Filter JavaScript array without keys
I have a two dimensional array:
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
I would like to filter by country and return all the animals "associated" with that country in another array.
For example filtering by Kenya places dog and cat into another array.
Hope that makes sense. Any help would be most appreciated. Thanks.
javascript arrays filtering
asked Nov 22 '18 at 9:48
user142553user142553
143
add a comment |
I have a two dimensional array:
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
I would like to filter by country and return all the animals "associated" with that country in another array.
For example filtering by Kenya places dog and cat into another array.
Hope that makes sense. Any help would be most appreciated. Thanks.
javascript arrays filtering
asked Nov 22 '18 at 9:48
user142553user142553
143
4
do you have tried something? please add your code.
– Nina Scholz
Nov 22 '18 at 9:50
1
Arrays have keys: We normally call them indexes. In your example, the country appears to always be at index 2.
– T.J. Crowder
Nov 22 '18 at 9:50
add a comment |
I have a two dimensional array:
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
I would like to filter by country and return all the animals "associated" with that country in another array.
For example filtering by Kenya places dog and cat into another array.
Hope that makes sense. Any help would be most appreciated. Thanks.
javascript arrays filtering
asked Nov 22 '18 at 9:48
user142553user142553
143
I have a two dimensional array:
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
I would like to filter by country and return all the animals "associated" with that country in another array.
For example filtering by Kenya places dog and cat into another array.
Hope that makes sense. Any help would be most appreciated. Thanks.
javascript arrays filtering
javascript arrays filtering
asked Nov 22 '18 at 9:48
user142553user142553
143
asked Nov 22 '18 at 9:48
user142553user142553
143
asked Nov 22 '18 at 9:48
user142553user142553
143
asked Nov 22 '18 at 9:48
user142553user142553
143
asked Nov 22 '18 at 9:48
user142553user142553
143
143
4
do you have tried something? please add your code.
– Nina Scholz
Nov 22 '18 at 9:50
1
Arrays have keys: We normally call them indexes. In your example, the country appears to always be at index 2.
– T.J. Crowder
Nov 22 '18 at 9:50
add a comment |
4
do you have tried something? please add your code.
– Nina Scholz
Nov 22 '18 at 9:50
1
Arrays have keys: We normally call them indexes. In your example, the country appears to always be at index 2.
– T.J. Crowder
Nov 22 '18 at 9:50
4
4
do you have tried something? please add your code.
– Nina Scholz
Nov 22 '18 at 9:50
do you have tried something? please add your code.
– Nina Scholz
Nov 22 '18 at 9:50
1
1
Arrays have keys: We normally call them indexes. In your example, the country appears to always be at index 2.
– T.J. Crowder
Nov 22 '18 at 9:50
Arrays have keys: We normally call them indexes. In your example, the country appears to always be at index 2.
– T.J. Crowder
Nov 22 '18 at 9:50
add a comment |
5 Answers
5
active
oldest
votes
Assuming that your animal is always at index 1 you can use can use Array.prototype.filter()
and Array.prototype.map() to achieve this.
.filter() will "filter" your 2d array to only include arrays which have the country within it, then .map() will convert this 2d array to a 1d array by "replacing" all the inner arrays to be the animal (ie index 1).
See working example below:
const array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]],
filterBy = "kenya", // The contry to filter by
animals = array.filter(arr => arr[2] == filterBy).map(elem => elem[1]);
console.log(animals);answered Nov 22 '18 at 9:52
Nick ParsonsNick Parsons
5,3722721
1
Great that worked a treat.
– user142553
Nov 24 '18 at 14:33
@user142553 no worries, glad to help ;)
– Nick Parsons
Nov 24 '18 at 14:36
add a comment |
You could filter the array and then map the wanted item.
This solution take the advantage of destructuring assignment, where an array is taken and the items gets a name.
var array = [["car", "dog", "kenya"], ["plane", "cat", "kenya"], ["boat", "mouse", "england"]],
result = array
.filter(([,, country]) => country === "kenya")
.map(([, animal]) => animal)
console.log(result);answered Nov 22 '18 at 9:52
Nina ScholzNina Scholz
180k1493160
add a comment |
Looking at the code you have provided and considering that the country is always in index-2 and animals are in index-1 you can use a forEach() loop to get animals for that particular country.
var array = [
["car", "dog", "kenya"],
["plane", "cat", "kenya"],
["boat", "mouse", "england"]
];
var country = 'kenya';
var animals = ;
array.forEach((item) => {
if (item[2] === country) {
animals.push(item[1]);;
}
});
console.log(animals);answered Nov 22 '18 at 9:55
Ankit AgarwalAnkit Agarwal
23.8k52044
add a comment |
You can create a generic function which gets the index of what type you want to filter ('2' for countries) and the value you want to match ('kenya' for example)
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
const FILTER_TYPE = { vehicle: 0, animal: 1, country: 2 }
const filter_by = (index, value) => (array.filter(item => (item[index] === value)).map(item => item[FILTER_TYPE.animal]))
console.log(filter_by(FILTER_TYPE.country, 'kenya'))answered Nov 22 '18 at 9:52
omri_saadonomri_saadon
7,00541444
add a comment |
Here in country kenya you can find the related animals, of that country.
Let me know, if any changes require.
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
array.map((data,i) => {
data.map((dataKey)=>{
if(dataKey === "kenya"){
console.log(array[i])
}
})
})
answered Nov 22 '18 at 10:14
Anupam MauryaAnupam Maurya
868
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Assuming that your animal is always at index 1 you can use can use Array.prototype.filter()
and Array.prototype.map() to achieve this.
.filter() will "filter" your 2d array to only include arrays which have the country within it, then .map() will convert this 2d array to a 1d array by "replacing" all the inner arrays to be the animal (ie index 1).
See working example below:
const array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]],
filterBy = "kenya", // The contry to filter by
animals = array.filter(arr => arr[2] == filterBy).map(elem => elem[1]);
console.log(animals);answered Nov 22 '18 at 9:52
Nick ParsonsNick Parsons
5,3722721
1
Great that worked a treat.
– user142553
Nov 24 '18 at 14:33
@user142553 no worries, glad to help ;)
– Nick Parsons
Nov 24 '18 at 14:36
add a comment |
Assuming that your animal is always at index 1 you can use can use Array.prototype.filter()
and Array.prototype.map() to achieve this.
.filter() will "filter" your 2d array to only include arrays which have the country within it, then .map() will convert this 2d array to a 1d array by "replacing" all the inner arrays to be the animal (ie index 1).
See working example below:
const array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]],
filterBy = "kenya", // The contry to filter by
animals = array.filter(arr => arr[2] == filterBy).map(elem => elem[1]);
console.log(animals);answered Nov 22 '18 at 9:52
Nick ParsonsNick Parsons
5,3722721
1
Great that worked a treat.
– user142553
Nov 24 '18 at 14:33
@user142553 no worries, glad to help ;)
– Nick Parsons
Nov 24 '18 at 14:36
add a comment |
Assuming that your animal is always at index 1 you can use can use Array.prototype.filter()
and Array.prototype.map() to achieve this.
.filter() will "filter" your 2d array to only include arrays which have the country within it, then .map() will convert this 2d array to a 1d array by "replacing" all the inner arrays to be the animal (ie index 1).
See working example below:
const array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]],
filterBy = "kenya", // The contry to filter by
animals = array.filter(arr => arr[2] == filterBy).map(elem => elem[1]);
console.log(animals);answered Nov 22 '18 at 9:52
Nick ParsonsNick Parsons
5,3722721
Assuming that your animal is always at index 1 you can use can use Array.prototype.filter()
and Array.prototype.map() to achieve this.
.filter() will "filter" your 2d array to only include arrays which have the country within it, then .map() will convert this 2d array to a 1d array by "replacing" all the inner arrays to be the animal (ie index 1).
See working example below:
const array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]],
filterBy = "kenya", // The contry to filter by
animals = array.filter(arr => arr[2] == filterBy).map(elem => elem[1]);
console.log(animals);const array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]],
filterBy = "kenya", // The contry to filter by
animals = array.filter(arr => arr[2] == filterBy).map(elem => elem[1]);
console.log(animals);const array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]],
filterBy = "kenya", // The contry to filter by
animals = array.filter(arr => arr[2] == filterBy).map(elem => elem[1]);
console.log(animals);answered Nov 22 '18 at 9:52
Nick ParsonsNick Parsons
5,3722721
edited Nov 26 '18 at 10:12
answered Nov 22 '18 at 9:52
Nick ParsonsNick Parsons
5,3722721
answered Nov 22 '18 at 9:52
Nick ParsonsNick Parsons
5,3722721
answered Nov 22 '18 at 9:52
Nick ParsonsNick Parsons
5,3722721
5,3722721
1
Great that worked a treat.
– user142553
Nov 24 '18 at 14:33
@user142553 no worries, glad to help ;)
– Nick Parsons
Nov 24 '18 at 14:36
add a comment |
1
Great that worked a treat.
– user142553
Nov 24 '18 at 14:33
@user142553 no worries, glad to help ;)
– Nick Parsons
Nov 24 '18 at 14:36
1
1
Great that worked a treat.
– user142553
Nov 24 '18 at 14:33
Great that worked a treat.
– user142553
Nov 24 '18 at 14:33
@user142553 no worries, glad to help ;)
– Nick Parsons
Nov 24 '18 at 14:36
@user142553 no worries, glad to help ;)
– Nick Parsons
Nov 24 '18 at 14:36
add a comment |
You could filter the array and then map the wanted item.
This solution take the advantage of destructuring assignment, where an array is taken and the items gets a name.
var array = [["car", "dog", "kenya"], ["plane", "cat", "kenya"], ["boat", "mouse", "england"]],
result = array
.filter(([,, country]) => country === "kenya")
.map(([, animal]) => animal)
console.log(result);answered Nov 22 '18 at 9:52
Nina ScholzNina Scholz
180k1493160
add a comment |
You could filter the array and then map the wanted item.
This solution take the advantage of destructuring assignment, where an array is taken and the items gets a name.
var array = [["car", "dog", "kenya"], ["plane", "cat", "kenya"], ["boat", "mouse", "england"]],
result = array
.filter(([,, country]) => country === "kenya")
.map(([, animal]) => animal)
console.log(result);answered Nov 22 '18 at 9:52
Nina ScholzNina Scholz
180k1493160
add a comment |
You could filter the array and then map the wanted item.
This solution take the advantage of destructuring assignment, where an array is taken and the items gets a name.
var array = [["car", "dog", "kenya"], ["plane", "cat", "kenya"], ["boat", "mouse", "england"]],
result = array
.filter(([,, country]) => country === "kenya")
.map(([, animal]) => animal)
console.log(result);answered Nov 22 '18 at 9:52
Nina ScholzNina Scholz
180k1493160
You could filter the array and then map the wanted item.
This solution take the advantage of destructuring assignment, where an array is taken and the items gets a name.
var array = [["car", "dog", "kenya"], ["plane", "cat", "kenya"], ["boat", "mouse", "england"]],
result = array
.filter(([,, country]) => country === "kenya")
.map(([, animal]) => animal)
console.log(result);var array = [["car", "dog", "kenya"], ["plane", "cat", "kenya"], ["boat", "mouse", "england"]],
result = array
.filter(([,, country]) => country === "kenya")
.map(([, animal]) => animal)
console.log(result);var array = [["car", "dog", "kenya"], ["plane", "cat", "kenya"], ["boat", "mouse", "england"]],
result = array
.filter(([,, country]) => country === "kenya")
.map(([, animal]) => animal)
console.log(result);answered Nov 22 '18 at 9:52
Nina ScholzNina Scholz
180k1493160
answered Nov 22 '18 at 9:52
Nina ScholzNina Scholz
180k1493160
answered Nov 22 '18 at 9:52
Nina ScholzNina Scholz
180k1493160
answered Nov 22 '18 at 9:52
Nina ScholzNina Scholz
180k1493160
180k1493160
add a comment |
add a comment |
Looking at the code you have provided and considering that the country is always in index-2 and animals are in index-1 you can use a forEach() loop to get animals for that particular country.
var array = [
["car", "dog", "kenya"],
["plane", "cat", "kenya"],
["boat", "mouse", "england"]
];
var country = 'kenya';
var animals = ;
array.forEach((item) => {
if (item[2] === country) {
animals.push(item[1]);;
}
});
console.log(animals);answered Nov 22 '18 at 9:55
Ankit AgarwalAnkit Agarwal
23.8k52044
add a comment |
Looking at the code you have provided and considering that the country is always in index-2 and animals are in index-1 you can use a forEach() loop to get animals for that particular country.
var array = [
["car", "dog", "kenya"],
["plane", "cat", "kenya"],
["boat", "mouse", "england"]
];
var country = 'kenya';
var animals = ;
array.forEach((item) => {
if (item[2] === country) {
animals.push(item[1]);;
}
});
console.log(animals);answered Nov 22 '18 at 9:55
Ankit AgarwalAnkit Agarwal
23.8k52044
add a comment |
Looking at the code you have provided and considering that the country is always in index-2 and animals are in index-1 you can use a forEach() loop to get animals for that particular country.
var array = [
["car", "dog", "kenya"],
["plane", "cat", "kenya"],
["boat", "mouse", "england"]
];
var country = 'kenya';
var animals = ;
array.forEach((item) => {
if (item[2] === country) {
animals.push(item[1]);;
}
});
console.log(animals);answered Nov 22 '18 at 9:55
Ankit AgarwalAnkit Agarwal
23.8k52044
Looking at the code you have provided and considering that the country is always in index-2 and animals are in index-1 you can use a forEach() loop to get animals for that particular country.
var array = [
["car", "dog", "kenya"],
["plane", "cat", "kenya"],
["boat", "mouse", "england"]
];
var country = 'kenya';
var animals = ;
array.forEach((item) => {
if (item[2] === country) {
animals.push(item[1]);;
}
});
console.log(animals);var array = [
["car", "dog", "kenya"],
["plane", "cat", "kenya"],
["boat", "mouse", "england"]
];
var country = 'kenya';
var animals = ;
array.forEach((item) => {
if (item[2] === country) {
animals.push(item[1]);;
}
});
console.log(animals);var array = [
["car", "dog", "kenya"],
["plane", "cat", "kenya"],
["boat", "mouse", "england"]
];
var country = 'kenya';
var animals = ;
array.forEach((item) => {
if (item[2] === country) {
animals.push(item[1]);;
}
});
console.log(animals);answered Nov 22 '18 at 9:55
Ankit AgarwalAnkit Agarwal
23.8k52044
answered Nov 22 '18 at 9:55
Ankit AgarwalAnkit Agarwal
23.8k52044
answered Nov 22 '18 at 9:55
Ankit AgarwalAnkit Agarwal
23.8k52044
answered Nov 22 '18 at 9:55
Ankit AgarwalAnkit Agarwal
23.8k52044
23.8k52044
add a comment |
add a comment |
You can create a generic function which gets the index of what type you want to filter ('2' for countries) and the value you want to match ('kenya' for example)
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
const FILTER_TYPE = { vehicle: 0, animal: 1, country: 2 }
const filter_by = (index, value) => (array.filter(item => (item[index] === value)).map(item => item[FILTER_TYPE.animal]))
console.log(filter_by(FILTER_TYPE.country, 'kenya'))answered Nov 22 '18 at 9:52
omri_saadonomri_saadon
7,00541444
add a comment |
You can create a generic function which gets the index of what type you want to filter ('2' for countries) and the value you want to match ('kenya' for example)
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
const FILTER_TYPE = { vehicle: 0, animal: 1, country: 2 }
const filter_by = (index, value) => (array.filter(item => (item[index] === value)).map(item => item[FILTER_TYPE.animal]))
console.log(filter_by(FILTER_TYPE.country, 'kenya'))answered Nov 22 '18 at 9:52
omri_saadonomri_saadon
7,00541444
add a comment |
You can create a generic function which gets the index of what type you want to filter ('2' for countries) and the value you want to match ('kenya' for example)
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
const FILTER_TYPE = { vehicle: 0, animal: 1, country: 2 }
const filter_by = (index, value) => (array.filter(item => (item[index] === value)).map(item => item[FILTER_TYPE.animal]))
console.log(filter_by(FILTER_TYPE.country, 'kenya'))answered Nov 22 '18 at 9:52
omri_saadonomri_saadon
7,00541444
You can create a generic function which gets the index of what type you want to filter ('2' for countries) and the value you want to match ('kenya' for example)
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
const FILTER_TYPE = { vehicle: 0, animal: 1, country: 2 }
const filter_by = (index, value) => (array.filter(item => (item[index] === value)).map(item => item[FILTER_TYPE.animal]))
console.log(filter_by(FILTER_TYPE.country, 'kenya'))array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
const FILTER_TYPE = { vehicle: 0, animal: 1, country: 2 }
const filter_by = (index, value) => (array.filter(item => (item[index] === value)).map(item => item[FILTER_TYPE.animal]))
console.log(filter_by(FILTER_TYPE.country, 'kenya'))array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
const FILTER_TYPE = { vehicle: 0, animal: 1, country: 2 }
const filter_by = (index, value) => (array.filter(item => (item[index] === value)).map(item => item[FILTER_TYPE.animal]))
console.log(filter_by(FILTER_TYPE.country, 'kenya'))answered Nov 22 '18 at 9:52
omri_saadonomri_saadon
7,00541444
edited Nov 22 '18 at 10:02
answered Nov 22 '18 at 9:52
omri_saadonomri_saadon
7,00541444
answered Nov 22 '18 at 9:52
omri_saadonomri_saadon
7,00541444
answered Nov 22 '18 at 9:52
omri_saadonomri_saadon
7,00541444
7,00541444
add a comment |
add a comment |
Here in country kenya you can find the related animals, of that country.
Let me know, if any changes require.
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
array.map((data,i) => {
data.map((dataKey)=>{
if(dataKey === "kenya"){
console.log(array[i])
}
})
})
answered Nov 22 '18 at 10:14
Anupam MauryaAnupam Maurya
868
add a comment |
Here in country kenya you can find the related animals, of that country.
Let me know, if any changes require.
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
array.map((data,i) => {
data.map((dataKey)=>{
if(dataKey === "kenya"){
console.log(array[i])
}
})
})
answered Nov 22 '18 at 10:14
Anupam MauryaAnupam Maurya
868
add a comment |
Here in country kenya you can find the related animals, of that country.
Let me know, if any changes require.
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
array.map((data,i) => {
data.map((dataKey)=>{
if(dataKey === "kenya"){
console.log(array[i])
}
})
})
answered Nov 22 '18 at 10:14
Anupam MauryaAnupam Maurya
868
Here in country kenya you can find the related animals, of that country.
Let me know, if any changes require.
array = [["car","dog","kenya"],["plane", "cat", "kenya"],["boat", "mouse", "england"]]
array.map((data,i) => {
data.map((dataKey)=>{
if(dataKey === "kenya"){
console.log(array[i])
}
})
})
answered Nov 22 '18 at 10:14
Anupam MauryaAnupam Maurya
868
answered Nov 22 '18 at 10:14
Anupam MauryaAnupam Maurya
868
answered Nov 22 '18 at 10:14
Anupam MauryaAnupam Maurya
868
answered Nov 22 '18 at 10:14
Anupam MauryaAnupam Maurya
868
868
add a comment |
add a comment |
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do you have tried something? please add your code.
– Nina Scholz
Nov 22 '18 at 9:50
1
Arrays have keys: We normally call them indexes. In your example, the country appears to always be at index 2.
– T.J. Crowder
Nov 22 '18 at 9:50