Ytukyg

I am going through basics of C# and .NET programming. I have a for loop as shown below.

for(var i = minHour; i <= maxHour; i++)

When i replace the above as:

for(var i = minHour; i <= maxHour; i+=0.5)

then i see an error as:

Cannot implicitly convert type double to int.

I do not want to declare i as of type double, please help. I do not know anything about implicit conversion.

Can someone please help me how do I correct this,thanks in advance.

I am not sure I follow why you want to keep using var for this situation instead of simply defining double i = which would solve your problem, but because you specified it in your question, I will ignore that for now.

Instead, let's take a look at why it is throwing this error in the first place. You are using var i = to define your variable, which you might think simply puts i into a generic variable. This isn't accurate in C#. Instead, C# will attempt to infer the type of this variable and because you are using var i = minHour the type of i is being inferred by the type of minHour.

You have a few options to fix this issue:

1. You can change minHour to be a double, which will solve this problem.


2. You can cast minHour as a double like so: var i = (double)minHour
   


3. You can do what you probably should and specify it when you declare i as so: double i = minHour
   

I hope this helps!

You can solve it like this:

//beware when using i as indexer.

for(var i = minHour * 2; i <= maxHour * 2; i++)

//note: both minHour and maxHour need to be multiplied by 2

//Proof:

// n = maxHour - minHour =>

// 2 n = 2 (maxHour - minHour) =>

// (maxHour - minHour) * 2 = 2 * maxHour - 2 * minHour

//

Or, alternatively:

//type changed to double:

double minHour = 0, maxHour = 1;

for(var i = minHour; i <= maxHour; i+=0.5)

Or better (but not your favorite);

for(double i = minHour; i <= maxHour; i+=0.5)

In the two examples, the variable i is being initialized to minHour. The compiler will infer the type from that statement alone, not any other usage. Presumably minHour is an int, so in both examples i is an int. Since it is an int the error message should now make more sense.

Note that var isn't some kind of dynamic type, which I suspect is the source of your misunderstanding. It is a known, fixed typed whose type is decided at compile time from its usage. So in both examples they are the equivalent of having the word var replaced by int. If you explicitly declare it as a double it will do what you want.

Tip: if you want to know what type the var will be, hover over it with the mouse.