Why is $x=4$ as a fixed point of a map $sqrt{2}^{x}$ unstable?












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My question is motivated by this What is wrong with this funny proof that 2 = 4 using infinite exponentiation? discussion, namely an example of a map $x mapsto f(x)$ is given, with $$f(x)= (sqrt{2})^{x}.$$ In that thread, it is stated the map has 2 fixed points, at $x = 2$ and $x=4$. Now to examine their stability we look at the derivative $$f'(x) = (sqrt{2})^{x} log sqrt{2}.$$



Now we have $f'(4) <1$, so $x=4$ should be stable. However, it is claimed, on the contrary, that $x=4$ is, in fact, $textbf{unstable}$. Why is this?










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  • 1




    $begingroup$
    Around $x=4$? The derivative is $2 log 2$, or roughly $1.4$.
    $endgroup$
    – Patrick Stevens
    Nov 7 '18 at 21:40










  • $begingroup$
    My apologies! Was doing computations in terms of logs to base 10, rather than natural logarithms. May close the thread. @PatrickStevens
    $endgroup$
    – Alex
    Nov 7 '18 at 21:48










  • $begingroup$
    I'd like to have the question closed/deleted because it's on a false premise. For the case this is not wanted I added a formal answer which is "acceptable" for closing the case.
    $endgroup$
    – Gottfried Helms
    Dec 26 '18 at 10:26


















2












$begingroup$


My question is motivated by this What is wrong with this funny proof that 2 = 4 using infinite exponentiation? discussion, namely an example of a map $x mapsto f(x)$ is given, with $$f(x)= (sqrt{2})^{x}.$$ In that thread, it is stated the map has 2 fixed points, at $x = 2$ and $x=4$. Now to examine their stability we look at the derivative $$f'(x) = (sqrt{2})^{x} log sqrt{2}.$$



Now we have $f'(4) <1$, so $x=4$ should be stable. However, it is claimed, on the contrary, that $x=4$ is, in fact, $textbf{unstable}$. Why is this?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    Around $x=4$? The derivative is $2 log 2$, or roughly $1.4$.
    $endgroup$
    – Patrick Stevens
    Nov 7 '18 at 21:40










  • $begingroup$
    My apologies! Was doing computations in terms of logs to base 10, rather than natural logarithms. May close the thread. @PatrickStevens
    $endgroup$
    – Alex
    Nov 7 '18 at 21:48










  • $begingroup$
    I'd like to have the question closed/deleted because it's on a false premise. For the case this is not wanted I added a formal answer which is "acceptable" for closing the case.
    $endgroup$
    – Gottfried Helms
    Dec 26 '18 at 10:26
















2












2








2





$begingroup$


My question is motivated by this What is wrong with this funny proof that 2 = 4 using infinite exponentiation? discussion, namely an example of a map $x mapsto f(x)$ is given, with $$f(x)= (sqrt{2})^{x}.$$ In that thread, it is stated the map has 2 fixed points, at $x = 2$ and $x=4$. Now to examine their stability we look at the derivative $$f'(x) = (sqrt{2})^{x} log sqrt{2}.$$



Now we have $f'(4) <1$, so $x=4$ should be stable. However, it is claimed, on the contrary, that $x=4$ is, in fact, $textbf{unstable}$. Why is this?










share|cite|improve this question









$endgroup$




My question is motivated by this What is wrong with this funny proof that 2 = 4 using infinite exponentiation? discussion, namely an example of a map $x mapsto f(x)$ is given, with $$f(x)= (sqrt{2})^{x}.$$ In that thread, it is stated the map has 2 fixed points, at $x = 2$ and $x=4$. Now to examine their stability we look at the derivative $$f'(x) = (sqrt{2})^{x} log sqrt{2}.$$



Now we have $f'(4) <1$, so $x=4$ should be stable. However, it is claimed, on the contrary, that $x=4$ is, in fact, $textbf{unstable}$. Why is this?







dynamical-systems exponentiation fixed-point-theorems power-towers






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asked Nov 7 '18 at 21:37









AlexAlex

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71248








  • 1




    $begingroup$
    Around $x=4$? The derivative is $2 log 2$, or roughly $1.4$.
    $endgroup$
    – Patrick Stevens
    Nov 7 '18 at 21:40










  • $begingroup$
    My apologies! Was doing computations in terms of logs to base 10, rather than natural logarithms. May close the thread. @PatrickStevens
    $endgroup$
    – Alex
    Nov 7 '18 at 21:48










  • $begingroup$
    I'd like to have the question closed/deleted because it's on a false premise. For the case this is not wanted I added a formal answer which is "acceptable" for closing the case.
    $endgroup$
    – Gottfried Helms
    Dec 26 '18 at 10:26
















  • 1




    $begingroup$
    Around $x=4$? The derivative is $2 log 2$, or roughly $1.4$.
    $endgroup$
    – Patrick Stevens
    Nov 7 '18 at 21:40










  • $begingroup$
    My apologies! Was doing computations in terms of logs to base 10, rather than natural logarithms. May close the thread. @PatrickStevens
    $endgroup$
    – Alex
    Nov 7 '18 at 21:48










  • $begingroup$
    I'd like to have the question closed/deleted because it's on a false premise. For the case this is not wanted I added a formal answer which is "acceptable" for closing the case.
    $endgroup$
    – Gottfried Helms
    Dec 26 '18 at 10:26










1




1




$begingroup$
Around $x=4$? The derivative is $2 log 2$, or roughly $1.4$.
$endgroup$
– Patrick Stevens
Nov 7 '18 at 21:40




$begingroup$
Around $x=4$? The derivative is $2 log 2$, or roughly $1.4$.
$endgroup$
– Patrick Stevens
Nov 7 '18 at 21:40












$begingroup$
My apologies! Was doing computations in terms of logs to base 10, rather than natural logarithms. May close the thread. @PatrickStevens
$endgroup$
– Alex
Nov 7 '18 at 21:48




$begingroup$
My apologies! Was doing computations in terms of logs to base 10, rather than natural logarithms. May close the thread. @PatrickStevens
$endgroup$
– Alex
Nov 7 '18 at 21:48












$begingroup$
I'd like to have the question closed/deleted because it's on a false premise. For the case this is not wanted I added a formal answer which is "acceptable" for closing the case.
$endgroup$
– Gottfried Helms
Dec 26 '18 at 10:26






$begingroup$
I'd like to have the question closed/deleted because it's on a false premise. For the case this is not wanted I added a formal answer which is "acceptable" for closing the case.
$endgroup$
– Gottfried Helms
Dec 26 '18 at 10:26












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The question was based on a false premise and is superflous now (see comments below question) as based on a simple error as understood by the OP.






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    $begingroup$

    The question was based on a false premise and is superflous now (see comments below question) as based on a simple error as understood by the OP.






    share|cite|improve this answer









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      0












      $begingroup$

      The question was based on a false premise and is superflous now (see comments below question) as based on a simple error as understood by the OP.






      share|cite|improve this answer









      $endgroup$
















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        $begingroup$

        The question was based on a false premise and is superflous now (see comments below question) as based on a simple error as understood by the OP.






        share|cite|improve this answer









        $endgroup$



        The question was based on a false premise and is superflous now (see comments below question) as based on a simple error as understood by the OP.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 26 '18 at 10:30









        Gottfried HelmsGottfried Helms

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