Most general version of Hensel's Lemma
$begingroup$
Roughly speaking, Hensel's Lemma states that a polynomial $f in O[X]$ over a certain local ring $(O,mathfrak{m})$ which factors over the residue field $O/mathfrak{m}$ into coprime polynomials also factors over $O$ in a compatible way. However, there are different versions of the lemma with different requirements on $O$. For example the statement holds true if $O$ is complete with respect to the $mathfrak{m}$-adic topology, and it also holds true if $O$ is the valuation ring of a nontrivial non-archimedean absolute value on some field $K$, which is complete with respect to this absolute value.
Is there a more general version of Hensel's Lemma which implies both of the above statements?
abstract-algebra commutative-algebra algebraic-number-theory
$endgroup$
add a comment |
$begingroup$
Roughly speaking, Hensel's Lemma states that a polynomial $f in O[X]$ over a certain local ring $(O,mathfrak{m})$ which factors over the residue field $O/mathfrak{m}$ into coprime polynomials also factors over $O$ in a compatible way. However, there are different versions of the lemma with different requirements on $O$. For example the statement holds true if $O$ is complete with respect to the $mathfrak{m}$-adic topology, and it also holds true if $O$ is the valuation ring of a nontrivial non-archimedean absolute value on some field $K$, which is complete with respect to this absolute value.
Is there a more general version of Hensel's Lemma which implies both of the above statements?
abstract-algebra commutative-algebra algebraic-number-theory
$endgroup$
add a comment |
$begingroup$
Roughly speaking, Hensel's Lemma states that a polynomial $f in O[X]$ over a certain local ring $(O,mathfrak{m})$ which factors over the residue field $O/mathfrak{m}$ into coprime polynomials also factors over $O$ in a compatible way. However, there are different versions of the lemma with different requirements on $O$. For example the statement holds true if $O$ is complete with respect to the $mathfrak{m}$-adic topology, and it also holds true if $O$ is the valuation ring of a nontrivial non-archimedean absolute value on some field $K$, which is complete with respect to this absolute value.
Is there a more general version of Hensel's Lemma which implies both of the above statements?
abstract-algebra commutative-algebra algebraic-number-theory
$endgroup$
Roughly speaking, Hensel's Lemma states that a polynomial $f in O[X]$ over a certain local ring $(O,mathfrak{m})$ which factors over the residue field $O/mathfrak{m}$ into coprime polynomials also factors over $O$ in a compatible way. However, there are different versions of the lemma with different requirements on $O$. For example the statement holds true if $O$ is complete with respect to the $mathfrak{m}$-adic topology, and it also holds true if $O$ is the valuation ring of a nontrivial non-archimedean absolute value on some field $K$, which is complete with respect to this absolute value.
Is there a more general version of Hensel's Lemma which implies both of the above statements?
abstract-algebra commutative-algebra algebraic-number-theory
abstract-algebra commutative-algebra algebraic-number-theory
asked Dec 29 '14 at 21:50
DuneDune
4,46711231
4,46711231
add a comment |
add a comment |
1 Answer
1
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$begingroup$
Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
$S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
equivalent.
$(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.
$(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
$f (t) in R[t]$.
$(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
A/mathfrak{m}A$ induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$
$(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$
$(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
$g(t)$ and $h(t)$ is $R[t].$
$(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$
$(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$
If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.
Examples: (1) A complete local ring is henselian.
(2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)
The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.
$endgroup$
$begingroup$
Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
$endgroup$
– Dune
Dec 30 '14 at 10:45
$begingroup$
@Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
$endgroup$
– Krish
Dec 30 '14 at 11:20
$begingroup$
@Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
$endgroup$
– Dune
Dec 30 '14 at 19:46
add a comment |
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1 Answer
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1 Answer
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$begingroup$
Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
$S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
equivalent.
$(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.
$(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
$f (t) in R[t]$.
$(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
A/mathfrak{m}A$ induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$
$(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$
$(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
$g(t)$ and $h(t)$ is $R[t].$
$(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$
$(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$
If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.
Examples: (1) A complete local ring is henselian.
(2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)
The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.
$endgroup$
$begingroup$
Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
$endgroup$
– Dune
Dec 30 '14 at 10:45
$begingroup$
@Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
$endgroup$
– Krish
Dec 30 '14 at 11:20
$begingroup$
@Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
$endgroup$
– Dune
Dec 30 '14 at 19:46
add a comment |
$begingroup$
Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
$S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
equivalent.
$(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.
$(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
$f (t) in R[t]$.
$(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
A/mathfrak{m}A$ induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$
$(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$
$(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
$g(t)$ and $h(t)$ is $R[t].$
$(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$
$(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$
If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.
Examples: (1) A complete local ring is henselian.
(2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)
The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.
$endgroup$
$begingroup$
Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
$endgroup$
– Dune
Dec 30 '14 at 10:45
$begingroup$
@Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
$endgroup$
– Krish
Dec 30 '14 at 11:20
$begingroup$
@Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
$endgroup$
– Dune
Dec 30 '14 at 19:46
add a comment |
$begingroup$
Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
$S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
equivalent.
$(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.
$(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
$f (t) in R[t]$.
$(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
A/mathfrak{m}A$ induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$
$(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$
$(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
$g(t)$ and $h(t)$ is $R[t].$
$(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$
$(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$
If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.
Examples: (1) A complete local ring is henselian.
(2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)
The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.
$endgroup$
Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
$S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
equivalent.
$(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.
$(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
$f (t) in R[t]$.
$(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
A/mathfrak{m}A$ induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$
$(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$
$(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
$g(t)$ and $h(t)$ is $R[t].$
$(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$
$(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$
If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.
Examples: (1) A complete local ring is henselian.
(2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)
The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.
edited Dec 27 '18 at 19:28
user26857
39.4k124183
39.4k124183
answered Dec 30 '14 at 4:21
KrishKrish
6,33411020
6,33411020
$begingroup$
Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
$endgroup$
– Dune
Dec 30 '14 at 10:45
$begingroup$
@Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
$endgroup$
– Krish
Dec 30 '14 at 11:20
$begingroup$
@Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
$endgroup$
– Dune
Dec 30 '14 at 19:46
add a comment |
$begingroup$
Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
$endgroup$
– Dune
Dec 30 '14 at 10:45
$begingroup$
@Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
$endgroup$
– Krish
Dec 30 '14 at 11:20
$begingroup$
@Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
$endgroup$
– Dune
Dec 30 '14 at 19:46
$begingroup$
Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
$endgroup$
– Dune
Dec 30 '14 at 10:45
$begingroup$
Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
$endgroup$
– Dune
Dec 30 '14 at 10:45
$begingroup$
@Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
$endgroup$
– Krish
Dec 30 '14 at 11:20
$begingroup$
@Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
$endgroup$
– Krish
Dec 30 '14 at 11:20
$begingroup$
@Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
$endgroup$
– Dune
Dec 30 '14 at 19:46
$begingroup$
@Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
$endgroup$
– Dune
Dec 30 '14 at 19:46
add a comment |
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