Difference between amplitude and range?
$begingroup$
Why Vertical axis changes name when we talk about waves? is there any differences between Range
and Amplitude
?
also i didn't knew what tag should i use for this, sorry for inappropriate tags.
EDIT:
I always see ppl using fourier transform and stuff, they write Amplitude as the label of their frequency domain plot.
graphing-functions fourier-transform
$endgroup$
add a comment |
$begingroup$
Why Vertical axis changes name when we talk about waves? is there any differences between Range
and Amplitude
?
also i didn't knew what tag should i use for this, sorry for inappropriate tags.
EDIT:
I always see ppl using fourier transform and stuff, they write Amplitude as the label of their frequency domain plot.
graphing-functions fourier-transform
$endgroup$
$begingroup$
I am not sure what context are you talking about. What's the definition of range/amplitude that you are using? What vertical axis?
$endgroup$
– Andrei
Dec 27 '18 at 20:53
$begingroup$
@Andrei I'm talking about Cartesian Coordinate system in 2D(like X Y plane) or sth. when we draw waves like sinusoidal waves we call the old Y (vertical axis) Amplitude axis i think?
$endgroup$
– no0ob
Dec 27 '18 at 20:59
$begingroup$
That's the wrong name for the axis.Amplitude
means the the maximum deviation of a periodic function from the average. So if your function is $y=Asin t+B$, $A$ is the amplitude. Therange
of values that this function takes is from $B-A$ to $B+A$.
$endgroup$
– Andrei
Dec 27 '18 at 21:22
1
$begingroup$
@Andrei The reason that I had made this mistake if it is, is that I always see ppl using fourier transform and stuff, they writeAmplitude
as the label of their frequency domain plot.
$endgroup$
– no0ob
Dec 27 '18 at 21:27
$begingroup$
@no0ob You should edit that into the question - I think people were thinking of simple waves (sine waves) plotted in time, rather than complex waves plotted in frequency domain. That comment changes the answers you'd get a lot.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:29
add a comment |
$begingroup$
Why Vertical axis changes name when we talk about waves? is there any differences between Range
and Amplitude
?
also i didn't knew what tag should i use for this, sorry for inappropriate tags.
EDIT:
I always see ppl using fourier transform and stuff, they write Amplitude as the label of their frequency domain plot.
graphing-functions fourier-transform
$endgroup$
Why Vertical axis changes name when we talk about waves? is there any differences between Range
and Amplitude
?
also i didn't knew what tag should i use for this, sorry for inappropriate tags.
EDIT:
I always see ppl using fourier transform and stuff, they write Amplitude as the label of their frequency domain plot.
graphing-functions fourier-transform
graphing-functions fourier-transform
edited Dec 27 '18 at 21:31
no0ob
asked Dec 27 '18 at 20:40
no0obno0ob
788
788
$begingroup$
I am not sure what context are you talking about. What's the definition of range/amplitude that you are using? What vertical axis?
$endgroup$
– Andrei
Dec 27 '18 at 20:53
$begingroup$
@Andrei I'm talking about Cartesian Coordinate system in 2D(like X Y plane) or sth. when we draw waves like sinusoidal waves we call the old Y (vertical axis) Amplitude axis i think?
$endgroup$
– no0ob
Dec 27 '18 at 20:59
$begingroup$
That's the wrong name for the axis.Amplitude
means the the maximum deviation of a periodic function from the average. So if your function is $y=Asin t+B$, $A$ is the amplitude. Therange
of values that this function takes is from $B-A$ to $B+A$.
$endgroup$
– Andrei
Dec 27 '18 at 21:22
1
$begingroup$
@Andrei The reason that I had made this mistake if it is, is that I always see ppl using fourier transform and stuff, they writeAmplitude
as the label of their frequency domain plot.
$endgroup$
– no0ob
Dec 27 '18 at 21:27
$begingroup$
@no0ob You should edit that into the question - I think people were thinking of simple waves (sine waves) plotted in time, rather than complex waves plotted in frequency domain. That comment changes the answers you'd get a lot.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:29
add a comment |
$begingroup$
I am not sure what context are you talking about. What's the definition of range/amplitude that you are using? What vertical axis?
$endgroup$
– Andrei
Dec 27 '18 at 20:53
$begingroup$
@Andrei I'm talking about Cartesian Coordinate system in 2D(like X Y plane) or sth. when we draw waves like sinusoidal waves we call the old Y (vertical axis) Amplitude axis i think?
$endgroup$
– no0ob
Dec 27 '18 at 20:59
$begingroup$
That's the wrong name for the axis.Amplitude
means the the maximum deviation of a periodic function from the average. So if your function is $y=Asin t+B$, $A$ is the amplitude. Therange
of values that this function takes is from $B-A$ to $B+A$.
$endgroup$
– Andrei
Dec 27 '18 at 21:22
1
$begingroup$
@Andrei The reason that I had made this mistake if it is, is that I always see ppl using fourier transform and stuff, they writeAmplitude
as the label of their frequency domain plot.
$endgroup$
– no0ob
Dec 27 '18 at 21:27
$begingroup$
@no0ob You should edit that into the question - I think people were thinking of simple waves (sine waves) plotted in time, rather than complex waves plotted in frequency domain. That comment changes the answers you'd get a lot.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:29
$begingroup$
I am not sure what context are you talking about. What's the definition of range/amplitude that you are using? What vertical axis?
$endgroup$
– Andrei
Dec 27 '18 at 20:53
$begingroup$
I am not sure what context are you talking about. What's the definition of range/amplitude that you are using? What vertical axis?
$endgroup$
– Andrei
Dec 27 '18 at 20:53
$begingroup$
@Andrei I'm talking about Cartesian Coordinate system in 2D(like X Y plane) or sth. when we draw waves like sinusoidal waves we call the old Y (vertical axis) Amplitude axis i think?
$endgroup$
– no0ob
Dec 27 '18 at 20:59
$begingroup$
@Andrei I'm talking about Cartesian Coordinate system in 2D(like X Y plane) or sth. when we draw waves like sinusoidal waves we call the old Y (vertical axis) Amplitude axis i think?
$endgroup$
– no0ob
Dec 27 '18 at 20:59
$begingroup$
That's the wrong name for the axis.
Amplitude
means the the maximum deviation of a periodic function from the average. So if your function is $y=Asin t+B$, $A$ is the amplitude. The range
of values that this function takes is from $B-A$ to $B+A$.$endgroup$
– Andrei
Dec 27 '18 at 21:22
$begingroup$
That's the wrong name for the axis.
Amplitude
means the the maximum deviation of a periodic function from the average. So if your function is $y=Asin t+B$, $A$ is the amplitude. The range
of values that this function takes is from $B-A$ to $B+A$.$endgroup$
– Andrei
Dec 27 '18 at 21:22
1
1
$begingroup$
@Andrei The reason that I had made this mistake if it is, is that I always see ppl using fourier transform and stuff, they write
Amplitude
as the label of their frequency domain plot.$endgroup$
– no0ob
Dec 27 '18 at 21:27
$begingroup$
@Andrei The reason that I had made this mistake if it is, is that I always see ppl using fourier transform and stuff, they write
Amplitude
as the label of their frequency domain plot.$endgroup$
– no0ob
Dec 27 '18 at 21:27
$begingroup$
@no0ob You should edit that into the question - I think people were thinking of simple waves (sine waves) plotted in time, rather than complex waves plotted in frequency domain. That comment changes the answers you'd get a lot.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:29
$begingroup$
@no0ob You should edit that into the question - I think people were thinking of simple waves (sine waves) plotted in time, rather than complex waves plotted in frequency domain. That comment changes the answers you'd get a lot.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:29
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
This very much depends on how you represent a wave and what it means.
In time domain, generally one plots an $x$-axis representing time and the $y$-axis represents a physical quantity, such as pressure or voltage or displacement. The amplitude, while not being an axis of this graph, is a quantity that one can find from the graph - it is the distance between an extreme point and the average point ("equilibrium" in a physical context). In particular, the wave $Asin(x)$ has amplitude $A$ because its extreme points are at $pm A$ and its equilibrium would like at $0$. The "range" (or "peak-to-peak amplitude") sometimes refers to the difference of largest and smallest values in a wave - so $2A$ for $sin(x)$.
It's harder to give a single value for amplitude for more complex waveforms - there's still a notion that making a wave twice as tall doubles its amplitude, but there are many definitions that try to capture various desirable quantities of a wave.
For the most part, amplitude would not be an appropriate label for the $y$-axis of a plot of a waveform - the possible exception would be if you're plotting a standing wave where the $x$-axis is distance and the $y$-axis is the amplitude of some time-varying quantity when observed at the prescribed point in space.
In frequency domain, a complicated wave is shown to be decomposed into a sum of sine waves. For instance, if you started with a wave such as
$$F(t)=sin(2pi tcdot 1000 text{ Hz})$$
where $t$ is some duration, the Fourier transform would show* a single bar showing amplitude $1$ at $1000text{ Hz}$, meaning that the wave is just a sine wave with that amplitude at that frequency. A more complicated wave such as
$$F(t)=1/3cdot sin(2pi tcdot 1000 text{ Hz})+ 1/4 cdot sin(2pi tcdot 2000 text{ Hz})$$
would show an amplitude of $1/3$ at $1000text{ Hz}$ and $1/4$ at $2000text{ Hz}$, showing that the bigger wave is a sum of simpler waves with the prescribed amplitudes. In general, any complex wave can be written as a sum of sine waves with various phases, and the Fourier transform displays, at each frequency, what amplitude of wave would be necessary.
(*There are many caveats here: if you're, for instance, working with digital audio, you won't see a sharp peak because those programs take an arbitrary chunk of your sound, pretend it repeats forever, then decompose that wave; if the chunk doesn't line up with the periods of your wave, the transform won't represent a sine wave. There are also issues with the fact that Fourier transforms most naturally work on continuous signals whereas they are most commonly applied to discrete signals obtained via sampling at some rate. Also, in this context, usually both axes are using logarithmic scales, which makes them look a bit odd)
$endgroup$
$begingroup$
Are you sure about both axes are using logarithmic? cause i think for the DTFT the frequency axis is just thek
/2πk
from the fourier summation formula
$endgroup$
– no0ob
Dec 27 '18 at 21:54
1
$begingroup$
@no0ob The frequency axis is just $k$ - but it is often displayed laid out logarithmically (in my experience, equalizer effects in various music software generally show a logarithmic $x$-axis, even though the data points are discrete) - but you can just look at the labels on the $x$-axis to see whether it's spaced linearly or not.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:57
add a comment |
$begingroup$
As mentioned in a comment, if you have a sine wave in the time domain $y=Asinomega t$, $A$ is the amplitude. If you add multiple such functions you get something like $$y=sum_i A_isinomega_it$$
When you do the Fourier transform, this will show up as a set of points $(pmomega_i, A_i)$ (up to some normalization constant). The same thing is occurring if you have a continuous distributions of $omega$ angular frequencies. So in the case of the Fourier transform the thing that you plot is the amplitude
of each contributing sine wave.
The above answer is the same if you add sine and cosine contributions.
$endgroup$
add a comment |
$begingroup$
Important point: $y=sin(ωt)+1$ has exactly the same amplitude as $y=sin(ωt)$. But the first has $[0,2]$ as its range and the second, $[-1,1]$.
The amplitude measures the size of the waveform, not the set of values it assumes.
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This very much depends on how you represent a wave and what it means.
In time domain, generally one plots an $x$-axis representing time and the $y$-axis represents a physical quantity, such as pressure or voltage or displacement. The amplitude, while not being an axis of this graph, is a quantity that one can find from the graph - it is the distance between an extreme point and the average point ("equilibrium" in a physical context). In particular, the wave $Asin(x)$ has amplitude $A$ because its extreme points are at $pm A$ and its equilibrium would like at $0$. The "range" (or "peak-to-peak amplitude") sometimes refers to the difference of largest and smallest values in a wave - so $2A$ for $sin(x)$.
It's harder to give a single value for amplitude for more complex waveforms - there's still a notion that making a wave twice as tall doubles its amplitude, but there are many definitions that try to capture various desirable quantities of a wave.
For the most part, amplitude would not be an appropriate label for the $y$-axis of a plot of a waveform - the possible exception would be if you're plotting a standing wave where the $x$-axis is distance and the $y$-axis is the amplitude of some time-varying quantity when observed at the prescribed point in space.
In frequency domain, a complicated wave is shown to be decomposed into a sum of sine waves. For instance, if you started with a wave such as
$$F(t)=sin(2pi tcdot 1000 text{ Hz})$$
where $t$ is some duration, the Fourier transform would show* a single bar showing amplitude $1$ at $1000text{ Hz}$, meaning that the wave is just a sine wave with that amplitude at that frequency. A more complicated wave such as
$$F(t)=1/3cdot sin(2pi tcdot 1000 text{ Hz})+ 1/4 cdot sin(2pi tcdot 2000 text{ Hz})$$
would show an amplitude of $1/3$ at $1000text{ Hz}$ and $1/4$ at $2000text{ Hz}$, showing that the bigger wave is a sum of simpler waves with the prescribed amplitudes. In general, any complex wave can be written as a sum of sine waves with various phases, and the Fourier transform displays, at each frequency, what amplitude of wave would be necessary.
(*There are many caveats here: if you're, for instance, working with digital audio, you won't see a sharp peak because those programs take an arbitrary chunk of your sound, pretend it repeats forever, then decompose that wave; if the chunk doesn't line up with the periods of your wave, the transform won't represent a sine wave. There are also issues with the fact that Fourier transforms most naturally work on continuous signals whereas they are most commonly applied to discrete signals obtained via sampling at some rate. Also, in this context, usually both axes are using logarithmic scales, which makes them look a bit odd)
$endgroup$
$begingroup$
Are you sure about both axes are using logarithmic? cause i think for the DTFT the frequency axis is just thek
/2πk
from the fourier summation formula
$endgroup$
– no0ob
Dec 27 '18 at 21:54
1
$begingroup$
@no0ob The frequency axis is just $k$ - but it is often displayed laid out logarithmically (in my experience, equalizer effects in various music software generally show a logarithmic $x$-axis, even though the data points are discrete) - but you can just look at the labels on the $x$-axis to see whether it's spaced linearly or not.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:57
add a comment |
$begingroup$
This very much depends on how you represent a wave and what it means.
In time domain, generally one plots an $x$-axis representing time and the $y$-axis represents a physical quantity, such as pressure or voltage or displacement. The amplitude, while not being an axis of this graph, is a quantity that one can find from the graph - it is the distance between an extreme point and the average point ("equilibrium" in a physical context). In particular, the wave $Asin(x)$ has amplitude $A$ because its extreme points are at $pm A$ and its equilibrium would like at $0$. The "range" (or "peak-to-peak amplitude") sometimes refers to the difference of largest and smallest values in a wave - so $2A$ for $sin(x)$.
It's harder to give a single value for amplitude for more complex waveforms - there's still a notion that making a wave twice as tall doubles its amplitude, but there are many definitions that try to capture various desirable quantities of a wave.
For the most part, amplitude would not be an appropriate label for the $y$-axis of a plot of a waveform - the possible exception would be if you're plotting a standing wave where the $x$-axis is distance and the $y$-axis is the amplitude of some time-varying quantity when observed at the prescribed point in space.
In frequency domain, a complicated wave is shown to be decomposed into a sum of sine waves. For instance, if you started with a wave such as
$$F(t)=sin(2pi tcdot 1000 text{ Hz})$$
where $t$ is some duration, the Fourier transform would show* a single bar showing amplitude $1$ at $1000text{ Hz}$, meaning that the wave is just a sine wave with that amplitude at that frequency. A more complicated wave such as
$$F(t)=1/3cdot sin(2pi tcdot 1000 text{ Hz})+ 1/4 cdot sin(2pi tcdot 2000 text{ Hz})$$
would show an amplitude of $1/3$ at $1000text{ Hz}$ and $1/4$ at $2000text{ Hz}$, showing that the bigger wave is a sum of simpler waves with the prescribed amplitudes. In general, any complex wave can be written as a sum of sine waves with various phases, and the Fourier transform displays, at each frequency, what amplitude of wave would be necessary.
(*There are many caveats here: if you're, for instance, working with digital audio, you won't see a sharp peak because those programs take an arbitrary chunk of your sound, pretend it repeats forever, then decompose that wave; if the chunk doesn't line up with the periods of your wave, the transform won't represent a sine wave. There are also issues with the fact that Fourier transforms most naturally work on continuous signals whereas they are most commonly applied to discrete signals obtained via sampling at some rate. Also, in this context, usually both axes are using logarithmic scales, which makes them look a bit odd)
$endgroup$
$begingroup$
Are you sure about both axes are using logarithmic? cause i think for the DTFT the frequency axis is just thek
/2πk
from the fourier summation formula
$endgroup$
– no0ob
Dec 27 '18 at 21:54
1
$begingroup$
@no0ob The frequency axis is just $k$ - but it is often displayed laid out logarithmically (in my experience, equalizer effects in various music software generally show a logarithmic $x$-axis, even though the data points are discrete) - but you can just look at the labels on the $x$-axis to see whether it's spaced linearly or not.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:57
add a comment |
$begingroup$
This very much depends on how you represent a wave and what it means.
In time domain, generally one plots an $x$-axis representing time and the $y$-axis represents a physical quantity, such as pressure or voltage or displacement. The amplitude, while not being an axis of this graph, is a quantity that one can find from the graph - it is the distance between an extreme point and the average point ("equilibrium" in a physical context). In particular, the wave $Asin(x)$ has amplitude $A$ because its extreme points are at $pm A$ and its equilibrium would like at $0$. The "range" (or "peak-to-peak amplitude") sometimes refers to the difference of largest and smallest values in a wave - so $2A$ for $sin(x)$.
It's harder to give a single value for amplitude for more complex waveforms - there's still a notion that making a wave twice as tall doubles its amplitude, but there are many definitions that try to capture various desirable quantities of a wave.
For the most part, amplitude would not be an appropriate label for the $y$-axis of a plot of a waveform - the possible exception would be if you're plotting a standing wave where the $x$-axis is distance and the $y$-axis is the amplitude of some time-varying quantity when observed at the prescribed point in space.
In frequency domain, a complicated wave is shown to be decomposed into a sum of sine waves. For instance, if you started with a wave such as
$$F(t)=sin(2pi tcdot 1000 text{ Hz})$$
where $t$ is some duration, the Fourier transform would show* a single bar showing amplitude $1$ at $1000text{ Hz}$, meaning that the wave is just a sine wave with that amplitude at that frequency. A more complicated wave such as
$$F(t)=1/3cdot sin(2pi tcdot 1000 text{ Hz})+ 1/4 cdot sin(2pi tcdot 2000 text{ Hz})$$
would show an amplitude of $1/3$ at $1000text{ Hz}$ and $1/4$ at $2000text{ Hz}$, showing that the bigger wave is a sum of simpler waves with the prescribed amplitudes. In general, any complex wave can be written as a sum of sine waves with various phases, and the Fourier transform displays, at each frequency, what amplitude of wave would be necessary.
(*There are many caveats here: if you're, for instance, working with digital audio, you won't see a sharp peak because those programs take an arbitrary chunk of your sound, pretend it repeats forever, then decompose that wave; if the chunk doesn't line up with the periods of your wave, the transform won't represent a sine wave. There are also issues with the fact that Fourier transforms most naturally work on continuous signals whereas they are most commonly applied to discrete signals obtained via sampling at some rate. Also, in this context, usually both axes are using logarithmic scales, which makes them look a bit odd)
$endgroup$
This very much depends on how you represent a wave and what it means.
In time domain, generally one plots an $x$-axis representing time and the $y$-axis represents a physical quantity, such as pressure or voltage or displacement. The amplitude, while not being an axis of this graph, is a quantity that one can find from the graph - it is the distance between an extreme point and the average point ("equilibrium" in a physical context). In particular, the wave $Asin(x)$ has amplitude $A$ because its extreme points are at $pm A$ and its equilibrium would like at $0$. The "range" (or "peak-to-peak amplitude") sometimes refers to the difference of largest and smallest values in a wave - so $2A$ for $sin(x)$.
It's harder to give a single value for amplitude for more complex waveforms - there's still a notion that making a wave twice as tall doubles its amplitude, but there are many definitions that try to capture various desirable quantities of a wave.
For the most part, amplitude would not be an appropriate label for the $y$-axis of a plot of a waveform - the possible exception would be if you're plotting a standing wave where the $x$-axis is distance and the $y$-axis is the amplitude of some time-varying quantity when observed at the prescribed point in space.
In frequency domain, a complicated wave is shown to be decomposed into a sum of sine waves. For instance, if you started with a wave such as
$$F(t)=sin(2pi tcdot 1000 text{ Hz})$$
where $t$ is some duration, the Fourier transform would show* a single bar showing amplitude $1$ at $1000text{ Hz}$, meaning that the wave is just a sine wave with that amplitude at that frequency. A more complicated wave such as
$$F(t)=1/3cdot sin(2pi tcdot 1000 text{ Hz})+ 1/4 cdot sin(2pi tcdot 2000 text{ Hz})$$
would show an amplitude of $1/3$ at $1000text{ Hz}$ and $1/4$ at $2000text{ Hz}$, showing that the bigger wave is a sum of simpler waves with the prescribed amplitudes. In general, any complex wave can be written as a sum of sine waves with various phases, and the Fourier transform displays, at each frequency, what amplitude of wave would be necessary.
(*There are many caveats here: if you're, for instance, working with digital audio, you won't see a sharp peak because those programs take an arbitrary chunk of your sound, pretend it repeats forever, then decompose that wave; if the chunk doesn't line up with the periods of your wave, the transform won't represent a sine wave. There are also issues with the fact that Fourier transforms most naturally work on continuous signals whereas they are most commonly applied to discrete signals obtained via sampling at some rate. Also, in this context, usually both axes are using logarithmic scales, which makes them look a bit odd)
answered Dec 27 '18 at 21:43
Milo BrandtMilo Brandt
40k476140
40k476140
$begingroup$
Are you sure about both axes are using logarithmic? cause i think for the DTFT the frequency axis is just thek
/2πk
from the fourier summation formula
$endgroup$
– no0ob
Dec 27 '18 at 21:54
1
$begingroup$
@no0ob The frequency axis is just $k$ - but it is often displayed laid out logarithmically (in my experience, equalizer effects in various music software generally show a logarithmic $x$-axis, even though the data points are discrete) - but you can just look at the labels on the $x$-axis to see whether it's spaced linearly or not.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:57
add a comment |
$begingroup$
Are you sure about both axes are using logarithmic? cause i think for the DTFT the frequency axis is just thek
/2πk
from the fourier summation formula
$endgroup$
– no0ob
Dec 27 '18 at 21:54
1
$begingroup$
@no0ob The frequency axis is just $k$ - but it is often displayed laid out logarithmically (in my experience, equalizer effects in various music software generally show a logarithmic $x$-axis, even though the data points are discrete) - but you can just look at the labels on the $x$-axis to see whether it's spaced linearly or not.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:57
$begingroup$
Are you sure about both axes are using logarithmic? cause i think for the DTFT the frequency axis is just the
k
/2πk
from the fourier summation formula$endgroup$
– no0ob
Dec 27 '18 at 21:54
$begingroup$
Are you sure about both axes are using logarithmic? cause i think for the DTFT the frequency axis is just the
k
/2πk
from the fourier summation formula$endgroup$
– no0ob
Dec 27 '18 at 21:54
1
1
$begingroup$
@no0ob The frequency axis is just $k$ - but it is often displayed laid out logarithmically (in my experience, equalizer effects in various music software generally show a logarithmic $x$-axis, even though the data points are discrete) - but you can just look at the labels on the $x$-axis to see whether it's spaced linearly or not.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:57
$begingroup$
@no0ob The frequency axis is just $k$ - but it is often displayed laid out logarithmically (in my experience, equalizer effects in various music software generally show a logarithmic $x$-axis, even though the data points are discrete) - but you can just look at the labels on the $x$-axis to see whether it's spaced linearly or not.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:57
add a comment |
$begingroup$
As mentioned in a comment, if you have a sine wave in the time domain $y=Asinomega t$, $A$ is the amplitude. If you add multiple such functions you get something like $$y=sum_i A_isinomega_it$$
When you do the Fourier transform, this will show up as a set of points $(pmomega_i, A_i)$ (up to some normalization constant). The same thing is occurring if you have a continuous distributions of $omega$ angular frequencies. So in the case of the Fourier transform the thing that you plot is the amplitude
of each contributing sine wave.
The above answer is the same if you add sine and cosine contributions.
$endgroup$
add a comment |
$begingroup$
As mentioned in a comment, if you have a sine wave in the time domain $y=Asinomega t$, $A$ is the amplitude. If you add multiple such functions you get something like $$y=sum_i A_isinomega_it$$
When you do the Fourier transform, this will show up as a set of points $(pmomega_i, A_i)$ (up to some normalization constant). The same thing is occurring if you have a continuous distributions of $omega$ angular frequencies. So in the case of the Fourier transform the thing that you plot is the amplitude
of each contributing sine wave.
The above answer is the same if you add sine and cosine contributions.
$endgroup$
add a comment |
$begingroup$
As mentioned in a comment, if you have a sine wave in the time domain $y=Asinomega t$, $A$ is the amplitude. If you add multiple such functions you get something like $$y=sum_i A_isinomega_it$$
When you do the Fourier transform, this will show up as a set of points $(pmomega_i, A_i)$ (up to some normalization constant). The same thing is occurring if you have a continuous distributions of $omega$ angular frequencies. So in the case of the Fourier transform the thing that you plot is the amplitude
of each contributing sine wave.
The above answer is the same if you add sine and cosine contributions.
$endgroup$
As mentioned in a comment, if you have a sine wave in the time domain $y=Asinomega t$, $A$ is the amplitude. If you add multiple such functions you get something like $$y=sum_i A_isinomega_it$$
When you do the Fourier transform, this will show up as a set of points $(pmomega_i, A_i)$ (up to some normalization constant). The same thing is occurring if you have a continuous distributions of $omega$ angular frequencies. So in the case of the Fourier transform the thing that you plot is the amplitude
of each contributing sine wave.
The above answer is the same if you add sine and cosine contributions.
answered Dec 27 '18 at 21:41
AndreiAndrei
13.1k21230
13.1k21230
add a comment |
add a comment |
$begingroup$
Important point: $y=sin(ωt)+1$ has exactly the same amplitude as $y=sin(ωt)$. But the first has $[0,2]$ as its range and the second, $[-1,1]$.
The amplitude measures the size of the waveform, not the set of values it assumes.
$endgroup$
add a comment |
$begingroup$
Important point: $y=sin(ωt)+1$ has exactly the same amplitude as $y=sin(ωt)$. But the first has $[0,2]$ as its range and the second, $[-1,1]$.
The amplitude measures the size of the waveform, not the set of values it assumes.
$endgroup$
add a comment |
$begingroup$
Important point: $y=sin(ωt)+1$ has exactly the same amplitude as $y=sin(ωt)$. But the first has $[0,2]$ as its range and the second, $[-1,1]$.
The amplitude measures the size of the waveform, not the set of values it assumes.
$endgroup$
Important point: $y=sin(ωt)+1$ has exactly the same amplitude as $y=sin(ωt)$. But the first has $[0,2]$ as its range and the second, $[-1,1]$.
The amplitude measures the size of the waveform, not the set of values it assumes.
answered Dec 27 '18 at 23:26
timtfjtimtfj
2,468420
2,468420
add a comment |
add a comment |
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$begingroup$
I am not sure what context are you talking about. What's the definition of range/amplitude that you are using? What vertical axis?
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– Andrei
Dec 27 '18 at 20:53
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@Andrei I'm talking about Cartesian Coordinate system in 2D(like X Y plane) or sth. when we draw waves like sinusoidal waves we call the old Y (vertical axis) Amplitude axis i think?
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– no0ob
Dec 27 '18 at 20:59
$begingroup$
That's the wrong name for the axis.
Amplitude
means the the maximum deviation of a periodic function from the average. So if your function is $y=Asin t+B$, $A$ is the amplitude. Therange
of values that this function takes is from $B-A$ to $B+A$.$endgroup$
– Andrei
Dec 27 '18 at 21:22
1
$begingroup$
@Andrei The reason that I had made this mistake if it is, is that I always see ppl using fourier transform and stuff, they write
Amplitude
as the label of their frequency domain plot.$endgroup$
– no0ob
Dec 27 '18 at 21:27
$begingroup$
@no0ob You should edit that into the question - I think people were thinking of simple waves (sine waves) plotted in time, rather than complex waves plotted in frequency domain. That comment changes the answers you'd get a lot.
$endgroup$
– Milo Brandt
Dec 27 '18 at 21:29