Most general version of Hensel's Lemma












7












$begingroup$


Roughly speaking, Hensel's Lemma states that a polynomial $f in O[X]$ over a certain local ring $(O,mathfrak{m})$ which factors over the residue field $O/mathfrak{m}$ into coprime polynomials also factors over $O$ in a compatible way. However, there are different versions of the lemma with different requirements on $O$. For example the statement holds true if $O$ is complete with respect to the $mathfrak{m}$-adic topology, and it also holds true if $O$ is the valuation ring of a nontrivial non-archimedean absolute value on some field $K$, which is complete with respect to this absolute value.



Is there a more general version of Hensel's Lemma which implies both of the above statements?










share|cite|improve this question









$endgroup$

















    7












    $begingroup$


    Roughly speaking, Hensel's Lemma states that a polynomial $f in O[X]$ over a certain local ring $(O,mathfrak{m})$ which factors over the residue field $O/mathfrak{m}$ into coprime polynomials also factors over $O$ in a compatible way. However, there are different versions of the lemma with different requirements on $O$. For example the statement holds true if $O$ is complete with respect to the $mathfrak{m}$-adic topology, and it also holds true if $O$ is the valuation ring of a nontrivial non-archimedean absolute value on some field $K$, which is complete with respect to this absolute value.



    Is there a more general version of Hensel's Lemma which implies both of the above statements?










    share|cite|improve this question









    $endgroup$















      7












      7








      7


      7



      $begingroup$


      Roughly speaking, Hensel's Lemma states that a polynomial $f in O[X]$ over a certain local ring $(O,mathfrak{m})$ which factors over the residue field $O/mathfrak{m}$ into coprime polynomials also factors over $O$ in a compatible way. However, there are different versions of the lemma with different requirements on $O$. For example the statement holds true if $O$ is complete with respect to the $mathfrak{m}$-adic topology, and it also holds true if $O$ is the valuation ring of a nontrivial non-archimedean absolute value on some field $K$, which is complete with respect to this absolute value.



      Is there a more general version of Hensel's Lemma which implies both of the above statements?










      share|cite|improve this question









      $endgroup$




      Roughly speaking, Hensel's Lemma states that a polynomial $f in O[X]$ over a certain local ring $(O,mathfrak{m})$ which factors over the residue field $O/mathfrak{m}$ into coprime polynomials also factors over $O$ in a compatible way. However, there are different versions of the lemma with different requirements on $O$. For example the statement holds true if $O$ is complete with respect to the $mathfrak{m}$-adic topology, and it also holds true if $O$ is the valuation ring of a nontrivial non-archimedean absolute value on some field $K$, which is complete with respect to this absolute value.



      Is there a more general version of Hensel's Lemma which implies both of the above statements?







      abstract-algebra commutative-algebra algebraic-number-theory






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Dec 29 '14 at 21:50









      DuneDune

      4,46711231




      4,46711231






















          1 Answer
          1






          active

          oldest

          votes


















          3












          $begingroup$

          Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
          $S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
          equivalent.



          $(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.



          $(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
          $f (t) in R[t]$.



          $(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
          A/mathfrak{m}A$
          induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$



          $(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$



          $(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
          polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
          $g(t)$ and $h(t)$ is $R[t].$



          $(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
          that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$



          $(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$



          If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.



          Examples: (1) A complete local ring is henselian.



          (2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)



          The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
            $endgroup$
            – Dune
            Dec 30 '14 at 10:45










          • $begingroup$
            @Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
            $endgroup$
            – Krish
            Dec 30 '14 at 11:20












          • $begingroup$
            @Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
            $endgroup$
            – Dune
            Dec 30 '14 at 19:46











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1085023%2fmost-general-version-of-hensels-lemma%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3












          $begingroup$

          Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
          $S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
          equivalent.



          $(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.



          $(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
          $f (t) in R[t]$.



          $(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
          A/mathfrak{m}A$
          induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$



          $(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$



          $(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
          polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
          $g(t)$ and $h(t)$ is $R[t].$



          $(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
          that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$



          $(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$



          If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.



          Examples: (1) A complete local ring is henselian.



          (2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)



          The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
            $endgroup$
            – Dune
            Dec 30 '14 at 10:45










          • $begingroup$
            @Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
            $endgroup$
            – Krish
            Dec 30 '14 at 11:20












          • $begingroup$
            @Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
            $endgroup$
            – Dune
            Dec 30 '14 at 19:46
















          3












          $begingroup$

          Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
          $S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
          equivalent.



          $(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.



          $(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
          $f (t) in R[t]$.



          $(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
          A/mathfrak{m}A$
          induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$



          $(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$



          $(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
          polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
          $g(t)$ and $h(t)$ is $R[t].$



          $(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
          that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$



          $(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$



          If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.



          Examples: (1) A complete local ring is henselian.



          (2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)



          The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
            $endgroup$
            – Dune
            Dec 30 '14 at 10:45










          • $begingroup$
            @Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
            $endgroup$
            – Krish
            Dec 30 '14 at 11:20












          • $begingroup$
            @Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
            $endgroup$
            – Dune
            Dec 30 '14 at 19:46














          3












          3








          3





          $begingroup$

          Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
          $S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
          equivalent.



          $(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.



          $(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
          $f (t) in R[t]$.



          $(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
          A/mathfrak{m}A$
          induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$



          $(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$



          $(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
          polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
          $g(t)$ and $h(t)$ is $R[t].$



          $(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
          that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$



          $(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$



          If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.



          Examples: (1) A complete local ring is henselian.



          (2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)



          The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.






          share|cite|improve this answer











          $endgroup$



          Let $(R, mathfrak{m})$ be a local ring, $k = R/mathfrak{m}$ its residue field,
          $S = operatorname{Spec}R$, and $s$ the closed point of $S$. The following conditions are
          equivalent.



          $(i)$ Every finite $R$-algebra $A$ is a direct product of local rings.



          $(ii)$ The condition $(i)$ holds for $A = R[t]/(f (t))$ for any monic polynomial
          $f (t) in R[t]$.



          $(iii)$ For any finite $R$-algebra $A$, the canonical homomorphism $A rightarrow
          A/mathfrak{m}A$
          induces a one-to-one correspondence between the set of idempotent elements in $A$ and the set of idempotent elements in $A/mathfrak{m}A.$



          $(iv)$ The condition $(iii)$ holds for $A = R[t]/(f (t))$ for any monic polynomial $f (t) in R[t].$



          $(v)$ For any monic polynomial $f (t) in R[t]$ and any factorization $overline{f}(t) = overline{g}(t) overline{h}(t)$, where $overline{f}(t)$ is the image of $f (t)$ in $k[t]$, and $overline{g}(t)$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t]$, there exist uniquely determined
          polynomials $g(t)$ and $h(t)$ in $R[t]$ such that $f (t) = g(t)h(t)$, $overline{g}(t)$ and $overline{h}(t)$ are images of $g(t)$ and $h(t)$ in $k[t]$, respectively, and the ideal generated by
          $g(t)$ and $h(t)$ is $R[t].$



          $(vi)$ The condition $(v)$ holds for any factorization $overline{f} (t) = (t− overline{a}) overline{h}(t)$ such
          that $t − overline{a}$ and $overline{h}(t)$ are relatively prime monic polynomials in $k[t].$



          $(vii)$ For any etale morphism $g : X rightarrow S$, any section of $g_s : X otimes _R k rightarrow operatorname{Spec} k$ is induced by a section $g.$



          If a local ring $(R, mathfrak{m})$ satisfies any (and hence every) of these properties, we call the ring henselian.



          Examples: (1) A complete local ring is henselian.



          (2) The convergent power series ring $mathbb{C}{z_1, z_2, dots , z_n}$ is also henselian. (This ring is not a complete local ring.)



          The above definition is taken from Etale Cohomology Theory, Lei Fu. You can also look at here.







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Dec 27 '18 at 19:28









          user26857

          39.4k124183




          39.4k124183










          answered Dec 30 '14 at 4:21









          KrishKrish

          6,33411020




          6,33411020












          • $begingroup$
            Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
            $endgroup$
            – Dune
            Dec 30 '14 at 10:45










          • $begingroup$
            @Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
            $endgroup$
            – Krish
            Dec 30 '14 at 11:20












          • $begingroup$
            @Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
            $endgroup$
            – Dune
            Dec 30 '14 at 19:46


















          • $begingroup$
            Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
            $endgroup$
            – Dune
            Dec 30 '14 at 10:45










          • $begingroup$
            @Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
            $endgroup$
            – Krish
            Dec 30 '14 at 11:20












          • $begingroup$
            @Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
            $endgroup$
            – Dune
            Dec 30 '14 at 19:46
















          $begingroup$
          Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
          $endgroup$
          – Dune
          Dec 30 '14 at 10:45




          $begingroup$
          Is there an obvious reason why complete local rings and valuation rings of complete fields satisfy any of those conditions (other than (v) or (vi))?
          $endgroup$
          – Dune
          Dec 30 '14 at 10:45












          $begingroup$
          @Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
          $endgroup$
          – Krish
          Dec 30 '14 at 11:20






          $begingroup$
          @Dune: I don't know. Sorry!! But the conditions (v) and (vi) have a very beautiful geometric picture (namely, Newton-Raphson method). You can look at these two links: (1) math.stackexchange.com/questions/48419/… (2) math.stackexchange.com/questions/709533/…
          $endgroup$
          – Krish
          Dec 30 '14 at 11:20














          $begingroup$
          @Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
          $endgroup$
          – Dune
          Dec 30 '14 at 19:46




          $begingroup$
          @Krish: No problem. :) I just wonder if there is a unifying way to show that these two kinds of rings are henselian. But nevertheless, thank you for your answer!
          $endgroup$
          – Dune
          Dec 30 '14 at 19:46


















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Mathematics Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1085023%2fmost-general-version-of-hensels-lemma%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          To store a contact into the json file from server.js file using a class in NodeJS

          Redirect URL with Chrome Remote Debugging Android Devices

          Dieringhausen