Avoid specifying guard clause when using struct












0















I have a struct:



defmodule Company do
defstruct [:id, :name, :active]
end


I have a function that requires one of its arguments to be of this struct:



def create(connection, %Company{id: id} = company) do
# stuff
end


Is there any way I can enforce type-checking without using a guard clause? Right now I have to do this:



def create(connection, %Company{id: id, name: name, active: active})
when is_integer(id) and is_binary(name) and is_boolean(active) do
# stuff
end


Edit: this question in specific is regarding arguments in a function definition that use a struct.










share|improve this question

























  • Possible duplicate of How can types and values be validated / enforced for Elixir structs?

    – Gabriel Prá
    Nov 25 '18 at 15:23
















0















I have a struct:



defmodule Company do
defstruct [:id, :name, :active]
end


I have a function that requires one of its arguments to be of this struct:



def create(connection, %Company{id: id} = company) do
# stuff
end


Is there any way I can enforce type-checking without using a guard clause? Right now I have to do this:



def create(connection, %Company{id: id, name: name, active: active})
when is_integer(id) and is_binary(name) and is_boolean(active) do
# stuff
end


Edit: this question in specific is regarding arguments in a function definition that use a struct.










share|improve this question

























  • Possible duplicate of How can types and values be validated / enforced for Elixir structs?

    – Gabriel Prá
    Nov 25 '18 at 15:23














0












0








0








I have a struct:



defmodule Company do
defstruct [:id, :name, :active]
end


I have a function that requires one of its arguments to be of this struct:



def create(connection, %Company{id: id} = company) do
# stuff
end


Is there any way I can enforce type-checking without using a guard clause? Right now I have to do this:



def create(connection, %Company{id: id, name: name, active: active})
when is_integer(id) and is_binary(name) and is_boolean(active) do
# stuff
end


Edit: this question in specific is regarding arguments in a function definition that use a struct.










share|improve this question
















I have a struct:



defmodule Company do
defstruct [:id, :name, :active]
end


I have a function that requires one of its arguments to be of this struct:



def create(connection, %Company{id: id} = company) do
# stuff
end


Is there any way I can enforce type-checking without using a guard clause? Right now I have to do this:



def create(connection, %Company{id: id, name: name, active: active})
when is_integer(id) and is_binary(name) and is_boolean(active) do
# stuff
end


Edit: this question in specific is regarding arguments in a function definition that use a struct.







elixir






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share|improve this question













share|improve this question




share|improve this question








edited Nov 25 '18 at 19:42







dimiguel

















asked Nov 25 '18 at 9:48









dimigueldimiguel

730824




730824













  • Possible duplicate of How can types and values be validated / enforced for Elixir structs?

    – Gabriel Prá
    Nov 25 '18 at 15:23



















  • Possible duplicate of How can types and values be validated / enforced for Elixir structs?

    – Gabriel Prá
    Nov 25 '18 at 15:23

















Possible duplicate of How can types and values be validated / enforced for Elixir structs?

– Gabriel Prá
Nov 25 '18 at 15:23





Possible duplicate of How can types and values be validated / enforced for Elixir structs?

– Gabriel Prá
Nov 25 '18 at 15:23












3 Answers
3






active

oldest

votes


















2














No, there is no way to enforce type check without guards. Erlang (and hence Elixir) is a dynamically typed language and you might want to have different clauses for different types passed, e.g. an error message if the types do not conform, or just sink the input out, or whatever.



def create(connection, %Company{id: id})
when not is_integer(id) do
raise "Must be integer"
end


Erlang does not take out the liberty to deal with not proper input in the way you need, that is why guards you use is the way to go.





There is static analysis tool, dialyzer, you might use to statically check types, also it does not prevent the compiler and runtime to pass whatever type is passed.






share|improve this answer































    0














    As @Aleksei has already pointed out, type-checking is not enforced in Elixir since it's a dynamically-typed language, so to do it manually we usually do it in a guard clause.



    But repeating the same set of clauses over and over again can be messy, tiring and error-prone. Though you could "validate" them in a separate function and make it easier, but it won't be as performant as guards:





    defmodule Company do
    defstruct [:id, :name, :active]

    def create(connection, company) do
    with :ok <- validate(company) do
    # do something
    end
    end

    defp validate(%Company{id: id, name: name, active: active})
    when is_integer(id) and is_binary(name) and is_boolean(active),
    do: :ok

    defp validate(_term), do: raise "Invalid Company"
    end


    Now calling the function for Company would work as expected, while it would raise errors for other terms:



    Company.create(1, %Company{})
    # => ** (RuntimeError) Invalid Company

    Company.create(2, %Company{id: 1, name: "hello", active: false})
    # => ... (works normally)




    If your use-case was simpler, you could've retained the performance by defining a custom guard-clause.






    share|improve this answer

































      0














      I think its more idiomatic in Elixir to consider the contents of a struct to be valid data. And to provide a factory function to create a struct as part of your public API as @Sheharyar suggests above. I typically see the function be called new not create but thats preference more than dogma.



      As long as your code adheres to using the <module>.new function to create structs you don't need to add repetitive guards on every function. If it all goes wrong, let it crash.






      share|improve this answer























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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        No, there is no way to enforce type check without guards. Erlang (and hence Elixir) is a dynamically typed language and you might want to have different clauses for different types passed, e.g. an error message if the types do not conform, or just sink the input out, or whatever.



        def create(connection, %Company{id: id})
        when not is_integer(id) do
        raise "Must be integer"
        end


        Erlang does not take out the liberty to deal with not proper input in the way you need, that is why guards you use is the way to go.





        There is static analysis tool, dialyzer, you might use to statically check types, also it does not prevent the compiler and runtime to pass whatever type is passed.






        share|improve this answer




























          2














          No, there is no way to enforce type check without guards. Erlang (and hence Elixir) is a dynamically typed language and you might want to have different clauses for different types passed, e.g. an error message if the types do not conform, or just sink the input out, or whatever.



          def create(connection, %Company{id: id})
          when not is_integer(id) do
          raise "Must be integer"
          end


          Erlang does not take out the liberty to deal with not proper input in the way you need, that is why guards you use is the way to go.





          There is static analysis tool, dialyzer, you might use to statically check types, also it does not prevent the compiler and runtime to pass whatever type is passed.






          share|improve this answer


























            2












            2








            2







            No, there is no way to enforce type check without guards. Erlang (and hence Elixir) is a dynamically typed language and you might want to have different clauses for different types passed, e.g. an error message if the types do not conform, or just sink the input out, or whatever.



            def create(connection, %Company{id: id})
            when not is_integer(id) do
            raise "Must be integer"
            end


            Erlang does not take out the liberty to deal with not proper input in the way you need, that is why guards you use is the way to go.





            There is static analysis tool, dialyzer, you might use to statically check types, also it does not prevent the compiler and runtime to pass whatever type is passed.






            share|improve this answer













            No, there is no way to enforce type check without guards. Erlang (and hence Elixir) is a dynamically typed language and you might want to have different clauses for different types passed, e.g. an error message if the types do not conform, or just sink the input out, or whatever.



            def create(connection, %Company{id: id})
            when not is_integer(id) do
            raise "Must be integer"
            end


            Erlang does not take out the liberty to deal with not proper input in the way you need, that is why guards you use is the way to go.





            There is static analysis tool, dialyzer, you might use to statically check types, also it does not prevent the compiler and runtime to pass whatever type is passed.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 25 '18 at 15:15









            Aleksei MatiushkinAleksei Matiushkin

            83.2k95694




            83.2k95694

























                0














                As @Aleksei has already pointed out, type-checking is not enforced in Elixir since it's a dynamically-typed language, so to do it manually we usually do it in a guard clause.



                But repeating the same set of clauses over and over again can be messy, tiring and error-prone. Though you could "validate" them in a separate function and make it easier, but it won't be as performant as guards:





                defmodule Company do
                defstruct [:id, :name, :active]

                def create(connection, company) do
                with :ok <- validate(company) do
                # do something
                end
                end

                defp validate(%Company{id: id, name: name, active: active})
                when is_integer(id) and is_binary(name) and is_boolean(active),
                do: :ok

                defp validate(_term), do: raise "Invalid Company"
                end


                Now calling the function for Company would work as expected, while it would raise errors for other terms:



                Company.create(1, %Company{})
                # => ** (RuntimeError) Invalid Company

                Company.create(2, %Company{id: 1, name: "hello", active: false})
                # => ... (works normally)




                If your use-case was simpler, you could've retained the performance by defining a custom guard-clause.






                share|improve this answer






























                  0














                  As @Aleksei has already pointed out, type-checking is not enforced in Elixir since it's a dynamically-typed language, so to do it manually we usually do it in a guard clause.



                  But repeating the same set of clauses over and over again can be messy, tiring and error-prone. Though you could "validate" them in a separate function and make it easier, but it won't be as performant as guards:





                  defmodule Company do
                  defstruct [:id, :name, :active]

                  def create(connection, company) do
                  with :ok <- validate(company) do
                  # do something
                  end
                  end

                  defp validate(%Company{id: id, name: name, active: active})
                  when is_integer(id) and is_binary(name) and is_boolean(active),
                  do: :ok

                  defp validate(_term), do: raise "Invalid Company"
                  end


                  Now calling the function for Company would work as expected, while it would raise errors for other terms:



                  Company.create(1, %Company{})
                  # => ** (RuntimeError) Invalid Company

                  Company.create(2, %Company{id: 1, name: "hello", active: false})
                  # => ... (works normally)




                  If your use-case was simpler, you could've retained the performance by defining a custom guard-clause.






                  share|improve this answer




























                    0












                    0








                    0







                    As @Aleksei has already pointed out, type-checking is not enforced in Elixir since it's a dynamically-typed language, so to do it manually we usually do it in a guard clause.



                    But repeating the same set of clauses over and over again can be messy, tiring and error-prone. Though you could "validate" them in a separate function and make it easier, but it won't be as performant as guards:





                    defmodule Company do
                    defstruct [:id, :name, :active]

                    def create(connection, company) do
                    with :ok <- validate(company) do
                    # do something
                    end
                    end

                    defp validate(%Company{id: id, name: name, active: active})
                    when is_integer(id) and is_binary(name) and is_boolean(active),
                    do: :ok

                    defp validate(_term), do: raise "Invalid Company"
                    end


                    Now calling the function for Company would work as expected, while it would raise errors for other terms:



                    Company.create(1, %Company{})
                    # => ** (RuntimeError) Invalid Company

                    Company.create(2, %Company{id: 1, name: "hello", active: false})
                    # => ... (works normally)




                    If your use-case was simpler, you could've retained the performance by defining a custom guard-clause.






                    share|improve this answer















                    As @Aleksei has already pointed out, type-checking is not enforced in Elixir since it's a dynamically-typed language, so to do it manually we usually do it in a guard clause.



                    But repeating the same set of clauses over and over again can be messy, tiring and error-prone. Though you could "validate" them in a separate function and make it easier, but it won't be as performant as guards:





                    defmodule Company do
                    defstruct [:id, :name, :active]

                    def create(connection, company) do
                    with :ok <- validate(company) do
                    # do something
                    end
                    end

                    defp validate(%Company{id: id, name: name, active: active})
                    when is_integer(id) and is_binary(name) and is_boolean(active),
                    do: :ok

                    defp validate(_term), do: raise "Invalid Company"
                    end


                    Now calling the function for Company would work as expected, while it would raise errors for other terms:



                    Company.create(1, %Company{})
                    # => ** (RuntimeError) Invalid Company

                    Company.create(2, %Company{id: 1, name: "hello", active: false})
                    # => ... (works normally)




                    If your use-case was simpler, you could've retained the performance by defining a custom guard-clause.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 26 '18 at 1:02

























                    answered Nov 25 '18 at 22:40









                    SheharyarSheharyar

                    45.9k12109162




                    45.9k12109162























                        0














                        I think its more idiomatic in Elixir to consider the contents of a struct to be valid data. And to provide a factory function to create a struct as part of your public API as @Sheharyar suggests above. I typically see the function be called new not create but thats preference more than dogma.



                        As long as your code adheres to using the <module>.new function to create structs you don't need to add repetitive guards on every function. If it all goes wrong, let it crash.






                        share|improve this answer




























                          0














                          I think its more idiomatic in Elixir to consider the contents of a struct to be valid data. And to provide a factory function to create a struct as part of your public API as @Sheharyar suggests above. I typically see the function be called new not create but thats preference more than dogma.



                          As long as your code adheres to using the <module>.new function to create structs you don't need to add repetitive guards on every function. If it all goes wrong, let it crash.






                          share|improve this answer


























                            0












                            0








                            0







                            I think its more idiomatic in Elixir to consider the contents of a struct to be valid data. And to provide a factory function to create a struct as part of your public API as @Sheharyar suggests above. I typically see the function be called new not create but thats preference more than dogma.



                            As long as your code adheres to using the <module>.new function to create structs you don't need to add repetitive guards on every function. If it all goes wrong, let it crash.






                            share|improve this answer













                            I think its more idiomatic in Elixir to consider the contents of a struct to be valid data. And to provide a factory function to create a struct as part of your public API as @Sheharyar suggests above. I typically see the function be called new not create but thats preference more than dogma.



                            As long as your code adheres to using the <module>.new function to create structs you don't need to add repetitive guards on every function. If it all goes wrong, let it crash.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 26 '18 at 9:19









                            KipKip

                            37927




                            37927






























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