman problem"

    – BlueRaja - Danny Pflughoeft
    Nov 24 '18 at 17:14



















  • What have you done so far? I did a quick google search and a few introduction popped up. Could you please add your attempts you did so far? Finally, you are mentioning three towns but to me it looks like every character represents one town and you have five characters (=5 towns).

    – Alex_P
    Nov 24 '18 at 8:12











  • sounds very similar to node pathing in a network

    – John Lord
    Nov 24 '18 at 8:24











  • @Alex_P Sorry, there are indeed 5 towns, that was a typo. Could you link the resources you found? I couldn't really find anything myself, but that might just be my search query. As for what I've already tried, I've updated the post with that.

    – Melluh
    Nov 24 '18 at 8:48











  • Did you see the links I posted? Did you find them before?

    – Alex_P
    Nov 24 '18 at 15:19











  • Voting to close due to lack of research. The keywords to google are "directed graphs" and "traveling salesman problem"

    – BlueRaja - Danny Pflughoeft
    Nov 24 '18 at 17:14

















What have you done so far? I did a quick google search and a few introduction popped up. Could you please add your attempts you did so far? Finally, you are mentioning three towns but to me it looks like every character represents one town and you have five characters (=5 towns).

– Alex_P
Nov 24 '18 at 8:12





What have you done so far? I did a quick google search and a few introduction popped up. Could you please add your attempts you did so far? Finally, you are mentioning three towns but to me it looks like every character represents one town and you have five characters (=5 towns).

– Alex_P
Nov 24 '18 at 8:12













sounds very similar to node pathing in a network

– John Lord
Nov 24 '18 at 8:24





sounds very similar to node pathing in a network

– John Lord
Nov 24 '18 at 8:24













@Alex_P Sorry, there are indeed 5 towns, that was a typo. Could you link the resources you found? I couldn't really find anything myself, but that might just be my search query. As for what I've already tried, I've updated the post with that.

– Melluh
Nov 24 '18 at 8:48





@Alex_P Sorry, there are indeed 5 towns, that was a typo. Could you link the resources you found? I couldn't really find anything myself, but that might just be my search query. As for what I've already tried, I've updated the post with that.

– Melluh
Nov 24 '18 at 8:48













Did you see the links I posted? Did you find them before?

– Alex_P
Nov 24 '18 at 15:19





Did you see the links I posted? Did you find them before?

– Alex_P
Nov 24 '18 at 15:19













Voting to close due to lack of research. The keywords to google are "directed graphs" and "traveling salesman problem"

– BlueRaja - Danny Pflughoeft
Nov 24 '18 at 17:14





Voting to close due to lack of research. The keywords to google are "directed graphs" and "traveling salesman problem"

– BlueRaja - Danny Pflughoeft
Nov 24 '18 at 17:14












0






active

oldest

votes











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53456331%2fpathfinding-algorithm-constrained-to-one-way-roads%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53456331%2fpathfinding-algorithm-constrained-to-one-way-roads%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Wiesbaden

Marschland

Dieringhausen