Problem to implement an insertion algorithms
0
I write such a insertion algorithms:
In [33]: %paste
def insertion_sort2(arr):
for i in range(1, len(arr)):
insert_item = arr[i]
for j in range(i):#insert to sorted array arr[:i]
if insert_item < arr[j]:
arr[j] = insert_item
Test it
In [35]: arr
Out[35]: [0, 0, 0, 2, 3, 3, 6, 6, 6]
In [36]: arr = list(range(9))
In [37]: random.shuffle(arr)
In [38]: insertion_sort2(arr)
In [39]: arr
Out[39]: [0, 0, 0, 0, 0, 0, 3, 3, 3]
I check the logic but cannot find any problem.
1. i in arr[1:len]
2. insert arr[i] to arr[:i]
What' the problem with my implementation?
python algorithm
asked Nov 24 '18 at 6:04
JawSawJawSaw
4,57811837
add a comment |
0
I write such a insertion algorithms:
In [33]: %paste
def insertion_sort2(arr):
for i in range(1, len(arr)):
insert_item = arr[i]
for j in range(i):#insert to sorted array arr[:i]
if insert_item < arr[j]:
arr[j] = insert_item
Test it
In [35]: arr
Out[35]: [0, 0, 0, 2, 3, 3, 6, 6, 6]
In [36]: arr = list(range(9))
In [37]: random.shuffle(arr)
In [38]: insertion_sort2(arr)
In [39]: arr
Out[39]: [0, 0, 0, 0, 0, 0, 3, 3, 3]
I check the logic but cannot find any problem.
1. i in arr[1:len]
2. insert arr[i] to arr[:i]
What' the problem with my implementation?
python algorithm
asked Nov 24 '18 at 6:04
JawSawJawSaw
4,57811837
add a comment |
0
0
0
I write such a insertion algorithms:
In [33]: %paste
def insertion_sort2(arr):
for i in range(1, len(arr)):
insert_item = arr[i]
for j in range(i):#insert to sorted array arr[:i]
if insert_item < arr[j]:
arr[j] = insert_item
Test it
In [35]: arr
Out[35]: [0, 0, 0, 2, 3, 3, 6, 6, 6]
In [36]: arr = list(range(9))
In [37]: random.shuffle(arr)
In [38]: insertion_sort2(arr)
In [39]: arr
Out[39]: [0, 0, 0, 0, 0, 0, 3, 3, 3]
I check the logic but cannot find any problem.
1. i in arr[1:len]
2. insert arr[i] to arr[:i]
What' the problem with my implementation?
python algorithm
asked Nov 24 '18 at 6:04
JawSawJawSaw
4,57811837
I write such a insertion algorithms:
In [33]: %paste
def insertion_sort2(arr):
for i in range(1, len(arr)):
insert_item = arr[i]
for j in range(i):#insert to sorted array arr[:i]
if insert_item < arr[j]:
arr[j] = insert_item
Test it
In [35]: arr
Out[35]: [0, 0, 0, 2, 3, 3, 6, 6, 6]
In [36]: arr = list(range(9))
In [37]: random.shuffle(arr)
In [38]: insertion_sort2(arr)
In [39]: arr
Out[39]: [0, 0, 0, 0, 0, 0, 3, 3, 3]
I check the logic but cannot find any problem.
1. i in arr[1:len]
2. insert arr[i] to arr[:i]
What' the problem with my implementation?
python algorithm
python algorithm
asked Nov 24 '18 at 6:04
JawSawJawSaw
4,57811837
asked Nov 24 '18 at 6:04
JawSawJawSaw
4,57811837
asked Nov 24 '18 at 6:04
JawSawJawSaw
4,57811837
asked Nov 24 '18 at 6:04
JawSawJawSaw
4,57811837
asked Nov 24 '18 at 6:04
JawSawJawSaw
4,57811837
4,57811837
add a comment |
add a comment |
1 Answer
1
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1
The line
arr[j] = insert_item
overwrites arr[j]. It does NOT insert.
>>> l = list(range(10))
>>> l
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> l[3] = 'foo'
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 7, 8, 9]
>>> l.insert(7, 'bar')
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 'bar', 7, 8, 9]
answered Nov 24 '18 at 6:10
Martin ThomaMartin Thoma
42.9k60304525
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
The line
arr[j] = insert_item
overwrites arr[j]. It does NOT insert.
>>> l = list(range(10))
>>> l
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> l[3] = 'foo'
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 7, 8, 9]
>>> l.insert(7, 'bar')
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 'bar', 7, 8, 9]
answered Nov 24 '18 at 6:10
Martin ThomaMartin Thoma
42.9k60304525
add a comment |
1
The line
arr[j] = insert_item
overwrites arr[j]. It does NOT insert.
>>> l = list(range(10))
>>> l
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> l[3] = 'foo'
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 7, 8, 9]
>>> l.insert(7, 'bar')
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 'bar', 7, 8, 9]
answered Nov 24 '18 at 6:10
Martin ThomaMartin Thoma
42.9k60304525
add a comment |
1
1
1
The line
arr[j] = insert_item
overwrites arr[j]. It does NOT insert.
>>> l = list(range(10))
>>> l
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> l[3] = 'foo'
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 7, 8, 9]
>>> l.insert(7, 'bar')
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 'bar', 7, 8, 9]
answered Nov 24 '18 at 6:10
Martin ThomaMartin Thoma
42.9k60304525
The line
arr[j] = insert_item
overwrites arr[j]. It does NOT insert.
>>> l = list(range(10))
>>> l
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> l[3] = 'foo'
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 7, 8, 9]
>>> l.insert(7, 'bar')
>>> l
[0, 1, 2, 'foo', 4, 5, 6, 'bar', 7, 8, 9]
answered Nov 24 '18 at 6:10
Martin ThomaMartin Thoma
42.9k60304525
answered Nov 24 '18 at 6:10
Martin ThomaMartin Thoma
42.9k60304525
answered Nov 24 '18 at 6:10
Martin ThomaMartin Thoma
42.9k60304525
answered Nov 24 '18 at 6:10
Martin ThomaMartin Thoma
42.9k60304525
42.9k60304525
add a comment |
add a comment |
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