Javascript percentage of winning algorithm
up vote
-1
down vote
favorite
I have a slots machine game HTML5 + Javascript.
I have found the below algoritm on Stackoverflow, but i need another percentage
this.d = Math.random();
if (this.d < 0.3333) {
this.nextSymbols = [
['320', '320', 'jackpot'],
['jackpot', '320', '400'],
['320', '320', 'jackpot'],
];
} else if (this.d < 0.005) {
this.nextSymbols = [
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
];
} else {
this.nextSymbols = [
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
];
}
I need to have:
1 of 3 spins to be a winning prize 2
1 of 200 spins wins big prize
Any math expert advice would be much appreciate.
Thanks
javascript algorithm
asked Nov 19 at 21:59
PixelArtie
23
add a comment |
up vote
-1
down vote
favorite
I have a slots machine game HTML5 + Javascript.
I have found the below algoritm on Stackoverflow, but i need another percentage
this.d = Math.random();
if (this.d < 0.3333) {
this.nextSymbols = [
['320', '320', 'jackpot'],
['jackpot', '320', '400'],
['320', '320', 'jackpot'],
];
} else if (this.d < 0.005) {
this.nextSymbols = [
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
];
} else {
this.nextSymbols = [
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
];
}
I need to have:
1 of 3 spins to be a winning prize 2
1 of 200 spins wins big prize
Any math expert advice would be much appreciate.
Thanks
javascript algorithm
asked Nov 19 at 21:59
PixelArtie
23
1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 at 22:04
2
Hint: 1/3 =0.3333…, 1/200 =0.005(compared to 50% =0.5, 20% =0.2in the existing code)
– Bergi
Nov 19 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 at 22:21
1
<means less than. Soif (this.d < 0.005)means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in theelseclause of the <0.3333, so nobody will ever win the big prize.
– Richardissimo
Nov 19 at 22:39
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I have a slots machine game HTML5 + Javascript.
I have found the below algoritm on Stackoverflow, but i need another percentage
this.d = Math.random();
if (this.d < 0.3333) {
this.nextSymbols = [
['320', '320', 'jackpot'],
['jackpot', '320', '400'],
['320', '320', 'jackpot'],
];
} else if (this.d < 0.005) {
this.nextSymbols = [
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
];
} else {
this.nextSymbols = [
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
];
}
I need to have:
1 of 3 spins to be a winning prize 2
1 of 200 spins wins big prize
Any math expert advice would be much appreciate.
Thanks
javascript algorithm
asked Nov 19 at 21:59
PixelArtie
23
I have a slots machine game HTML5 + Javascript.
I have found the below algoritm on Stackoverflow, but i need another percentage
this.d = Math.random();
if (this.d < 0.3333) {
this.nextSymbols = [
['320', '320', 'jackpot'],
['jackpot', '320', '400'],
['320', '320', 'jackpot'],
];
} else if (this.d < 0.005) {
this.nextSymbols = [
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
['320', 'jackpot', '400'],
];
} else {
this.nextSymbols = [
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
[Symbol.random(), Symbol.random(), Symbol.random()],
];
}
I need to have:
1 of 3 spins to be a winning prize 2
1 of 200 spins wins big prize
Any math expert advice would be much appreciate.
Thanks
javascript algorithm
javascript algorithm
asked Nov 19 at 21:59
PixelArtie
23
asked Nov 19 at 21:59
PixelArtie
23
edited Nov 19 at 22:07
asked Nov 19 at 21:59
PixelArtie
23
asked Nov 19 at 21:59
PixelArtie
23
asked Nov 19 at 21:59
PixelArtie
23
23
1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 at 22:04
2
Hint: 1/3 =0.3333…, 1/200 =0.005(compared to 50% =0.5, 20% =0.2in the existing code)
– Bergi
Nov 19 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 at 22:21
1
<means less than. Soif (this.d < 0.005)means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in theelseclause of the <0.3333, so nobody will ever win the big prize.
– Richardissimo
Nov 19 at 22:39
add a comment |
1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 at 22:04
2
Hint: 1/3 =0.3333…, 1/200 =0.005(compared to 50% =0.5, 20% =0.2in the existing code)
– Bergi
Nov 19 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 at 22:21
1
<means less than. Soif (this.d < 0.005)means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in theelseclause of the <0.3333, so nobody will ever win the big prize.
– Richardissimo
Nov 19 at 22:39
1
1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 at 22:04
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 at 22:04
2
2
Hint: 1/3 =
0.3333…, 1/200 = 0.005 (compared to 50% = 0.5, 20% = 0.2 in the existing code)– Bergi
Nov 19 at 22:05
Hint: 1/3 =
0.3333…, 1/200 = 0.005 (compared to 50% = 0.5, 20% = 0.2 in the existing code)– Bergi
Nov 19 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 at 22:21
@Bergi thanks. I figured out
– PixelArtie
Nov 19 at 22:21
1
1
< means less than. So if (this.d < 0.005) means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in the else clause of the <0.3333, so nobody will ever win the big prize.– Richardissimo
Nov 19 at 22:39
< means less than. So if (this.d < 0.005) means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in the else clause of the <0.3333, so nobody will ever win the big prize.– Richardissimo
Nov 19 at 22:39
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 at 23:25
Konowy
320420
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 at 23:25
Konowy
320420
add a comment |
up vote
0
down vote
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 at 23:25
Konowy
320420
add a comment |
up vote
0
down vote
up vote
0
down vote
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 at 23:25
Konowy
320420
To summarize - as @Bergi and @Richardissimo written in comments.
1 / 3 is 0.(3), but you can just write thid.d < 1/3 interpreter will calculate it for you.
And if you are making else if the second case will never fire. You have to change the order of conditions.
answered Nov 19 at 23:25
Konowy
320420
answered Nov 19 at 23:25
Konowy
320420
answered Nov 19 at 23:25
Konowy
320420
answered Nov 19 at 23:25
Konowy
320420
320420
add a comment |
add a comment |
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1
How is "I have 10 big prizes" relevant for the probability of a single spin?
– Bergi
Nov 19 at 22:04
2
Hint: 1/3 =
0.3333…, 1/200 =0.005(compared to 50% =0.5, 20% =0.2in the existing code)– Bergi
Nov 19 at 22:05
@Bergi thanks. I figured out
– PixelArtie
Nov 19 at 22:21
1
<means less than. Soif (this.d < 0.005)means that the value is less than 0.005. Any value where that is the case is also less than 0.3333. However the if-test for <0.005 is in theelseclause of the <0.3333, so nobody will ever win the big prize.– Richardissimo
Nov 19 at 22:39