Making a Chrome extension for a site that uses React. How to persist changes after re-rendering?

I want my extension to add elements to a page. But the site uses React which means every time there's a change the page is re-rendered but without the elements that I added.

I'm only passingly familiar with React from some tutorial apps I built a long time ago.

edited Nov 23 at 11:01

Xan

53.2k10102129

asked Nov 20 at 23:28

MCB

1,41411328

1

You can probably use MutationObserver to detect the changes in DOM and re-add your stuff.
– wOxxOm
Nov 21 at 5:15

@wOxxOm Hey, that worked post it as an answer and I'll accept it.
– MCB
Nov 22 at 18:50

I think it'd be more useful if you post an answer with the working code.
– wOxxOm
Nov 22 at 18:56

add a comment |

I want my extension to add elements to a page. But the site uses React which means every time there's a change the page is re-rendered but without the elements that I added.

I'm only passingly familiar with React from some tutorial apps I built a long time ago.

edited Nov 23 at 11:01

Xan

53.2k10102129

asked Nov 20 at 23:28

MCB

1,41411328

1

You can probably use MutationObserver to detect the changes in DOM and re-add your stuff.
– wOxxOm
Nov 21 at 5:15

@wOxxOm Hey, that worked post it as an answer and I'll accept it.
– MCB
Nov 22 at 18:50

I think it'd be more useful if you post an answer with the working code.
– wOxxOm
Nov 22 at 18:56

add a comment |

I want my extension to add elements to a page. But the site uses React which means every time there's a change the page is re-rendered but without the elements that I added.

I'm only passingly familiar with React from some tutorial apps I built a long time ago.

edited Nov 23 at 11:01

Xan

53.2k10102129

asked Nov 20 at 23:28

MCB

1,41411328

I want my extension to add elements to a page. But the site uses React which means every time there's a change the page is re-rendered but without the elements that I added.

I'm only passingly familiar with React from some tutorial apps I built a long time ago.

javascript reactjs google-chrome-extension

edited Nov 23 at 11:01

Xan

53.2k10102129

asked Nov 20 at 23:28

MCB

1,41411328

edited Nov 23 at 11:01

Xan

53.2k10102129

asked Nov 20 at 23:28

MCB

1,41411328

edited Nov 23 at 11:01

Xan

53.2k10102129

edited Nov 23 at 11:01

Xan

53.2k10102129

edited Nov 23 at 11:01

Xan

53.2k10102129

asked Nov 20 at 23:28

MCB

1,41411328

asked Nov 20 at 23:28

MCB

1,41411328

asked Nov 20 at 23:28

MCB

1,41411328

1

You can probably use MutationObserver to detect the changes in DOM and re-add your stuff.
– wOxxOm
Nov 21 at 5:15

@wOxxOm Hey, that worked post it as an answer and I'll accept it.
– MCB
Nov 22 at 18:50

I think it'd be more useful if you post an answer with the working code.
– wOxxOm
Nov 22 at 18:56

add a comment |

1

You can probably use MutationObserver to detect the changes in DOM and re-add your stuff.
– wOxxOm
Nov 21 at 5:15

@wOxxOm Hey, that worked post it as an answer and I'll accept it.
– MCB
Nov 22 at 18:50

I think it'd be more useful if you post an answer with the working code.
– wOxxOm
Nov 22 at 18:56

You can probably use MutationObserver to detect the changes in DOM and re-add your stuff.
– wOxxOm
Nov 21 at 5:15

@wOxxOm Hey, that worked post it as an answer and I'll accept it.
– MCB
Nov 22 at 18:50

I think it'd be more useful if you post an answer with the working code.
– wOxxOm
Nov 22 at 18:56

add a comment |

1 Answer
1

active

oldest

votes

I implemented @wOxxOm's comment to use MutationObserver and it worked very well.

  static placeAndObserveMutations (insertionBoxSelector) {

    let placer = new Placement ();

    placer.place(insertionBoxSelector);

    placer.observeMutations(insertionBoxSelector);



  }



  place (insertionBoxSelector) {

    let box = $(insertionBoxSelector)

    this.insertionBox = box; //insertionBox is the element that the content

    // will be appended to

    this.addedBox = EnterBox.addInfo(box); //addedBox is the content

// Worth noting that at this point it's fairly empty. It'll get filled by

// async ajax calls while this is running. And all that will still be there

// when it's added back in the callback later.

  }



  observeMutations(insertionBoxSelector) {

    let observer = new MutationObserver (this.replaceBox.bind(this));

// this.insertionBox is a jQuery object and I assume `observe` doesn't accept that

    let insertionBox = document.querySelector(insertionBoxSelector);

    observer.observe(title, {attributes: true});

  }



  replaceBox () {

    this.insertionBox.append(this.addedBox);

    _position (this.addedBox);

  }

That being said someone suggested adding the content above the React node (i.e. the body) and just positioning the added content absolutely relative to the window. And as this will actually solve a separate problem I was having on some pages of a site I'll probably do that. Also, it's far simpler.

But I thought this was still an interesting solution to a rare problem so I wanted to post it as well.

answered Nov 22 at 20:10

MCB

1,41411328

add a comment |

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1 Answer
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1 Answer
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I implemented @wOxxOm's comment to use MutationObserver and it worked very well.

  static placeAndObserveMutations (insertionBoxSelector) {

    let placer = new Placement ();

    placer.place(insertionBoxSelector);

    placer.observeMutations(insertionBoxSelector);



  }



  place (insertionBoxSelector) {

    let box = $(insertionBoxSelector)

    this.insertionBox = box; //insertionBox is the element that the content

    // will be appended to

    this.addedBox = EnterBox.addInfo(box); //addedBox is the content

// Worth noting that at this point it's fairly empty. It'll get filled by

// async ajax calls while this is running. And all that will still be there

// when it's added back in the callback later.

  }



  observeMutations(insertionBoxSelector) {

    let observer = new MutationObserver (this.replaceBox.bind(this));

// this.insertionBox is a jQuery object and I assume `observe` doesn't accept that

    let insertionBox = document.querySelector(insertionBoxSelector);

    observer.observe(title, {attributes: true});

  }



  replaceBox () {

    this.insertionBox.append(this.addedBox);

    _position (this.addedBox);

  }

But I thought this was still an interesting solution to a rare problem so I wanted to post it as well.

answered Nov 22 at 20:10

MCB

1,41411328

add a comment |

I implemented @wOxxOm's comment to use MutationObserver and it worked very well.

  static placeAndObserveMutations (insertionBoxSelector) {

    let placer = new Placement ();

    placer.place(insertionBoxSelector);

    placer.observeMutations(insertionBoxSelector);



  }



  place (insertionBoxSelector) {

    let box = $(insertionBoxSelector)

    this.insertionBox = box; //insertionBox is the element that the content

    // will be appended to

    this.addedBox = EnterBox.addInfo(box); //addedBox is the content

// Worth noting that at this point it's fairly empty. It'll get filled by

// async ajax calls while this is running. And all that will still be there

// when it's added back in the callback later.

  }



  observeMutations(insertionBoxSelector) {

    let observer = new MutationObserver (this.replaceBox.bind(this));

// this.insertionBox is a jQuery object and I assume `observe` doesn't accept that

    let insertionBox = document.querySelector(insertionBoxSelector);

    observer.observe(title, {attributes: true});

  }



  replaceBox () {

    this.insertionBox.append(this.addedBox);

    _position (this.addedBox);

  }

But I thought this was still an interesting solution to a rare problem so I wanted to post it as well.

answered Nov 22 at 20:10

MCB

1,41411328

add a comment |

I implemented @wOxxOm's comment to use MutationObserver and it worked very well.

  static placeAndObserveMutations (insertionBoxSelector) {

    let placer = new Placement ();

    placer.place(insertionBoxSelector);

    placer.observeMutations(insertionBoxSelector);



  }



  place (insertionBoxSelector) {

    let box = $(insertionBoxSelector)

    this.insertionBox = box; //insertionBox is the element that the content

    // will be appended to

    this.addedBox = EnterBox.addInfo(box); //addedBox is the content

// Worth noting that at this point it's fairly empty. It'll get filled by

// async ajax calls while this is running. And all that will still be there

// when it's added back in the callback later.

  }



  observeMutations(insertionBoxSelector) {

    let observer = new MutationObserver (this.replaceBox.bind(this));

// this.insertionBox is a jQuery object and I assume `observe` doesn't accept that

    let insertionBox = document.querySelector(insertionBoxSelector);

    observer.observe(title, {attributes: true});

  }



  replaceBox () {

    this.insertionBox.append(this.addedBox);

    _position (this.addedBox);

  }

But I thought this was still an interesting solution to a rare problem so I wanted to post it as well.

answered Nov 22 at 20:10

MCB

1,41411328

I implemented @wOxxOm's comment to use MutationObserver and it worked very well.

  static placeAndObserveMutations (insertionBoxSelector) {

    let placer = new Placement ();

    placer.place(insertionBoxSelector);

    placer.observeMutations(insertionBoxSelector);



  }



  place (insertionBoxSelector) {

    let box = $(insertionBoxSelector)

    this.insertionBox = box; //insertionBox is the element that the content

    // will be appended to

    this.addedBox = EnterBox.addInfo(box); //addedBox is the content

// Worth noting that at this point it's fairly empty. It'll get filled by

// async ajax calls while this is running. And all that will still be there

// when it's added back in the callback later.

  }



  observeMutations(insertionBoxSelector) {

    let observer = new MutationObserver (this.replaceBox.bind(this));

// this.insertionBox is a jQuery object and I assume `observe` doesn't accept that

    let insertionBox = document.querySelector(insertionBoxSelector);

    observer.observe(title, {attributes: true});

  }



  replaceBox () {

    this.insertionBox.append(this.addedBox);

    _position (this.addedBox);

  }

But I thought this was still an interesting solution to a rare problem so I wanted to post it as well.

answered Nov 22 at 20:10

MCB

1,41411328

answered Nov 22 at 20:10

MCB

1,41411328

answered Nov 22 at 20:10

MCB

1,41411328

answered Nov 22 at 20:10

MCB

1,41411328

add a comment |

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