solve variable in base
$begingroup$
I am asking very petty question. I am confused to solve following equation. Answer should be 9.03. When I calculate, I constantly get different answer (696.4).
How would you solve? then I wanna know where I failed.
$$
14=frac{100^2}{a+0.17*100}
$$
Thanks a lot
arithmetic exponentiation
$endgroup$
add a comment |
$begingroup$
I am asking very petty question. I am confused to solve following equation. Answer should be 9.03. When I calculate, I constantly get different answer (696.4).
How would you solve? then I wanna know where I failed.
$$
14=frac{100^2}{a+0.17*100}
$$
Thanks a lot
arithmetic exponentiation
$endgroup$
add a comment |
$begingroup$
I am asking very petty question. I am confused to solve following equation. Answer should be 9.03. When I calculate, I constantly get different answer (696.4).
How would you solve? then I wanna know where I failed.
$$
14=frac{100^2}{a+0.17*100}
$$
Thanks a lot
arithmetic exponentiation
$endgroup$
I am asking very petty question. I am confused to solve following equation. Answer should be 9.03. When I calculate, I constantly get different answer (696.4).
How would you solve? then I wanna know where I failed.
$$
14=frac{100^2}{a+0.17*100}
$$
Thanks a lot
arithmetic exponentiation
arithmetic exponentiation
edited Dec 27 '18 at 20:30
gt6989b
34.9k22557
34.9k22557
asked Dec 27 '18 at 20:23
user3063user3063
1143
1143
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
You have
$$
14 = frac{100^2}{a + 0.17 times 100} = frac{10000}{a + 17}
$$
Therefore,
$$
a + 17 = frac{10000}{14} = frac{5000}{7}
$$
and finally, $a = 5000/7 - 17$.
$endgroup$
$begingroup$
Now I am confident with my calculation with the helps of both of you. Thank you so much.
$endgroup$
– user3063
Dec 27 '18 at 20:39
add a comment |
$begingroup$
$$14=dfrac{100^2}{(a+0.17*100)}$$
$$14(a+17)=100^2$$
$$14a+238=100^2$$
$$14a=100^2-238$$
$$a=dfrac{100^2-238}{14}=697.285714286$$
You are correct (not entirely). Decimals and numbers are different in your case.
$endgroup$
add a comment |
$begingroup$
You can write $$14=frac{100^2}{a+17}$$ and then $$frac{1}{14}=frac{a+17}{100^2}$$ so $$frac{100^2}{14}-17=a$$
$endgroup$
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You have
$$
14 = frac{100^2}{a + 0.17 times 100} = frac{10000}{a + 17}
$$
Therefore,
$$
a + 17 = frac{10000}{14} = frac{5000}{7}
$$
and finally, $a = 5000/7 - 17$.
$endgroup$
$begingroup$
Now I am confident with my calculation with the helps of both of you. Thank you so much.
$endgroup$
– user3063
Dec 27 '18 at 20:39
add a comment |
$begingroup$
You have
$$
14 = frac{100^2}{a + 0.17 times 100} = frac{10000}{a + 17}
$$
Therefore,
$$
a + 17 = frac{10000}{14} = frac{5000}{7}
$$
and finally, $a = 5000/7 - 17$.
$endgroup$
$begingroup$
Now I am confident with my calculation with the helps of both of you. Thank you so much.
$endgroup$
– user3063
Dec 27 '18 at 20:39
add a comment |
$begingroup$
You have
$$
14 = frac{100^2}{a + 0.17 times 100} = frac{10000}{a + 17}
$$
Therefore,
$$
a + 17 = frac{10000}{14} = frac{5000}{7}
$$
and finally, $a = 5000/7 - 17$.
$endgroup$
You have
$$
14 = frac{100^2}{a + 0.17 times 100} = frac{10000}{a + 17}
$$
Therefore,
$$
a + 17 = frac{10000}{14} = frac{5000}{7}
$$
and finally, $a = 5000/7 - 17$.
answered Dec 27 '18 at 20:27
gt6989bgt6989b
34.9k22557
34.9k22557
$begingroup$
Now I am confident with my calculation with the helps of both of you. Thank you so much.
$endgroup$
– user3063
Dec 27 '18 at 20:39
add a comment |
$begingroup$
Now I am confident with my calculation with the helps of both of you. Thank you so much.
$endgroup$
– user3063
Dec 27 '18 at 20:39
$begingroup$
Now I am confident with my calculation with the helps of both of you. Thank you so much.
$endgroup$
– user3063
Dec 27 '18 at 20:39
$begingroup$
Now I am confident with my calculation with the helps of both of you. Thank you so much.
$endgroup$
– user3063
Dec 27 '18 at 20:39
add a comment |
$begingroup$
$$14=dfrac{100^2}{(a+0.17*100)}$$
$$14(a+17)=100^2$$
$$14a+238=100^2$$
$$14a=100^2-238$$
$$a=dfrac{100^2-238}{14}=697.285714286$$
You are correct (not entirely). Decimals and numbers are different in your case.
$endgroup$
add a comment |
$begingroup$
$$14=dfrac{100^2}{(a+0.17*100)}$$
$$14(a+17)=100^2$$
$$14a+238=100^2$$
$$14a=100^2-238$$
$$a=dfrac{100^2-238}{14}=697.285714286$$
You are correct (not entirely). Decimals and numbers are different in your case.
$endgroup$
add a comment |
$begingroup$
$$14=dfrac{100^2}{(a+0.17*100)}$$
$$14(a+17)=100^2$$
$$14a+238=100^2$$
$$14a=100^2-238$$
$$a=dfrac{100^2-238}{14}=697.285714286$$
You are correct (not entirely). Decimals and numbers are different in your case.
$endgroup$
$$14=dfrac{100^2}{(a+0.17*100)}$$
$$14(a+17)=100^2$$
$$14a+238=100^2$$
$$14a=100^2-238$$
$$a=dfrac{100^2-238}{14}=697.285714286$$
You are correct (not entirely). Decimals and numbers are different in your case.
answered Dec 27 '18 at 20:27
K Split XK Split X
4,30421233
4,30421233
add a comment |
add a comment |
$begingroup$
You can write $$14=frac{100^2}{a+17}$$ and then $$frac{1}{14}=frac{a+17}{100^2}$$ so $$frac{100^2}{14}-17=a$$
$endgroup$
add a comment |
$begingroup$
You can write $$14=frac{100^2}{a+17}$$ and then $$frac{1}{14}=frac{a+17}{100^2}$$ so $$frac{100^2}{14}-17=a$$
$endgroup$
add a comment |
$begingroup$
You can write $$14=frac{100^2}{a+17}$$ and then $$frac{1}{14}=frac{a+17}{100^2}$$ so $$frac{100^2}{14}-17=a$$
$endgroup$
You can write $$14=frac{100^2}{a+17}$$ and then $$frac{1}{14}=frac{a+17}{100^2}$$ so $$frac{100^2}{14}-17=a$$
answered Dec 27 '18 at 20:46
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.9k42866
77.9k42866
add a comment |
add a comment |
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