Mongodb sum, sort and rank





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{_id:123
"name":"Amy"
"Num_1":NumberInt(2),
"Num_2":NumberInt(4),
"Num_3":NumberInt(0),
"Num_4":NumberInt(4),}


Now I have this structure in MongoDB as above, I am wondering how can I have an output that gives me the user's name that has the highest sum of all num (sum of "Num_1","Num_2","Num_3","Num_4")










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    1















    {_id:123
    "name":"Amy"
    "Num_1":NumberInt(2),
    "Num_2":NumberInt(4),
    "Num_3":NumberInt(0),
    "Num_4":NumberInt(4),}


    Now I have this structure in MongoDB as above, I am wondering how can I have an output that gives me the user's name that has the highest sum of all num (sum of "Num_1","Num_2","Num_3","Num_4")










    share|improve this question



























      1












      1








      1








      {_id:123
      "name":"Amy"
      "Num_1":NumberInt(2),
      "Num_2":NumberInt(4),
      "Num_3":NumberInt(0),
      "Num_4":NumberInt(4),}


      Now I have this structure in MongoDB as above, I am wondering how can I have an output that gives me the user's name that has the highest sum of all num (sum of "Num_1","Num_2","Num_3","Num_4")










      share|improve this question
















      {_id:123
      "name":"Amy"
      "Num_1":NumberInt(2),
      "Num_2":NumberInt(4),
      "Num_3":NumberInt(0),
      "Num_4":NumberInt(4),}


      Now I have this structure in MongoDB as above, I am wondering how can I have an output that gives me the user's name that has the highest sum of all num (sum of "Num_1","Num_2","Num_3","Num_4")







      mongodb mongodb-query






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 26 '18 at 16:14









      Anthony Winzlet

      18.2k42346




      18.2k42346










      asked Nov 26 '18 at 14:28









      Kimberly JonesKimberly Jones

      142




      142
























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