PHP ~ Check if a date occurs during the next (proper) week












0















I've searched for this one, and I have a solution that gets dates for Monday and Friday (only looking for working week) of next week, and then checks if my date falls within that range. It works.



<?php
$check_count = 0 ;
$check_date = 20181127 ;

if ( $check_date >= date ( 'Ymd' , strtotime ( 'monday next week' ) ) &&
$check_date <= date ( 'Ymd' , strtotime ( 'friday next week' ) ) ) {

// DATE IS NEXT WEEK
echo 'Next week!' ;
$check_count++ ;

}
?>


But I would like to know if there is a one-liner of sorts, which can take a date ( 'Ymd' ) and see if it occurs "next week."



Any help will be much appreciated.



Thanks,
furi0usBee










share|improve this question

























  • Please add your current code.

    – user3783243
    Nov 24 '18 at 17:19











  • Please use the edit function, stackoverflow.com/posts/53460560/edit.

    – user3783243
    Nov 24 '18 at 17:25











  • Isn't that already a one liner? Do you mean a single function?

    – user3783243
    Nov 24 '18 at 17:27











  • I'm actually looking to check a date that falls within Monday - Friday of the next week, not through Sunday, per the code. Sorry about that. Rough start to my account here LOL.

    – furi0usBee
    Nov 24 '18 at 17:29











  • Rather than having to get a start/finish date for next week, I though maybe there was just a single check, such as date_interval ( "+1 weeks") or something to that effect.

    – furi0usBee
    Nov 24 '18 at 17:31
















0















I've searched for this one, and I have a solution that gets dates for Monday and Friday (only looking for working week) of next week, and then checks if my date falls within that range. It works.



<?php
$check_count = 0 ;
$check_date = 20181127 ;

if ( $check_date >= date ( 'Ymd' , strtotime ( 'monday next week' ) ) &&
$check_date <= date ( 'Ymd' , strtotime ( 'friday next week' ) ) ) {

// DATE IS NEXT WEEK
echo 'Next week!' ;
$check_count++ ;

}
?>


But I would like to know if there is a one-liner of sorts, which can take a date ( 'Ymd' ) and see if it occurs "next week."



Any help will be much appreciated.



Thanks,
furi0usBee










share|improve this question

























  • Please add your current code.

    – user3783243
    Nov 24 '18 at 17:19











  • Please use the edit function, stackoverflow.com/posts/53460560/edit.

    – user3783243
    Nov 24 '18 at 17:25











  • Isn't that already a one liner? Do you mean a single function?

    – user3783243
    Nov 24 '18 at 17:27











  • I'm actually looking to check a date that falls within Monday - Friday of the next week, not through Sunday, per the code. Sorry about that. Rough start to my account here LOL.

    – furi0usBee
    Nov 24 '18 at 17:29











  • Rather than having to get a start/finish date for next week, I though maybe there was just a single check, such as date_interval ( "+1 weeks") or something to that effect.

    – furi0usBee
    Nov 24 '18 at 17:31














0












0








0








I've searched for this one, and I have a solution that gets dates for Monday and Friday (only looking for working week) of next week, and then checks if my date falls within that range. It works.



<?php
$check_count = 0 ;
$check_date = 20181127 ;

if ( $check_date >= date ( 'Ymd' , strtotime ( 'monday next week' ) ) &&
$check_date <= date ( 'Ymd' , strtotime ( 'friday next week' ) ) ) {

// DATE IS NEXT WEEK
echo 'Next week!' ;
$check_count++ ;

}
?>


But I would like to know if there is a one-liner of sorts, which can take a date ( 'Ymd' ) and see if it occurs "next week."



Any help will be much appreciated.



Thanks,
furi0usBee










share|improve this question
















I've searched for this one, and I have a solution that gets dates for Monday and Friday (only looking for working week) of next week, and then checks if my date falls within that range. It works.



<?php
$check_count = 0 ;
$check_date = 20181127 ;

if ( $check_date >= date ( 'Ymd' , strtotime ( 'monday next week' ) ) &&
$check_date <= date ( 'Ymd' , strtotime ( 'friday next week' ) ) ) {

// DATE IS NEXT WEEK
echo 'Next week!' ;
$check_count++ ;

}
?>


But I would like to know if there is a one-liner of sorts, which can take a date ( 'Ymd' ) and see if it occurs "next week."



Any help will be much appreciated.



Thanks,
furi0usBee







php date time compare






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 17:34







furi0usBee

















asked Nov 24 '18 at 17:13









furi0usBeefuri0usBee

62




62













  • Please add your current code.

    – user3783243
    Nov 24 '18 at 17:19











  • Please use the edit function, stackoverflow.com/posts/53460560/edit.

    – user3783243
    Nov 24 '18 at 17:25











  • Isn't that already a one liner? Do you mean a single function?

    – user3783243
    Nov 24 '18 at 17:27











  • I'm actually looking to check a date that falls within Monday - Friday of the next week, not through Sunday, per the code. Sorry about that. Rough start to my account here LOL.

    – furi0usBee
    Nov 24 '18 at 17:29











  • Rather than having to get a start/finish date for next week, I though maybe there was just a single check, such as date_interval ( "+1 weeks") or something to that effect.

    – furi0usBee
    Nov 24 '18 at 17:31



















  • Please add your current code.

    – user3783243
    Nov 24 '18 at 17:19











  • Please use the edit function, stackoverflow.com/posts/53460560/edit.

    – user3783243
    Nov 24 '18 at 17:25











  • Isn't that already a one liner? Do you mean a single function?

    – user3783243
    Nov 24 '18 at 17:27











  • I'm actually looking to check a date that falls within Monday - Friday of the next week, not through Sunday, per the code. Sorry about that. Rough start to my account here LOL.

    – furi0usBee
    Nov 24 '18 at 17:29











  • Rather than having to get a start/finish date for next week, I though maybe there was just a single check, such as date_interval ( "+1 weeks") or something to that effect.

    – furi0usBee
    Nov 24 '18 at 17:31

















Please add your current code.

– user3783243
Nov 24 '18 at 17:19





Please add your current code.

– user3783243
Nov 24 '18 at 17:19













Please use the edit function, stackoverflow.com/posts/53460560/edit.

– user3783243
Nov 24 '18 at 17:25





Please use the edit function, stackoverflow.com/posts/53460560/edit.

– user3783243
Nov 24 '18 at 17:25













Isn't that already a one liner? Do you mean a single function?

– user3783243
Nov 24 '18 at 17:27





Isn't that already a one liner? Do you mean a single function?

– user3783243
Nov 24 '18 at 17:27













I'm actually looking to check a date that falls within Monday - Friday of the next week, not through Sunday, per the code. Sorry about that. Rough start to my account here LOL.

– furi0usBee
Nov 24 '18 at 17:29





I'm actually looking to check a date that falls within Monday - Friday of the next week, not through Sunday, per the code. Sorry about that. Rough start to my account here LOL.

– furi0usBee
Nov 24 '18 at 17:29













Rather than having to get a start/finish date for next week, I though maybe there was just a single check, such as date_interval ( "+1 weeks") or something to that effect.

– furi0usBee
Nov 24 '18 at 17:31





Rather than having to get a start/finish date for next week, I though maybe there was just a single check, such as date_interval ( "+1 weeks") or something to that effect.

– furi0usBee
Nov 24 '18 at 17:31












1 Answer
1






active

oldest

votes


















0














Hi furi0usBee and welcome to stackoverflow,



you could shorten your if-statement a little by using the date_format function to check for the week number ('W') and the ISO day of the week ('N').



To use the date_format function you have to create a DateTime object from your Ymd date:



<?php
$check_count = 0 ;
$check_date = 20181127 ;

$objDate = new DateTime($check_date);

if ( date('W', strtotime('monday next week')) == date_format($objDate, 'W')
&& date_format($objDate, 'N') < 6 ) {

// DATE IS NEXT WEEK
echo 'Next week!' ;
$check_count++ ;
}
?>


The code looks a bit cleaner with this.






share|improve this answer























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53460560%2fphp-check-if-a-date-occurs-during-the-next-proper-week%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Hi furi0usBee and welcome to stackoverflow,



    you could shorten your if-statement a little by using the date_format function to check for the week number ('W') and the ISO day of the week ('N').



    To use the date_format function you have to create a DateTime object from your Ymd date:



    <?php
    $check_count = 0 ;
    $check_date = 20181127 ;

    $objDate = new DateTime($check_date);

    if ( date('W', strtotime('monday next week')) == date_format($objDate, 'W')
    && date_format($objDate, 'N') < 6 ) {

    // DATE IS NEXT WEEK
    echo 'Next week!' ;
    $check_count++ ;
    }
    ?>


    The code looks a bit cleaner with this.






    share|improve this answer




























      0














      Hi furi0usBee and welcome to stackoverflow,



      you could shorten your if-statement a little by using the date_format function to check for the week number ('W') and the ISO day of the week ('N').



      To use the date_format function you have to create a DateTime object from your Ymd date:



      <?php
      $check_count = 0 ;
      $check_date = 20181127 ;

      $objDate = new DateTime($check_date);

      if ( date('W', strtotime('monday next week')) == date_format($objDate, 'W')
      && date_format($objDate, 'N') < 6 ) {

      // DATE IS NEXT WEEK
      echo 'Next week!' ;
      $check_count++ ;
      }
      ?>


      The code looks a bit cleaner with this.






      share|improve this answer


























        0












        0








        0







        Hi furi0usBee and welcome to stackoverflow,



        you could shorten your if-statement a little by using the date_format function to check for the week number ('W') and the ISO day of the week ('N').



        To use the date_format function you have to create a DateTime object from your Ymd date:



        <?php
        $check_count = 0 ;
        $check_date = 20181127 ;

        $objDate = new DateTime($check_date);

        if ( date('W', strtotime('monday next week')) == date_format($objDate, 'W')
        && date_format($objDate, 'N') < 6 ) {

        // DATE IS NEXT WEEK
        echo 'Next week!' ;
        $check_count++ ;
        }
        ?>


        The code looks a bit cleaner with this.






        share|improve this answer













        Hi furi0usBee and welcome to stackoverflow,



        you could shorten your if-statement a little by using the date_format function to check for the week number ('W') and the ISO day of the week ('N').



        To use the date_format function you have to create a DateTime object from your Ymd date:



        <?php
        $check_count = 0 ;
        $check_date = 20181127 ;

        $objDate = new DateTime($check_date);

        if ( date('W', strtotime('monday next week')) == date_format($objDate, 'W')
        && date_format($objDate, 'N') < 6 ) {

        // DATE IS NEXT WEEK
        echo 'Next week!' ;
        $check_count++ ;
        }
        ?>


        The code looks a bit cleaner with this.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 24 '18 at 22:53









        digijaydigijay

        5861715




        5861715
































            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53460560%2fphp-check-if-a-date-occurs-during-the-next-proper-week%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Wiesbaden

            Marschland

            Dieringhausen